. A child has a toy tied to the end of a string and whirls the toy at constant speed in a horizontal circular path of radius R. The toy completes each revolution of its motion in a time period T. What is the magnitude of the acceleration of the toy? a. c. Zero d. 4T2R/T2 e. TR/T2

The maximum loss of water vapor per breath is 0.088 g. The partial pressure of water vapor is 6286.41 N/m², which closely matches the given vapor pressure of 6.31 × 10³ N/m², confirming the saturation condition.

To solve the given problem, we need to perform the following calculations:

(a) Maximum Loss of Water Vapor

The saturation vapor density of water vapor at 37.0°C is 44.0 g/m³. Given that 2.00 L of air is exhaled, we first convert the volume to cubic meters (since the density is in g/m³):

[tex]2.00 L = 2.00 * 10^{-3} m^3[/tex]

Now, using the density to find the mass of water vapor exhaled:

[tex]mass = density * volume = 44.0 g/m^3 *2.00 * 10^{-3} m^3 = 0.088 g[/tex]

Thus, the maximum loss of water vapor per breath is 0.088 g.

(b) Partial Pressure of Water Vapor

To find the partial pressure of water vapor, we use the Ideal Gas Law: PV = nRT. First, we convert the given water vapor density into moles per unit volume:

Density (44.0 g/m³) divided by the molar mass of water (18.015 g/mol) gives us:

44.0 g/m³ ÷ 18.015 g/mol = 2.44 mol/m³

So the number of moles, n, per unit volume is 2.44 mol/m³. Now using the Ideal Gas Law:

P = nRT, where R is the universal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin (310.15 K)

[tex]P = 2.44 mol/m^3 * 8.314 J/(mol.K) * 310.15 K = 6286.41 N/m^2[/tex]

Thus, the partial pressure of water vapor is 6286.41 N/m². Comparing this with the vapor pressure of 6.31 × 10³ N/m², we see they are very close, confirming the saturation condition.

Answer:

1.

Explanation:

because 12,000 divided by 300 is 40 so its 40m

Answer:

40%

Explanation:

The other person got it right up until making it opposite because its a percentage. The equation is correct but you'd just need to take the 60% answer and subtract it from 100% because 60% is equal to how much effiency the exhaust is taking away, thus making your answer 40%

Answer:

the athlete spends 2.4 times more time at the upper part of his way than in the lower one.

Explanation:

Let’s find the velocity V1 of an athlete to reach half of the maximum height equation

V1 = v20 -2gh = v20 -2g(ymax)/2

Here, Vo is the initial velocity of athlete, v1 is the velocity of athlete at half the maximum height, g is the acceleration due to gravity, h=ymax /2 is half of the maximum height.

We can fund the maximum height that athlete can reach from the law of conservation of energy

KE = PE

1/2M v20 = mg ymax

ymax = v20 /2g

Then, substituting ymax into the first equation we get

V21 = v20 – v20/2 = v20/2

V1 = V0/∫2, we can find the time that the athlete needs to reach the maximum height (ymax) from the kinematic equation

V = V0 – gt

Here, V is the final velocity of an athlete at the maximum height; V0 is the initial velocity of an athlete

Since, V=0ms-1, we get t=V0/g

Similarly, we can find the time t1 that an athlete needs to reach maximum height from the Ymax/2:

T1 = V1/g =V0/g∫2

So, it is obvious that the time to reach Ymax from Ymax/2 is nothing more than the difference between t and t1:

t-t1 =V0/g(1-1/∫2)

finally, we can calculate the ratio of the time he is above Ymax/2 to the time it takes him to go from floor to that height.

T1/t-t1 =V0/g∫2V0 ×g∫2/∫2-1 =2.4

Answer; the athlete spends 2.4 times more time at the upper part of his way than in the lower one.

Answer:

5541Hz

Explanation:

If the frequency of a wave is directly proportional to the velocity we have;

F = kV where;

F is the frequency

K is the constant of proportionality

V is the velocity

Since f = kV

K = f/v

K = F1/V1 = F2/V2

Given f1 = 412Hz v1 = 25.8m/s f2 = ? V2 = 347m/s

Substituting in the formula we have;

412/25.8=f2/347

Cross multiplying

25.8f2 = 412×347

F2 = 412×347/25.8

F2 = 5541Hz

The frequency heard will be 5541Hz

Answer: Bodies of water

Explanation:

Large bodies of water, such as oceans, seas and large lakes, can affect the climate of an area

Answer:

From longest to shortest wavelength:

1) Radio waves

2) Microwaves

3) Infrared

4) Visible light

5) Ultraviolet

6) X-rays

7) Gamma rays

Explanation:

Electromagnetic waves are periodic oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion the wave itself.

All electromagnetic waves travel in a vacuum with the the same speed, which is know as the speed of light; it is one of the fundamental constants of nature, and its value is

[tex]c=3.0\cdot 10^8 m/s[/tex]

Electromagnetic waves are classified into 7 different types, depending on their wavelength/frequency. From longest to shortest wavelength (and so, from lowest to highest frequency, since frequency is inversely proportional to wavelength), we have (with their correspondant wavelength):

Radio waves (>1 m)

Microwaves (1 mm - 1 m)

Infrared (750 nm - 1 mm)

Visible light (380 nm - 750 nm)

Ultraviolet (10 nm - 380 nm)

X-rays (0.01 nm - 10 nm)

Gamma rays (<0.01 nm)

The electromagnetic spectrum spans from radio waves with the longest wavelength to gamma rays with the shortest. The order is: radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma rays.

The question asks you to match the various types of light to their respective wavelengths on the EM spectrum. The Electromagnetic Spectrum (EM Spectrum) arranges different types of electromagnetic radiation in order of their wavelengths. Light types in order of longest to shortest wavelengths are as follows:

https://brainly.com/question/23727978

#SP3

Answer:

The aanswers to the question are

(a) 5.33 m³

(b) 1.83 kg/m³

Explanation:

Volume of leak = 40 L, density of propane = 0.24g/cm³

Mass of leak = Volume × Density = 40000 cm³×0.24 g/cm³ = 9600 gram

Molar mass of propane = 44.1 g/mol Number of moles = 9600/44.1 = 217.69 moles

at 1 atmosphare and 298.15 K we have

PV = nRT therefore V = nRT/P = (217.69×8.3145×298.15)/‪101325‬ = 5.33 m³

The volume of the vapour = 5.33 m³

(b) Density = mass/volume

Recalculating the above for T = 293 K we have V = 5.33×293÷298.15 = 5.23 m³

Therefore density of propane vapor = 9600/5.23 = 1834.22 g/m³ or 1.83 kg/m³

The current will double

Explanation:

The relationship between voltage and current in an electric circuit is given by the following equation (Ohm's law):

[tex]V=IR[/tex]

where

V is the voltage

I is the current

R is the resistance

making R the subject,

[tex]R=\frac{V}{I}[/tex]

Since in this experiment the resistance is kept constant, we can write:

[tex]\frac{V_1}{I_1}=\frac{V_2}{I_2}[/tex]

where

[tex]V_1=25 V[/tex] is the voltage in the 1st experiment

[tex]V_2=50 V[/tex] is the voltage in the 2nd experiment

[tex]I_1,I_2[/tex] are the currents in the 1st and 2nd experiment

We can re-arrange the equation as

[tex]\frac{I_2}{I_1}=\frac{V_2}{V_1}=\frac{50}{25}=2[/tex]

This means that the current will double in the 2nd experiment.

Learn more about current and voltage:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

Answer:

Yes, this is according to the Newton's first law of motion.

Neither its direction nor its velocity changes during this course of motion.

Explanation:

Yes, it is very well in accordance with Newton's first law of motion for a body with no force acting on it and it travels with a non-zero velocity.

During such a condition the object will have a constant velocity in a certain direction throughout its motion. Neither its direction nor its velocity changes during this course of motion.

An object can maintain a nonzero velocity in the absence of a net external force due to Newton's first law of motion. The object will continue to move with the velocity it has until a net force acts upon it. This state of motion with constant velocity is known as dynamic equilibrium.

Yes, it is possible for an object to be traveling with a velocity that is not zero even if the net external force acting on it is zero. According to Newton's first law of motion, also known as the law of inertia, an object will maintain its state of motion unless acted upon by a net external force. This means that if there is no net external force on the object, its acceleration is zero, and it will continue moving at its current velocity, which can be nonzero. This constant velocity can be in any direction and of any magnitude, and it remains constant until acted upon by a net force.

For example, when your car is moving at a constant velocity down the street, even though it is moving, the net external force on it can be zero. The forces such as friction and air resistance are balancing out the driving force, leading to no net force on the car, which is a state of dynamic equilibrium.

To find the speed of the tip of the woman's shadow, we use related rates and the similarities of triangles. The rate at which the shadow tip moves is found by setting up a proportion based on similar triangles and differentiating with respect to time. The result is that the tip of the shadow moves at 10.67 ft/sec when the woman is 50 ft from the light pole.

The question is about a real-world application of related rates, which is a concept in calculus where one rate is determined based on another rate. In this scenario, we have a woman walking away from a light pole, and we need to find out how fast the tip of her shadow is moving. To solve it, we use the similarities of triangles created by the woman and the light pole with their respective shadows.

Let's let the height of the light pole be P (16 ft), the height of the woman be W (6 ft), the distance of the woman from the pole be w (50 ft), and the distance of the tip of her shadow from the pole be s. We will use the fact that the ratios P/s and W/(s-w) are equal because the triangles are similar. Setting up the proportions, after some algebra, we find that ds/dt (the rate at which the tip of the shadow moves) is a function of dw/dt (the rate at which the woman walks).

By differentiating both sides of the proportion with respect to time t, applying the chain rule, and plugging in the known values, we can solve for ds/dt as follows:

ds/dt = P/W * dw/dt * (s/w) = (16/6) * 4 * (50/50) = 64/6 = 10.67 ft/sec

The tip of her shadow is moving along the ground at a rate of [tex]\frac{1600}{61}\) ft/sec[/tex] when she is 50 ft from the base of the pole

To solve this problem, we can use similar triangles to relate the woman's height to the height of the street light and their respective shadows. Let [tex]\(x\)[/tex] be the distance from the woman to the pole, [tex]\(s\)[/tex] be the length of her shadow, and [tex]\(h = 16\)[/tex] ft be the height of the street light. The woman's height is [tex]\(w = 6\) ft.[/tex] At any given moment, the triangles formed by the woman and her shadow and the street light and the woman's shadow are similar. Therefore, we have the proportion:

[tex]\[\frac{h}{w} = \frac{h + s}{x}\][/tex]

We can solve for [tex]\(s\):[/tex]

[tex]\[h \cdot x = w \cdot (h + s)\][/tex]

[tex]\[h \cdot x = w \cdot h + w \cdot s\][/tex]

[tex]\[h \cdot x - w \cdot h = w \cdot s\][/tex]

[tex]\[s = \frac{h \cdot x - w \cdot h}{w}\][/tex]

Now, we want to find the rate at which [tex]\(s\)[/tex] is changing with respect to time, denoted as [tex]\(\frac{ds}{dt}\).[/tex] To do this, we differentiate the expression for [tex]\(s\)[/tex] with respect to time [tex]\(t\):[/tex]

[tex]\[\frac{ds}{dt} = \frac{d}{dt}\left(\frac{h \cdot x - w \cdot h}{w}\right)\][/tex]

[tex]\[\frac{ds}{dt} = \frac{h}{w} \cdot \frac{dx}{dt}\][/tex]

Given that [tex]\(h = 16\) ft, \(w = 6\) ft, and \(\frac{dx}{dt} = 4\) ft/sec,[/tex] we can substitute these values into the equation:

[tex]\[\frac{ds}{dt} = \frac{16}{6} \cdot 4\][/tex]

[tex]\[\frac{ds}{dt} = \frac{64}{6}\][/tex]

[tex]\[\frac{ds}{dt} = \frac{160}{15}\][/tex]

[tex]\[\frac{ds}{dt} = \frac{1600}{150}\][/tex]

[tex]\[\frac{ds}{dt} = \frac{1600}{61}\][/tex]

Answer:

Magnitude the of the acceleration is 3.32[tex]m/s^2[/tex] and direction is south

Explanation:

[tex]v_{0} =70.9 m/s\\v=14 m/s\\S=727 m[/tex]

we know that

[tex]v^2 = v_{0}^2 +2aS[/tex]

by substituting the values we can get the required acceleration

[tex]v^2 = v_{0}^2 +2aS\\14^2 = 70.9^2 +2\times a\times 727\\a=3.32 m/s^2[/tex]

Magnitude the of the acceleration is 3.32[tex]m/s^2[/tex] and direction is south

a) Final velocity after docking: +0.094 m/s

b) Kinetic energy loss: 31.6 J

c) Final velocity after docking: -0.056 m/s

d) Kinetic energy loss: 31.6 J

Explanation:

a)

Since the system of two satellites is an isolated system, the total momentum is conserved. So we can write:

[tex]p_i = p_f[/tex]

Or

[tex]m_1 u_1 + m_2 u_2 = (m_1 + m_2)v[/tex]

where, in the reference frame in which the first satellite was originally at rest, we have:

[tex]m_1 = 4.50\cdot 10^3 kg[/tex] is the mass of the 1st satellite

[tex]m_2 = 7.50\cdot 10^3 kg[/tex] is the mass of the 2nd satellite

[tex]u_1 = 0[/tex] is the initial velocity of the 1st satellite

[tex]u_2 = +0.150 m/s[/tex] is the initial velocity of the 2nd satellite

v is their final velocity after docking

Solving for v,

[tex]v=\frac{m_2 u_2}{m_1 +m_2}=\frac{(7.50\cdot 10^3)(0.150)}{4.50\cdot 10^3 + 7.50\cdot 10^3}=0.0938 m/s[/tex]

b)

The initial kinetic energy of the system is just the kinetic energy of the 2nd satellite:

[tex]K_i = \frac{1}{2}m_2 u_2^2 = \frac{1}{2}(7.50\cdot 10^3)(0.150)^2=84.4 J[/tex]

The final kinetic energy of the two combined satellites is:

[tex]K_f = \frac{1}{2}(m_1 +m_2)v^2=\frac{1}{2}(4.50\cdot 10^3+7.50\cdot 10^3)(0.0938)^2=52.8 J[/tex]

Threfore, the loss in kinetic energy during the collision is:

[tex]\Delta K = K_f - K_i = 52.8 - 84.4=-31.6 J[/tex]

c)

In this case, we are in the reference  frame in which the second satellite is at rest. So, we have

[tex]u_2 = 0[/tex] (initial velocity of satellite 2 is zero)

[tex]u_1 = -0.150 m/s[/tex] (initial velocity of a satellite 1)

Therefore, by applying the equation of conservation of momentum,

[tex]m_1 u_1 + m_2 u_2 = (m_1 + m_2)v[/tex]

And solving for v,

[tex]v=\frac{m_1 u_1}{m_1 +m_2}=\frac{(4.50\cdot 10^3)(-0.150)}{4.50\cdot 10^3 + 7.50\cdot 10^3}=-0.0563 m/s[/tex]

d)

The initial kinetic energy of the system is just the kinetic energy of satellite 1, since satellite 2 is at rest:

[tex]K_i = \frac{1}{2}m_1 u_1^2 = \frac{1}{2}(4.50\cdot 10^3)(-0.150)^2=50.6 J[/tex]

The final kinetic energy of the system is the kinetic energy of the two combined satellites after docking:

[tex]K_f = \frac{1}{2}(m_1 + m_2)v^2=\frac{1}{2}(4.50\cdot 10^3+ 7.50\cdot 10^3)(-0.0563)^2=19.0 J[/tex]

Therefore, the kinetic energy lost in the collision is

[tex]\Delta K = K_f - K_i = 19.0 -50.6 = -31.6 J[/tex]

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

#LearnwithBrainly

Answer:

hard line, soft line

Explanation:

Answer:

The student needs to group variables into dimensionless quantities.  

Explanation:

Large experiments take a lot of time to perform because the significant variables need to be separated from the non-significant variables. However, for large quantities of variables, it is necessary to focus on the key variables.

One technique to do that is to use the Buckingham Pi Theorem. The theorem states that the physical variables can be expressed in terms or independent fundamental physical quantities. In other words:

P = n- k

n = total number of quantities

k = independent physical quantities.

A place to start with will be to find dimensionless quantities involving the mass, length, time, and at times temperature. These units are given as M, L, T, and Θ

The grouping helps because it eliminates unwanted and unnecessary experiments.

Answer:

I just took the test, It's hypothesis then design an experiment, the last one i got wrong but its not dependent. hope that helped a little.

Explanation:

Speed= distance / time

Making distance the subject of the formula.

Distance = speed × time

Convert km/hr to m/ s

(40× 1000)/3600= 11.1m/s

Distance = 11.1m/s × 5s

Distance= 55.6m

So it is vector ,although the question is not complete.

Answer:

speed: 40 km/h

distance: 40 km

acceleration 8 km/h/s south

velocity: 5 km/h north

Answer:

(a). The speed of transverse wave on the rope is 15.78 m/s.

(b). The wavelength is 0.122 m.

(c). The changed speed of transverse wave on the rope is 21.56 m/s.

The changed wavelength is 0.167 m.

Explanation:

Given that,

Frequency = 129 Hz

mass = 1.50 kg

Linear mass density of the rope = 0.0590 kg/m

(a). We need to calculate the speed of a transverse wave on the rope

Using formula of speed

[tex]v=\sqrt{\dfrac{T}{\mu}}[/tex]

Put the value into the formula

[tex]v=\sqrt{\dfrac{1.50\times9.8}{0.0590}}[/tex]

[tex]v=15.78\ m/s[/tex]

(b). We need to calculate the wavelength

Using formula of wavelength

[tex]\lambda =\dfrac{v}{f}[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{15.78}{129}[/tex]

[tex]\lambda=0.122\ m[/tex]

(c). If the mass were increased to 2.80 kg.

We need to calculate the speed of a transverse wave on the rope

Using formula of speed

[tex]v=\sqrt{\dfrac{T}{\mu}}[/tex]

Put the value into the formula

[tex]v=\sqrt{\dfrac{2.80\times9.8}{0.0590}}[/tex]

[tex]v=21.56\ m/s[/tex]

We need to calculate the wavelength

Using formula of wavelength

[tex]\lambda =\dfrac{v}{f}[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{21.56}{129}[/tex]

[tex]\lambda=0.167\ m[/tex]

Hence, (a). The speed of transverse wave on the rope is 15.78 m/s.

(b). The wavelength is 0.122 m.

(c). The changed speed of transverse wave on the rope is 21.56 m/s.

The changed wavelength is 0.167 m.

The speed of the transverse wave on the rope is 2.48 m/s and the wavelength is 0.019 m. If the mass were increased to 2.80 kg, the speed of the wave would stay the same but the wavelength would be different.

To find the speed of a transverse wave on the rope, we can use the equation:

v = √(T/μ)

where v is the speed of the wave, T is the tension in the rope, and μ is the linear mass density of the rope. Plugging in the values given in the question, we get:

v = √(1.50 kg * 9.8 m/s^2 / 0.0590 kg/m) = 2.48 m/s

To find the wavelength of the wave, we can use the equation:

λ = v/f

where λ is the wavelength, v is the speed of the wave, and f is the frequency of the tuning fork. Plugging in the values given in the question, we get:

λ = 2.48 m/s / 129 Hz = 0.019 m

If the mass were increased to 2.80 kg, the speed of the wave on the rope would remain the same. However, the wavelength would be different because it is determined by the frequency of the tuning fork and the speed of the wave, not the mass of the hanging weight.

https://brainly.com/question/32893092

#SPJ3

Answer:

Net charge = 2.59nC

Explanation:

Gauss' Law states that the net electric flux is given by:

∮→E⋅→d/A = q enc/ϵ0

At this point, we have to solve the net electric flux through each side.

One corner is at (4.8, 3.9, 0).

The other corners are each 1.9m apart, so the other corners are at

(4.8, 5.8, 0), (6.7, 3.9, 0) and (6.7, 5.8, 0).

The other four corners are 1.9m away in the z-axis:

(4.8, 5.8, 2), (6.7, 3.9, 2) and (6.7, 5.8, 2).

Therefore, there are two planes (parallel to the x-z plane), one at

y = 3.9

and the other at

y = 5.8 which have a constant y-coordinate and are facing in the −^j and +^j respectively.

Area = 1.9m * 1.9m = 3.61m²

The flux through the first plane (area of 3.61m²) is given by:

E.A = (3.4i + 4.4 * 3.9²j + 3.0k) * (-3.61m²j) = -241.59564

The flux through the other plane is

E.A = (3.4i + 4.4 * 5.8²j + 3.0k)* (3.61m²j) = 534.33776

Now, for the other planes. There are no ^j components for the unit vectors for the area.

Therefore, even though they change in y-coordinate, those terms cancel out.

Therefore, for the planes with unit vector in the x-direction, we get:

E.A = (3.4i + 4.4y²j + 3.0k) * (1.9m * 1.9m) = ±12.274

And in the z-direction:

E.A = (3.4i + 4.4y²j + 3.0k) * (1.9m * 1.9m) = ±10.83

Now, when we sum all these fluxes together, the contribution from the x- and z-directions cancel out. Therefore, our net flux is:

-241.59564 + 534.33776 = 292.74212

Therefore, the enclosed charge is given by

q enc = ϵ0* (292.74212)

= 2.5856871136363E−9C

= 2.59E-9 nC--_- Approximated

= 2.59nC

Answer:

Q_enclosed = 1.576 nC

Explanation:

Given:

- The edge length of the cube L = 1.9 m

- One corner of the cube P_1 = ( 4.8 , 13.9 ) m

- The Electric Field vector is given by:

                             E = 3.4 i + 4.4*y^2 j + 3.0 k   N/C

Find:

What is the net charge contained by the cube?

Solution:

- The flux net Ф through faces parallel to y-z plane is:

                           net Ф_yz = E_x . A . cos (θ)

Where, E_x is the component of E with unit vector i.

            θ is the angle between normal vector dA and E.

Hence,

             net Ф_yz = 3.4 . 1.9^2 . cos (0) + 3.4 . 1.9^2 . cos (180)  

             net Ф_yz = 3.4 . 1.9^2  - 3.4 . 1.9^2 . cos (180)    

             net Ф_yz = 0.

- Similarly, The flux net Ф through faces parallel to x-y plane is:

                            net Ф_xy = E_z . A . cos (θ)

Where, E_z is the component of E with unit vector k.    

             net Ф_xy = 3 . 1.9^2 . cos (0) + 3 . 1.9^2 . cos (180)  

             net Ф_xy = 3 . 1.9^2  - 3 . 1.9^2 . cos (180)    

             net Ф_xy = 0                    

-The flux net Ф through faces parallel to x-z plane is:

                           net Ф_xz = E_y . A . cos (θ)

Where, E_y is the component of E with unit vector j.

             net Ф_xz = 4.4y_1^2 * 1.9^2 . cos (0) + 4.4y_2^2. 1.9^2 . cos (180)  

Where, The y coordinate for face 1 y_1 = 3.9 - 1.9 = 2, & face 2 y_2 = 3.9

             net Ф_xz = - 4.4*2^2*1.9^2 . cos (0) - 4.4*3.9^2. 1.9^2 . cos (180)

            net Ф_xz = -63.536 + 241.59564 = 178.0596 Nm^2/C      

- From gauss Law we have:

             Total net Ф_x,y,z = Q_enclosed / ∈_o

Where,

Q_enclosed is the charge contained in the cube

∈_o is the permittivity of free space = 8.85*10^-12

Hence,

             Total net Ф_x,y,z =  net Ф_xz +  net Ф_yz + net Ф_xy

             Total net Ф_x,y,z =  178.0596 + 0 + 0 = 178.0596 Nm^2/C  

We have,

             Q_enclosed = Total net Ф_x,y,z *  ∈_o

             Q_enclosed = 178.0596 *  8.85*10^-12

             Q_enclosed = 1.576 nC        

Final answer:

To calculate the work done to compress the gas by a factor of 11.0, we can use the relationship between work and volume changes. The work required to compress the gas by a factor of 11.0 is -11,000 J.

Explanation:

To calculate the work done to compress the gas by a factor of 11.0, we can use the relationship between work and volume changes. The work done on a gas during compression is given by the equation:

Work = Pressure ×Change in Volume

In this case, we know that the work required to compress the gas to half its initial volume is 550 J. Let's assume the initial volume of the gas is V. So the work done to compress the gas by a factor of 11.0 can be calculated as:

Work = Pressure × Change in Volume
550 J = Pressure ×(V/2 - V)
550 J = Pressure ×(-V/2)

Solving for Pressure, we get:

Pressure = -1100 J/V

Therefore, the work required to compress the gas by a factor of 11.0 is -1100 J/V× (11V - V) = -11,000 J (negative sign indicates work is done on the gas).

Answer:

[tex]W=-183.1\ J[/tex]

Explanation:

Given:

force applied, [tex]\vec{F} =(33 N)\hat{i} - (41 N)\hat{j}[/tex]

displacement caused, [tex]\vec{s} = (-9.4 m)\hat{i} - (3.1 m)\hat{j}[/tex]

Work done by the force on the cart:

[tex]W=\vec F.\vec s[/tex]

[tex]W=[(33 N)\hat{i} - (41 N)\hat{j}].[(-9.4 m)\hat{i} - (3.1 m)\hat{j}][/tex]

[tex]W=-310.2+127.1[/tex]

[tex]W=-183.1\ J[/tex]

Negative work means that the force and displacement have an obtuse angle between them.

Answer:

-180 J

Explanation:

We are given that

Constant force=[tex]F=(33 N)\hat{i}-(41 N)\hat{j}[/tex]

Displacement=[tex]\vec{s}=(-9.4m)\hat{i}-(3.1m)\hat{j}[/tex]

We have to find the work done .

We know that

Work done=[tex]F\cdot s[/tex]

Using the formula

Work done=[tex](33i-41j)\cdot (-9.4i-3.1j)[/tex]

Work done =[tex]33i\cdot (-9.4)i+41j\cdot 3.1 j[/tex]

By using rule [tex]i\cdot i=j\cdot j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=i\cdot k=k\cdot j=j\cdot i=0[/tex]

Work done=[tex]-310.2+127.1[/tex]

Work done=-183.1 J

We have to write answer in two significant figures.

When units digit 3 is less than 5 then digits on left side of 3 remains same and digits on right side of 3 and 3 will be replace by zero

Work done=-180 J

Hence, the work done =-180 J

Answer:

a. True

Explanation:

Equipotential lines are the imaginary lines in the space where actually the electric potential is same at each and every point.

Work is not required to move along such points of the equipotential line because the movement is always perpendicular to the electric field lines because these lines are always perpendicular to the electric field lines.

The electric potential for a point charge is given mathematically as:

[tex]V=\frac{1}{4\pi.\epsilon_0}\times \frac{Q}{r}[/tex]

where:

[tex]Q=[/tex] magnitude of the point charge

[tex]r=[/tex] radial distance form the charge

[tex]\epsilon_0=[/tex] permittivity of free space

Equipotential lines in physics are lines where the electric potential remains constant, perpendicular to electric field lines, and require no work to move a charge along them.

Equipotential lines are lines along which the electric potential remains constant. These lines are perpendicular to the electric field lines. It requires no work to move a charge along an equipotential line, but work is needed to move a charge from one equipotential line to another.

Molecules are moving slow, as they run into faster molecules, they speed up.

Explanation:

The model that best depicts heat being added to the molecules is that slow moving molecules run into faster ones and they speed up.

When heat is added to a body, the kinetic energy of the system increases.

learn more;

Kinetic molecular theory https://brainly.com/question/12362857

#learnwithBrainly

Answer:

2930.90 ft

Explanation:

*Attached are two rough sketches I made to represent the problem.

In diagram 2, the bearings are represented relative to the boat's position.

To find x, the distance between the boat and point having bearing 110° to the boat, we can use sine rule:

(sin 10°) / 550 = (sin 100) / x

=> x = (550 * sin 100°) / sin 10°

x = 3119 ft

Having found this, we can now find the distance between the host and the shore, as represented in diagram 1.

Using trigonometric function of SOHCAHTOA, we have that:

cos 20° = y / 3119

=> y = 3119 * cos 20°

y = 2930.90 ft

Hence, the distance between the boat and the shore is 2930.90 ft

Answer:

2eVI

Explanation:

The final kinetic energy of an oxygen ion, with a charge of 2e, accelerated from one plate to another separated by a potential difference V, equals twice the product of the electron charge and the potential difference, or 2eV.

The question involves an oxygen ion with a charge of 2e that is accelerated between two conducting plates separated by a distance d and connected to a potential difference V. This physical scenario falls under the domain of physics, specifically electromagnetism. The energy an ion gains when accelerated through a potential difference is called its kinetic energy. From conservation of energy, we understand that the kinetic energy of the accelerated ion should equal the work done on it by the electrical force, which is itself equal to the charge of the ion times the potential difference of the plates.

Therefore, the kinetic energy (KE) of the ion can be expressed as follows: KE = qV, where q is the charge of the particle and V is the potential difference. In this case, the charge is 2e (twice the electron charge), and the potential difference is V. Thus, the final kinetic energy of the ion is 2eV. It's important to note that this equation is derived from the principle of conservation of energy, which states that energy cannot be created or destroyed, only transferred or converted from one form to another.

https://brainly.com/question/33908837

#SPJ3

Answer: Option (c) is the correct answer.

Explanation:

An elastic object is defined as the object that is able to retain its shape when a force is applied on it.

For example, when we pull a rubber band then it stretches and when we withdraw the force applied on it then it retain its shape.

As we know that potential energy is the energy obtained by an object due to its position.

So, when we stretch a rubber band then it will have elastic potential energy as position of the rubber band is changing and since, it will retain it shape hence it has elastic potential energy.

Thus, we can conclude that a stretched rubber band has elastic potential energy.

A stretched rubber band has elastic potential energy. Option C

A rubber band that has been stretched holds elastic potential energy. The energy held in an object when it is stretched or distorted is known as elastic potential energy. The deformation of a rubber band's molecular structure causes it to gain potential energy when it is stretched.

Rubber bands are comprised of materials that are elastic and can be stretched before snapping back into place. Stretching the rubber band causes its structure to distort and its molecular structure to store potential energy. This potential energy is turned into kinetic energy when the rubber band is released, causing it to rebound and return to its original shape.

Learn more about elastic potential energy:https://brainly.com/question/29311518

#SPJ6

Answer:

(a) 72.9 kg

Explanation:

Before the elevator starts to move, only gravitational force exerts on the man, this force is generated by the man mass and the gravitational acceleration, which in turn register in the scale. So the scale would probably indicate the man mass, which is 72.9 kg.

Explanation:

Besides human error, other sources of error include friction on the cart (we assumed there is no friction, but in reality, that's never the case), and instrument errors (imprecision in the spring scale).

Besides human error, experiments can also encounter sampling errors, nonsampling errors, uncertainty factors, and spontaneous errors. These can be caused by an inaccurate sampling process, equipment malfunctions, variability in samples, and limitations in the measuring device.

Possible sources of error in an experiment, besides human error, could include sampling errors and non-sampling errors. Sampling errors occur when the sample utilized may not be large enough or not accurately representative of the larger population.

This can lead to inaccurate assumptions and conclusions. Non-sampling errors, on the other hand, are unrelated to the sampling process and could be a result of equipment or instrument malfunction (like a faulty counting device). An example for this would be an uncertainty in measurement induced by the fact that smallest division on a measurement ruler is 0.1 inches.

Further, variability in samples can also lead to errors called spontaneous errors. These can be due to natural phenomena such as exposure to ultraviolet or gamma radiation, or to intercalating agents. Lastly, uncertainty factors can contribute to errors as well. These factors include limitations of the measuring device, inaccuracies caused by the instrument itself (e.g., a paper cutting machine that causes one side of the paper to be longer than the other).

https://brainly.com/question/28241483

#SPJ2

Answer:

(a) [tex]P=33000W[/tex]

(b) [tex]P=51000W[/tex]

Explanation:

The average power is defined as the amount of work done during a time interval:

[tex]P=\frac{W}{t}(1)[/tex]

According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:

[tex]W=\Delta K\\W=K_f-K_0\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\(2)[/tex]

Recall that the weight is given by:

[tex]w=mg\\m=\frac{w}{g}(3)[/tex]

The car accelerates uniformly from rest ([tex]v_0=0[/tex]). Replacing (3) in (2), we have:

[tex]W=\frac{wv_f^2}{2g}[/tex]

(a) Finally, we replace this in (1):

[tex]P=\frac{wv_f^2}{2gt}\\P=\frac{9000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=33000W[/tex]

(b)

[tex]P=\frac{14000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=51000W[/tex]

(a) The average power required to accelerate the car of 9000 N is 32798.57 W.

(b)  The average power required to accelerate the car of 14,000 N is 51020.40 W.

Given data:

The initial velocity of car is, u = 0 m/s. (Since car was initially at rest)

The final velocity of car is, v = 20 m/s.

The time interval is, t = 5.6 s.

The given problem is based on the concept of average power. The average power is defined as the amount of work done during a time interval. Then,

P = W/t

Here, W is the work done and its value is obtained from the work - energy theorem as,

[tex]W = \Delta KE\\\\W = \dfrac{1}{2}m(v^{2}-u^{2})[/tex]

Here, m is the mass.

(a)

For the weight of 9000 N, the mass of car is,

[tex]w = mg\\\\9000 = m \times 9.8\\\\m =918.36 \;\rm kg[/tex]

So, the Work is obtained as,

[tex]W =\dfrac{1}{2} \times 918.36 \times (20^{2}-0^{2})\\\\W =183672\;\rm J[/tex]

Then, the average power required to accelerate the car is,

P = W/t

P = 183672 / 5.6

P = 32798.57 W

Thus, we can conclude that the average power required to accelerate the car of 9000 N is 32798.57 W.

(b)

For the weight of 14,000 N, the mass of car is,

[tex]w = mg\\\\14,000 = m \times 9.8\\\\m =1428.57 \;\rm kg[/tex]

So, the Work is obtained as,

[tex]W =\dfrac{1}{2} \times 1428.57.36 \times (20^{2}-0^{2})\\\\W =285714.28\;\rm J[/tex]

Then, the average power required to accelerate the car is,

P = W/t

P = 285714.28 / 5.6

P = 51020.40 W

Thus, we can conclude that the average power required to accelerate the car of 14,000 N is 51020.40 W.

Learn more about the average power here:

https://brainly.com/question/19509206

Answer:

Option (B)

Explanation:

In the stabilizing natural selection, the extreme traits from both the ends are eliminated by natural selection and natural selection favors the intermediate trait. So over time individuals having the intermediate traits are selected over the individuals having extreme traits.

So here the population of the bat which possesses moderate wing length is selected over the individual with extreme traits like individuals with short wings and long wings. As a result, the population of moderate length wing bats increased.

Therefore the correct answer is (B)- stabilizing natural selection.

Final answer:

The new angular velocity of the merry-go-round can be calculated using the conservation of angular momentum. By considering the initial angular momentum of the merry-go-round and the child after they grab the outer edge, we can determine the final angular velocity. The new angular velocity is approximately 0.414 rad/s.

Explanation:

To calculate the new angular velocity of the merry-go-round, we can use the conservation of angular momentum. The initial angular momentum of the merry-go-round is equal to the sum of the angular momentum of the original system and the child after they grab the outer edge. The initial angular momentum of the merry-go-round is given by Li = Imerry-go-round ● ωi, where Imerry-go-round is the moment of inertia of the merry-go-round and ωi is the initial angular velocity. The angular momentum of the original system is zero since the children are initially at rest. The angular momentum of the child after they grab the outer edge is equal to child ● child ● ω, where child is the mass of the child, the child is the distance of the child from the axis of rotation, and ω is the angular velocity.

Applying the principle of conservation of angular momentum, we have:

Li = (Imerry-go-round + child ● child) ● ωf

Solving for ωf, we get:

ωf = Li / (Imerry-go-round + child ● child)

Substituting the given values, we have:

ωf = (1000.0 kg.m² ● 6.0 rev/min) / (1000.0 kg.m² + 22.0 kg ● 0.455 m)

Converting rev/min to rad/s, we get:

ωf = (1000.0 kg.m² ● (6.0 rev/min ● 2π rad/rev) / (60 s/min)) / (1000.0 kg.m² + 22.0 kg ● 0.455 m)

Simplifying the expression, we find that the new angular velocity of the merry-go-round is approximately 0.414 rad/s.