a needle palm tree at the park is growing an average of 4.35 cm per day. A cabbage palm tree next to it is growing an avrege of 1.26 in per day. which? one is growing faster?

To solve the equation 4r + 8 + 5 = -15 - 3r, combine like terms and isolate the variable r leading to the solution r = -4.

The student is asking how to solve the algebraic equation 4r + 8 + 5 = -15 - 3r. To solve for r, we must first simplify and combine like terms. This means we need to get all the terms with r on one side of the equation and the constant numbers on the other side.

Therefore, the solution to the equation is r = -4.

Final answer:

The solution to the equation 4r + 8 + 5 = -15 - 3r is r = -4.

Explanation:

The algebraic equation provided by the student is 4r + 8 + 5 = -15 - 3r.

To solve for r, we must first simplify and rearrange the equation by combining like terms and moving the variables to one side and the constants to the other.

By subtracting 3r from both sides and also subtracting 8 + 5 from both sides, we end up with 4r + 3r = -15 - 8 - 5. Simplifying further, we get 7r = -28.

Finally, dividing both sides by 7 yields r = -4.

Answer:

the area of a circle is [tex]\pi[/tex]rsqr

32 x 32 =1024[tex]\pi[/tex]

Step-by-step explanation:

Answer:

A= 1024 x^{2}

Step-by-step explanation:

Answer:

  The area is multiplied by 9.

Step-by-step explanation:

The original square has an area of ...

  A = (4 in)² = 16 in²

The larger square has an area of ...

  A = (3·4 in)² = (3²)(4²) in² = 9·16 in² . . . . . 9 times the original area

The area is multiplied by the square of the scale factor: 9.

Answer:

y=-x+7

Step-by-step explanation:

every year she goes down how many times she is younger than him by 1 so -x is actually -1x, and it starts at 7 years so we put that as our y intercept

Answer:

[tex]Equation\ of\ line:\ y=\frac{1}{2}x-10[/tex]

Step-by-step explanation:

[tex]Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c[/tex]

[tex]-5=-5+c\\\\c=-10[/tex]

[tex]Equation\ of\ line:\ y=\frac{1}{2}x-10[/tex]

Answer:

Angles: 40.9°, 99.05°, 40.05°

Step-by-step explanation:

Triangles

When we are given the lengths of the 3 sides of a triangle, we can easily compute all the internal angles by using the cosine's law or formula. Being x,y and z the sides of a triangle, and \alpha, \beta , \gamma the three opposite angles respectively, then

[tex]x^2=y^2+z^2-2yzcos\alpha[/tex]

[tex]y^2=x^2+z^2-2xzcos\beta[/tex]

[tex]z^2=x^2+y^2-2xycos\gamma[/tex]

We have x=5.9, y=8.9, z=5.8, then from

[tex]x^2=y^2+z^2-2yzcos\alpha[/tex]

We solve for [tex]\alpha[/tex]

[tex]\displaystyle cos\alpha=\frac{y^2+z^2-x^2}{2yz}[/tex]

[tex]\displaystyle cos\alpha=\frac{8.9^2+5.8^2-5.9^2}{2\times 8.9\times 5.8}[/tex]

[tex]cos \alpha=0.756[/tex]

[tex]\alpha=40.9 ^o[/tex]

Similarly

[tex]\displaystyle cos\beta=\frac{x^2+z^2-y^2}{2xz}[/tex]

[tex]\displaystyle cos\beta=\frac{5.9^2+5.8^2-8.9^2}{2\times 5.9\times 5.8}[/tex]

[tex]cos\beta=-0.157[/tex]

[tex]\beta=99.05^o[/tex]

Finally

[tex]\displaystyle cos\gamma=\frac{5.9^2+8.9^2-5.8^2}{2\times 5.9\times 8.9}[/tex]

[tex]cos\gamma=0.765[/tex]

[tex]\gamma=40.05^o[/tex]

Answer:

Answer is D

Step-by-step explanation:

Answer:

The mid point of the line segment is [tex]$ \bigg(- \frac{3}{2}, -\frac{3}{2} \bigg ) $[/tex].

Step-by-step explanation:

From the graph we can find the end points of the line segment. The end points are: [tex]$ (- 1, - 4) $[/tex] and [tex]$ (4, 1) $[/tex].

When the end points of a line segment are known, the mid point of the line segment is given by:

                                   [tex]$ \bigg ( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \bigg ) $[/tex]

where [tex]$ (x_1, y_1) $[/tex] and [tex]$ (x_2, y_2) $[/tex] are the end points.

Here: [tex]$ (x_1, y_1) = (- 1, - 4) $[/tex] and [tex]$ (x_2, y_2) = (4, 1) $[/tex]

Therefore, the mid point of the line segment would be:

[tex]$ \bigg ( \frac{- 1 + 4}{2}, \frac{- 4 + 1}{2} \bigg) $[/tex]

[tex]$ \bigg(- \frac{3}{2}, -\frac{3}{2} \bigg ) $[/tex] is the required answer.

Answer:

Here, the coordinates aren't telling special characteristic of any shape, so it would be Paralleogram

In short, Your Answer would be Option B

Step-by-step explanation:

Answer:

0.

Step-by-step explanation:

Using the laws of logarithms:

log81/8 + 2log2/3 - 3log 3/2 + log 3/4​

= log 81/8 + log (2/3)^2 - log (3/2)^3 + log 3/4

= log 81/8 + log 4/9 - log 27/8 + log 3/4

= log 81/8 + log 4/9 - (log 27/8 - log 3/4)

= log (81/8 *  4/9) - log (27/8 * 4/3)

= log 9/2 - log 9/2

= 0.

Answer:

1655

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3

This indicates the sequence is arithmetic with sum to n terms

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ]

Here a₁ = - 4, d = 3 and n = 90, thus

[tex]S_{90}[/tex] = [tex]\frac{90}{2}[/tex] [ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655

Answer:D

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

U will add 5 plus 3 and then divide 8 by 2

Answer:4

Step-by-step explanation:

Answer:

112

Step-by-step explanation:

Given: Joe gave 1/4 of his total candies to his classmate.

            Then, he gave 4/6 of when he had left to his brother.

             He gave 25% of the remaining candies to his sister.

             Finally, he only had 21 candies left.

Lets assume the total number of candies at the beginning be "x".

First, finding the number candies left after giving candies to classmate.

∴ Remaining candies=  [tex]x- x\times \frac{1}{4}[/tex]

Solving it to find remaining candies after giving candies to clasmate.

⇒ Remaining candies= [tex]x-\frac{x}{4}[/tex]

Taking LCD as 4

⇒ Remaining candies= [tex]\frac{4x-x}{4} = \frac{3x}{4}[/tex]

∴ Remaining candies after giving candies to clasmate= [tex]\frac{3x}{4}[/tex]

now, finding the candies left after giving candies to his brother.

∴ Remaining candies= [tex]\frac{3x}{4} - \frac{3x}{4} \times \frac{4}{6}[/tex]

Solving it to find the remaining candies after giving candies to his brother.

⇒ Remaining candies= [tex]\frac{3x}{4} - \frac{x}{2}[/tex]

Taking LCD 4

⇒ Remaining candies= [tex]\frac{3x-2x}{4} = \frac{x}{4}[/tex]

∴ Remaining candies after giving candies to his brother= [tex]\frac{x}{4}[/tex]

We know, Joe was left with only 21 candies after giving candies to his sister.

Therefore, putting an equation for remaining candies to find the number of candies at the beginning.

⇒[tex]\frac{x}{4} - 25\% \times \frac{x}{4} = 21[/tex]

⇒[tex]\frac{x}{4} - \frac{0.25x}{4} = 21[/tex]

Taking LCD 4

⇒ [tex]\frac{x-0.25x}{4} = 21[/tex]

⇒ [tex]\frac{0.75x}{4} = 21[/tex]

Multiplying both side by 4

⇒[tex]0.75x= 21\times 4[/tex]

dividing both side by 0.75

⇒[tex]x= \frac{21\times 4}{0.75}[/tex]

∴[tex]x= 112[/tex]

Hence, Joe had 112 candies at the beginning.

Answer:

m<B=m<K=100

m<A=m<J=133

m<L=m<C=41

m<M=m<D=86

Step-by-step explanation:

Since [tex]ABCD\cong JKLM[/tex], the corresponding angles are congruent.

This implies that:

[tex]m\angle A=133=m\angle J[/tex]

m<L=41=m<C

m<M=86=m<D

The sum of angles in a quadrilateral is 360 degrees.

m<B+133+41+86=360

m<B+260=360

m<B=360-260

m<B=m<K=100

Answer:

Yes 60 is the answer

Step-by-step explanation:

Multiply the numbers in the bracket

Then multiply by 5

Answer:

Step-by-step explanation: 5×(3×4) =60

5×(12) =60

5×12 =60

Answer:

W= -2

Step-by-step explanation:

Simply the expression: 9(w – 4) – 7w = 5(3w – 2)

First step: 9w -36-7w = 15w-10

Second step: 2w-36=15w-10

Third step:-36+10=15w-2w

Fourth step:-26=13w

Fifth step: w=[tex]\frac{-26}{13}[/tex]

Six step: w=-2

Answer:

-2=w

Step-by-step explanation:

9(w-4) - 7w= 5(3w-2)

9w-36-7w= 15w - 10

2w-36=15w-10

- 2w      -2w

-36=13w-10

+10         +10

-26= 13w

-2=w

Answer:

A(x1,y1) and B(x2,y2)

Step-by-step explanation:

you take two points your start and your stop and put them into the equations and solve

Answer: Noelle's age is 20 years

Noelle's father is 54 years

Step-by-step explanation: First of all, let Noelle's age be represented by x. Given that her father's age is 6 less than three times her age, her father's age would be expressed as

3n - 6

Note also that their ages sum up to 74.

Therefore,

n + (3n - 6) = 74

n + 3n - 6 = 74

4n - 6 = 74

Add 6 to both sides of the equation

4n = 80

Divide both sides of the equation by 4

n = 20

Hence, Noelle's father's age is 54 (that is 3n - 6)

While Noelle's age is 20

Noelle’s age is 20

her dads age is 54

Answer: No

Step-by-step explanation:

5 + 1/2 = 5 1/2

Answer:

Step-by-step explanation:

Just multiply the first equation by -1 and then add them together to find x. Should look something like

-2x - y = -7

5x + y = 9

--------------------

3x + 0 = 2

x = 2/3

Now back substitute using either equation to find y. I'll use the first:

2(2/3) + y = 7

4/3 + y = 7

y = 7 - 4/3 = 21/3 - 4/3 = 17/3

Answer:

x=2/3

y=17/3

Answer:

x=-9/4, y=-27/4. (-9/4, -27/4).

Step-by-step explanation:

y=7x+9

2y+2x=-18

----------------

simplify 2y+2x=-18 into y+x=-9

------------------

7x+9+x=-9

8x+9=-9

8x=-9-9

8x=-18

x=-18/8

simplify

x=-9/4

y=7(-9/4)+9=-63/4+9=-27/4

I think it might be D

The size of the sample space is the total number of possible outcomes. For example, when you roll 1 die, the sample space is 1, 2, 3, 4, 5, or 6. So the size of the sample space is 6. Then you need to determine the size of the event space.

Answer:

I think it's the last one

Step-by-step explanation:

Answer:

The solution to the system of equations given is (3, 2)

Step-by-step explanation:

Let's solve the system of equations given:

2y = 4  

-x = -3

****************

2y = 4

y = 4/2

y = 2

____________________

-x = - 3

x = 3

The solution to the system of equations given is (3, 2)

The solution to the system of equations is x = 3 and y = 2.

To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using the substitution method.

From the first equation, we can solve for y:

2y = 4

y = 4/2

y = 2

Now, substitute this value of y into the second equation:

-x = -3

x = 3

So the solution to this system of equations is x = 3 and y = 2.

Answer:

(sqrt(5))/4

Step-by-step explanation:

Simplify the following:

sqrt(5/16)

sqrt(5/16) = (sqrt(5))/(sqrt(16)):

(sqrt(5))/(sqrt(16))

sqrt(16) = sqrt(2^4) = 2^2:

(sqrt(5))/(2^2)

2^2 = 4:

Answer: (sqrt(5))/4

Answer:

srry that was my lil bro

Step-by-step explanation:

Answer:

No, it's not

Step-by-step explanation:

Lets simplify the two fractions to the lowest term

for 5/20 we'll divide the numerator and denominator by 5 (the HCF of the two)

it then becomes 1/4

For 4/12 we'll divide the numerator and denominator by 4 (the HCF of the two)

it then becomes 1/3

1/4 = 0.25

1/3 = 0.33

therefore 5/20 is not equal to 4/12

Answer:

Step-by-step explanation:

Ratio=3:4

so,the pair of adjacent sides are 3x,4x

Pythagorean theorem,

[tex](3x)^{2}+(4x)^{2}=20^{2}\\9x^{2}+16x^{2}=400\\\\25x^{2}=400\\\\x^{2}=\frac{400}{25}\\\\ x^{2}=16\\\\x=\sqrt{16}\\\\x=4\\\\length=4x=4*4=16cm\\\\breadth=3x=3*4=12cm\\\\Perimeter=2*(l+b)\\\\=2*(16+12)=2*28\\\\=56cm[/tex]

Amil's unit rate is calculated by dividing the distance traveled (15 miles) by the time in hours (0.917 hours), resulting in approximately 16.36 mph. Abe's unit rate is faster but cannot be precisely determined without more information about his distance or time.

Amil rode 15 miles in 55 minutes. To find Amil's unit rate, we divide the total distance by the total time. The unit rate is a measure of speed, indicating how many miles are traveled in one minute. To find this unit rate, we perform the following calculation:

Convert the time from minutes to hours to find the unit rate in miles per hour (mph), since speed is often expressed this way: ​55 minutes × (1 hour/60 minutes) = 0.917 hours

Divide the distance by the time: 15 miles ÷ 0.917 hours = 16.36 mph (rounded to two decimal places).

Amil's unit rate is approximately 16.36 mph. This information can be used to estimate Abe's unit rate, knowing that Abe rode at a faster rate. If we knew how far Abe rode or his unit rate in miles per minute, we could compare the two directly. Without additional information about Abe's distance or time, we can only say that Abe's unit rate exceeds 16.36 mph.

The width of the rectangle is 9 cm.

The length of the rectangle is 34 cm.

Step-by-step explanation:

step 1 :

Let width of the rectangle be 'x'

The length of the rectangle = 7 + 3x

step 2 :

Perimeter of the rectangle = 2 (length + width)

⇒ 86 = 2 (7 + 3x + x)

⇒ 86 = 2 (7 + 4x)

⇒ 86 = 14 + 8x

⇒ 72 = 8x

x = 72/8

x = 9

∴ The width of the rectangle is 9 cm

step 3 :

The length of the rectangle = 7 + 3x

                                              = 7 + 3(9)

                                              = 7+27 = 34 cm

Answer:

[tex]E(p)=51,450p+346,920[/tex]

Step-by-step explanation:

The function

[tex]m(p) = 175p + 1,180[/tex]

gives the mass of the car as a function of the number of passengers in it.

And the function

[tex]E(m) = 9.8m*h[/tex]

gives the potential energy of the car as a function of the car's mass.

Now if the height of the ramp is 30 meters, we have

[tex]E(m) =9.8m*(30)[/tex]

[tex]E(m) =294m[/tex]

And to find the potential energy as a function of the number of passengers, we just substitute [tex]m(p)[/tex] into [tex]E(m)[/tex] to get:

[tex]E(m(p))=294(175p+1180)[/tex]

[tex]\boxed{ E(p)=51,450p+346,920}[/tex]

which gives the potential energy as a function of the number of passengers.

Answer:

its A on edge2021

Step-by-step explanation: