In server-side discovery pattern, load balancing and routing of the request to the service instances are taken care of by the service discovery tool. False True

Answer:

Option A and Option D are the correct options.

Explanation:

They decided to allow their users with a different perspective when viewing a Salesforce1 transaction records rather than the specific web edition. So, they accomplish the following scenario by adding and allocating a Mobile Design to a profile and by adding the following page to the mobile card section.

Answer:

Object-oriented programming (OOP) is a procedural language and based on classes associated with an object. Without classes and object relationship OOP is not possible. According to program's design concept classes provide abstraction and encapsulation with the help of object. Object have states and behaviors like cat has states like name, color and  cat has also behaviors like  wagging the tail, eating, jumping etc. A class forms template or blueprints for these states and behaviors because different cats have different behaviors and states.

Methods provide a way for encapsulation and accessing private class members with public methods and static fields are sometimes best alternative for global variable. We can use static field when it same for all and shared by all objects of that class and it can save memory because we do not have to initialize it for each object

Final answer:

In Object-Oriented Programming (OOP), a class is a blueprint for creating objects, while an object is an instance of a class. The relationship between a class and an object is that a class defines the structure of an object. Methods in OOP are used to perform actions or computations, while static fields are shared among all objects of a class.

Explanation:

Design Concepts and Assumptions in OOP:

In Object-Oriented Programming (OOP), a class is a blueprint for creating objects, while an object is an instance of a class. The design concept behind a class is to define the common characteristics and behaviors that objects of that class will have. Assumptions made when designing a class include creating a hierarchy of classes to represent different levels of abstraction and encapsulating data and behaviors within the class.

Relationship between Class and Object:

In OOP, the relationship between a class and an object is that a class defines the structure (attributes and behaviors) of an object, while an object is an instance of a class that can be created and manipulated using the defined structure.

Roles of Methods and Static Fields in OOP:

In OOP, methods are functions or behaviors associated with an object or class, which are used to perform certain actions or computations. They define how objects or classes interact with each other and with the outside world. Static fields, on the other hand, are variables or data that are shared among all objects of a class. They hold values that are common to all instances of the class and can be accessed without creating an object.

Answer:

Following is attached the solution of each part step-by-step. I hope it will help you!

Explanation:

Answer:

Algorithm for the above problem:

Output:

Explanation:

False, as it is not necessary for Bob to return the chunks to Alice in the same interval in Bit Torrent.

Explanation:

Answer:

"Case-Based Reasoning" is the answer for the above question.

Explanation:

Answer:

yes ! you can see below.

Explanation:

EHR is a health record of a patient that gives information about the patient and securely authorized it. Electronic Health record allows medical professionals to enter data and update a new encounter.

DOC is a document used by Microsoft. DOC file is a file that contains formatted text, images, tables, graphs, and charts, etc.

Unstructured data is data that can be entered in free text format. Structured information is a type of data contain check boxes, images table, and other the user chooses from the given option.

As the DOC system contain free text format, then data in the EHR is structured.

The data sent from a DOS system to an EHR and populating an indexed field is typically considered structured data. EHR systems play a critical role in maintaining accessible and secure patient records, improving healthcare quality and efficiency while safeguarding privacy.

If data from a DOS system is electronically sent to an EHR (Electronic Health Record) or other Windows-based system via an interface to populate an indexed data field in the EHR, the data can be either structured or unstructured depending on the format it is sent and how it is handled by the receiving system. In this context, if the data populates a specific field within the EHR, it is typically considered to be structured data because it is organized in a predefined manner, making it easily searchable and analyzable within the system.

EHR systems are essential for maintaining accurate and accessible patient records. They ensure that in the event of a disaster, such as a hurricane, health information can be retrieved due to effective data backup solutions. Additionally, because EHRs are designed to be shared securely among healthcare providers, they facilitate improved coordination of care.

Overall, the transformation from paper-based records to EHRs serves to enhance the quality and efficiency of healthcare delivery, while also maintaining the privacy and security of personal health information under federal laws such as HIPAA.

Answer:

Explanation:

Error-correcting code memory (ECC memory) these kinds of memories can detect and correct errors but only in single bit of the byte, in this case, if there is more than one bit, for example, two bits, the ECC memory can detect the error but cannot fix it, there are some memories without ECC can detect errors but not correct it.

Answer:

Option C.

Explanation:

Search engine use of pre-stored search that results is not mostly accurate.

Search engines shouldn't search the whole Internet each time when user requests for a search because It might be taken more time than the user might have expected and Many users were not involved in exploring the whole Internet.

Answer:

The below code is pasted in the place of "/*Your solution goes here */"

while(numInsects<200) // while loop

       {

            System.out.print(numInsects+" "); // print statement

            numInsects=numInsects*2; // operation to print double.

       }

Output:

Explanation:

Using Python 3 programming, the code blocks below displays the required instructions. The program goes thus :

numInsects = int(input())

#takes input from the user on the number of insects

while numInsects < 200 :

#while loop checks if variable is below 200

print(numInsects, end=' ')

#displays the value with the cursor remaining on the same line

numInsects*=2

print(numInsects)

Learn more : https://brainly.com/question/12483071

Answer:

def max_magnitude(user_val1, user_val2):

if abs(user_val1) > abs(user_val2):

return user_val1

else:

return user_val2

if __name__ == '__main__':

n1 = int(input("Enter the first integer number: "))

n2 = int(input("Enter the second integer number: "))

print("The largest magnitude value of", n1, "and", n2, "is", max_magnitude(n1, n2))

Explanation:

Answer:

False

Explanation:

Interfaces are similar to classes in Java, but they are not a type of class. A class defines the attributes and behaviours of objects, while interface contains the methods that shows the behaviours to be implemented by a class.

A method is one or more group of statements, it does not need to end with a semicolon. Methods in interfaces are abstract and for a class to contain these abstract method, it must be defined in the class.

An interface is a class that contains only the method headings and each method heading is terminated with a semicolon is a true statement.

An interface is known to be a kind of reference that is seen in Java. It is same to look the same with class.

It is known as a series of abstract methods that shows the description of the work that a specific object can do. Here, An interface is a class that has  only the method headings and the method heading is ended with a semicolon.

Learn more about interface from

https://brainly.com/question/7282578

Answer:

Hi there! This question is good to check your understanding of loops. To illustrate, I have implemented the answer in Python and explained it below.

Explanation:

Assuming user input for the country and population list as provided in the question, we can write the python script "country_pop.py" and run it from the command line. First we prompt user for the input, after which we split the country-population list which is separated or delimited with a comma into an array of country-population list. We then create a hash of country and its corresponding population by further splitting the country-population combo into a hash, and finally, printing the resultant hash as the output.    

country_pop.py

def add_country_pop(country, population):

 countrypop_hash[country]=population

countrypop_hash = {}

input_string = input("Enter country population list: ")

print(input_string)

countrypop_array = input_string.split(",")

for country in countrypop_array:

 country_pop = country.split(':')

 pop_country = country_pop[0]

 population = country_pop[1]

 add_country_pop(pop_country, population)

 print(country + ' has ' + population + ' people')

Output

> country_pop.py

Enter country population list: China:1365830000,India:1247220000,United States:318463000,Indonesia:252164800

China:1365830000,India:1247220000,United States:318463000,Indonesia:252164800

China:1365830000 has 1365830000 people

India:1247220000 has 1247220000 people

United States:318463000 has 318463000 people

Indonesia:252164800 has 252164800 people

Answer:user_input = input()

entries = user_input.split(',')

country_pop = {}

for pair in entries:

   split_pair = pair.split(':')

   country_pop[split_pair[0]] = split_pair[1]

   # country_pop is a dictionary, Ex: { 'Germany':'82790000', 'France':'67190000' }

for country,pop in country_pop.items():  

   print(f'{country} has {pop} people.')

Explanation:

Answer:

Following are the Pseudocode for the above problem:

Explanation:

Output:

Pseudocode Explanation:

Full Question

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal

#include <iostream>

#include <cmath>

using namespace std;

int main() {

double targetValue;

double sensorReading;

cin >> targetValue;

cin >> sensorReading;

if (/* Your solution goes here */) {

cout << "Equal" << endl;

} else {

cout << "Not equal" << endl;

} return 0;

}

Answer:

if (abs(targetValue - sensorReading) <= 0.0001)

Explanation:

Replace

if (/* Your solution goes here */) {

With

if (abs(targetValue - sensorReading) <= 0.0001)

Two values are considered to be close enough if the difference between the values is 0.0001

Splitting the codes into bits;

abs

targetValue - sensorReading

<=

0.0001

The keyword abs is to return the absolute value of the expression in bracket.

This is needed because the expression in the bracket is expected to return a positive value.

To do this the absolute keyword is required.

targetValue - sensorReading returns the difference between the variables

<= compares if the difference falls within range that should be considered to be close enough

0.0001 is the expected range

Answer:

The correct answer is: Organizing.

Explanation:

Management functions refer to the roles high-rank executives must play to handle businesses. Those functions are Planning, Organizing, Staffing, Directing, and Controlling. Organizing refers to the steps taken to create a structure in the organization. Managers should find the most optimal way to group the firm's resources to ensure efficiency and effectiveness. The process of organizing includes:

Answer:

Represent each of the following bit patterns in decimal notation.

Process for conversion:

1. Divide the bit pattern into equal parts.

2. Every digit represent by base 2 with different powers from 0 to 7.

3. Then match the binary number to respective digits of base 2.

4. Neglect numbers that represent by 0 and add numbers that represent by 1.

5. Then place dot between results obtained from different parts.

Part 1:  Answer = 15.15

Part 2:  Answer=51.0.128

Part 3:  Answer=10.160

See attachment for each part

Answer:

a) with Array

class array{

   int arrA[MAX],location,item,nA;

   int arrB[MAX],nB;

   int arr_merge[MAX+MAX],nM;

   public:

   array(){

      location=0;item=0;nA=0;

      nB=0;nM=0;

   }

   void init(); //initial data assignment  

void traverse(); //process is display (assumed)void insert();

   void del();

   void search();

   void sort();

   void merge();

};

void array :: del(){

    clrscr();

    int i;

    cout<<"\n\n*****Deleting Element*****\n";

    if(nA < 0){

   cout<<"\nArray is Empty\nDeletion Not Possible\n";

   goto end;

    }

    cout<<"\nEnter Location of deletion : ";

    cin>>location;

    location--;

    if(location<0 || location>=nA)

    {

   cout<<"\n\nInvalid Position\n";

   goto end;

    }

    cout<<"\nItem deleted is : "<<arrA[location];

    for(i=location;i<nA;i++){

    arrA[i] = arrA[i+1];

    }

    arrA[nA-1]=0;

    nA--;

end:

     getch();

}

void array :: search(){

    clrscr();

    int i,found=-1;

    cout<<"\n\n*****Searching Element*****\n";

    cout<<"\nEnter Item value to be search : ";

    cin>>item;

    for(i=0;i<nA;i++){

    if(arrA[i] == item){

       found=i+1;

       break;

    }

    }

    if(found==-1)

    cout<<"\nSearch NOT FOUND\n";

    else

    cout<<"\nSearch is FOUND at "<<found<<" location\n";

    getch();

}

void array :: sort(){

    clrscr();

    int i,j,temp;

    cout<<"\n\n*****Sorting Element*****\n";

    for(i=0;i<nA;i++){

   for(j=i;j<nA;j++){

     if(arrA[i] > arrA[j]){

        temp    = arrA[i];

        arrA[i] = arrA[j];

        arrA[j] = temp;

     }

   }

    }

   cout<<"\nData are Sorted\n";

   getch();

}

// b) with pointer

#include <stdio.h>

#include <conio.h>

#include <math.h>

#include <alloc.h>

void main()

{

char *a[10],dum[10],s;

int i,k,j,n;

clrscr();

printf("enter the no of std....");

scanf("%d",&n);

printf("enter the name of students ");

for(k=0;k<n;k++)

scanf("%s",a[k]);

for(i=1;i<n;i++)

{

for(j=1;j<n-i;j++)

{if(strcmp(a[j-1],a[j])>0)

 {strcpy(*dum,*a[j-1]);

  strcpy(*a[j-1],*a[j]);

  strcpy(*a[j],*dum);

}

}  }

for(i=0;i<n;i++)

printf("%s",a[i]);

getch();

}

c) with cursor implementations of lists.

#include<stdio.h>

#include<stdlib.h>

typedef struct Node  

{

       int data;

       struct Node *next;

}node;

void insert(node *pointer, int data)

{

       /* Iterate through the list till we encounter the last node.*/

       while(pointer->next!=NULL)

       {

               pointer = pointer -> next;

       }

       /* Allocate memory for the new node and put data in it.*/

       pointer->next = (node *)malloc(sizeof(node));

       pointer = pointer->next;

       pointer->data = data;

       pointer->next = NULL;

}

int find(node *pointer, int key)

{

       pointer =  pointer -> next; //First node is dummy node.

       /* Iterate through the entire linked list and search for the key. */

       while(pointer!=NULL)

       {

               if(pointer->data == key) //key is found.

               {

                       return 1;

               }

               pointer = pointer -> next;//Search in the next node.

       }

       /*Key is not found */

       return 0;

}

void delete(node *pointer, int data)

{

       /* Go to the node for which the node next to it has to be deleted */

       while(pointer->next!=NULL && (pointer->next)->data != data)

       {

               pointer = pointer -> next;

       }

       if(pointer->next==NULL)

       {

               printf("Element %d is not present in the list\n",data);

               return;

       }

       /* Now pointer points to a node and the node next to it has to be removed */

       node *temp;

       temp = pointer -> next;

       /*temp points to the node which has to be removed*/

       pointer->next = temp->next;

       /*We removed the node which is next to the pointer (which is also temp) */

       free(temp);

       /* Beacuse we deleted the node, we no longer require the memory used for it .  

          free() will deallocate the memory.

        */

       return;

}

void print(node *pointer)

{

       if(pointer==NULL)

       {

               return;

       }

       printf("%d ",pointer->data);

       print(pointer->next);

       }

}

Running Time:

a) 2 minute

b) 1 minutes  

c) 1 & half minutes

Explanation:

a) Initialize the array and traverse it by using for loop. Sort the array with the help of a temporary variable.  

b) Declare a pointer to the array and take the input from user using for loop.

c) Declare a Structure containing an integer and a pointer. Iterate through the list, allocate memory for the new node and insert the data in it.

Answer:

The three types of technical information sources are:      

Vendor and manufacturer Web sites.

Technology-oriented Web sites and publications.

Professional society Web sites.              

Explanation:

Professional society Web sites provide most unbiased information.

These professional social websites are non profit companies as opposed to other sources of information that are profit making.

Social websites provides with the information that can help their members in a best way about getting information of their interest. This is done in an unbiased way because they do not work for some specific organizations or companies that want to sell their products or services.

Answer:

 public static void main(String[] args)

 {

   int studentnumber = 123456;

   int divisor = 0;

   int chapter = (studentnumber%4)+2;

   switch(chapter) {

     case 2:

      divisor = 23;

      break;

     case 3:  

      divisor = 34;

       break;

     case 4:

      divisor = 38;

       break;

     case 5:  

      divisor = 46;

       break;

   }

   int exercise = (studentnumber % divisor) + 1;

  System.out.printf("Studentnumber %d divided by 4 plus 2 is chapter %d.\n", studentnumber, chapter);        

  System.out.printf("Studentnumber %d divided by %d is exercise %d.", studentnumber, divisor, exercise);  

 }

Explanation:

Above is just a bit of code to get you started with the first part. Hope you can figure out the rest.

Final answer:

The question asks for a program that reads an integer representing the number of words in a list, the words themselves, and a character, and then prints each word from the list that contains the character at least once. A sample Python script has been provided to illustrate how this can be achieved by iterating through the list and checking for the presence of the character in each word.

Explanation:

To create a program that reads an integer, a list of words, and a character, where the integer indicates the number of words in the list, and the output displays every word containing the specified character at least once, you would typically use a programming language like Python. The task involves iterating through the list of words and checking if each word contains the character. Here is a simple example in Python:

This script prompts the user to input the number of words, the words themselves, and the character to search for. It then prints out any word that contains the character.

Answer:

Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!

Explanation:

```csharp

using System;

class ClassifiedAd

{

   // Fields

   private string category;

   private int numberOfWords;

   // Properties

   public string Category

   {

       get { return category; }

       set { category = value; }

   }

   public int NumberOfWords

   {

       get { return numberOfWords; }

       set { numberOfWords = value; }

   }

   public double Price

   {

       get { return numberOfWords * 0.09; } // Price calculated at nine cents per word

   }

}

class TestClassifiedAd

{

   static void Main(string[] args)

   {

       // Instantiate ClassifiedAd objects

       ClassifiedAd ad1 = new ClassifiedAd();

       ad1.Category = "Used Cars";

       ad1.NumberOfWords = 50;

       ClassifiedAd ad2 = new ClassifiedAd();

       ad2.Category = "Help Wanted";

       ad2.NumberOfWords = 80;

       // Display information about the ClassifiedAd objects

       Console.WriteLine("Classified Ad 1:");

       Console.WriteLine($"Category: {ad1.Category}");

       Console.WriteLine($"Number of Words: {ad1.NumberOfWords}");

       Console.WriteLine($"Price: ${ad1.Price}");

       Console.WriteLine("\nClassified Ad 2:");

       Console.WriteLine($"Category: {ad2.Category}");

       Console.WriteLine($"Number of Words: {ad2.NumberOfWords}");

       Console.WriteLine($"Price: ${ad2.Price}");

   }

}

```

1. ClassifiedAd Class:

  - This class represents a classified advertisement with three fields: `category`, `numberOfWords`, and a private field `price` (which is calculated internally).

  - Properties:

    - `Category`: This property has both a getter (`get`) and a setter (`set`) to allow getting and setting the category of the advertisement.

    - `NumberOfWords`: Similarly, this property has both a getter and a setter for getting and setting the number of words in the advertisement.

    - `Price`: This property only has a getter (`get`). It calculates the price based on the number of words (`numberOfWords * 0.09`), where each word costs nine cents.

2. TestClassifiedAd Class:

  - This is the main application class that demonstrates the use of `ClassifiedAd` objects.

  - Main Method:

    - It instantiates two `ClassifiedAd` objects (`ad1` and `ad2`) and assigns values to their properties (`Category` and `NumberOfWords`).

    - It then prints out information about each `ClassifiedAd` object:

      - Displays the category using `ad1.Category` and `ad2.Category`.

      - Displays the number of words using `ad1.NumberOfWords` and `ad2.NumberOfWords`.

      - Displays the calculated price using `ad1.Price` and `ad2.Price`.

3. Execution:

  - When you run the `TestClassifiedAd` application, it will output the category, number of words, and price for each of the two `ClassifiedAd` objects that were instantiated and configured.

4. Purpose:

  - This code demonstrates basic object-oriented principles such as encapsulation (using properties to access fields), calculation within properties, and object instantiation and usage in a simple console application.

Overall, the `ClassifiedAd` class encapsulates the data and behavior related to a classified advertisement, and the `TestClassifiedAd` application showcases the instantiation and usage of these objects with specific examples.

Explanation:

Virtualization can be defined as a virtual or software-based representation of virtual applications, storage, network and servers. Through this process it is possible to run a variety of different operating systems on the same physical server at the same time, which reduces information technology expenses, increases the speed and agility of the systems.

Some of the benefits of virtualization are:

Answer:

Increase the left and right margins.

Explanation:

Microsoft Excel is a spreadsheet application package from the Microsoft office package. It is a tool used for analysing and cleaning and/or organising information.

It's worksheets are made of cells located by columns or fields and rows or records. A collection of worksheets is called a workbook. An Excel file can be printed after use.

When a print layout is viewed and printed, and columns of the file is printed on another page. To avoid this, reduce the size of the columns and the size of the left and right margins and also decrease the scale value and change to a bigger paper printer size if required.

This question is incomplete. The complete question is given below:

Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:

  A

 ABA

ABCBA

ABCDCBA

Answer:

#include <stdio.h>

void printTri(char asciiCharacter){

   // Row printer

//   for(int i = 65; i <= ((int)asciiCharacter); i++){

   int i = 65;

   while(i <= ((int)asciiCharacter)){

       int leftMargin = ((int)asciiCharacter) - i; +

       int j = 1;

       while(j <= leftMargin){

           printf(" ");

           j++;

       }

       int k = 65;

       while(k < ((int)i)){

           printf("%c",(char)k);

           k++;

       }

       int l = ((int)i);

       while(l >= 65){

           printf("%c",(char)l);

           l--;

       }

       printf("\n");

       i++;

   }

}

int main()

{

   for(;;){

       printf("Please enter a character between A and Z. Enter (!) to exit \n");

       char in;

//       scanf("%c",&in);

       in = getchar();

       getchar();

       printf("Printing Triangle for: %c \n",in);

       if(((int)in) >= 65 && ((int)in) <= 90){

           printTri(in);

           printf("\n");

       }else if(((int)in) == 33){

           break;

       } else {

           continue;

       }

   }

   return 0;

}

Explanation:

Answer:

Software and Hardware virtualization.

Explanation:

Virtualization is a process or the ability of a system to run multiple operating systems and virtually using all the physical resources, as though they are individual systems.

Hardware virtualization allows for hardware components like the storage, CPU, memory etc to be virtually used by multiple virtual machines. Software virtualization uses software managers to run individual guest operating systems on virtual machines.

Answer:

Explanation:

function draw()

 {

 var ctx = document.getElementById("myCanvas").getContext("2d");

 var counter = 0;

 for (var i=0;i<6;i++)

 {

 for (var j=0;j<6;j++)

 {

 //Start from white and goes to black

 ctx.fillStyle = "rgb(" + Math.floor(255-42.5*i) + "," + Math.floor(255-42.5*i) +

 "," + Math.floor(255-42.5*j) + ")";

ctx.beginPath();

 if (i === counter && j === counter)

 {

 //creates the circles

 ctx.arc(25+j*50,30+i*50,20,0,Math.PI*2,true);

 ctx.fill();

 //creates a border around the circles so white one will be vissible

 ctx.stroke();

 }  

 }

 counter++;

 }

 }

 draw();

Answer:

#include <iostream>

#include <stack>

#include <queue>

using namespace std;

bool checkfor(stack<int> &stk, int x){

   queue<int> q;

   bool flag = false;

   while(!stk.empty()){

       int p = stk.top();

       stk.pop();

       if(p == x){

           flag = true;

       }

       q.push(p);

   }

   while(!q.empty()){

       stk.push(q.front());

       q.pop();

   }

   while(!stk.empty()){

       q.push(stk.top());

       stk.pop();

   }

   // from queue to stack

   while(!q.empty()){

       stk.push(q.front());

       q.pop();

   }

   return flag;

}

int main(){

   stack<int> stk;

   // pushing data to stack

   stk.push(1);

   stk.push(3);

   stk.push(43);

   stk.push(2);

   stk.push(5);

   cout<<(checkfor(stk, 5)?"Found": "Not Found")<<'\n';

   cout<<(checkfor(stk, 10)?"Found": "Not Found")<<'\n';

   return 0;

}

Explanation:

Answer:

Trap is a software interrupt that occurs when there is a system call, while hardware interrupt occurs when a hardware component needs urgent attention.

Explanation:

Interrupt is an input signal that disrupt the activities of a computer system, giving immediate attention to a hardware or software request.

In trap interrupt, the system activities are stop for a routine kernel mode operation, since it has a higher priority than the user mode. At the end of the interrupt, it switches control to the user mode.

The hardware interrupt is a signal from hardware devices like the input/output devices, storage and even peripheral devices that draws an immediate attention of the processor, stopping and saving other activities and executing the event with an interrupt handler.

Answer:

"Web browser" is the correct answer for the above question.

Explanation: