Walk from home to the bus stop at the average speed of 5 km an hour he immediately got on the school bus and traveled at an average speed of 60 hour until he got the total distance from her is 35 km and the entire trip 1.5 hours how many kilometers did your Canon covered by walking and how many kilometers did you cover by traveling on the bus

Answers

Answer 1

Answer:

5 km walking, 30 km on the bus.

Step-by-step explanation:

Let

w

be the distance walking and

b

be the distance on the bus.

The total distance is 35 km.

w

+

b

=

35

The total time is 1.5 hours. Each leg has time equal to distance/speed.

w

5

+

b

60

=

1.5

Multiply by 60 to clear the fractions.

12

w

+

b

=

90

Subtract the first equation,

11

w

=

90

35

=

55

w

=

5

b

=

30

Check:


Related Questions

At Jefferson High School, there are 325 students who drive to school 400 students that ride the bus to school. The number of students who drive to school is % of the number of students who ride the bus to school.

Answers

Answer:

81.25%

Step-by-step explanation:

Given: There are 325 students who drive to school.

           There are 400 students that ride the bus to school.

           

Now, finding percentage of the number of student who drive to school over number of students who ride the bus to school.

Percentage of student who drive to school= [tex]\frac{325}{400} \times 100[/tex]

⇒ Percentage of student who drive to school= [tex]\frac{325}{4}[/tex]

⇒ Percentage of student who drive to school= [tex]81.25\%[/tex]

Hence, 81.25% is the percent of students who drive to school on the number of students who ride the bus to school.

A rain gutter is made from sheets of aluminum that are 16 inches wide by turning up the edges to form right angles. Determine the depth of the gutter that will maximize its​ cross- sectional area and allow the greatest amount of water to flow. What is the maximum​ cross-sectional area?

Answers


Final answer:

The depth of the gutter that will maximize its cross-sectional area is 4 inches, and the maximum cross-sectional area that allows the greatest amount of water to flow is 32 square inches.

Explanation:

To determine the depth of the gutter that will maximize its cross-sectional area, we first need to assume that turning up the edges of the aluminum sheet at right angles will form a rectangular cross-section. If the width of the aluminum is 16 inches and 'x' represents the depth of the gutter (the height of the sides when bent), the width of the base of the gutter will be 16 - 2x (since both sides are turned up).

This means the cross-sectional area 'A' in square inches will be A = x(16 - 2x). This is a quadratic equation and can be expanded as A = -2x^2 + 16x. To find the maximum area, we need to find the vertex of this parabola, which occurs at x = -b/(2a), where 'a' is the coefficient of x^2 and 'b' is the coefficient of 'x'.

In our case, a = -2 and b = 16, so the depth that maximizes the area is x = -16/(2*(-2)) = 4 inches. Therefore, the maximum cross-sectional area is A = 4(16 - 2*4) = 4(8) = 32 square inches.

The depth of the gutter that will maximize its cross-sectional area is 16 inches, and the maximum cross-sectional area is[tex]\( 768 \)[/tex] square inches.

To solve this problem, we will use calculus to find the depth of the gutter that maximizes its cross-sectional area. We will start by defining the dimensions of the gutter and then use the derivative of the area function to find the critical points. Finally, we will determine which of these critical points gives the maximum area.

Let's denote the depth of the gutter as [tex]\( x \)[/tex]inches. Since the width of the aluminum sheets is 16 inches, the base of the gutter will also be 16 inches. When the edges are turned up to form right angles, the gutter will have a rectangular base and two rectangular sides.

 The area of the base of the gutter is [tex]\( 16x \)[/tex]. The area of each side is [tex]\( x^2 \),[/tex] and there are two sides, so the total area of the sides is[tex]\( 2x^2 \).[/tex] Therefore, the total cross-sectional area [tex]\( A \)[/tex]of the gutter is the sum of the area of the base and the areas of the two sides:

[tex]\[ A(x) = 16x + 2x^2 \][/tex]

To find the depth that maximizes the area, we need to take the derivative of [tex]\( A(x) \)[/tex] with respect to[tex]\( x \)[/tex]and set it equal to zero:

[tex]\[ A'(x) = \frac{d}{dx}(16x + 2x^2) = 16 + 4x \][/tex]

 Setting [tex]\( A'(x) \)[/tex] equal to zero gives us the critical points:

[tex]\[ 16 + 4x = 0 \][/tex]

[tex]\[ 4x = -16 \][/tex]

[tex]\[ x = -4 \][/tex]

Since the depth of the gutter cannot be negative, we discard[tex]\( x = -4 \)[/tex]and realize that we need to consider the physical constraints of the problem. The actual critical point occurs at the endpoint of the domain of [tex]\( x \),[/tex]which is[tex]\( x = 0 \)[/tex](no gutter) or[tex]\( x = 16 \)[/tex] (the gutter's width). Since[tex]\( x = 0 \)[/tex]gives a minimum area (no gutter at all), the maximum area must occur at [tex]( x = 16 \).[/tex]

 Now, we calculate the cross-sectional area at [tex]\( x = 16 \)[/tex]

[tex]\[ A(16) = 16(16) + 2(16)^2 \][/tex]

[tex]\[ A(16) = 256 + 2(256) \][/tex]

[tex]\[ A(16) = 256 + 512 \][/tex]

[tex]\[ A(16) = 768 \][/tex]

 Therefore, the maximum cross-sectional area of the gutter is[tex]\( 768 \)[/tex]square inches when the depth is equal to the width, which is 16 inches.

Sammy and kaden went fishing using live shrimp as bait. Sammy brought 8 more shrimp than kaden brought. When they combined their shrimp they had 32 shrimp altogether. How many shrimp did each boy bring

Answers

Answer: kaeden brough 12 sammy brought 20

Step-by-step explanation:

i know that 16+16=32 and

15+17=32 and

14+18=32 and

13+19= 32 and

12+20=32. it’s gonna be 12 and 20 because those numbers add up to 32 and are 8 away from each other. since sammy had more fish he brought 20 and kaeden brough 12.

Final answer:

Kaden brought 12 shrimp and Sammy brought 20 shrimp to their fishing trip. This was determined by solving an algebraic equation set up based on the given information.

Explanation:

The question involves Sammy and Kaden, who went fishing and brought live shrimp as bait. Sammy brought 8 more shrimp than Kaden. Together, they had 32 shrimp. To solve for how many shrimp each boy brought, we can set up algebraic equations. Let the number of shrimp Kaden brought be represented by k, hence Sammy brought k + 8 shrimp. Adding together the shrimp both boys brought gives us:

k + (k + 8) = 32

Simplifying the equation:

2k + 8 = 32

2k = 32 - 8

2k = 24

k = 24 / 2

k = 12

Kaden brought 12 shrimp and Sammy brought 12 + 8 shrimp, which equals 20 shrimp.

So, Kaden brought 12 shrimp, and Sammy brought 20 shrimp.

Tesha withdrew $22.75 each weak for four weeks from her savings account to pay for her piano lessons. By how much did these lessons change her savings account balance

Answers

Final answer:

Tesha's savings account balance was decreased by $91.00 after withdrawing $22.75 each week for four weeks to pay for piano lessons.

Explanation:

To calculate the change in Tesha's savings account balance due to payment for her piano lessons, we need to multiply the weekly withdrawal amount by the number of weeks. Tesha withdrew $22.75 each week for four weeks.

Multiply the weekly withdrawal amount by the number of weeks: $22.75 × 4.This results in a total withdrawal of $91.00 over the four weeks ($22.75 × 4 = $91.00).Therefore, Tesha's lessons decreased her savings account balance by $91.00 after four weeks.

Which equation does not support the fact that polynomials are closed under multiplication?

−1⋅−1=1

1/x⋅x=1

1⋅x=x

1/3⋅3=1

Answers

Answer:

The second choice:

          [tex]\large\boxed{\large\boxed{1/x\cdot x=1}}[/tex]

Explanation:

The closure property on an operation means that the operation between two elements of a set produce one element of the same set.

In this case, the operation is multiplication and the set is the polynomials.

Then, the closrue property is that the multiplication of two polynomials will always produce a polynomial.

Since, [tex]1/x[/tex] is not a polynomial, the equation [tex]1/x\cdot x=1[/tex] does not support the fact that polynomials are closed under multiplication.

The build a dream construction company has plans for two models of the homes they build, model a and model b. The model a home requires 18 single windows and 3 double windows. The model b home requires 20 single windows and 5 double windows. A total of 1,800 single windows and 375 double windows have been ordered for the developments. Write and solve a system of equations to represent this situation. Define your variables. Interpet the solution of the linear system in terms of the problem situation

Answers

Answer:

a = 50 houses

b = 45 houses

Step-by-step explanation:

Given

Number of houses called Model A = a

Number of houses called Model B = b

Total of single windows = 1800

Total of double windows = 375

then we have the system of equations

18a + 20b = 1800  (I)

3a + 5b = 375     (II)

Solving the system by whatever method we prefer, we obtain

(I)     a = (1800 - 20b)/18

then (II)

3((1800 - 20b)/18) + 5b = 375

⇒ 300 - (10/3)*b + 5b = 375

⇒ (5/3)*b  = 75

⇒ b = 45 houses

then

a = (1800 - 20*45)/18

⇒ a = 50 houses

50 model A homes and 45 model B homes will be built.

To solve the problem, let's define our variables:

A = number of model A homesB = number of model B homes

We then create the following system of equations based on the given information:

1. For single windows:

18A + 20B = 1800

2. For double windows:

3A + 5B = 375

We can solve this system using the substitution or elimination method.

Step-by-Step Solution:

Multiply the second equation by 4 to align the coefficients of A:12A + 20B = 1500Subtract the modified second equation from the first equation:(18A + 20B) - (12A + 20B) = 1800 - 15006A = 300A = 50Substitute A = 50 back into the second original equation:3(50) + 5B = 375150 + 5B = 3755B = 225B = 45

The solution to the system is A = 50 and B = 45, meaning that the construction company plans to build 50 model A homes and 45 model B homes.

Find and equation for the line with the given properties. Express the equation in general form. Slope -6/7; containing the point (10,-9) what is the equation for the line?

Answers

Answer:

[tex]6x+7y+3=0[/tex]

Step-by-step explanation:

We are asked to find the equation of the line in general form, which has a of -6/7 and containing the point (10,-9).

We know that genera equation of a line is in form [tex]Ax+By+C=0[/tex], where, A, B and C are real numbers.

First of all, we will write our equation in point-slope form as:

[tex]y-y_1=m(x-x_1)[/tex], where,

m = Slope of line,

[tex](x_1,y_1)[/tex] = Given point on line.

[tex]y-(-9)=-\frac{6}{7}(x-10)[/tex]

[tex]y+9=-\frac{6}{7}x+\frac{60}{7}[/tex]

[tex]y*7+9*7=-\frac{6}{7}x*7+\frac{60}{7}*7[/tex]

[tex]7y+63=-6x+60[/tex]

[tex]6x+7y+63-60=-6x+6x+60-60[/tex]

[tex]6x+7y+3=0[/tex]

Therefore, our required equation would be [tex]6x+7y+3=0[/tex].

The following data reflect the number of customers who return merchandise for a refund on Monday. Note these data reflect the population of all 10 Mondays for which data are available. 40 12 17 25 9 46 13 22 16 7Based on these data, what is the standard deviation?

Answers

Answer:

The standard deviation of given data is 12.36  

Step-by-step explanation:

We are given the following data in the question:

40, 12, 17, 25, 9, 46, 13, 22, 16,7

Formula:

[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}[/tex]  

where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.  

[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]

[tex]Mean =\displaystyle\frac{207}{10} = 20.7[/tex]

Sum of squares of differences =

372.49 + 75.69 + 13.69 + 18.49 + 136.89 + 640.09 + 59.29 + 1.69 + 22.09 + 187.69 = 1528.1

[tex]\sigma = \sqrt{\dfrac{1528.1}{10}} = 12.36[/tex]

Thus, the standard deviation of given data is 12.36

Final answer:

The standard deviation of the provided data set (number of merchandise returns on Mondays) is approximately 14.8.

Explanation:

To calculate the standard deviation of the provided data set (40, 12, 17, 25, 9, 46, 13, 22, 16, 7), we will follow these steps:

Find the mean of the data set.Subtract the mean from each data point and square the result.Calculate the sum of the squared differences.Divide this sum by the number of data points (since we have the population standard deviation).Take the square root of the result from step 4.

Let's apply these steps:

The mean (average) is (40 + 12 + 17 + 25 + 9 + 46 + 13 + 22 + 16 + 7) / 10 = 20.7Squared differences (rounded to two decimal places) would be: (40 - 20.7)², (12 - 20.7)², (17 - 20.7)², and so on.The sum of these squared differences is approximately 2190.1Divide by the number of points, 2190.1 / 10 = 219.01The square root of 219.01 is approximately 14.8

Therefore, the standard deviation is about 14.8.

A large container has a maximum capacity of 64 ounces. The container is filled with 8 ounces less than it's maximum capacity. What is the percent of its capacity is the large container filled?

Answers

Answer:

87.5%

Step-by-step explanation:

64:64-8

64:56

56/64 *100 = 87.5%

what is 155.78=2.95h+73.18
a. 28
b. 36
c. 3.6
d. none of these

Answers

Answer:

a. 28

Step-by-step explanation:

Given:

[tex]155.78=2.95h+73.18[/tex]

We need to evaluate given expression to find the value of 'h'.

Solution:

[tex]155.78=2.95h+73.18[/tex]

Now first we will apply Subtraction property of equality and subtract both side by 73.18 we get;

[tex]155.78-73.18=2.95h+73.18-73.18\\\\82.6=2.95h[/tex]

Now we will use Division property of equality and divide both side by 2.95 we get;

[tex]\frac{82.6}{2.95}=\frac{2.95h}{2.95}\\\\h=28[/tex]

Hence After evaluating given expression we get the value of 'h' as 28.

What is the surface area of a cube that has a side length of 2.2 meters? Use the formula S A = 6 s squared, where SA is the surface area of the cube and s is the length of each side

Answers

Answer:

Step-by-step explanation:

surface area=6*2.2²=6×4.84=29.04 m²

Answer:

29.04

Step-by-step explanation:

just took the test

The box plot shows information about the marks scored in a test. Nobody gained 30, 48 or 70 marks. 120 students gained less than 70 marks. How many students gained more than 48 marks?

Answers

80 students gained more than 48 marks.

In the given box plot, we have the following information:

- The lowest test score is **10**, and the highest is **100**.

- The 25th percentile (Q1) is **30**, the median (Q2) is **48**, and the 75th percentile (Q3) is **70**.

- No student scored exactly **30**, **48**, or **70** marks.

- **120 students** scored less than **70** marks.

Let's analyze this:

1. The interquartile range (IQR) contains the middle **50%** of the data. Since the median (Q2) is **48**, we know that **50%** of the students scored more than **48** marks.

2. We are interested in how many students scored above **48**. Since **50%** scored more than **48**, the remaining **50%** scored less than or equal to **48**.

3. Given that **120 students** scored less than **70**, we can infer that **75%** of the students scored below **70** (since each region contains **25%** of the data).

4. Therefore, **25%** of the students scored between **48** and **70** (the region between Q2 and Q3).

5. To find out how many students scored more than **48**, we look at the region above Q2. Since there are **2 regions** above Q2, each containing **40 students** (since 120 students = 75%), the total number of students who scored more than **48** is:

[tex]\(2 \times 40 = 80\)[/tex]

Therefore, 80 students gained more than 48 marks.

The number of students who gained more than 48 marks is : 60

Using the information in the boxplot ;

48 marks = median Total number of students = 120

The median represents 50% of the data .

The number above the median value can be calculated thus ;

50% × number of students

Now we have :

50% × 120 = 60

Hence, the number of students who gained more than 48 marks is : 60

Identify the type of sampling used (random, systematic, convenience, stratified, or cluster sampling) in the situation described below. A woman is selected by a marketing company to participate in a paid focus group. The company says that the woman was selected because everyone in five randomly selected towns was being selected. Which type of sampling did the marketing company use?
A) Stratified sampling
B) Systematic sampling
C) Random sampling
D) Convenience sampling
E) Cluster sampling

Answers

Stratified sampling method - where population were divided into different groups called strata and the sample is then drawn from EACH group.

Systematic sampling method - sampling method using probability where elements are chosen from a target population.

Random sampling - each sample chosen has equal probability to be chosen.

Convenience sampling method - Not a random sampling method where the sample is being chosen as per ease of access.

Cluster sampling method - population were divided into different groups as known as clusters. The clusters were then chosen randomly as the samples. Each individuals in the clusters chosen are used as the samples.

Answer: E. Cluster sampling where selected towns refer to the clusters and were chosen randomly.

The type of sampling used by the researcher is cluster sampling.

What is cluster sampling?

Cluster sampling is a technique used when it becomes difficult to study the target population spread across a wide area and simple random sampling cannot be applied.

The researcher divides the entire population into sections or clusters. Then the researcher randomly selects a few clusters from the total clusters for the research.

In this case, the clusters are the five randomly selected towns. Everyone in these selected towns is included in the sample. This makes it a cluster sample.

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The quadratic mean of two real numbers x and y equals p (x 2 y 2)/2. By computing the arithmetic and quadratic means of different pairs of positive real numbers, formulate a conjecture about their relative sizes and prove your conjecture.?

Answers

Answer:

The quadratic mean of 2 real positive numbers is greater than or equal to the arithmetic mean.

Step-by-step explanation:

x and y      Quadratic Mean       Arithmetic mean

3 and 3                    3                                    3

2 and 3                   2.55                               2.5

3 and  6                  4.74                                4.5

2 and 5                   3.8                                  3.5

2 and 17                 12.1                                   9.5

18 and 28              23.5                                  23

10 and  48             34.7                                  29

The quadratic mean is always greater than the arithmetic mean except when  x and y are the same.

When the difference between the pairs is  small the difference in the means is also small. As that difference increases the difference in the means also increases.

So we conjecture that the quadratic mean is always greater than or equal to the arithmetic mean.

Proof.

Suppose it is true then:

√(x^2 + y^2) / 2) ≥ (x + y)/2       Squaring  both sides:

(x ^2 + y^2) / 2 ≥ (x + y)^2 / 4    Multiply through by 4:

2x^2 +2y^2  ≥  (x + y)^2

2x^2 +2y^2 >=  x^2 + 2xy + y^2

x^2 + y^2 >= 2xy.

x^2 - 2xy + y^2 ≥ 0

(x - y)^2 ≥ 0

This is true  because the square of any real number is positive so the original inequality must also be true.

The quadratic mean of two real numbers, x and y, is given by the formula sqrt((x^2 + y^2)/2). A conjecture can be made that the quadratic mean is greater than or equal to the arithmetic mean for positive real numbers. This conjecture can be proved using the AM-QM inequality and algebraic manipulations.

The quadratic mean of two real numbers, x and y, is given by the formula:

Q(x, y) = sqrt((x^2 + y^2)/2)

To formulate a conjecture about the relative sizes of the arithmetic and quadratic means of different pairs of positive real numbers, we can compare the two means for various pairs of numbers. Based on observations, it can be conjectured that the quadratic mean is always greater than or equal to the arithmetic mean for positive real numbers.

To prove the conjecture, we can use the AM-QM inequality, which states that the quadratic mean is greater than or equal to the arithmetic mean:

Q(x, y) >= A(x, y)

Where Q(x, y) is the quadratic mean and A(x, y) is the arithmetic mean.

Let's consider two positive real numbers, a and b:

Q(a, b) = sqrt((a^2 + b^2)/2)

A(a, b) = (a + b)/2

Now, we need to prove that Q(a, b) >= A(a, b):

Start with the inequality:

(a^2 + b^2)/2 >= (a + b)/2

Multiply both sides of the inequality by 2:a^2 + b^2 >= a + bCombine like terms:

a^2 - a + b^2 - b >= 0

Factor the expression:

(a^2 - a) + (b^2 - b) >= 0

Factor out 'a' and 'b':

a(a - 1) + b(b - 1) >= 0

Since 'a' and 'b' are positive numbers, both terms on the left side of the inequality are non-negative.

a(a - 1) >= 0

The above inequality is true for all positive 'a' values, and the same holds for 'b'.

Therefore, Q(a, b) >= A(a, b), which confirms the conjecture that the quadratic mean is always greater than or equal to the arithmetic mean for positive real numbers.

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Suppose triangle DEF = triangle WXY. Which choice below shows corresponding parts to congruent triangles that are congruent? Explain your answer. (A) angle E = angle X; DF = XY (B) angle D = angle Y; EF = XY ( C) angle E = angle X; DF = XY; (D) angle F = angle X; DE = WX

Answers

Answer:

(C )  angle E = angle X; DF = XY

Step-by-step explanation:

a triangle is said to be congruent if SAS(two sides and included angle)

SSS (all the sides are equal), ASA (two angles and an included sides).

therefore,  if angle E and angle X are equal

line DF and line XY are also equal.

The army bus has 12 seats on one side. Two soldiers can sit in each seat. If five seats are reserved for equipment, how many buses will they need for 1120 soldiers

Answers

Answer:

80 buses will be required for 1120 soldiers.

Step-by-step explanation:

Given:

Number of seats on One side = 12 seats.

Now Given:

five seats are reserved for equipment.

So we can say that;

Number of seats used by soldiers = [tex]12-5=7\ seats[/tex]

Number of soldiers on Each seat =2

So we will now find number of soldiers on each bus.

number of soldiers on each bus is equal to Number of seats used by soldiers multiplied by Number of soldiers on Each seat.

framing in equation form we get;

number of soldiers on each bus = [tex]7\times2 = 14\ soldiers[/tex]

Now we know that;

For 14 soldiers = 1 bus

So 1120 soldiers = Number of buses required for 1120 soldiers.

By Using Unitary method we get;

Number of buses required for 1120 soldiers = [tex]\frac{1120}{14} =80[/tex]

Hence 80 buses will be required for 1120 soldiers.

what is the length of the missing side of the triangle? 24,66 29.15 26.5 30.6

Answers

Answer:

24.66

Step-by-step explanation:

You use the Pythagorean Theorem and do 27^2 -11^2= x            

What is the 6th term in the sequence described by the following recursive formula?
a1=9
an=an−1−4

Answers

Answer:

[tex] a_{6} = - 11[/tex]

Final answer:

The 6th term in the recursive sequence with the first term 9 and each subsequent term decreasing by 4 from the previous term is -11.

Explanation:

To find the 6th term in the sequence described by the recursive formula given:

a1=9

an=an-1−4

We will apply the formula recursively to determine each term up to the 6th term.

First term (a1): 9

Second term (a2): a1 − 4 = 9 − 4 = 5

Third term (a3): a2 − 4 = 5 − 4 = 1

Fourth term (a4): a3 − 4 = 1 − 4 = -3

Fifth term (a5): a4 − 4 = -3 − 4 = -7

Sixth term (a6): a5 − 4 = -7 − 4 = -11

Therefore, the 6th term in the sequence is -11.

Miles earns a 6% commission on each vehicles he sells. Today he sold a truck for 18500 and a car for 9600. What is the total amount of his commision on these vehicles

Answers

Answer:

The total amount of commission on these vehicles is 1686.

Step-by-step explanation:

Given:

Miles earns a 6% commission on each vehicles he sells.

Today he sold a truck for 18500 and a car for 9600.

Now, to get the total amount of his commision on these vehicles.

Percent of commission Miles earns on each vehicles he sells = 6%.

He sold a truck for = 18500.

He sold a car for = 9600.

So, the total amount of vehicles:

[tex]18500+9600=28100.[/tex]

Now, to get the total amount of commission on vehicles:

[tex]6\%\ of\ 28100[/tex]

[tex]=\frac{6}{100} \times 28100[/tex]

[tex]=0.06\times 28100[/tex]

[tex]=1686.[/tex]

Therefore, the total amount of commission on these vehicles is 1686.

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2, and 3. During a certain week, each member of the family visits the clinic once and is assigned at random to a station. The experiment consists of recording the station number for each member. Suppose that any incoming individual is equally likely to be assigned to any of the three stations irrespective of where other individuals have been assigned. What is the probability that
(a) All three family members are assigned to the same station? (Round your answer to three decimal places.)
(b) At most two family members are assigned to the same station? (Round your answer to three decimal places.)
(c) Every family member is assigned to a different station? (Round your answer to three decimal places.)

Answers

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

[tex]PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}[/tex]

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

[tex]PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111[/tex]

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

[tex]PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666[/tex]

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

[tex]PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222[/tex]

Why would there be different published values for the normal range of a particular measurement? why do these values have to be updated periodically?

Answers

Answer and Step-by-step explanation:

For general measurements, different people or organizations normally make slightly different measurements. Measurements are never a hundred percent accurate.

The published values are usually updated because in the modern world of discoveries, change is the only constant thing. As new discoveries roll in or not, it becomes necessary to update the current standards; no change in the updated value means the old standards hold, and any change is also updated in the published update.

For health standards/ranges, Different countries have different standards of health

And this requires regular updating because standards of health changes frim time to time.

The table shows the highest daily temperature in degrees Fahrenheit averaged over the month for Cosine City, where m is the number of months since January 2001. (m = 0 represents January 2001.)


A sine function is written to represent the data.

What is the amplitude, period, and vertical shift of this equation?

Drag a value into each box to correctly complete the statements.

Answers

Answer:

Part A) The amplitude = 24

Part B) The period = 24

Part C) Vertical shift = 36

Step-by-step explanation:

The general equation of the sine function:

y = A sin (Bx) + C

Where A is the amplitude and B = 360°/Period  and C is the vertical shift

See the attached figure which represents the graph of m and f(m)

So,

Part A:

The function has minimum at 12 and maximum at 60

The difference is = 60 - 12 = 48

So, The amplitude = 48/2 = 24

Part B:

Period: The period of a periodic function is the interval on which the cycle of the graph that's repeated in both directions lies.

We can deduce that the function completes one cycle within 24 months

So, the period = 24

Part C:

Vertical shift is obtained at m = 0

So, f(m) = 36

36 = A sin (0) + C

C = 36 ⇒ Vertical shift

So, The amplitude = 24

The period = 24

Vertical shift = 36

Answer:

Answer:

Part A) The amplitude = 24

Part B) The period = 24

Part C) Vertical shift = 36

Step-by-step explanation:

The general equation of the sine function:

y = A sin (Bx) + C

Where A is the amplitude and B = 360°/Period  and C is the vertical shift

See the attached figure which represents the graph of m and f(m)

So,

Part A:

The function has minimum at 12 and maximum at 60

The difference is = 60 - 12 = 48

So, The amplitude = 48/2 = 24

Part B:

Period: The period of a periodic function is the interval on which the cycle of the graph that's repeated in both directions lies.

We can deduce that the function completes one cycle within 24 months

So, the period = 24

Part C:

Vertical shift is obtained at m = 0

So, f(m) = 36

36 = A sin (0) + C

C = 36 ⇒ Vertical shift

So, The amplitude = 24

The period = 24

Vertical shift = 36

Step-by-step explanation:

Your math test has 38 questions and is worth 200 points. This test consists of multiple-choice questions worth 4 points each and open-ended questions worth 20 points each. How many of each type of question are there?

Answers

Answer: the number of multiple-choice questions in the math test is 35 and the number of open-ended questions in the math test is 3

Step-by-step explanation:

Let x represent the number of multiple-choice questions in the math test.

Let y represent the number of open-ended questions in the math test.

The math test has 38 questions. It means that

x + y = 38

This test consists of multiple-choice questions worth 4 points each and open-ended questions worth 20 points each. The total number of points is 200. It means that

4x + 20y = 200 - - - - - - - - - -1

Substituting x = 38 - y into equation 1, it becomes

4(38 - y) + 20y = 200

152 - 4y + 20y = 200

- 4y + 20y = 200 - 152

16y = 48

48/16

y = 3

Substituting y = 3 into x = 38 - y, it becomes

x = 38 - 3 = 35

HELP!! i dont understand this math question and need help

Answers

Answer:

  52.2 ft

Step-by-step explanation:

Triangle JSV is similar to triangle HTV so you have the proportion ...

  JS/SV = HT/TV

  JS/(36 ft) = (5.8 ft)/(4 ft) . . . . . . . fill in the given values

  JS = (36 ft)(5.8/4) = 52.2 ft . . . . multiply by 36 ft

The height of the wall is 52.2 ft.

We know that m<HVT = m<JVS because the mirror projects equal angles. We can claim this about the angle theta.

tan(θ) = 5.8/4

θ = [tex]tan^{-1}(5.8/4)=55.4[/tex] degrees approx.

So, we want sin theta in the other triangle. Luckily, we also know that...

cos(55.4°) x hypotenuse = 36

hypotenuse = 63.4 ft approx.

So we can find the height by evaluating...

sin(55.4°) x 63.4 = 52.2 ft

answer: 52.2 ft

Solve the system using elimination.
2x+8y = 6
3x -8y = 9

Answers

You would do this:

 2x+8y=6

+ 3x-8y=9

5x=15

x=3

2x+8y=6

2(3)+8y=6

6+8y=6

8y=0

y=0

So x=3 and y=0

Very simple way to do that. Hope it helped.

Answer: x = 3, y = 0

Step-by-step explanation:

The given system of equations is expressed as

2x+8y = 6 - - - - - - - - - - - - - -1

3x -8y = 9- - - - - - - - - - - - - -2

We would eliminate y by adding equation 1 to equation 2. It becomes

2x + 3x = 6 + 9

5x = 15

Dividing the left hand side and the right hand side of the equation by 5, it becomes

5x/5 = 15/5

x = 3

Substituting x = 3 into equation 1, it becomes

2 × 3 + 8y = 6

6 + 8y = 6

Subtracting 6 from the left hand side and the right hand side of the equation, it becomes

6 - 6 + 8y = 6 - 6

8y = 0

Dividing the left hand side and the right hand side of the equation by 8, it becomes

8y/8 = 0/8

y = 0

Brandon eats half the amount of pie that Mollie eats.Yuki eats four times as much pie as Brandon. Mollie eats 1/4 of the pie. How much pie does Anna eat?

Answers

Answer: Anna eats 1/8 of pie

Step-by-step explanation: Let total pie =1

Mollie eats 1/4 of pie

Brandon eats half the amount of pie that Mollie eats i.e 1/2 of (1/4)

⇒1/8

Yuki eats 4 times as much as pie as Brandon i.e 4*(1/8)

⇒1/2

Total pie eaten by Mollie +Brandon+Yuki = 1/4+1/8+1/2

⇒7/8

Therefore Anna eats (1-7/8)

⇒ 1/8 of pie

If you invested $500 at 5% simple interest for 2 years, how much interest do you earn? Show work and answer in complete sentences to earn full credit.



If you invest $500 at 3% compounded monthly for 2 years, how much interest you do earn? Show work and answer in complete sentences to earn full credit.



Which would you rather do?

Answers

Answer:

$50

$30.45

Simple interest.

Step-by-step explanation:

If I invested $500 at 5% simple interest for 2 years, then the amount of interest that I will get will be calculated by the simple interest formula as

[tex]I = \frac{Prt}{100} = \frac{500 \times 5 \times 2}{100} = 50[/tex] dollars.

Now, if I invest $500 at 3% compounded monthly for 2 years, then the amount of compound interest will be calculated by the compound interest formula as

[tex]I = P(1 + \frac{r}{100})^{t} - P = 500(1 + \frac{3}{100})^{2} - 500 = 30.45[/tex] dollars.

So, I will prefer to invest in simple interest as the interest there is more. (Answer)

Which equation best shows that 55 is a multiple of 11? Choose 1 answer: (Choice A) A 55 = 44 + 1155=44+1155, equals, 44, plus, 11 (Choice B) B 11\times5=5511×5=5511, times, 5, equals, 55 (Choice C) C 11\div55 = 511÷55=511, divided by, 55, equals, 5 (Choice D) D 55 - 11 = 4455−11=44

Answers

Answer:

11x5=55

Step-by-step explanation:

Final answer:

The equation that best shows that 55 is a multiple of 11 is 11 × 5 = 55.

Explanation:

The equation that best shows that 55 is a multiple of 11 is Choice B: 11 × 5 = 55.

To determine if a number is a multiple of another number, we need to check if the first number can be divided evenly by the second number without any remainder. In this case, 55 can be divided evenly by 11 because 11 × 5 equals 55.

The other choices, A, C, and D, do not represent the relationship of 55 being a multiple of 11.

What is the slope of this line?​

Answers

The slope of the line is -2/-5

Slope of this line is -2.5

Step-by-step explanation:

Step 1: Slope of the line, m = (y2 - y1)/(x2 - x1)

Here, from the graph, x1 = -2, x2 = -4, y1 = 3, y2 = 8

⇒ m  = (8 - 3)/(-4 - -2) = 5/-2 = -2.5

Angie has some red and blue beads. 40% of her beads were red. When she lost 50 blue beads, the number of blue beads was reduced by 1/3 its original number of beads. How many beads did Angie have in the end?

Answers

Answer:

Step-by-step explanation:

Let x represent the total number of red and blue beads

Angie has some red and blue beads. 40% of her beads were red. This means that the total number of red beads is

40/100 × x = 0.4x

The number of blue beads would be

x - 0.4x = 0.6x

When she lost 50 blue beads, the number of blue beads was reduced by 1/3 its original number of beads. This means that

0.6x - 50 = 0.6x - 0.6x/3

0.6x - 50 = 0.6x - 0.2x = 0.4x

0.6x - 0.4x = 50

0.2x = 50

x = 50/0.2 = 250

The number of blue beads that Angie had initially is

0.6 × 250 = 150

The number of blue beads that Angie has left is

150 - 50 = 100 beads

The number of beads that Angie has in the end is

250 - 50 = 200 beads

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