Answer:
B. Earth, Venus, Mercury
Explanation:
2. A man walks 38 m west from home, rest, then walks 20 m east. What is the man's displacement?
Answer:18m west
Explanation:
Since they are moving in opposite direction we subtract to get the displacement
Displacement =38-20
Displacement =18m in west direction
3. What is the net force acting on the box in the diagram below? (1 mark)
Answer: Fnet = 40 N on the right
Explanation: The net force is the summation of forces acting on an object. Add the forces in the same direction and subtract to the opposing force moving in the opposite side.
Fnet= F1 + F2 - F3
= 120 N + 60 N - 140 N
= 180 N - 140 N
= 40 N on the right
superposition of a crest and trough produces
Answer:
pure constructive interference
Explanation:
The crests of two waves and the troughs are aligned. The superposition produces pure constructive interference. Because the disturbances add pure constructive interference, it produces a wave that has twice the amplitude of the individual waves but has the same wavelength.
Sound travels slower in colder air than it does in warmer air. Make a claim about the effect of air temperature on the speed of sound.
Answer: The temperature of the air affects the speed of sound in the due to the fact that colder contains air molecules with low kinetic energy. For warm air the kinetic energy of the molecules is high causing them to move in rapid motion. Because of these vibrations and collisions sound waves moves in a faster rate.
Explanation:
5) Consider pushing a 50.0 kg box through a 5.00m displacement on both a flat surface and up a
ramp inclined to the horizontal by 15.0°. In both cases, you apply a force of 100. N parallel to the
surface (parallel to the floor or parallel to the ramp). Calculate the work done by:
a) the gravitational force as the box is pushed across the flat ground
b) the gravitational force as the box is pushed up the ramp
c) the force you apply as the box is pushed across the flat ground
d) the force you apply as the box is pushed up the ramp
Explanation:
Work equals the force times the parallel distance.
a) Force gravity is in the downward direction. The box is moving on flat ground, so there's no displacement in that direction.
W = Fd
W = (50 kg) (-9.8 m/s²) (0 m)
W = 0 J
b) This time, there is a displacement in the vertical direction.
W = Fd
W = (50 kg) (-9.8 m/s²) (5.00 m sin 15.0°)
W = -634 J
c) The force is parallel to the displacement.
W = Fd
W = (100. N) (5.00 m)
W = 500. J
d) Again, the force is parallel to the displacement.
W = Fd
W = (100. N) (5.00 m)
W = 500. J
An object is placed 12cm from a converging lens of focal length 18cm. Find the position of the image.
Answer:
The position of the image = 7.2 cm.
Explanation:
Given:
A Converging lens:
Object distance [tex](d_o)[/tex] = 12 cm = -12 cm (sign convention)
Focal length [tex](f)[/tex] = 18 cm
We have to find the position of the image.
Let the position of the image be [tex](d_i)[/tex] .
Sign convention:
The focal length of converging (convex) lens is always positive,while object distance is negative.
Using lens formula:
⇒ [tex]\frac{1}{object\ distance} + \frac{1}{image\ distance} =\frac{1}{focal\ length}[/tex]
⇒ [tex]\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}[/tex]
⇒ [tex]\frac{1}{d_i} =\frac{1}{f} - \frac{1}{d_o}[/tex]
⇒ [tex]\frac{1}{d_i} =\frac{1}{f} - \frac{1}{-d_o}[/tex]
⇒ [tex]\frac{1}{d_i} =\frac{1}{f} + \frac{1}{d_o}[/tex]
⇒ [tex]d_i=\frac{d_o\times f}{d_o+f}[/tex]
⇒ [tex]d_i=\frac{12\times 18}{12+18}[/tex]
⇒ [tex]d_i=\frac{216}{30}[/tex]
⇒ [tex]d_i=7.2[/tex] cm
So the position of the image = 7.2 cm.
Which statement describes Newton’s conception of the Solar System?
1.) the Sun at the center, with the Earth and other planets orbiting the Sun
2.) the Earth orbiting the Sun, with other planets orbiting the Earth
3.) the Earth at the center, with the Sun and other planets orbiting Earth
4.) the Sun orbiting the Earth, with other planets orbiting the Sun
PLEASE HELP I NEED THIS ANSWER QUICK!
Answer:
1). the sun at the center, with the earth and other planets orbiting the sun.
Explanation:
Newton believes that it's gravity between the sun and the other planets even at the large distances that cause them to orbit around the sun. This force build up by the masses of the sun and the planets which keeps the planets in their orbit.
Answer:the sun at the center, with the earth and other planets orbiting the sun.
Explanation:
A 12.0 V battery is attached to a circuit with a resistor of 5.5 Ohms. The internal resistance of the circuit is 1.75 Ohms. What is the terminal voltage of the circuit?
The end voltage is 9.01 volts.
Explanation:The emf of the battery is 12 volts.
The resistance of the circuit = 1.75 ohms.
The resistance of the applicant attached = 5.5 ohms.
So, total resistance of the circuit = [tex]1.75 + 5.5[/tex] ohms = 7.25 ohms.
According to the equation, the voltage applied is equal to the product of the current and the resistance.
V=iR.
So, 12 = [tex]i \times7.25[/tex].
So, i = 1.66.
Therefore, the voltage at the end of the circuit = [tex]12 - 1.66\times1.75[/tex]volts
= 9.01volts.
So the end voltage is 9.01 volts.
67. Race Car A race car is slowed with a constant accel-
eration of 11 m/s2 opposite the direction of motion.
a. If the car is going 55 m/s, how many meters will it
travel before it stops?
b. How many meters will it take to stop a car going
twice as fast?
Answer:
a. 137.5 m
b. 550 m
Explanation:
Accelerated Motion
If an object is changing its velocity at a constant rate, it has a uniformly accelerated motion. When the object is moving in one fixed axis, then the sign of the acceleration is negative if the object is braking, and positive if the object is increasing its speed.
The initial speed vo, final speed vt, acceleration a, and distance traveled x are related by the formula
[tex]v_f^2=v_o^2+2ax[/tex]
a. The Race Car A has an initial speed of 55 m/s and it's said to stop. We must find at what distance it goes to vf=0. This means that the above formula becomes
[tex]0=v_o^2+2ax[/tex]
Solving for x
[tex]\displaystyle x=-\frac{v_o^2}{2a}[/tex]
The acceleration is [tex]-11\ m/s^2[/tex], negative because it's against the movement. Thus
[tex]\displaystyle x=-\frac{55^2}{2\times (-11)}[/tex]
[tex]x=137.5\ m[/tex]
b. If the car is going twice as fast (v0=110 m/s), then
[tex]\displaystyle x=-\frac{110^2}{2\times (-11)}[/tex]
[tex]x=550\ m[/tex]
Fiona claims that the diagram below shows simple machines, but Chad claims that it shows a compound machine.
Answer:
Simple machine
Explanation:
It is a simple machine because the person wants to raise the load by an inclined plane. Simple machines perform work with the mechanical advantage offered by the machine itself, such as using a bar as Lever, lifting a load by means of a pulley. simple machines multiply or change direction a force. While Composite machines are the Union of several simple machines that perform a given job, examples of combined machines are found on bicycles, a washing machine, a car, and others.
Answer:
b
Explanation:
took test, other answer said b and was verified
During a rising tide Ocean waves often become larger if the amplitude of a wave increases by a Factor of 1.1, by how much does the energy increase
Answer:
The energy of the wave will increase by a factor of 1.21.
Explanation:
Given:
The amplitude of the ocean wave is increased by a factor of 1.1.
The energy associated with a wave depends on the amplitude of the wave.
The energy (E) is directly proportional to the square of the amplitude (A) of the wave and is expressed as:
[tex]E=kA^2\\Where\ k\to constant\ of\ proportionality[/tex]
So, if the amplitude is doubled, then the energy will become 4 times and if the amplitude is halved, then the energy reduced by a factor of one by four.
Here, the amplitude is increased by a factor of 1.1. So, the energy associated with it will increase by a factor of square of 1.1 which is given as:
[tex]Increase\ in\ Energy=(1.1)^2=1.21\ of\ the\ initial\ value[/tex]
Therefore, the energy of the wave will increase by a factor of 1.21.
Calculate the work done by a 47 N force pushing a pencil 0.26 m.
Answer:
Workdone = 12.2 Joules
Explanation:
Given:
Force applied on the pencil = 47 N
Displacement of the pencil = 0.26 m
We have to find the work done .
Note:
Workdone = Product of force and its displacement (in the direction of the force) .
So,
Plugging the values.
Workdone = [tex]Force\times displacement[/tex]
⇒ [tex]W=F\times d[/tex]
⇒ [tex]W =47\times 0.26[/tex]
⇒ [tex]W=12.2[/tex] Joules (J)
OR
We can say that the displacement is against the direction of applied force.
Displacement = - 0.26
Workdone = [tex]F\times d\times cos(\theta)[/tex]
⇒ [tex]\theta[/tex] is the angle between force and displacement.
⇒ Here, [tex]\theta=180[/tex]
⇒ [tex]cos(180) = -1[/tex]
Workdone (W) = [tex]Fdcos(\theta)[/tex]
⇒ [tex]47\times -0.26\times -1[/tex]
⇒ [tex]12.2[/tex] Joules (J).
Workdone on pushing the pencil = 12.2 Joules.
Work is the product of the force and displacement. The work done by in the given situation 12.2 J.
Work:
It is the change in the energy due displacement of the object by the applied force. Work is the product of the force and displacement.
W = f.d
Where,
W - work
f- force = 47 N
d - displacement = 0.26 m.
put the values in the formula,
W = 47 N x 0.26 m.
W = 12.2 J
Therefore, the work done by in the given situation 12.2 J.
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Which of the following is not an SI unit?
Answer:
Pound
Explanation:
SI Unit stands for the International Standard of Unit. Thus from the options given, metre is a measure of length which is an SI unit. Kilogram is a measure of mass of a goven matter which is also an SI unit. Second is a measure of time which is an SI unit. Pound is a measure of masswhich is not an SI unit but has to be converted to kilograms which an SI unit.
The pound is not an SI unit, while the kilogram, meter, and nanometer are part of the International System of Units (SI).
The SI (International System of Units) is a globally recognized system of measurement that includes specific base units, derived units, and prefixes for expressing measurements consistently. It was developed to standardize measurements worldwide. Let's identify which of the options is not an SI unit:
Kilogram (kg): The kilogram is one of the seven base SI units and is the unit of mass. It is used to measure the amount of matter in an object. The symbol for the kilogram is "kg."
Meter (m): The meter is another base SI unit and is the unit of length. It is used to measure distance or length. The symbol for the meter is "m."
Nanometer (nm): The nanometer is not a base SI unit, but it is an SI-accepted metric prefix. It represents one billionth (1/1,000,000,000) of a meter (10^-9 meters). It is used for very small lengths, particularly in fields like nanotechnology.
Pound: The pound is not an SI unit. It is a unit of mass commonly used in the United States and a few other countries that have not fully adopted the SI system. The pound is equivalent to approximately 0.453592 kilograms.
So, among the given options, the pound is the unit that is not an SI unit. The other three options (kg, meter, nanometer) are all related to the SI system. The SI system promotes consistency and clarity in scientific measurements and is widely used in most countries around the world.
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The question probable may be:
Which of the following is not an SI unit?
kg , pound, meter, nanometer
1. Suppose you give a shopping cart a push and it begins t
give a shopping cart a push and it begins to roll across the parking
lot. Once you have stopped pushing it, it slows down and comes to a sto
observation consistent with Newton's First Law? Why or why not?
Newton's first law says the cart should keep going if there's no force acting on it to slow it down. But it slows down and stops. Is there any force acting on it ? You bet ! There's friction in the wheels, and a little bit of air resistance too.
Nitrogen -13 has a half life of 10 minutes how long will it take for a sample of 500 g to be reduced to 62.5 g?
Answer:
30 minutes
Explanation:
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount, A₀ is the initial amount, t is time, and T is the half life.
A = A₀ (½)^(t / T)
62.5 = 500 (½)^(t / 10)
0.125 = ½^(t / 10)
t / 10 = 3
t = 30
It will take 30 minutes.
Final answer:
To find the time it takes for a 500 g sample of Nitrogen-13 to be reduced to 62.5 g, we can use the equation for radioactive decay. The time is approximately 40 minutes.
Explanation:
To solve this problem, we can use the equation for radioactive decay: N = N0 * (1/2)(t/t1/2), where N is the final amount, N0 is the initial amount, t is the time passed, and t1/2 is the half-life. In this case, we have N = 62.5 g, N0 = 500 g, and t1/2 = 10 minutes. Substituting these values into the equation:
62.5 g = 500 g * (1/2)(t/10)
Now, we can solve for t by taking the logarithm of both sides and rearranging the equation:
t = 10 * log2(62.5/500)
Using a calculator, the value of t is approximately 40 minutes.
How much pressure is applied to the ground
by a 93 kg man who is standing on square
stilts that measure 0.04 m on each edge?
Answer in units of Pa.
003 (part 2 of 2) 10.0 points
What is this pressure in pounds per square
inch?
Answer in units of lb/in.
Answer:
Pressure applied by the man= 285103.125 [tex]Pa[/tex] or 41.35 [tex]lb/in^{2}[/tex]
Explanation:
Pressure is defined as the perpendicular force applied per unit area.
i.e. [tex]Pressure=\frac{Force}{Area}[/tex]
Now, [tex]Force= mg[/tex]
where, [tex]m[/tex] = mass of the body(man) = 93 kg
[tex]g[/tex] = acceleration due to gravity of Earth = 9.81 [tex]m/{s^{2}}[/tex]
[tex]Area[/tex] covered is equal to the area of both stilts(a man generally stands on two feet)
therefore [tex]Area=2(0.04)^{2}[/tex] [tex]m^{2}[/tex]
and putting in the values, we get,
[tex]Pressure=\frac{93\times9.81}{2\times(0.04)^{2}}Nm^{-2}=285103.125Nm^{-2}[/tex]
Now we need to convert to our required units:
[tex]1Nm^{-2}=1Pa\\1Pa=0.000145038lb/in^{2}[/tex]
(We can get the above result by individually converting kg to lb and meters to inches respectively)
Using the above relations we get,
[tex]Pressure=285103.125Pa=0.000145038\times285103.125lb/in^{2}=41.35lb/in^{2}[/tex]
Based on the formula for pressure, the pressure applied on the ground is 570206.25 N/m² or 82.7 pound per square inch
What is pressure?Pressure is defined as the perpendicular force applied per unit area.
Pressure = Force/AreaAlso,
Force = mgwhere,
mass of the body = 93 kg
g = 9.81 m/s²
Force = 93 * 9,81
Force = 912.33 N
Area of square stilt = (0.04m)²
Area = 1.6 * 10⁻³ m²
Then;
Pressure = 912.33 N/1.6 * 10⁻³ m²
Pressure = 570206.25 N/m²
Converting to pounds per square inch:
1 pound per square inch = 6894.76 N/m²
570206.25 N/m² = 570206.25 N/m² * 1 pound per square inch/6894.76 N/m²
Pressure = 82.7 pound per square inch
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The energy stored in gasoline is
A chemical energy
B electromagnetic energy
C mechanical energy
D nuclear energy
Gasoline stores chemical energy, which can be transformed to other types of energy via chemical reactions, such as the combustion in a car engine.
Explanation:The energy encapsulated within gasoline can be precisely characterized as chemical energy. This type of energy is encapsulated within the chemical bonds of various compounds, encompassing molecules and atoms. It is significant to note that chemical energy, as a versatile energy form, can be both liberated and harnessed as a source of power in diverse applications.
In the case of gasoline, it represents a potent reservoir of chemical energy. When gasoline undergoes combustion in the engine of a car, it engages in a chemical reaction. This reaction leads to the release of the energy contained within the chemical bonds of gasoline molecules. This released energy manifests in the form of mechanical power, propelling the vehicle, and heat energy, which warms the engine and the surrounding environment. In this process, gasoline's chemical energy is converted into mechanical and thermal energy, illustrating the dynamic interplay between different forms of energy in our daily lives.
The precise understanding of chemical energy's role in powering engines and facilitating various industrial processes underscores the fundamental principles of energy transformation and utilization, forming the basis of many technological advancements and applications.
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A short circuit is _____.
Answer:
in a device, an electrical circuit of lower resistance than that of a normal circuit, typically resulting from the unintended contact of components and consequent accidental diversion of the current.
Explanation:
Answer: A short circuit is simply a low resistance connection between the two conductors supplying electrical power to any circuit. This results in excessive current flow in the power source through the 'short,' and may even cause the power source to be destroyed.
Explanation:
Calculate the kinetic energy in joules of a 10 g bullet moving at 300 m/s.
____J
1. 900
2. 450
3. 15
4. 45
Answer:450joules
Explanation:
Let mass=m velocity =v
Mass given=10g=(10/1000)kg=0.01kg
Velocity given =300m/s
Kinetic energy =(m x v^2)/2
Kinetic energy =(0.01x300^2)/2
Kinetic energy =(0.01 x 90000)/2
Kinetic energy =900/2
Kinetic energy =450joules
A 20-newton weight is attached to a spring.
causing it to stretch, as shown in the diagram.
What is the spring constant of this spring?
Answer:
40 N/m
Explanation:
Assuming that the missing diagram is as attached, then we can deduce from Hooke's law that the extension of a spring is directly proportional to the applied force. This is mathematically expressed as
F=kx
Here, F represent the applied force, x denote the extension of the spring while k is the spring constant.
From the attached diagram, extension of the spring x=1-0.5=0.5m
Substituting 20 N for F and 0.5 m for x then
20=0.5k
k=20/0.5=40 N/m
two different examples of forces that could cause a change in motion
Answer:
a)Kicking a ball; b) A car that gets hit
Explanation:
a)
A classic example is when a soccer player kicks a moving ball in another direction by modifying the original direction and speed that the ball brought.
b)
Another example is when a car goes on a highway and suddenly is hit by another car on its side modifying the original direction and speed.
A 20-newton weight is attached to a spring.
causing it to stretch, as shown in the diagram.
What is the spring constant of this spring?
Answer:
40 N/m
Explanation:
The diagram attached is used to answer the question
We know from Hooke's law that extension is directly proportional to the applied force hence
F=kx where x is extension, F is applied force and k is the spring constant. Making k the subject of the formula then
[tex]k=\frac {F}{k}[/tex]
From the attached diagram extension is given by subtracting unstretched spring from stretched spring hence extension, x=1-0.5=0.5m
Substituting 20 N for F and 0.5 m for x then
[tex]k=\frac {20}{0.5}=40 N/m[/tex]
A force of 30N acts through a distance of 4m in the direction of the force, what is the work done
Answer:
120J
Explanation:
Work done = Force (N) X Distance (m)
Answer:
Work = 120Nm or 120J
Explanation:
Work is said to be done when a force moves a body over a distance, in the direction of force applied.
Work done = force x distance (in the direction of the force)
Therefore work = force x displacement
As displacement is distance in a specific or specified direction.
From the parameters given
Force = 30N
Displacement = 4m.
Therefore work = force x displacement
= 30N x 4m
Work = 120Nm or 120J
Note :J is joules which is the S. I unit of work
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A battery is marked. As having a voltage of 12V and is connected to a circuit that has a resistance of 5 ohms.if the terminal voltage is 8.75V. What is the internal resistance
Answer:
1.857 Ohms
Explanation:
The marked voltage of the battery is it's E.M.F. (Electromotive force). It is the maximum voltage the battery can supply because, ideally internal resistance of a cell or battery should be zero. Let us denote the E.M.F. as E.
In reality we get a lower voltage called the Terminal Voltage (Voltage across the terminals of the battery). Let us call that V. This is due to the voltage drop caused by the internal resistance (say 'r').
So when the circuit is connected a current I flows through a resistance
R(= 5 ohms, given).
Now, potential difference = Terminal Voltage = V = 8.75 Volts
Hence, [tex]I=\frac{V}{R} =\frac{8.75}{5}=1.75 Amperes[/tex]
Now, by conservation of energy we can say that,
E.M.F. = Terminal Voltage + Voltage drop due to the battery's internal resistance
or, [tex]E=V+Ir[/tex]
or, [tex]r=\frac{E-V}{I}=\frac{12-8.75}{1.75}=1.857[/tex] Ohms
Light in a vacuum travels at a constant speed of 3x10^8 m/s. If the moons average distance from the earth is 38776106 km how long would it take for a beam of light to travel from earth to the moon and back to earth again?
Answer: 258.3 s
Explanation:
The speed [tex]s[/tex] is given by the following equation:
[tex]s=\frac{D}{t}[/tex]
Where:
[tex]s=3(10)^{8} m/s[/tex] is the speed of light in vacuum
[tex]D=2(38776106 km \frac{1000 m}{1 km})=7.75(10)^{10} m[/tex] is the double of the distance between Earth and Moon, since the beam of light travels from Earth to the Moon and back to Earth again.
[tex]t[/tex] is the time it takes to the beam of light to travel the mentioned distance
Isolating [tex]t[/tex] and solving with the given information:
[tex]t=\frac{D}{s}[/tex]
[tex]t=\frac{7.75(10)^{10} m}{3(10)^{8} m/s}[/tex]
Finally:
[tex]t=258.3 s \approx 258 s[/tex]
A fully loaded Saturn V rocket has a mass of 2.92 x 106 kg. Its engines have a thrust of 3.34 x 107 N.
Complete Question:
A fully loaded Saturn V rocket has a mass of 2.92 x 106 kg. Its engines have a thrust of 3.34 x 107 N. (8 marks)
a) What is the downward force of gravity on the rocket at blast-off?
b) What is the unbalanced force on the rocket at blast-off?
c) What is the acceleration of the rocket as it leaves the launching pad?
d) As the rocket travels upwards, the engine thrust remains constant, but the mass of the rocket decreases. Why?
e) Does the acceleration of the rocket increase, decrease, or remain the same as the engines continue to fire?
Answer:
a) [tex]-2.8616 \times 10^{7} N[/tex] is the downward force of gravity on the rocket at blast-off.
b) [tex]4.784 \times 10^{6} N[/tex] is the unbalanced force on the rocket at blast-off
c) [tex]1.638 \mathrm{m} / \mathrm{s}^{2}[/tex] is the acceleration of the rocket as it leaves the launching pad
d) Because the propellant here is burned up, hence the mass of the rocket seems to be varied (total mass of all its parts). Thereby, the mass decreases when the rocket moves upward.
e) The acceleration of the rocket increases when engines continue to fire
Explanation:
Given:
Mass (m) = [tex]2.92 \times 10^{6} \mathrm{kg}[/tex]
a) In physics, weight can be defined as the applied force on a body by gravity. It is the product of mass (m) and gravity [tex]\left(g=9.8 \mathrm{m} / \mathrm{s}^{2}\right)[/tex]
[tex]\text { weight }(W)=m \times g=2.92 \times 10^{6} \times(-9.8)=28.616 \times 10^{6}=-2.8616 \times 10^{7} N[/tex]
The negative sign indicates the downward force of gravity.
b) To find the unbalanced force on the rocket at blast-off,
Accelerating force,
[tex]F_{a}=F+W=3.34 \times 10^{7}+\left(-2.8616 \times 10^{7}\right)=(3.34-2.8616) \times 10^{7}[/tex]
[tex]F_{a}=0.4784 \times 10^{7}=4.784 \times 10^{6} N[/tex]
c) Newton’s second law of motion states that the object’s acceleration depends on two variable:
Directly proportionate to the object’s force existed Inversely proportionate to the mass of the objectsThe equation can be given as below,
[tex]Force =m \times acceleration[/tex]
[tex]\text { Acceleration }=\frac{F_{a}}{m}=\frac{4.784 \times 10^{6}}{2.92 \times 10^{6}}=1.638 \mathrm{m} / \mathrm{s}^{2}[/tex]
d) The pushing of rocket upward will happen as long as the engine gets fired. The propellant here is burned up, hence the mass of the rocket seems to be varied (total mass of all its parts). Thereby, the mass decreases (taotal mass) when the rocket moves upward.
e) The acceleration of the rocket increases when engines continue to fire
Let consider [tex]F_{a}[/tex] is constant, mass gets decreasing, then the acceleration would be increasing (as mass and acceleration are inversely proportionate to each other) .
At which point(s) is the net force the greatest?
At which point(s) is the net force zero?
Final answer:
The net force is the greatest when the forces are in the same direction and have the greatest magnitude. The net force is zero when the forces are balanced and cancel each other out.
Explanation:
The net force on an object is the vector sum of all the forces acting on it. The magnitude of the net force can be determined by considering the individual forces acting on the object. The net force is the greatest at points where the forces acting on the object are in the same direction and have the greatest magnitude.
The net force is zero when the forces acting on the object are balanced and cancel each other out. This occurs at points where the forces are equal in magnitude and opposite in direction.
For example, let's say we have two forces acting on an object: 10 N to the right and 5 N to the left. At the point where the forces are added, the net force would be 5 N to the right (10 N - 5 N). This is the greatest net force. At the point where the forces cancel each other out, the net force would be zero (10 N - 10 N).
what is 1/12+7/9 hj
Explanation:
[tex] \frac{1}{12} + \frac{7}{9} \\ \\ = \frac{1 \times 3}{12 \times 3} + \frac{7 \times 4}{9 \times 4} \\ \\ = \frac{3}{36} + \frac{28}{36} \\ \\ = \frac{3 + 28}{36} \\ \\ = \frac{31}{36} \\ \\ \huge \purple{ \boxed{\therefore \: \frac{1}{12} + \frac{7}{9} = \frac{31}{36} }} \\ [/tex]
Answer:
31/36
Explanation:
do the math you will see
Which of the following is true about the movement of stars in the night sky?
A.
Stars in the sky appear to move slowly from south to north.
B.
Stars in the sky appear to move slowly from north to south.
C.
Stars in the sky appear to move slowly from west to east.
D.
Stars in the sky appear to move slowly from east to west.
"Stars in the sky appear to move slowly from east to west" is true about the movement of stars in the night sky.
Answer: Option D
Explanation:
The Sun, Moon and stars all are understood to wake up in the East and set in the West direction, as every 24 hours the Earth rotates on its axis in the reverse direction from West to East. Consequently, the acceleration we witness is not their action, but ourselves as we go zipping onto the Earth's surface to the North, and these gravitational anomalies fly over us. For illustrating this point, the North Star named as Polaris in Ursa Minor is useful.
Stars in the night sky seem to move slowly from east to west due to the Earth's rotation.
Stars in the sky appear to move slowly from east to west. This apparent motion is due to the rotation of the Earth. As the Earth rotates from west to east, the stars appear to move in the opposite direction.
How is temperature and viscosity related?
Answer:
With an increase in temperature, there is typically an increase in the molecular interchange as molecules move faster in higher temperatures. The gas viscosity will increase with temperature. ... With high temperatures, viscosity increases in gases and decreases in liquids, the drag force will do the same.