Answer:
Option C is the correct option.
Explanation:
In the above scenario, Advancements in storage technologies and fast-declining storage prices are undermining growth in the mobile device because current mobile devices have many useful features of data storage and it can also use in other fields such as cloud storage, also in word processing and many other areas which are useful for the users.
Option A is incorrect because it is not suitable according to the following case. Option B is incorrect because data storage is not related the individual privacy. Options D and E are incorrect because in the above case, it is about the data storage techniques not for the network advances and analytical procedures.
A slow response when opening applications or browsing the Internet, applications that do not work properly, an operating system that does not boot up correctly or does not function normally, and event logs that report numerous, unusual alerts are all:________. A. Signs of computer aging. B. Indications of antivirus software running in the background. C. Symptoms of malware mutation.
Answer:
C. Symptoms of malware mutation
Explanation:
They are signs that could indicate that ones system is infected by virus.
Such signs includes:
1.Slow booting or startup.
2.Low space storage.
3.Blue screen of death.
4.Slow Internet performance.
5.Sending of spam messages.
6.Disabled security.
7.Browsing error.
8.Pop-up messages.
9.Renaming of files.
10.Loss of certain files, music, messages, etc.
Answer:
Option c: Symptoms of malware mutation
Explanation:
The most common symptom of a malware mutation is a slow running computer. The main activity of malware programs is to slow down your operating system and cause problems with your local applications even you are not using the internet. Event log reports unusual alerts and RAM is consumed by virus programs which makes RAM unavailable for your tasks.
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline.
The completed function "PrintPopcornTime()" can be referred to as given below.
We have,
The completed function "PrintPopcornTime()" as requested:
void PrintPopcornTime(int bagOunces) {
if (bagOunces < 2) {
System.out.println("Too small");
} else if (bagOunces > 10) {
System.out.println("Too large");
} else {
int time = 6 * bagOunces;
System.out.println(time + " seconds");
}
System.out.println();
}
In this function, we check the value of "bagOunces" using conditional statements.
If it's less than 2, we print "Too small".
If it's greater than 10, we print "Too large".
Otherwise, we calculate the time by multiplying 6 with "bagOunces" and print it followed by " seconds".
Finally, we print a new line to end the output.
Thus,
The completed function "PrintPopcornTime()" can be referred to as given above.
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Final answer:
The question involves creating a function, PrintPopcornTime(), that uses conditional logic to print different messages based on the provided parameter value, demonstrating fundamental programming concepts such as if-else statements and arithmetic operations.
Explanation:
The question asks to complete a function named PrintPopcornTime() in a programming context, which requires conditional logic to print different outputs based on the value of the parameter bagOunces. The function is supposed to print "Too small" if the value of bagOunces is less than 2, "Too large" if the value is greater than 10, and compute the time in seconds (by multiplying bagOunces by 6) to print for any value between 2 and 10 inclusive.
To fulfill this requirement, a combination of if-else statements can be used to check the size of bagOunces and print the corresponding message. The computation and print statement for values between 2 and 10 inclusive uses the logic of 6 * bagOunces followed by appending " seconds" to the result. Here's an example in pseudocode:
void PrintPopcornTime(int bagOunces) {
if (bagOunces < 2) {
print("Too small");
} else if (bagOunces > 10) {
print("Too large");
} else {
print(6 * bagOunces + " seconds");
}
print("\n"); // Prints a newline
}
This function demonstrates basic control structures like conditional statements which are fundamental in programming.
Write a iterative function that finds the n-th integer of the Fibonacci sequence. Then build a minimal program (main function) to test it. That is, write the fib() solution as a separate function and call it in your main() function to test it
Answer:
Answer is provided in the Explanation section
Explanation:
#include <stdio.h>
// Function to find the nth integer of Fibonnaci sequence
int fib(int n)
{
if( n <= 1)
return n;
int prev_num = 0, curr_num =1;
for(int i =0; i < n-1 ; i++)
{
int newnum=prev_num + curr_num;
prev_num=curr_num;
curr_num=new_num;
}
return curr_num;
}
int main(void)
{
printf("%d",fib(8));
return 0;
}
Output = 21
. Write a shell script that copies the file named by its first argument to a file with the same name with the filename extension of .bak. Thus, if you call the script with the argument first (and a file named first exists in the working directory), after the script runs you would have two files: first and first.bak. Demonstrate that the script works properly
Answer:
Hi! The requirement of this question is a simple shell script that makes a copy of a file if it exists in the directory. The main command for this is "cp <file_to_copy> <copy_filename>"
Explanation:
We can write a code below to implement this in a file called "backup_script". The first argument to the script is taken as the fie_name. Then a check is done to see if the file exists with the "[-f file_name]" code, and the file is copied with a ".bak" if true. A success message is finally printed out to the user.
./backup_script
#! /bin/bash
set file_name = $1
if [ -f file_name ]; then
cp file_name file_name.bak
fi
if [ -f file_name.bak ]; then
echo "File successfully copied"
fi
Which of the registration patterns is best suited for complex architecture? A. Client side discovery pattern B. Third party registration pattern C. Self registration
Final answer:
In complex microservices architectures, the Client-side discovery pattern is often recommended due to the control it offers clients. However, the Server-side discovery pattern is more suitable for systems with many services or frequent changes. The Self-registration pattern is typically used with one of the other two patterns.
Explanation:
The question pertains to service registration patterns in microservices architectures. In a complex architecture, the most recommended registration pattern is often the A) Client-side discovery pattern. This pattern allows clients to query a service registry, which holds the locations of various service instances. The client-side discovery pattern enables the clients to handle the discovery logic, providing a high degree of control over service invocation.
However, in a system with many services or frequent changes, the Server-side discovery pattern might be more suitable. Here, a server-side service registry is responsible for tracking service instances, and clients make requests via a router that queries the registry and directs each call to the appropriate service. This pattern offloads discovery responsibility from the client, simplifying the client-side logic.
Finally, the Self-registration pattern is where each service instance is responsible for registering and de-registering itself with the service registry. It is often used in combination with either the client-side or server-side discovery pattern.Ultimately, the choice depends on the specific requirements and constraints of the architecture in question, including scale, complexity, and the ability to handle failure scenarios.
Final answer:
In complex architectures, the Third-Party Registration Pattern is typically better suited compared to the Client-Side Discovery Pattern or Self-Registration as it centralizes service information and simplifies the discovery process.
Explanation:
When dealing with complex architecture within a microservices or distributed systems context, the Client-Side Discovery Pattern may not be ideal due to its inherent complexity and the need for each client to manage discovery logic.
The Third-Party Registration Pattern, also known as the Service Registry pattern, is oftentimes more suited for complex architectures. In this pattern, services register themselves with a third-party registry, which clients then query to discover network locations of available service instances.
This decouples the discovery process from the client and the service, centralizing service information and simplifying the overall architecture.
The Self-Registration pattern can be used in conjunction with the Third-Party Registration Pattern; however, it requires that each service instance has the logic to register and deregister itself with the service registry, which could become cumbersome in a system that is very large or highly dynamic.
In this exercise, you’ll design a "starter" HealthProfile class for a person. The class attributes should include the person’s first name, last name, gender, date of birth (consisting of separate attributes for the month, day and year of birth), height (in inches) and weight (in pounds). Your class should have a constructor that receives this data. For each attribute, provide setters and getters.The class should include methods that calculate and return the user’s age in years, maximum heart rate and target heart rate range, and body mass index (BMI). Write a Java application that prompts for the person’s information, instantiates an object of class HealthProfile for that person and prints the information from that object—including the person’s first name, last name, gender, date of birth, height and weight—then calculates and prints the person’s age in years, BMI, maximum heart rate and target-heart-rate range. It should also display the BMI values chart.
Answer:
package healthcare;
import java.util.Calendar;
public class HealthProfile {
private String firstName;
private String lastName;
private char gender;
private int day;
private int month;
private int year;
private double height;
private double weight;
public HealthProfile(String firstName, String lastName, char gender, int day, int month, int year, double height,
double weight) {
super();
this.firstName = firstName;
this.lastName = lastName;
this.gender = gender;
this.day = day;
this.month = month;
this.year = year;
this.height = height;
this.weight = weight;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public char getGender() {
return gender;
}
public void setGender(char gender) {
this.gender = gender;
}
public int getDay() {
return day;
}
public void setDay(int day) {
this.day = day;
}
public int getMonth() {
return month;
}
public void setMonth(int month) {
this.month = month;
}
public int getYear() {
return year;
}
public void setYear(int year) {
this.year = year;
}
public double getHeight() {
return height;
}
public void setHeight(double height) {
this.height = height;
}
public double getWeight() {
return weight;
}
public void setWeight(double weight) {
this.weight = weight;
}
public int calculateAge() {
Calendar dateOfBirth = Calendar.getInstance();
dateOfBirth.set(year, month, day);
Calendar now = Calendar.getInstance();
return now.get(Calendar.YEAR) - dateOfBirth.get(Calendar.YEAR);
}
public int maximumHeartRate() {
return 220 - calculateAge();
}
public double[] targetHeartRateRange() {
double[] range = new double[2];
// Calculate Stating range(50 % of maximumHeartRate)
range[0] = 0.5 * maximumHeartRate();
// Calculate End range(85 % of maximumHeartRate)
range[1] = 0.85 * maximumHeartRate();
return range;
}
public double calculateBMI() {
return (weight * 703)/(height * height);
}
public String getBMIValue()
{
double bmi=calculateBMI();
if(bmi < 18.5)
{
return "Underweight";
}
else if (bmi>18.5 && bmi<24.9)
{
return "Normal";
}
else if (bmi>25 && bmi<29.9)
{
return "Normal";
}
else if (bmi>=30)
{
return "Obese";
}
return "DafultValue"; //you can give any default value of your choice here if no condition meets the given criteria
}
@Override
public String toString() {
return "HealthProfile [firstName=" + firstName + ", lastName=" + lastName + ", gender=" + gender + ", Date Of Birth="
+ day + "-" + month + "-" + year + ", height=" + height + ", weight=" + weight + "]";
}
}
package healthcare;
import java.util.Scanner;
public class TestHealthCare {
private static Scanner sc;
public static void main(String[] args) {
sc = new Scanner(System.in);
System.out.println("Please enter following details of the Patient");
System.out.println("First Name");
String firstName=sc.nextLine();
System.out.println("Last Name");
String lastName=sc.nextLine();
System.out.println("Gender ...... M or F ?");
char gender=sc.next().charAt(0);
System.out.println("Date of Birth");
System.out.println("Day");
int day=sc.nextInt();
System.out.println("Month");
int month=sc.nextInt();
System.out.println("Year");
int year=sc.nextInt();
System.out.println("Height in inches");
double height =sc.nextDouble();
System.out.println("weight (in pounds)");
double weight =sc.nextDouble();
HealthProfile obj=new HealthProfile(firstName, lastName, gender, day, month, year, height, weight);
int age=obj.calculateAge();
System.out.println("Patient age is "+age + " Years");
int maxHeartRate=obj.maximumHeartRate();
System.out.println("Patient Maximum Heart Rate is "+maxHeartRate + " beats per minute");
//Call targetHeartRateRange
double targetHeartRateRange []=obj.targetHeartRateRange();
System.out.println("Target Heart Range is "+targetHeartRateRange [0] + " - " +targetHeartRateRange [1]);
//Call calculateBMI
double bmi=obj.calculateBMI();
System.out.println("Patient BMI is "+bmi);
//call getBMIValue
System.out.println("Patient BMI Value is "+obj.getBMIValue());
}
}
Explanation:
Inside the calculate the age in years method, create Date of Birth of Object.Create Current Date .Inside the method maximumHeartRate , create a New Object of HealthProfile class and Call its constructor .Data governance consists of? A. the processes, methods, and techniques to ensure that data is of high quality, reliable, and unique (not duplicated), so that downstream uses in reports and databases are more trusted and accurate B. the overarching policies and processes to optimize and leverage information while keeping it secure and meeting legal and privacy obligations in alignment with organizationally stated business objectives; C. established frameworks and best practices to gain the most leverage and benefit out of IT investments and support the accomplishment of business objectives D. None of the above
Answer:
A. the processes, methods, and techniques to ensure that data is of high quality, reliable, and unique (not duplicated), so that downstream uses in reports and databases are more trusted and accurate
Explanation:
Data governance consists of the processes, methods, and techniques to ensure that data is of high quality, reliable, and unique (not duplicated), so that downstream uses in reports and databases are more trusted and accurate. Master data management (MDM) tools can assist in this effort.
Once the definitions of these three information-related governance disciplines are clear, their differences become more distinct.
Compare and Contrast IPv4 and IPv6. Find examples of companies who are currently using IPv6. What are some of the benefits of using IPv6 over IPv4 and vice versa.
Answer/Explanation:
IPv4 address field is of 32-bits while the address field of IPv6 is 128-bits.The IPv4 requires a packet size of 576 bytes with optional fragmentation whereas, IPv6 uses 1280 bytes without fragmentation.IPv6 is preferred over IPv4 because of its large address range. IPv4 uses 32-bit source and destination address and we are running out of addresses. To solve this issue, Internet Engineering Task Force has devised a solution by introducing IPv6 which uses 128-bits address field. It is being said that if we convert the water bodies present on earth into deserts and then we assign each particle of desert with an address even then the addresses of IPv6 won't end.IPv6 provides flexible options and extensions.IPv6 provides multi broadcast while, IPv4 just provides broadcast.Internet has switched from IPv4 to IPv6.
When you connect to an unsecured wireless network, what might dishonest or unscrupulous computer users try to do?
Answer:
Hackers can snoop on data sent over your network.
Hackers can use your network to access your computer's files and system information.
Explanation: Unsecured Wireless connections are wireless connections which are have no passwords they are open to the general public,such networks can be very risky to use as it gives easy access to dishonest persons who can manipulate that opportunity to SNOOP ON DATA SENT OVER YOUR NETWORKS. They can use this hacking to fraudulently steal from your bank account and obtain your private information.
When connecting to an unsecured wireless network, dishonest or unscrupulous computer users may try to eavesdrop, intercept data, and gain unauthorized access to personal information.
Explanation:When connecting to an unsecured wireless network, dishonest or unscrupulous computer users may attempt to carry out various malicious activities such as eavesdropping, data interception, and unauthorized access to your devices and personal information.
For example, they may use packet sniffing techniques to capture sensitive data transmitted between your devices and the network, such as passwords or credit card information. They can also launch man-in-the-middle attacks, where they intercept data between your device and the network to gain unauthorized access or manipulate the information exchanged.
To protect yourself, it is important to always connect to a secure and encrypted network, use a virtual private network (VPN) for added security, and avoid transmitting sensitive information over unsecured networks.
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Explain how increasingly standardized data, access to third-party datasets, and current trends in hardware and software are collectively enabling a new age of decision making?
Answer and Explanation:
The information revolution has had profound impacts on decision-making allowing more informed decision as a result of "stone throw" information reach- in our pockets, the desk, the TV, and the vast number of technologies that make this possible.
Standardized data which involves data formatted to bring uniformity and be easily understood and compared by programs and people , access to rich, outsider dataset and less tasking and flexible plus powerful programming have all contributed to empowering another time of information driven decision-making that are less prone to errors and mistakes.