An object has a mass of 1kg on Earth. What is its weight on the moon?

The equivalent resistance between the point A and B is 0.95 ohm.

Explanation:

Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be

                            1 / R = (1 /R3) + (1 / R4) + (1 / R5)

                                    = (1 / 4.4) + (1 / 3.5) + (1 / 5.5)

                            1 / R = 0.69

                                 R = 1.43 ohm.

Next solving R6 and leg of this resistance which are in series connection,

                                  r = R + R6

                                    = 1.43 + 7.1)

                                  r = 8.53 ohm.

Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,

                              1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)

                                     = 1.04 ohm

Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.

The equivalent resistance of the circuit shown in the attachment is 0.958 Ω.

The resistor can be defined as a device that has some electrical resistance and that is used in an electric circuit for protection, operation, or current control.

Given that there are 6 resistors connected in-between points A and B as shown in the attachment.

R1 = 1.9 Ω, R2 = 2.5 Ω, R3 = 4.4 Ω, R4 = 3.5 Ω, R5 = 5.5 Ω, and R6 = 7.1 Ω.

The resistors R3, R4, and R5 are in parallel connections. Let's consider that R' is the equivalent resistor of this parallel connection, then,

[tex]\dfrac {1}{R'} =\dfrac {1}{R_3} + \dfrac {1}{R_4}+\dfrac {1}{R_5}[/tex]

[tex]\dfrac {1}{R'}= \dfrac {1}{4.4}+ \dfrac {1}{3.5}+\dfrac {1}{5.5}[/tex]

[tex]\dfrac {1}{R'}= 0.69[/tex]

[tex]R' = 1.45[/tex]

The equivalent resistor is in series connection with R6. Hence, the equivalent resistance R'' is given below.

[tex]R'' = R' + R_6[/tex]

[tex]R'' = 1.45 + 7.1[/tex]

[tex]R'' = 8.55[/tex]

Now the resistors R1, R2, and R'' are in parallel connection, so the equivalent resistor R is given as,

[tex]\dfrac {1}{R} = \dfrac {1}{R_1} + \dfrac {1}{R_2} + \dfrac {1}{R''}[/tex]

[tex]\dfrac {1}{R} = \dfrac {1}{1.9} +\dfrac {1}{2.5} +\dfrac {1}{8.55}[/tex]

[tex]\dfrac {1}{R} = 1.043[/tex]

[tex]R = 0.958[/tex]

Hence we can conclude that the equivalent resistance of the circuit shown in the attachment is 0.958 Ω.

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Answer:

The direction of the force on a charged object moving through a magnetic field.

Explanation:

When considering the motion of a charged particle in a magnetic field, the important vectors are the magnetic field B, the velocity of the particle v, and the magnetic force exerted on the particle F. The vectors are all perpendicular to each other. As demonstrated by the right-hand rule.

Answer: small cars can stop and go fast big trucks can not

Explanation:

a) The work done by the gravitational force on the flat surface is zero

b) The work done by the gravitational force on the ramp is -634 J

c) The work done by the applied force on the flat surface is 500 J

d) The work done by the applied force on up along the ramp is 500 J

Explanation:

a)

The work done by a force is given by the equation

[tex]W=Fdcos \theta[/tex]

where

F is the magnitude of the force

d is the dispalcement of the object

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.

We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is [tex]90^{\circ}[/tex]; this means that [tex]cos 90^{\circ}=0[/tex], and therefore, the work done is zero:

[tex]W=0[/tex]

b)

In this case, the box is pushed along the ramp. We have:

[tex]F=mg=(50.0)(9.8)=490 N[/tex] is the magnitude of the force of gravity, where

m = 50.0 kg is the mass of the box

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

d = 5.00 m is the displacement of the box along the ramp

The ramp is inclined to the horizontal by [tex]15.0^{\circ}[/tex], therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:

[tex]\theta=90^{\circ}+15^{\circ}=105^{\circ}[/tex]

Therefore, the work done by gravity in this case is:

[tex]W=(490)(5.00)(cos 105^{\circ})=-634 J[/tex]

c)

In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.

Here we have:

F = 100.0 N (force applied)

d = 5.00 m (displacement of the box)

[tex]\theta=0^{\circ}[/tex] (the force is applied parallel to the flat surface, therefore force and displacement have same direction)

Therefore, the work done by the force you apply on the flat ground is:

[tex]W=(100.0)(5.00)(cos 0^{\circ})=500 J[/tex]

d)

In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.

This time we have:

F = 100.0 N (force applied is the same)

d = 5.00 m (displacement of the box is also the same)

[tex]\theta=0^{\circ}[/tex] (the force is applied parallel to the ramp, therefore force and displacement have again same direction)

Therefore, the work done by the force you apply while pushing the box along the ramp is:

[tex]W=(100.0)(5.00)(cos 0^{\circ})=500 J[/tex]

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Answer:

1. Force = -623.43 N

2.Tension = 106.65 N

Explanation:

Let us call the bigger mass [tex]M[/tex], and the smaller mass [tex]m[/tex].

Since the two masses are connected to each other, they must experience same acceleration (if they didn't, the unequal acceleration will cause the string to break. )

From the free body diagram, the forces acting on the mass [tex]M[/tex] are

[tex]T - Mg-F_p[/tex],

and according to Newton Second Law, this causes acceleration [tex]a[/tex]; therefore,

(1).  [tex]\boxed{ T-Mg-F_p=Ma}[/tex].

Similarly, the forces acting on the mass [tex]m[/tex] are

[tex]T -mg[/tex],

which causes the acceleration [tex]-a[/tex] (upward); therefore,

[tex]T-mg=-ma \\[/tex]

or

[tex]\boxed{ mg-T = ma}[/tex]

From this equation we solve for [tex]T[/tex] and get:

[tex]T = mg-ma \\\\T =m(g-a).[/tex]

We put this into equation (1) and get:

[tex]m(g-a)-Mg-F_p=Ma[/tex]

[tex]F_p = m(g-a)-M(g+a)[/tex]

putting in [tex]M=62.4kg,m=13.5kg,[/tex] and [tex]a=1.9m/s^2[/tex], we get:

[tex]F_p=13.5(9.8-1.9)-62.4(9.8+1.9)\\\\\boxed{ F_p=-623.43N}[/tex]

The tension in the wire is

[tex]T =m(g-a)\\\\T = 13.5(9.8-1.9)\\\\\boxed{ T= 106.65N}[/tex]

Answer:

20784.6m

Explanation:

Check attachment

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Answer:

26.8224

Explanation:

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Answer:

2m/s

Explanation:

Speed= distance / time

?         =  60m      / 30s

speed= 60/30

60/30=2

speed= 2m/s

Answer:

(A) Mitosis

Explanation:

Answer:

12 m

Explanation:

Work = change in energy

W = ΔE

Fd = ΔE

(4.0 N) d = 61 J

d = 15.25 m

Rounded to two significant figures, the distance the force would have to act over is 15 m, which is 12 m more than the 3.0 m it traveled.

Final answer:

To calculate the additional distance needed for the block to have 61 J of kinetic energy, we used the work-energy theorem and found that after applying a force of 4 N over 3 m, the kinetic energy is 12 J. An additional 49 J is needed, resulting in a requirement of an additional 12.25 m for the force to act upon.

Explanation:

To determine how much farther the force would have to act for the block to have 61 J of kinetic energy, we'll first use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy (KE). Initially, the block has 0 J of kinetic energy since it's at rest, and the work done by a constant force is W = F * d, where F is the force and d is the distance the force is applied over.

Since 4 N of force is applied over 3 m, the work done is:

W = 4 N * 3 m = 12 J

This means the kinetic energy of the block is now 12 J after the force has been applied for 3 m. To reach 61 J of kinetic energy, the block needs an additional:

KEneeded = 61 J - 12 J = 49 J

Now, we can find the additional distance (dadditional) required using the same work done equation:

49 J = 4 N * dadditional

dadditional = 49 J / 4 N = 12.25 m

Therefore, the force would have to act over an additional 12.25 m to give the block 61 J of kinetic energy.

Explanation:

Let the distance covered by the body be s, initial and final velocities be u and v respectively and time taken be t.

[tex] \therefore Average\: velocity = \frac{u+v}{2} \\\\ Now, \:we \:know\: that\\\\ Distance \:covered\\ = Average\: velocity \times time\\\\ \therefore s= \frac{(u+v) }{2} \times t..... (1)\\\\[/tex]

By first equation of motion:

[tex] v = u + at[/tex]

Substituting the value of v in equation (1), we find:

[tex] s= \frac{(u+u + at)}{2} \times t\\\\ \therefore s= \frac{(2u + at)}{2} \times t\\\\ \therefore s= \frac{(2ut + at^2)}{2}\\\\ \therefore s= \frac{2ut} {2}+ \frac{at^2}{2}\\\\ \huge \orange {\boxed {\therefore s= ut+ \frac{1}{2}at^2}} \\\\[/tex]

Hence proved.

Explanation:

a) Potential energy is weight times height.

PE = mgh

PE = (10.0 kg) (9.8 m/s²) (20.0 m)

PE = 1960 J

b) Energy is conserved.  As the block falls, potential energy is converted to kinetic energy.  Just before the block lands, all of the potential energy has been converted to kinetic energy.

KE = 1960 J

c) When the block has fallen half the distance, half the potential energy has been converted to kinetic energy.

KE = 1960 J / 2

KE = 980. J

d) Kinetic energy equals half the mass times the square of the velocity.

KE = ½ mv²

980. J = ½ (10.0 kg) v²

v = 14.0 m/s

Answer:

Elasticity

Explanation:

The  property of a body, by virtue of which it tends to regain its

original size and shape when the applied force is removed, is

known as elasticity and the deformation caused is known

as elastic deformation.

Ductility is the mechanical property that describes the extent to which solid materials can be plastically deformed without fracturing.

The mechanical property that describes the extent to which solid materials can be plastically deformed without fracturing is ductility.

Ductility is the ability of a material to undergo significant plastic deformation under tensile stress without breaking. Ductile materials, such as metals, can be stretched into thin wires or shaped into various forms without fracturing.

For example, copper and aluminum are highly ductile metals that can be easily drawn into wires and used for electrical conductivity, while brittle materials like glass or ceramic lack ductility and break easily when subjected to stress.

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Answer:

A ratio of equivalent units

Explanation:

A conversion factor is a ratio of equivalent units and depends on which units are to be converted.

For example we want to convert 275 [mm] to inches, so we have to find the right conversion factor to allow us to work that conversion.

275 [mm] = inches = ?

[tex]275 [mm] * \frac{1in}{25.4mm} = 10.82 [in][/tex]

In this case the ratio is 1/25.4 = 0.039 [in/mm]

Answer:

B H2O.

Explanation:

Because H2O stands for hydrogen, which has the amount of 2. And O stands for oxygen, which is by itself. When you put that together it makes H2O.

Answer:

122.5 m

Explanation:

Given:

Time taken by apple to reach ground (t) = 5 s

Acceleration of the apple is due to gravity (g) = 9.8 m/s²

The displacement of the apple is equal to the height of window (h) = ?

As the apple is dropped, the initial velocity is, [tex]u=0\ m/s[/tex]

Now, using Newton's equation of motion along the vertical direction that relates displacement, initial velocity, acceleration and time taken, we have:

[tex]h=ut+\frac{1}{2}gt^2[/tex]

Plug in the given values and solve for 'h'. This gives,

[tex]h=0+\frac{1}{2}\times 9.8\times 5^2\\\\h=4.9\times 25=122.5\ m[/tex]

Therefore, the height of the window above the ground is 122.5 m.

Mechanical waves are categorized into transverse, longitudinal, and surface waves. Transverse waves have disturbances perpendicular to wave direction, longitudinal waves have parallel disturbances, and surface waves are a combination of both.

Mechanical waves can be classified based on the type of motion involved in the wave's propagation. There are mainly two categories of mechanical waves, namely transverse waves and longitudinal waves. However, there is also a third category known as surface waves, which is a combination of both transverse and longitudinal motions.

Transverse waves are characterized by a disturbance that moves perpendicular to the direction of wave propagation. An example of a transverse wave is a wave on a string or an electromagnetic wave, such as visible light. Whereas, longitudinal waves have disturbances that move parallel to the direction of propagation, like sound waves in air or water.

Surface waves are typically observed in fluids, like water waves in the ocean, where the motion of the particles at the surface follows a circular path, thus involving both longitudinal and transverse motions.

Therefore, when considering the types of mechanical waves, the answer would be all of the above as it includes transverse waves, longitudinal waves, and surface waves.

Answer:

2.40

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the indexes of refraction, θ₁ is the angle of incidence (relative to the normal), and θ₂ is the angle of refraction (relative to the normal).

1.55 sin 39° = n sin 24°

n = 2.40

Boiling water causes molecular movement to increase without breaking H₂O bonds. It's a physical change where molecules move farther apart as steam forms. Cooling steam back into water is reversible, showcasing the unique properties of water's hydrogen bonding.

When water undergoes a physical change, such as boiling, the arrangement of the water molecules changes due to increased kinetic energy. However, the chemical composition remains the same, meaning that the hydrogen and oxygen atoms do not separate into different atoms; they stay bonded as H₂O. The molecules move farther apart, transitioning from a liquid to a gaseous state without changing their actual molecular structure. This transformation requires the input of heat energy, and it is completely reversible; if the steam (water vapor) is cooled, it will condense back into liquid water, demonstrating one of water's unique characteristics due to its ability to form and break hydrogen bonds.

During the boiling of water, the hydrogen bonds between water molecules are broken as they gain enough kinetic energy to escape into the air as steam. When water freezes, however, these molecules form a crystalline structure that is less dense than liquid water, which explains why ice floats. This phenomenon is distinctive to water and differs from most other liquids, where the solid form is denser than the liquid.

Final answer:

Relative time determines the sequence of events without specific ages, while absolute time gives a precise measurement of age or date. Geologists use relative dating for stratigraphy and absolute dating for techniques like carbon dating. Time dilation in relativity illustrates that the rate of time is relative to the observer's motion.

Explanation:

The difference between relative time and absolute time lies in how they quantify the duration and sequence of events. Relative time refers to the sequence of events without assigning a specific age or date to them; it's a way to determine the order in which events have occurred. For instance, geologists use relative time to assert that one rock layer is older than another. On the other hand, absolute time or radiometric dating provides a precise measurement, giving an actual number or date to an event or object, such as specifying that a rock layer is 300 million years old.

These concepts are critical in fields such as geology, paleontology, and astronomy. In special relativity, the concept of time dilation shows that absolute time is not a fixed unit across all references, as the observed rate at which time passes depends on the observer's relative motion.

An example of relative dating would be using stratigraphy to understand that one geological layer is younger than the layer below it, while an example of absolute dating would be using carbon dating to determine the exact age of an archaeological object.

Answer:

The big bang is a example of  scientific theory

Explanation:

The Big Bang is an example of a scientific theory about the origins and evolution of the universe. It has been substantiated through numerous tests and observations, specifically those related to the cosmic microwave background radiation and the expansion of the universe.

The 'Big Bang' is an example of a scientific theory. A scientific theory is an explanation for a range of phenomena that has been substantiated through repeated testing and observation. In this case, the Big Bang theory explains the origins and evolution of the universe. According to this theory, the universe originated from a singularity, a point of infinite density and temperature, about 13.8 billion years ago, and it has been expanding ever since. This theory is based on a wide range of observations, including those related to the cosmic microwave background radiation and the expansion of the universe.

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Answer: acceleration is equal to the change in velocity per unit time in seconds.

a= ∆v / t = vf - vi / t

Explanation: change in velocity or ∆v can be expressed as (vf - vi)

Electromagnetic waves are not mechanical and transverse in nature, while

Sound waves are mechanical and longitudinal

Explanation:

In physics, waves are classified into two types:

Moreover, depending on the direction of the vibration, waves are further classified into:

Electromagnetic waves are not mechanical and transverse in nature (the oscillations of the electric and magnetic fields occur in a plane perpendicular to the direction of the wave), while

Sound waves are mechanical and longitudinal (the vibrations of the particles of the medium is back-and-forth along the direction of propagation of the wave)

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Answer:

Is a particle

Explanation:

Gamma Ray is a particle and can be stopped with a very thick concrete and iron mixture.

Answer: Is a particle

Explanation:

Took a quiz!

Answer: 2.15secs

Explanation:

Force = mass*velocity/time

F = 5N

M = 2.75kg

V = 3.90m/s

5.00 = 2.75*3.90/time

Time = 10.725/5.0 = 2.15sec

It will take approximately 2.145 seconds to stop a 2.75 kg ball traveling at 3.90 m/s with a constant force of -5.00 N.

First, we need to calculate the initial momentum of the ball using the formula:

Momentum (p) = mass (m) × velocity (v)

Given:

p (momentum) = 2.75 kg × 3.90 m/s

p (momentum) = 10.725 kg·m/s

Next, we use the principle of impulse to find the time needed to stop the ball. Impulse (J) is equal to the change in momentum, and it is also equal to the applied force (F) times the time (t):

Since the force applied is -5.00 N (acting against the ball's motion), we rearrange the equation to solve for time:

The change in momentum is equal to the initial momentum (since the final momentum will be 0 when the ball stops):

Thus,

Therefore, it will take approximately 2.145 seconds to stop the ball.

Answer:

d

Explanation:

Neither the medium nor the energy travels with the wave.

A wave is a disturbance in a medium that includes power with out a internet motion of particles. it could take the shape of elastic deformation, a version of stress, electric or magnetic depth, electric powered potential, or temperature.

wave, propagation of disturbances from region to location in a regular and organized way. most acquainted are floor waves that tour on water, however sound, light, and the movement of subatomic debris all exhibit wavelike homes.

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Answer:

Rock breaking apart when it falls from a cliff

Rock breaking apart when it falls from a cliff is an example of physical weathering (option B)

Physical weathering, also known as mechanical weathering, involves the physical breakdown of rock into smaller pieces without changing its chemical composition.

In this case, the force of gravity and the impact of the falling rock cause it to break into smaller fragments, which is a mechanical process and a common example of physical weathering. The other options involve chemical weathering processes.

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Answer:

Momentum of Block B after collision  is 200 kg.m/s

Explanation:

Momentum of block A before collision is [tex]p_{1A} = 450kg.m/s[/tex]

Momentum of block B before collision is [tex]p_{1B} = -150kg.m/s[/tex]

Momentum of block A after collision is [tex]p_{2A} = 100kg.m/s[/tex]

According to conservation of momentum, total momentum before collision is equal to total momentum after collision

[tex]p_{1A}+p_{1B}=p_{2A}+p_{2B}\\450-150=100+p_{2B}\\p_{2B}=300-100\\p_{2B}=200 kg.m/s[/tex]

Momentum of Block B afterwards is 200 kg.m/s

Answer:

200

Explanation:

Answer:

It is due to the effect of temperature on our taste receptors.

Explanation: