Find the length of the apothem of a regular polygon that has a perimeter of 50 cm.

Find The Length Of The Apothem Of A Regular Polygon That Has A Perimeter Of 50 Cm.

Answers

Answer 1

Answer:

72

Step-by-step explanation:

72 i did the math


Related Questions

Mixed numbers 5 3\8 x 2 7\8

Answers

Answer:

15 29/64

Step-by-step explanation:

You will turn them both improper and then multiply

5 3/8= 43/8 2 7/8=23/8 66/8

A bag contains red,blue,and green marbles in the ratio of 7:6:8. If the bag contains 147 marbles, how many red marbles are there?

Answers

Answer:

49

Step-by-step explanation:

7:6:8 so 7+6+8=21

147 divided by 21 is 7

so 1 ratio equals 7

red = 7 so its gonna be 7x7=49

I believe it is 49
Because when you divided 147 by 3 you get 49.

Find the area of the following figure.

6.4 in^2
10.24 in^2
12.8 in^2

Answers

Yo sup??

area of a square =a*a

=a^2

where a is the lenght of its side

area=3.2*3.2

=10.2 unit2

pls do the conversion into inches

Hope this helps

The answer is: 10.24 in^2

A city law states that the area, x, of a new building on a lot must be less than 3/5 of the total area, y of the lot on which it is built which inequality shows the relationship?

Answers

Answer:

It’s A. I go To Uva too

Step-by-step explanation:

In a system of two linear equations what is the relationship between the slope of the lines and the numbers of solutions to the system?

Answers

In a system of two linear equations if the slopes are same then no solutions and different slope means exactly one solution.

Step-by-step explanation:

Let us consider two linear equations, each linear equation has slope and y-intercept.

Among those slope plays a major role, if there are no slope means than the line equation will be parallel to the x-axis. The slope will indicate the line's direction.

If two linear equations, having an identical slope then they will become like parallel lines. Thus the parallel lines won't intersect with each other. So there will be no solutions to the system.  (refer 1st image of both equations having slope 5)

If two linear equations have different slope they will intersect at any point. That is, it will result in exactly one solution. (refer 2nd image of both equations having different equations 1 and -1).

Let f(t) be the sale of a gaming product in thousand of units after t months f(t)=5t+11

Answers

Answer:

Since this dude got a Bird Brain I got ya'll

Step-by-step explanation:

Whats in Bold is what you put in the drop down menu. :)

So, f(3) = 26. This means that after 3 months, the number of products sold were 26,000.

If f(t) be the sale of a gaming product in thousand of units after t months f(t)=5t+11 the sale after three months will be 26 thousand.

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

Finding profit, populations, and distance traveled are some applications of functions. By entering a number into the formula, locating the independent variable on a table or graph, and then computing the resulting dependent variable, functions are employed.

It is given that,

f(t)=5t+11

So for the given condition after three months,

Substitute the value of t as 3,

f(3)=5(3)+11

f(3)=15+11

f(3)=26

Thus, if f(t) be the sale of a gaming product in thousand of units after t months f(t)=5t+11 the sale after three months will be 26 thousand.

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What does m equal?

3 3/4 m = 33 3/4

Answers

The believe the answer is m=9.

3x + 6y= 6
9x - 12y = 18 elimination with multiplication

Answers

Answer: x = 4y/3+2

   y = 0

Step-by-step explanation:

A the slope of f(x) is greater than the slope of g(x)

B the slope of f(x) is less than the slope of g(x)


C the slope of f(x) is equal than the slope of g(x)

The slope of g(x) is undefined

Answers

To find the slope of g(x), use the slope formula(m):

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]        And plug in two points, I will use:

(0, 2) = (x₁, y₁)

(5, 4) = (x₂, y₂)

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{4-2}{5-0}[/tex]

[tex]m=\frac{2}{5}[/tex]

You could do the same to find f(x) by finding two points and using the slope formula, or you could use this to tell visibly:

[tex]m=\frac{rise}{run}[/tex]

Rise is the number of units you go up(+) or down(-) from each distinguished point

Run is the number of units you go to the right from each distinguished point

If you look at the graph, you can see the points (0, -1) and (3, 1). From each point, you go up 2 units and to the right 3 units (you can make sure by using another point). So the slope of f(x) is  [tex]\frac{2}{3}[/tex]

Whichever line looks more vertical(and is positive) has the greater slope. So the slope of f(x) is greater than the slope of g(x). The answer is option A

MAPS On a map, Wilmington Street, Beech Drive, and Ash Grove Lane appear to all be parallel. The on

ilmington to Ash Grove along Kendall is 820 feet and along Magnolia, 660 feet. If the distance between Beech and

ove along Magnolia is 280 feet, what is the distance between the two streets along Kendall?

Answers

The distance between the two streets along Kendall is 347.9 feet.

Solution:

The image of the problem is attached below.

Distance between Wilmington to Ash Grove along Kendall = 820 feet

Distance between Wilmington to Ash Grove along Magnolia = 660 feet

Distance between Beech and  Ash Grove along Magnolia = 280 feet

Distance between Wilmington to Beech along Magnolia

                                       = 660 feet – 280 feet

                                       = 380 feet

Let us x be the distance between Wilmington to Beech along Kendall and

820 – x be the distance between Beech and  Ash Grove along Kendall.

The given streets are parallel.

By proportionality theorem, parallel lines cut by a transversal are in proportion.

[tex]$\Rightarrow\frac{380}{280} =\frac{x}{820-x}[/tex]

Do cross multiplication.

[tex]$\Rightarrow{380}({820-x}) =280x[/tex]

[tex]$\Rightarrow 311600-380x =280x[/tex]

[tex]$\Rightarrow 311600 =280x+380x[/tex]

[tex]$\Rightarrow 311600 =660x[/tex]

[tex]$\Rightarrow x=472.1[/tex]

Distance between Beech and  Ash Grove along Kendall          

                                    = 820 – x  

                                    = 820 – 472.1

                                    = 347.9

Hence the distance between the two streets along Kendall is 347.9 feet.

Final answer:

By analyzing the given distances along two parallel paths and using proportional reasoning, it is determined that the distance between Beech Drive and Ash Grove Lane along Kendall is approximately 547.33 feet.

Explanation:

Since Wilmington Street, Beech Drive, and Ash Grove Lane are parallel, and given the distances along Kendall and Magnolia, we can deduce the relationships between these distances to find the desired measurement. Utilizing the ratio of distances along Magnolia, we can apply the same ratio to the distances along Kendall.

We know that the total distance along Magnolia (660 feet) minus the distance between Beech and Ash Grove (280 feet) gives the distance between Wilmington and Beech along Magnolia, which is 380 feet. Assuming the distance distribution is proportional along Kendall, the distance between Beech and Ash Grove along Kendall would be given by:

(280 feet / 660 feet) * 820 feet = (2/3) * 820 feet = 547.33 feet.

Therefore, the distance between Beech Drive and Ash Grove Lane along Kendall is approximately 547.33 feet.

An architect is planning to make two triangular prisms out of iron. The architect will use ∆ABC for the bases of one prism and ∆DEF for the bases of the other prism.
-
-
(a) What is the scale factor from ∆ABC to ∆DEF?

(b) Suppose the height of the prism made by ∆ABC is 15 centimeters. What is the volume of the prism made by ∆ABC? Remember to show your work.

(c) Suppose the volume of the prism made by ∆ABC is 4459 cm^3. What is the volume of the prism made by ∆DEF? Remember to show your work.

Answers

a) 5/7

b) 4459 cm cube

c) 2275 cm cube

Step-by-step explanation:

Step 1 :

a)

The Side AB (28 cm) has been scaled to side DE (20 cm)

Let x b the scale factor.

Then we have 28 *x = 20

=> x = 20/28 = 5/7

Hence the scale factor is 5/7

Step 2 :

b)

Given the height of the triangular prism is 15 cm

Volume = ( 1/2 ) * base* height of the triangle * height of the prism

= (1/2)* 21*28*15 = 4410 cm cube.

Step 3 :

c)

Given volume of the triangular prism with base ABC is 4459 cm cube

The scale factor is 5/7

Hence the volume of the prism with DEF as base is

4459 * (5/7)*(5/7) = 2275 cm cube.

An eagle is flying from point A to point B in order to catch a sparrow. Its flying trajectory is a parabola shape

that has the equation y = -5(x+6) +10, where x and y are measured in meters. If the eagle is at a height of

20 meters, how far away are the two points from one another?

Answers

Answer:

From 10 to 20 meters.

Step-by-step explanation:

1) If the sparrow has a parabolic trajectory then it must be actually:

[tex]y=-5\left ( x+6 \right )^{2}+10[/tex]

2) If the eagle is at 20 meters high, then we write:

[tex]y=20[/tex]

Since the exact x coordinate was not given.

But since it wants to get the sparrow

3) If we expand the equation we have:

[tex]-5x^{2}-60x-170=0\\\\X_{v}=\frac{-b}{2a}=\frac{60}{-10} = -6\\Y_{v}=\frac{-\Delta}{4a} =\frac{-200}{-20} =10[/tex]

Since the maximum point is equal to 10. The distance where the sparrow is flying ranges from 10 to 20 meters to the eagles spot.

[tex]10\leq d \leq20 \:or \:[10,20][/tex]

4) Since the x coordinate was not given then we can neither precisely calculate the distance where A is nor where B is located.

Answer:

3 meters

Step-by-step explanation:

Min-jun travels 27 miles per hour. How long does it take him to travel 21 miles. Nearest tenth

Answers

Answer:

0.8 hours

Step-by-step explanation:

From the question;

Speed of Min-jun is 27 miles per hour Distance covered is 21 miles

We need to determine the time he takes to cover the distance given;

We need to know that;

Speed = Distance ÷ time

Rearranging the formula;

time = Distance ÷ speed

Thus;

Time = 21 miles ÷ 27 miles per hour

        = 7/9 hours

        = 0.8 hours

Thus, he took 0.8 hours to cover the distance covered

12. What steps do you need to take to solve
the equation 2x + 6 - 187
A Add 6. Then multiply by 2.
B Subtract 6. Then divide by 2.
C Add 6. Then divide by 2.
D Subtract 6. Then multiply by 2.

Answers

Answer:

B is the right answer.

Gumballs are 2 for 8 cents. How many gumballs can I get for 32 cents

Answers

Answer: 8 gumballs

Step-by-step explanation:

We can solve this problem with the Rule of three, since we are given as data three factors and one is unknown.

If 2 gumballs cost 8 cents, how many gumballs can we buy with 32 cents?:

[tex]2 gumballs[/tex]-----[tex]8 cents[/tex]

[tex]x[/tex]-----[tex]32 cents[/tex]

Then:

[tex]x=\frac{(2 gumballs)(32 cents)}{8 cents}[/tex]

[tex]x=8 gumballs[/tex] We can buy 8 gumballs with 32 cents

Find the equation of the line between (-7,4) and (5,9) in slope intercept form

Answers

Step-by-step explanation:

(9-4)/(5+7)= 5/12

y - 4 = 5/12(x + 7)

y - 48/12 = (5/12)x + 35/12

y = (5/12)x + 83/12

You are painting the walls and ceiling of a rectangular 20 x 30 ft room. The walls are 10 feet tall. You need two coats of paint. If a gallon of paint covers 400 square feet and cost $53 per gallon, how much will you spend on painting this room?

Answers

Answer:

The cost for painting will be $212.

Step-by-step explanation:

I am painting the walls and ceiling of a rectangular 20 x 30 ft room. The walls are 10 feet tall.

So, the total area to be painted = {2 × (20 + 30) × 10} + (20 × 30) = 1600 sq. ft.

Now, a gallon of paint covers 400 square feet and cost $53 per gallon.

So, the number of gallons of paint required will be [tex]\frac{1600}{400} = 4[/tex] gallons.

And the cost for painting will be $(4 × 53) = $212. (Answer)

(1 point
4. A regression line has a correlation coefficient of r=-0.91. Which of the following statements
must be true?
The data are so varied that there is almost no discernible trend whatsoever.
O The data are very tightly clustered around the trend line.
The trend line has a very steep negative slope.
The trend line reliably represents only 91 percent of the data.

Answers

Answer:

A: The data are so varied that there is almost no discernible trend whatsoever.

Step-by-step explanation:

The other 3 don't make sense and are not true for the question

A miners' cage of mass 420 kg contains 3 miners of total mass 280 kg. The cage
is lowered from rest by a cable. For the first 10 seconds the cage accelerates
uniformly and descends a distance of 75 m. What is the force in the cable during
the first 10 seconds?

Answers

Answer:

5817 Newtons.

Step-by-step explanation:

Total mass of the cage + the miners = 700 Kg which is a downward force of  700g N.

The net downward force = 700g - T where T is the tension (force) in the cable. The g = acceleration due to gravity = 9.81 m s-2.

We  calculate the  acceleration of the cage by using an equation of motion:

Distance = ut + 1/2 a t^2     where u = initial velocity , t = time and a = acceleration:

75 = 0(t) + 1/2 a (10^2)

50a =  75

a = 1.5 m s-2.

So using Newtons second law of motion

Force = mass * acceleration:

700*9.81 - T = 700 * 1.5

T = 700 * 9.81 - 700*1.5

= 5817 N.

Final answer:

The force in the cable during the first 10 seconds is 7930N. This was determined using the formulas s = ut + 1/2at² (to calculate acceleration) and F = ma + mg (to calculate the force).

Explanation:

The subject of this question is Physics, specifically dealing with forces and acceleration. The total weight of the miners and the cage equals the sum of the miners' weight and the cage's weight, giving a total of 700kg, using the formula weight = mass x gravity (assumed to be 9.8m/s²). Therefore, the total weight is 700kg x 9.8m/s² = 6860N.

Then, we'd calculate the acceleration. The formula used is s = ut + 1/2at², where s is distance, u is initial velocity, a is acceleration, and t is time. Given that initial velocity is 0, the formula is simplified to s = 1/2at². After rearranging, we get acceleration (a) = 2s/t² = 2*75/10² = 1.5m/s².

Finally, we can determine the force on the cable using the formula F = ma + mg (F = force, m = mass, a = acceleration, g = gravity). Substituting, we get F = 700kg x 1.5m/s² + 700kg x 9.8m/s² = 7930N. Therefore, the force in the cable during the first 10 seconds is 7930N.

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Tommy purchased a riding lawnmower with an original value of $2,500. If the value of the riding lawnmower decreases by $300 per year, what should be the value of the lawnmower after five years?


A. $1,000

B. $1,300

C. $1,500

D. $2,200

Answers

Answer:

A

Step-by-step explanation:

I also took a quiz with this question and I got the right answer.

prove that sin^4x - cos^4x = 2sin^2x - 1

Answers

Step-by-step explanation:

Step 1: From the given equation, taking the Left Hand Side (LHS) of the equation

Step 2: Simplify the LHS to make it equal to the Right Hand Side (RHS)

LHS = sin^4x - cos^4x = (sin²x)² - (cos²x)²

       = (sin²x - cos²x)(sin²x + cos²x)

       = sin²x - (1 - sin²x)  since sin²x + cos²x = 1

       = 2 sin²x - 1

       = RHS

Hence proved.

Shira’s Shoes sold 875,000 pairs of sandals in June, which was 70% of the total number of shoes sold. How many shoes did the company sell in June? Analyze Emily’s calculations. What error did she make?

Answers

Answer:

Emily solved for a part when she should have solved for the whole. 875,000 should be the numerator of the equivalent ratio. 70 x 12,500 is 875,000. So the answer is 100 x 12,500 which is 1,250,000.

Step-by-step explanation:

Shira Shoes sold 875,000 pairs of sandals in June, which was 70% of the total number of shoes sold. The number of shoes that the company sold in June is 612500.

If we looked carefully at the question, we will understand that it was from the total pairs of sandals sold that they deduce the percentage of the shoes sold.

From the information given:

Number of pairs of Sandals sold in June = 875,000Pairs of shoes sold = 70% of the pairs of sandals sold.

To determine the number of pairs of shoes sold, we have:

[tex]\mathbf{= 875000 \times \dfrac{70}{100}}[/tex]

[tex]\mathbf{= 8750 \times70}[/tex]

= 612500

Therefore, we can conclude that the number of shoes sold by the company in June is 612500

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Whoever gives me the right answer gets extra points, please help me

Answers

Area of the carpet needed = 38 ft²

Solution:

The given image is splitted into two shapes.

One is trapezoid and the other is triangle.

Top base of the trapezoid = 8 ft

Bottom base of the trapezoid = 12 ft

Height of the trapezoid = 3 ft

Area of the trapezoid = [tex]\frac{1}{2} (a+b)\times h[/tex]

                                    [tex]$=\frac{1}{2}(8+12)\times3[/tex]

                                    [tex]$=10\times3[/tex]

                                    = 30

Area of the trapezoid = 30 ft²

Base of the triangle = 12 ft – 8 ft = 4 ft

Height of the triangle = 4 ft

Area of the triangle = [tex]\frac{1}{2} b h[/tex]

                                 [tex]$=\frac{1}{2} \times4\times4[/tex]

                                 = 8

Area of the triangle = 8 ft²

Area of the carpet = Area of the trapezoid + Area of the triangle

                               = 30 ft² + 8 ft²

                               = 38 ft²

Area of the carpet = 38 ft²

Hence 38 square feet of outdoor carpet will need for this hole.

About 50 percent of the math questions are multiple choice and 50 percent are grid-in.

True. False

Answers

The answer I think is false

Answer:

True

Step-by-step explanation:

How do you graph y=5/3x +5

Answers

Answer:

Step-by-step explanation:

y = 5/3x + 5...in y = mx + b form, the slope is in the m position and the y int is in the b position.

so we have a slope of 5/3 and a y int of 5.....(0,5)

the x int can be found by subbing in 0 for y and solving for x

0 = 5/3x + 5

-5/3x = 5

x = 5 * -3/5

x = -15/5

x = -3......so ur x int is (-3,0)

go ahead and plot ur intercepts....(0,5) and (-3,0).....now start at (-3,0)....and since ur slope is 5/3....go up 5 spaces and to the right 3 spaces...plot that point.....then go up 5 and to the right 3...plot that point....keep doing this pattern....u should cross the y axis at (0,5). Then just connect ur dots and u have ur line.

The sum of 2 angles is 90 degrees and their difference is 40 degrees

Answers

Answer:

65 degrees

25 degrees

Step-by-step explanation:

x=first angle

y=second angle

x+y=90            x-y=40

                       x=40+y

(40+y)+y=90

40+2y=90

2y=50

y=25

                      x=40+25

                         x=65

Final answer:

The sum and difference of two angles can be found by setting up a system of equations and solving it. In this case, the two angles are 65 degrees and 25 degrees.

Explanation:

The question is asking for the sum and difference of two angles. Let's represent the two angles as x and y. We know that the sum of the two angles is 90 degrees, so we can write the equation x + y = 90. We also know that the difference of the two angles is 40 degrees, so we can write the equation x - y = 40.

We can solve this system of equations using substitution or elimination. Let's use the substitution method. From the second equation, we can rewrite it as x = y + 40. Substitute this value of x into the first equation:

(y + 40) + y = 90. Combine like terms: 2y + 40 = 90. Subtract 40 from both sides: 2y = 50. Divide by 2: y = 25.

Now substitute this value of y back into the equation x = y + 40: x = 25 + 40 = 65.

So, the two angles are x = 65 degrees and y = 25 degrees.

What is the approximate length of a pendulum that takes 2.4 pi seconds to swing back and forth?

Answers

Final answer:

The approximate length of a pendulum that takes 2.4 pi seconds to swing back and forth is about 14.7 meters.

Explanation:

To find the approximate length of a pendulum that takes 2.4 pi seconds to swing back and forth, we can use the formula for the period of a pendulum:

T = 2π √(L/g)

Where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Given that the period is 2.4 pi seconds, we can substitute this value into the formula:

2.4 pi = 2π √(L/g)

Simplifying the equation, we can divide both sides by 2π:

1.2 = √(L/g)

Squaring both sides of the equation, we get:

1.44 = L/g

Since we don't have the value of g, we cannot solve for L exactly. However, if we assume that g is approximately 9.8 m/s², which is the average acceleration due to gravity on Earth, we can estimate the value of L:

1.44 = L/9.8

Multiplying both sides by 9.8, we find:

L ≈ 14.7 m

In the order of operations, what is the first operation that you should take care of?

Answers

Answer: Remember PEMDAS. Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. But when trying to solve a problem with a variable, remember to go backwards.

Solve for x

X cubed =27/64

Answers

[tex]$x=\frac{3}{4}[/tex]

Solution:

Given expression is [tex]x^3=\frac{27}{64}[/tex].

To solve the expression and find the value of x.

[tex]$\Rightarrow x^3=\frac{27}{64}[/tex]

27 can be written as 3 × 3 × 3 = [tex]3^3[/tex]

64 can be written as 4 × 4 × 4 = [tex]4^3[/tex]

[tex]$\Rightarrow x^3=\frac{3^3}{4^3}[/tex]

Taking cube root on both sides of the function.

[tex]$\Rightarrow\sqrt[3]{x^3}=\sqrt[3]{\frac{3^3}{4^3}}[/tex]

Cube and cube roots are cancelled.

[tex]$\Rightarrow x=\frac{3}{4}[/tex]

Therefore, [tex]x=\frac{3}{4}[/tex].

two triangles are similar. The base of the first triangle is 10 cm and the height is 15 cm. The base of the second triangle is 12 cm. The height of the second triangle is?

Answers

Answer:

the height is 18cm

Explanation:

If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Are these ratios equal?

given that

Triangle 1 (first triangle)

base = 10cm

height = 15cm

Triangle 2 (second triangle)

base = 12cm

height = unknown

base 1 / base 2 = height 1 / height 2

10cm / 12cm = 15cm / xcm

xcm = 18cm

height = 18cm

Other Questions
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