Write a multiplication equation and a subtraction equation that both involve a fraction and have the same solution. Solve your equation to show that the solution are the same.

Answer:

Quotient =(3x²-5x-1)  and reminder = 1

Step-by-step explanation:

[tex]\frac{9x^3-18x^2+2x+2}{3x-1}[/tex]

3x-1)9x³-18x²+2x+2(3x²-5x-1

      9x³-3x²

    ------------------------

          -15x²+2x+2

          -15x²+5x

           ------------------

                  -3x+2

                   -3x+1

                    --------

                         1

Therefore 9x³-18x²+2x+2=(3x²-5x-1)(3x-1)+1

Quotient =(3x²-5x-1)  and reminder = 1

Answer:

Step-by-step explanation:

Since 8^2+15^2 = 289 and 17^2 = 289 then 8^2+15^2 = 17^2

8^2+15^2 = 17^2 Then according to the reciprocal of the Pythagorean theorem

it’s a right triangle

Answer:

YES

Step-by-step explanation:

Answer: 8%

Step-by-step explanation: 370 * 8% = 29.60

Answer: 8% sales tax rate

Step-by-step explanation:

First, you need to find what percentage 29.60 is from 370, so you divide 29.60 by 370 and you get 0.08 then you multiply that by 100 to get your answer in percent. 100 multiplied by 0.08 would be 8%.

6 3/11 that well be the answer

Answer:6 3/5

Step-by-step explanation: 10 2/5 - 3 4/5 = 33

5

= 63

5

= 6.6

Answer:

18.19

Step-by-step explanation:

$20-15%=$17

$17+7%=18.19

Lin's father pays $18.19 for the meal after the 15% discount and 7% sales tax.

To find out what Lin's father pays for the meal after the discount and sales tax, we need to follow these steps:

Let's apply these steps to the given information:

Step 1: Discount amount = $20 x 15% = $3

Step 2: Discounted price = $20 - $3 = $17

Step 3: Sales tax amount = $17 x 7% = $1.19

Step 4: Total amount paid = $17 + $1.19 = $18.19

Therefore, Lin's father pays $18.19 for the meal after the discount and sales tax.

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Step-by-step explanation:

We find,

[tex](x+2y)^7[/tex]

To find, the binomial expansion of of [tex](x+2y)^7[/tex] = ?

We know that,

[tex](x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n[/tex]

∴ [tex](x+2y)^7[/tex]

Here, n = 7, x = x and y = 2y

[tex](x+2y)^7[/tex]= [tex]^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7[/tex][tex]=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7[/tex]

[tex]=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7[/tex]

∴ The binomial expansion of of [tex](x+2y)^7[/tex]

[tex]=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7[/tex]

Thus, the required "option 4)"  is correct.

Answer:

D. x7 + 14x6y + 84x5y2 + 280x4y3 + 560x3y4 + 672x2y5 + 448xy6 + 128y7

Step-by-step explanation:

Answer:

s = 5/4

Step-by-step explanation:

Solve for s:

86 = 8 s + 76

86 = 8 s + 76 is equivalent to 8 s + 76 = 86:

8 s + 76 = 86

Subtract 76 from both sides:

8 s + (76 - 76) = 86 - 76

76 - 76 = 0:

8 s = 86 - 76

86 - 76 = 10:

8 s = 10

Divide both sides of 8 s = 10 by 8:

(8 s)/8 = 10/8

8/8 = 1:

s = 10/8

The gcd of 10 and 8 is 2, so 10/8 = (2×5)/(2×4) = 2/2×5/4 = 5/4:

Answer:  s = 5/4

Answer: s = 1.25

Step-by-step explanation:

Answer:

120.6

Step-by-step explanation:

Since we know that 67 percent of coins are quarters.

Total coins = 180

67% of 180= 180 * 67/100

120.6.

So he has about 120.6 quarters.

Answer:

126 quarters

Step-by-step explanation:

67% ≈ 70%

70% = 70/100

70% = 7/10

180 * 7/10 = 126 quarters

Answer:

y=(x+1)(x-1)(x+8)

Step-by-step explanation:

When creating a factor with a known zero, use (x-ZERO)

For instance: a zero of -1 would be reprsented as (x+1)

Answer:

One triangle

Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Verify the length sides of triangle

Applying the triangle inequality theorem

1) 3+5 > 6 ---> is true

2) 3+6 > 5 ---> is true

3) 5+6> 3----> is true

therefore

One triangle can be drawn with the given lengths

With side lengths of 3 inches, 5 inches, and 6 inches, only one triangle can be drawn as these dimensions meet the triangle inequality theorem, allowing for the creation of one unique triangle.

The question is about determining if a triangle can be constructed with given side lengths. According to the triangle inequality theorem, the sum of the lengths of any two sides of a triangle must be greater than the third side. In this case, the side lengths are 3 inches, 5 inches, and 6 inches.

Adding the lengths of the two shorter sides, 3 inches + 5 inches = 8 inches, which is greater than the length of the longest side, 6 inches. This means a triangle with these side lengths can be drawn. However, it is important to note that the lengths provided can only create one unique triangle, since the lengths are fixed and there can't be another triangle with different angles with the same side lengths.

Therefore, with side lengths of 3 inches, 5 inches, and 6 inches, exactly one triangle can be drawn.

Answer:

x= - 3.5

y= - 6.5

Step-by-step explanation:

-3x+y = 4 equation 1

-9x + 5y = -1 equation 2

and

equation 1 can be written as

y = 4+ 3x

so put this in equation 2

-9x + 5 ( 4+ 3x) = -1

-9x +20 +15x = -1

6x = -21

X= -21 ÷ 6

X = - 3.5

so put this value of x in equation 1 to find value of y

-3 ( -3.5) + y = 4

10.5 + y = 4

y = 4 - 10.5

Y = - 6.5

Answer:

x= - 3.5

y= - 6.5-

Answer:

4

Step-by-step explanation:

Answer:

Scalene triangle

Step-by-step explanation:

It is a scalene triangle because none of the sides are equal .equilateral triangle have the three sides equal. isosceles triangle have only two equal sides

Answer:

Step-by-step explanation:

 ∠ABC =   ∠ DEF         {GIVEN}

            =      ∠GHI      {   ∠DEF =   ∠GHI - given}

 ∠ ABC =  ∠GHI

Answer:

20

Step-by-step explanation:

-4/-0.2

When dividing numbers with the same sign, the result is always positive. In this case, -4 divided by -0.2 is equal to 20.

When dividing numbers with the same sign, the result is always positive. In this case, -4 divided by -0.2 is equal to 20.

Answer:

hotdog is $7.50

Step-by-step explanation:

hotdog = d soda = s

s + 2.5 = d

2d + s = 20

3s + 5 = 20

s = 5

5 + 2.5 = d

7.5 = d

Answer:

[tex]y=3x[/tex]

Step-by-step explanation:

Let

x ----> the number of kids in a group

y ----> the total number of caramel chews Erica gives to that group

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]

Find the value of the constant of proportionality k

take a ordered pair from the data in the table and determine the value of k

For x=2, y=6 ----> [tex]k=\frac{y}{x}[/tex] ----> [tex]k=\frac{6}{2}=3\ caramels/kid[/tex]

therefore

[tex]y=3x[/tex]

180 is the speed of the motorboat. I don't know the speed of the current.

........................................

120÷4=30

30×6=180

Answer:

49.5

Step-by-step explanation: 11x9=99/2

Answer: 19 and 31

Step-by-step explanation: Make the first number x, the second number y.

The sum of x and y is 50: x+y=50

x is 43 less than 2y: x=2y-43

replace x in equation x+y=50 with x=2y-43: 2y-43+y=50

combine like terms: 3y-43=50

add 43 to both sides: 3y=93

divide both sides by 3: y=31

replace y in equation x+y=50 with y=31: x+31=50

subtract 43 31 from both sides: x=19

the solution to the question is the first number is 19, the second number is 31

The two numbers that sum up to 50 with one being 43 less than twice the other, we set up a system of equations, solve for one variable, and then substitute it back into the other equation, resulting in the numbers 19 and 31.

The question asks us to find two numbers whose sum is 50 and where the first number is 43 less than twice the second number. To solve this, we can create a system of equations to represent the given conditions. Let the first number be x and the second number be y.

According to the question, the sum of the two numbers is 50, which gives us our first equation:

x + y = 50 (Equation 1)

The first number x is 43 less than twice the second number y. This provides the second equation:

x = 2y - 43 (Equation 2)

We now have a simple system of two linear equations:

x + y = 50

x = 2y - 43

We can substitute the second equation into the first to solve for y:

(2y - 43) + y = 50

3y - 43 = 50

Add 43 to both sides:

3y = 93

Divide both sides by 3:

y = 31

We can now substitute y = 31 back into Equation 2 to find x:

x = 2(31) - 43

x = 62 - 43

x = 19

Therefore, the two numbers are 19 and 31.

Answer: x = -6, and y = -6  (-6, -6)

Step-by-step explanation: What we have here is a pair of simultaneous equations. Since we have been instructed to solve by substitution, we shall begin with the one which has one of the variables as having a coefficient of 1. We shall start with equation 2 which is,

y = 2x + 6

Having taken note of this, we can now go on to the other equation and substitute for the value of y.

Hence, from equation 1,

4x - 4y = 0 (substitute for the value of y)

4x - 4(2x + 6) = 0

4x - 8x - 24 = 0

-4x -24 = 0

Add 24 to both sides of the equation

-4x = 24

Divide both sides of the equation by -4

x = -6

Having calculated the value of x, we can now go on to substitute for the value of x in equation 2.

Therefore,

y = 2x + 6

y = 2(-6) + 6

y = -12 + 6

y = -6.

So, x = -6 and y = -6

x + (-4) = 10.

We can use the positive - negative rule.

x + (-4) = 10.

x - 4 = 10.

x = 10 + 4

x = 14.

Answer:

E

Step-by-step explanation:

Given the system of two equations:

[tex]\left\{\begin{array}{l}\dfrac{2}{3}x-\dfrac{1}{2}y=1\\ \\-\dfrac{4}{3}x+y=-3\end{array}\right.[/tex]

Multiply the first equation by 6 and the second equation by 3 to eliminate fractions:

[tex]\left\{\begin{array}{l}4}x-3y=6\\ \\-4x+3y=-9\end{array}\right.[/tex]

Add these two equations:

[tex]4x-3y-4x+3y=6-9\\ \\0=-3[/tex]

You get false equality [tex](0\neq -9)[/tex], so the system of two equations has no solution (two equations represent parallel lines)

Answer:

A, D, E

Step-by-step explanation:

[tex]y = 48.28(1.06)^t[/tex] is the model giving the annual price p (in dollars) of a ticket t in years after 2000 is found

Solution:

Given that,

In 2000, the average price of a football ticket for a Minnesota Vikings game was $48.28

During the next 20 years, the price increased an average of 6% each year

The increasing function is given by:

[tex]y = a(1+r)^t[/tex]

Where,

y is the value after t years

t is the number of years

a is the initial value

r is rate of increase in decimal

From given,

a = 48.28

[tex]r = 6 \% = \frac{6}{100} = 0.06[/tex]

Substituting the values we get,

[tex]y = 48.28(1+0.06)^t\\\\y = 48.28(1.06)^t[/tex]

Thus the model giving the annual price p (in dollars) of a ticket t in years after 2000 is found

Answer:

4/7

Step-by-step explanation:

1/6-8/6=-7/6

-[1/6-8/6]=7/6

---------------------

(2/3)/(7/6)=(2/3)(6/7)=12/21=4/7

[tex]\boxed{g(x)=2x^2+31x+130}[/tex]

Hello! Remember to write complete questions in order to get good and exact answers. Here you haven't provided any quadratic equation, so I could help you in a general way. A quadratic equation is given by the form:

[tex]f(x)=ax^2+bx+c \\ \\ a,b,c \ constant \ and \ a\neq 0[/tex]

Suppose you have the following quadratic equation:

[tex]f(x)=2x^2+3x+6[/tex]

Perform the following transformation:

Then, we get:

[tex]g(x)=2(x+\mathbf{7})^2+3(x+\mathbf{7})+6+\mathbf{5}[/tex]

[tex]\left(x+7\right)^2:\quad x^2+14x+49 \\ \\ g(x)=2\left(x^2+14x+49\right)+3\left(x+7\right)+6+5 \\ \\ \\ g(x)=\:2x^2+28x+98+3x+21+6+5 \\ \\ \boxed{g(x)=2x^2+31x+130}[/tex]

Transformations to solve real life problems: https://brainly.com/question/1033817

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