Answer:
The unit price is 63 cent per kilogram bag of rice.
Step-by-step explanation:
Given:
A 6-kilogram bag of rice costs $3.80.
Now, to find the unit price.
So, to get the unit price we use unitary method:
If cost of 6 kilogram bag of rice = $3.80.
Then cost of 1 kilogram bag of rice = [tex]\frac{3.80}{6}[/tex] = [tex]\$0.633.[/tex]
Thus, the unit price is $0.633 per kilogram bag of rice.
Now, according to question we convert the unit price into cent by using conversion factor:
$1 = 100 cent
$0.633 = [tex]0.633\times 100=63.3\ cent.[/tex]
So, rounded to nearest cent = 63 cent.
Therefore, the unit price is 63 cent per kilogram bag of rice.
Jacob earns $8 per hour babysitting. The table below shows the amount of money he earns for hours worked. Which of the following is the independent variable
Answer:
What table below
Step-by-step explanation:
The independent variable is what you change
The dependent variable is what you measure
So the money he earns per hour seems like a constant, and it won't change. Therefore the dependent variable would be the amount of money he earns.
The number of hours he works can be changed, so the independent variable would the number of hours he works/babysits
A sphere intersects a plane that is 6 units away from its center; the intersection is a circle of radius 8. What is the radius of the sphere?
Answer:
10
Step-by-step explanation:
Consider the triangle consisting of the segment from the center of the sphere to the center of the circle, a radius of the circle, and the radius of the sphere to the other end of the radius of the circle. The given leg dimensions of that right triangle are 6 and 8, so the Pythagorean theorem tells you the hypotenuse (radius of the sphere) is ...
√(6²+8²) = √(36+64) = √100 = 10
The radius of the sphere is 10 units.
_____
You may recognize this as a 3-4-5 right triangle scaled by a factor of 2.
In this case, the radius of the sphere is 10 units.
The distance from the center of the sphere to the plane is given as 6 units.
According to the Pythagorean theorem, we have:
[tex]\[ r^2 = d^2 + r'^2 \][/tex]
[tex]\[ r^2 = 6^2 + 8^2 \][/tex]
[tex]\[ r^2 = 100 \][/tex]
Taking the square root
[tex]\[ r = \sqrt{100} \][/tex]
r = 10
The radius of the sphere is 10 units.
Use the table at the right.
a. What is the approximate volume of the small truck?
Volume of the small truck = 554.54 cubic ft
Solution:
Given data:
Length of the small truck = [tex]11\frac{1}{13}[/tex] ft
Width of the small truck = [tex]7\frac{5}{12}[/tex] ft
Height of the small truck = [tex]6\frac{3}{4}[/tex] ft
Volume of the small truck = length × width × height
[tex]$=11\frac{1}{13}\times7\frac{5}{12}\times 6\frac{3}{4}[/tex]
Let us change the mixed fraction into improper fraction.
[tex]$=\frac{11\times 13 + 1}{13}\times\frac{7 \times 12 + 5}{12}\times \frac{6 \times 4 + 3}{4}[/tex]
[tex]$=\frac{144}{13}\times\frac{89}{12}\times \frac{27}{4}[/tex]
[tex]$=\frac{7209}{13}[/tex]
= 554. 54 cubic ft
Volume of the small truck = 554.54 cubic ft
Solve S= 2HW + 2HL + 2WL for L.
To solve for L, you need to isolate/get the variable "L" by itself in the equation:
S = 2HW + 2HL + 2WL Subtract 2HW on both sides
S - 2HW = 2HW - 2HW + 2HL + 2WL
S - 2HW = 2HL + 2WL Take out the "L" in 2HL and 2WL
S - 2HW = L(2H + 2W) Now divide (2H + 2W) to get "L" by itself
[tex]\frac{S-2HW}{2H +2W} =\frac{L(2H+2W)}{2H+2W}[/tex]
[tex]\frac{S-2HW}{2H+2W} =L[/tex]
I think you can stop here, but if you need or want to simplify:
[tex]\frac{S}{2H+2W} -\frac{HW}{H+W} =L[/tex] which looks longer so I don't know if you need to do this
To solve for 'L' in the given equation, we subtract 2HW and 2WL from each side, then divide each side by 2H. The solution is L = (S - 2HW - 2WL) / 2H.
Explanation:We are given the equation S= 2HW + 2HL + 2WL and we are asked to solve for L. To do this, we will need to isolate L on one side of the equation. Here are the steps:
Subtract 2HW and 2WL from both sides of the equation. We are left with: S - 2HW - 2WL = 2HL Divide each side of the equation by 2H to solve for L. Our final solution is: L = (S - 2HW - 2WL) / 2H
So the value of L in terms of the other variables in the equation is (S - 2HW - 2WL) / 2H.
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converting to standard form y=3x-8
Standard form for a linear equation is Ax+By=C.
Problem: Write #y=3x-8 in standard form.
Subtract 3x from both sides of the equation.
−3x+y=−8
Multiply both sides by −1.
answer ==> 3x−y=8
If the mean of the following distribution is 91 and sum of frequencies is 150 find x and y
Answer:
Step-by-step explanation:
Mean = ∑x/ N
91 = ∑x / 150
∑x = 150 * 91 = 13650
x= 6825 and y = 6825
1) The table shows the height in centimeters, that a weight bouncing from a spring would achieve if there were no friction, for a given number of seconds.
From it's resting position, how long does it take the weight to bounce one direction, then the other, and then back to it's resting position?
Answer:
The graph shows that a consistent time to go from resting position to point A, then back to resting, then to point B, then back to resting, and so on is 0.75 seconds.
To bounce from resting to point A then point B and back to resting is 3 seconds.
The question pertains to the period of oscillation in a simple harmonic motion scenario involving a weight and a spring. The period is calculated using the formula T = 2π√(m/k). The student asks how long it takes for the weight to complete one full oscillation cycle, which can be calculated using mass and spring constant.
Explanation:The students asked about the period of oscillation for a weight attached to a spring. In physics, especially concerning simple harmonic motion (SHM), the period is the time it takes for one full cycle of motion: moving in one direction, reversing, and returning to the starting point. To find the period of a mass-spring system, we use the formula T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. This formula is derived from the motion equations that describe SHM.
For example, if you have a mass of 0.750 kg attached to a spring with a spring constant of 150 N/m, you would calculate the period using the mass (m) and the spring constant (k) from Hooke's Law. Similarly, when a spring exerts an upward force of 2.00 mg at the lowest point, this is due to the spring force being equal to the gravitational force at that point (mg) and also providing the restoring force needed for SHM (another mg).
Understanding SHM and its principles such as spring constant, and force of gravity are critical in solving these types of physics problems. These concepts explain how an attached weight on a spring moves in the absence of friction and other forces, such as air resistance.
NEED HELP ON THIS QUESTION ASAP PLEASE
Answer:
the last one
Step-by-step explanation:
y × 6 for y = 2/3. what is the y? please help.
Answer:
The answer is Y = 4. Hope this helps.
Answer: y is 2/3, or the answer to the equation is 4
Step-by-step explanation:
it tells you what y is with y=2/3, so you need to plug that into the equation nto get 4, or just use 2/3 as your answer
Two angles are supplementary.The larger angle is 15 more than 10 times the smaller angle. Find the measure of each angle
Step-by-step explanation:
Let the smaller angle = x and
The larger angle = 10x + 15°
To find, the measure of each angle = ?
We know that,
The sum of two supplementary anges = 180°
∴ x + (10x + 15°) = 180°
⇒ x + 10x + 15° = 180°
⇒ 11x = 180° - 15°
⇒ 11x = 165°
Dividing both sides by 11, we get
[tex]\dfrac{11x}{11} =\dfrac{165}{11}[/tex]
⇒ x = 15°
∴ The smaller angle = 15° and
The larger angle = 10(15° ) + 15° = 165°
You start at (6, 7). You move up 2 units. Where do you end?
NW u ovo
0
1
2
3
4
5
6
7
8
9 10
If you start at (6, 7) and you move up 2 units, you will end at point (6, 9) as shown in the image attached below.
In Mathematics and Euclidean Geometry, the translation a geometric figure upward means adding a digit to the value on the positive y-axis of the pre-image;
g(x) = f(x) + k
In this exercise, we would apply a translation of 2 units up to the point (6, 7), in order to determine the coordinates of its image as follows;
(x, y) → (x, y + 2)
A (6, 7) → (6, 7 + 2) = (6, 9).
So, if you start at (6, 7) and you move up 2 units, you will end at point (6, 9) as shown in the image attached below.
Decide whether the rates are equivalent.
$16 for 4 pounds
$1 for 4 ounces
Answer:
No i dont think so
Step-by-step explanation:
Because 16:4 isn't an equivilent ratio to 1:4
Stacey buys 6 pounds of chicken for $39 days how much will she pay for 11 more pounds of chicken?
Answer:
$110,5
Step-by-step explanation:
If 6 pounds costs $39, then 17 pounds (11+6) will cost $110,5
The solution can be found using famous math rule called "Rule of three".
In this case we have an unknown quantity [tex]\left \{ {{6=39}\atop {17=?}} \right.[/tex] where ? can be found multiplying $39 x 17 (new quantity) and dividing by the first quantity, [tex]? = \frac{39x17}{6}[/tex]
Find the volume of the pet carrier shown at the right
Answer:
Volume of the pet carrier [tex]=2702.5[/tex] cubic inches
Step-by-step explanation:
The Pet carrier in the image is in the shape of a cuboid
The volume of a cuboid can be found by the formula
volume of cuboid= [tex]Length*Breadth*Height[/tex]
Given:
Length = 20 inches, Breadth=[tex]11\frac{3}{4} =\frac{(11*4)+3}{4}=\frac{47}{4}[/tex] inches,
Height=[tex]11\frac{1}{2}=\frac{23}{2}[/tex] inches
Volume of the pet carrier:
[tex]=20*\frac{47}{4}* \frac{23}{2}\\\\= 5*47*\frac{23}{2} \\\\=5*47*11.5\\[/tex]
[tex]=2702.5[/tex] cubic inches
Volume of the pet carrier [tex]=2702.5[/tex] cubic inches
Polygon JKLMNO and polygon PQRSTU are similar. The area of polygon
PQRSTU is 75. What is the area of JKLMNO?
Answer:
The area of polygon JKLMNO is 48 square units
Step-by-step explanation:
The picture of the question in the attached figure
step 1
Find the scale factor
we know that
If two figures are similar, the the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
Let
z ----> the scale factor
The scale factor of the dilation of polygon PQRSTU to polygon JKLMNO is
[tex]z=\frac{KJ}{QP}[/tex]
substitute the given values
[tex]z=\frac{4}{5}[/tex]
step 2
Find the area of polygon JKLMNO
we know that
If two figures are similar, the the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> area of polygon JKLMNO
y ----> area of polygon PQRSTU
[tex]z^{2}=\frac{x}{y}[/tex]
we have
[tex]z=\frac{4}{5}[/tex]
[tex]y=75\ units^2[/tex]
substitute
[tex](\frac{4}{5})^{2}=\frac{x}{75}[/tex]
solve for x
[tex]x=(\frac{16}{25})75=48\ units^2[/tex]
therefore
The area of polygon JKLMNO is 48 square units
Answer:48units
Step-by-step explanation: I know
What is the value of d + e + fwhen d = 20, e = -4 and f = -2?
0-26
O 14
0-22
18
The value of d + e + f is 14
Solution:
Given that,
d = 20
e = -4
f = -2
We have to find the value of d + e + f
Substitute d = 20 and e = -4 and f = -2
Thus we get,
d + e + f = 20 + (-4) + (-2)
Remove the parenthesis
We know that, when we multiply negative sign with positive sign, we get negative sign as result
d + e + f = 20 - 4 - 2
d + e + f = 20 - 6
d + e + f = 14
Thus value of d + e + f is 14
Can someone answer this question please answer it correctly and show work please
Answer:
40) D
41) -56.33
Step-by-step explanation:
40)
Equation #1) 1 centimeter = 2.5 meters on the drawing
Equation #2) Length of the cafeteria on the drawing = 12.25 cm
Actual length:
Multiply both sides of equation #1 by 12.25 to get the actual length of the cafeteria
1(12.25) = 2.5(12.25)
12.25 cm = 30.625 meters
D
41)
[tex]\frac{0.5\left(8\ +\ 3.2\right)}{-0.1}+\ \frac{3}{\left(-2.7\ -\ 6.3\right)}[/tex]
Start with multiplication inside the parenthesis
[tex]\frac{4\ +\ 1.6}{-0.1}+\ \frac{3}{\left(-2.7\ -\ 6.3\right)}[/tex]
Add/Subtract
[tex]\frac{5.6}{-0.1}+\ \frac{3}{-9}[/tex]
Simplify
[tex]-56+\left(-0.33\right)[/tex]
[tex]-56 - 0.33[/tex]
[tex]-56.33[/tex]Hope this helps ツ
Dracula ate 70 fries in 14 minutes. Find his fry-eating rate in fries per
minute.
Answer
5 fries per minute
Step-by-step explanation:
To work out this question, you would need to divide 70 by 14. This would give you the rate of fries he eats per minute as 14 divided by 14 = 1.
Dracula's fry-eating rate is 5 fries per minute.
The subject of this question is Dracula's fry-eating rate. In mathematics, we often deal with rates, which are a measure of how something changes over time.
In this case, we are being asked to find how many fries Dracula eats per minute. This can be found by dividing the total number of fries he ate by the total time he took.
Given, Dracula ate 70 fries in 14 minutes.
To find the fry-eating rate, we need to divide the total fries by the total minutes. That is, fry-eating rate = total fries / total time.
So, the fry-eating rate = 70 fries / 14 minutes = 5 fries per minute. Therefore, Dracula's fry-eating rate is 5 fries per minute.
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The fact family model represents 3 + 14 = 17.
A triangle. 17 is in the top corner. 3 is in the bottom left corner. 14 is in the bottom right corner.
How does 17 compare to 3?
14 is 17 less than 3.
3 is 14 less than 17.
3 is 17 greater than 14.
3 is 14 greater than 17. ANSWER PLEASE 100 POINS
Answer:
3 is 14 less than 17
Step-by-step explanation:
17-3=14
Answer:
the answer is B 3 is 14 less than 17
hope it helps!
???????????anybody helppp
Answer:
B) 24 p-35
Step-by-step explanation:
Step :1
Apply distributive property a.(b+c) = a.b+a.c
Given data 1+4(6 p-9)
= 1+4.6 p - 4.9
multiply
= 1+ 24 p - 36
subtracting
= 24 p - 35
v(t)=659,500(0.91)
find the initial value of the house
Answer: 659,500 is the initial value
Step-by-step explanation:
Factor 18p-3618p−3618, p, minus, 36 to identify the equivalent expressions. Choose 2 answers: Choose 2 answers:
Answer:
18(p-2) and 2(9-18)
Step-by-step explanation:
Which one of these graphs matches the function below?
Answer:
The lower right graph.
Step-by-step explanation:
Angel and Jayden were at track practice. The track is 2/5 kilometers around.
•angel ran 1 lap in 2 minutes
•Jayden ran 3 laps in 5 minutes
How far does angel run in one minute
Answer: 66
Step-by-step explanation:
6 laps
Norachai traveled to the recycling plant and back. The trip back took 5 hours. He averaged 9mph faster on the trip there than on the return trip. What was norachai average speed on the outbound trip?
Answer:
[tex]His\ average\ speed\ to\ trip\ there\ =45\ mph\\\\His\ average\ speed\ in\ return\ trip=45-9=36\ mph\\\\His\ average\ speed\ during\ whole\ trip=40\ mph[/tex]
Step-by-step explanation:
[tex]Let\ distance\ from\ one\ side=d[/tex]
Trip:
[tex]Let\ speed\ when\ he\ was\ going=x\ mph\\\\Time\ taken=4\ hours\\\\distance=d\\\\distance=speed\times time\\\\d=x\times 4\\\\d=4x\ ...................................eq(1)[/tex]
Return Trip:
[tex]Speed=x-9\ \ \ \ \ (as\ it\ is\ 9\ mph\ slower)\\\\Time\ taken=5\ hours\\\\Distance=d\\\\Distance=speed\times time\\\\Distance=5\times (x-9)\\\\d=5x-45\ ........................................eq(2)[/tex]
[tex]from\ eq(1)\ and\ eq(2)\\\\5x-45=4x\\\\5x-4x=45\\\\x=45\ mph\\\\from\ eq(1)\\\\d=4\times 45=180\ miles[/tex]
[tex]Average\ speed\ during\ whole\ trip=\frac{total\ distance}{total\ time}=\frac{2\times 180}{5+4}=\frac{360}{9}=40\ mph[/tex]
[tex]His\ average\ speed\ to\ trip\ there\ =45\ mph\\\\His\ average\ speed\ in\ return\ trip=45-9=36\ mph\\\\His\ average\ speed\ during\ whole\ trip=40\ mph[/tex]
If f(x) = 2x^2+x find f(x+1)
Answer:
f(x+ 1) = 2x^2 + 5x + 3.
Step-by-step explanation:
We replace the x in the expression for f(x) by x+1:
f(x+1) = 2(x + 1)^2 + x + 1
= 2(x^2 + 2x + 1) + x + 1
= 2x^2 + 4x + 2 + x + 1
= 2x^2 + 5x + 3.
Please help. I’ll mark you as brainliest if correct
Answer:
527, no mistakes this time
Step-by-step explanation:
If Jeff washes his car in 6 minutes and bob washes the same car in 8 minutes. How long does it take both of them to wash the same car?
Answer:
3 3/7 or 24/7 mins
Step-by-step explanation:
Let total job = X
Jeff's rate = X/6
Bob's rate = X/8
Combined rate = X/6 + X/8
(4X × 3X)/24 = 7X/24
7X/24 = X/T
T = X ÷ (7X/24)
T = X × (24/7X)
T = 24/7 mins
Shortcut:
T = product of individual times/sum of individual times
T = (6×8)/(6+8)
T = 48/14
T = 24/7
T = 3 3/7 mins
Answer:
3 3/7 minutes or 3.4mins
Step-by-step explanation:
If Jeff washed husband car in 6 minutes and Bob washed the same car in 8 minutes , the time taken by both of them in washing the car ?
If Jeff washed the car in 6 minutes , in one minute, Jeff’s work = 1/6
If bob washed in 8mins, in one minute, bob’s work = 1/8
Add both together
1/6 + 1/8
Lcm of 6 and 8 Is 24
Divide the Lcm by the denominators and multiply the results by the numerator
We have 4+3 /24
7/24
Therefore time taken by both of them in Washing is 24/7
= 3 3/7 minutes 0r 3.4mins
There is another option that got cut off, it is
D: -1;the amount of water decreases by 1 gallon per minute
PLEASE ANSWER
Answer:
answer is b
Step-by-step explanation:
look at the picture
What is the answer for the question
r = 16/2 = 8 cm
C = 2π·r = 2×3.14×8 = 50.24 cm