Why does it take more energy to increase the temperature of 100 grams of liquid water by one degree Celsius than it does 100 grams of copper metal?

Answer:

The answer to your question is the fourth one.

Explanation:

From the description, we know that the reactants are two liquids and the products are a solid and a gas.

The first option is incorrect because it mentions that the reactants are one liquid and solid.

The second option is also incorrect for the same reason as the first one and one of the products must be a solid.

The third option is incorrect besides there are two liquids in the reactants and  a solid and gas in the liquids there is a minus sign that is not possible.

The fourth option is the correct one.

Answer : The maximum mass of sucralose is, 7952.8 grams.

Explanation :  Given,

Molal-freezing-point-depression constant [tex](K_f)[/tex] for water = [tex]1.86^oC/m[/tex]

Mass of water (solvent) = 2.00 kg

Molar mass of sucralose = 397.64 g/mole

Formula used :  

[tex]\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of sucralose}}{\text{Molar mass of sucralose}\times \text{Mass of water in Kg}}[/tex]

where,

[tex]\Delta T_f[/tex] = change in freezing point

[tex]\Delta T_s[/tex] = freezing point of solution = [tex]-18.6^oC[/tex]

[tex]\Delta T^o[/tex] = freezing point of water = [tex]0^oC[/tex]

i = Van't Hoff factor = 1 (for sucralose non-electrolyte)

[tex]K_f[/tex] = freezing point constant for water = [tex]1.86^oC/m[/tex]

m = molality

Now put all the given values in this formula, we get

[tex](0-(-18.6)^oC)=1\times (1.86^oC/m)\times \frac{\text{Mass of sucralose}}{397.64g/mol\times 2.00kg}[/tex]

[tex]\text{Mass of sucralose}=7952.8g[/tex]

Therefore, the maximum mass of sucralose is, 7952.8 grams.

Answer:

The atmosphere refers to the gaseous envelope of earth, comprised of variable gases with definite proportions. The layers of the earth's atmosphere are as follows-

This variation in temperature occurs because of the certain reason. In the troposphere and the mesosphere, the temperature decreases with height because the pressure and height are inversely proportional to each other. The stratosphere experiences increasing temperature because of the presence of the ozone layer that is responsible for holding the greenhouse gases and the harmful UV radiation. The thermosphere and the exosphere experience high temperatures because of the receiving of the direct sunlight. Due to these above reason, there occurs this temperature change in a unique pattern.

The temperature changes within the layers of the atmosphere follow a pattern of alternating increases and decreases. This unique pattern is influenced by factors such as sun angle, insolation intensity, day length, and proximity to water bodies.

The pattern of temperature changes within the layers of the atmosphere is characterized by alternating increases and decreases in temperature. This pattern can be observed in the five layers of the atmosphere, namely the troposphere, stratosphere, mesosphere, thermosphere, and exosphere. The temperature gradient varies with each layer, with the troposphere being the coldest and the thermosphere being the hottest. The unique pattern of temperature changes is caused by various factors such as sun angle, insolation intensity, day length, and proximity to water bodies.

Answer:

403.3 kPa is the new pressure

Explanation:

This problem is solved by this formula:

P₁ . V₁ = P₂ . V₂

101kPa . 575 mL = P₂ . 144mL

(101kPa . 575 mL) / 144 mL = P₂

403.3 kPa = P₂

Final answer:

Using Boyle's Law, the new pressure of neon gas compressed from 575 mL at 101 kPa to 144 mL, with temperature held constant, is found to be 403.125 kPa.

Explanation:

The student asked for the new pressure of neon gas that was compressed from 575 mL at 101 kPa to a volume of 144 mL, given that the temperature remained constant. This type of problem involves ideal gas behavior and can be solved using Boyle's Law, which states that for a given mass of gas at constant temperature, the volume of the gas is inversely proportional to its pressure (P₁V₁ = P₂V₂).

Starting with the initial conditions:

Initial volume (V₁) = 575 mL

Initial pressure (P₁) = 101 kPa

And the final condition:

Final volume (V₂) = 144 mL

Since temperature remains constant, we can calculate the final pressure (P₂) using the formula:

P₂ = (P₁* V₁) /V₂

Substitute the given values into the equation:

P₂ = (101 kPa* 575 mL) \/ 144 mL = 403.125 kPa

Hence, the new pressure of the neon gas after compression is 403.125 kPa.

Answer:

275.3 nm is the wavelength of light required for mercury.

Mercury can not be used to generate electricity from the sun because wavelength at which mercury will emit an electron is smaller than 500 nm.

Explanation:

The wavelength of light required for mercury  to emit an electron.

The wavelength of the radiation = [tex]\lambda [/tex]

Energy required fro mercury to to emit an electron = E

Energy required fro mercury to to emit an electron will the energy if the radiation = E' = [tex]7.22\times 10^{-19} J[/tex]

E' = E

To calculate the wavelength of light, we use the equation:

[tex]E=\frac{hc}{\lambda }[/tex]

where,

[tex]\lambda[/tex] = wavelength of the light  

h = Planck's constant = [tex]6.626\times 10^{-34} Js[/tex]

c = speed of light = [tex]3\times 10^8m/s[/tex]

[tex]\lambda =\frac{hc}{E}[/tex]

[tex]=\frac{6.626\times 10^{-34} Js\times 3\times 10^8m/s}{7.22\times 10^{-19} J}[/tex]

[tex]\lambda =2.753\times 10^{-7} m=2.753\times 10^{-7}\times 10^ nm =275.3 nm[/tex]

Wavelength of the sun light in the visible region = 500 nm

500 nm > 275.3 nm

[tex]E\propto \frac{1}{\lambda }[/tex]

Less energy < more energy

So, this means that mercury can not be used to generate electricity from the sun.

The wavelength of light in nm is

[tex]\lambda = \frac{hc}{E}\\\\ \lambda = \frac{6.626*10^{-34} * 3*10^8}{7.22*10^{-19}}\\\\ \lambda = 2.7531856*10^{−7}\\\\ \lambda = 275nm [/tex]

No, the therhold energy is larger than the wavelength of sun, therefore, electricity will not be generated.

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Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

The branch of science which deals with the study of chemicals and their bond is called chemistry.

The correct percentage yield of O2 is 66.7%

The Reaction for decomposition of potassium chlorate is as follows:-

[tex]2KClO_3 <---> 2KCl + 3O_2[/tex]

The formula is as follows:- [tex]\frac{Mass }{Molar\ mass} = Moles[/tex]

After putting the value in the question is:-

[tex]\frac{12.3 g}{123} = 0.1 mol[/tex]

So the ratio present in the reaction is 2:3.

Therefore, the 0.1 mole of chlorate produce [tex]\frac{(0.1 *3)}{2} = 0.15 moles[/tex]

Convert them into molar mass is:-

[tex]\frac{0.15*32 g}{1mol} = 4.8 g[/tex]

The percentage of the compound is [tex]\frac{(3.2g}{4.8g}* 100 = 66.7 %[/tex].

Hence, the correct answer is 66.7%

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Answer:

Calcite

Explanation:

Calcite is a mineral formed by calcium carbonate (CaCO3), class 05 of the Strunz classification, the so-called carbonate and nitrate minerals.

All members of this group crystallize in the trigonal system, have a perfect rhombohedral cleavage and exhibit a strong double refraction in transparent rhombohedra.

It presents a variety of shapes and colors. It is characterized by its low hardness, 3 on the Mohs scale, and by its high reactivity even with weak acids.

The best property to identify calcite is the acid test, since this mineral produces effervescence with acids. The reason for this is the following reaction:

CaCO3 + 2H + → Ca2+ + H2O + CO2 (gas)

Answer:

12.2 moles of H₂

Explanation:

P . V = n . R . T is the Ideal Gases Law, which is useful to solve this:

First of all, we need to convert the T°C to T° K

T° K = T°C + 273 → 27°C + 273 = 300 K

Let's replace the data given: 10 atm . 50L = m . 0.082L.atm/m.K . 300K

500 L.atm / 0.082L.atm/m.K . 300K = m

12.2 moles = n

Intramolecular Sn2 reaction is a bimolecular, second-order, elementary reaction. It involves a single, concerted step in which a nucleophile attacks the substrate, leading to a transition state, and then to expulsion of a leaving group. The stereochemistry of the molecule is usually inverted at the reaction centre.

To best describe the properties of an intramolecular Sn2 reaction mechanism, we can say that it's a bimolecular reaction, which means it involves two reactant species. In this case, the reaction mechanism involves a single, concerted step where a nucleophile attacks the substrate, leading to a transition state and finally the expulsion of a leaving group. This makes Sn2 a type of elementary reaction.

In these reactions, the rate is dependent on the concentration of both reactants, leading to a second-order rate law. Further, the rate-determining step (the slowest in the mechanism) for an Sn2 reaction is the single concerted step itself. One important aspect to remember about Sn2 mechanisms is the stereochemical alteration that takes place, typically resulting in inversion of configuration at the reaction centre.

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The intramolecular SN2 reaction mechanism is a bimolecular and concerted process characterized by inversion of configuration at the reaction center, second-order kinetics, and sensitivity to steric hindrance.

The intramolecular SN2 reaction mechanism is characterized by several distinct properties. Firstly, it is a bimolecular reaction, meaning the rate of the reaction depends on the concentration of two reactants: the nucleophile and the electrophile. Secondly, the reaction proceeds via a concerted process where bond-forming and bond-breaking occur simultaneously, leading to an inversion of configuration at the carbon center where the substitution takes place.

Lastly, the SN2 mechanism exhibits second-order kinetics, as the reaction rate depends on the concentration of both the nucleophile and the electrophile. It is important to note that SN2 reactions are sensitive to steric hindrance; bulky groups near the reactive site can inhibit the reaction by limiting the nucleophile's access to the electrophile.

Answer and Explanation:

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

This question pertains to the rate of a chemical reaction, which is  first order with respect to (CH3)3CBr and zero order with respect to OH-. An Arrhenius plot indicating temperature and rate constant is used to find activation energy and frequency factor.

The reaction you're describing is a typical chemical reaction. This type of reaction is first order with respect to (CH3)3CBr, which means the rate of the reaction depends on the concentration of this compound. OH-, on the other hand, is zero order, meaning its concentration doesn't affect the reaction's rate.

The plot you've mentioned is an Arrhenius plot, and it is used to determine the activation energy and frequency factor of a reaction from the slop and y-intercept respectively. Given the slope value of –1.10 x 10^4 K you mentioned, you can find the activation energy (Ea) from the formula Ea = -slope * R , where the slope is –1.10 x 10^4 K and R is the universal gas constant (8.3145 Joule/(mole*K)). Similarly, from the y-intercept value, you can find the frequency factor by the formula A=e^(y-intercept), where A is frequency factor and e is natural base.

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E) two or more atoms chemically joined together.

The following information should be considered:

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Answer:

two or more atoms chemically joined together.

Explanation:

Answer:

33.78 g

Explanation:

NaClO3 decomposes to NaCl and O2 by this reaction:

2NaClO3 --> 2NaCl + 3O2

Let's determines the mole of chlorate we used (mass / molar mass)

61.5 g / 106.45 g/mol = 0.578 moles.

Ratio is 2:2, so x amount of chlorate will produce x amount of chloride. In conclussion we made 0.578 moles of NaCl from 0.578 moles of chlorate. Let's convert the moles to mass:

0.578 mol . 58.45g/1mol = 33.78 g

That is the theoretical yield of NaCl.

Answer:

Empirical CHO

molecular C4H4O4

Explanation:

From the question, we know that it contains 41.39% C , 3.47% H and the rest oxygen. To get the % composition of the oxygen, we simply add the carbon and hydrogen together and subtract from 100%.

This means : O = 100 - 41.39 - 3.47 = 55.14%

Next is to divide the percentage compositions by their atomic masses.

C = 41.39/12 = 3.45

O = 55.14/16 = 3.45

H = 3.47/1 = 3.47

Now we divide by the smallest value which is 3.45. We can deduce that this will definitely give us an answer of 1 all through as the values are very similar.

Hence the empirical formula of Maleic acid is CHO

Now we go on to deduce the molecular formula.

To do this we need the molar mass. I.e the amount in grammes per one mole of the compound.

Now we can see that 0.378mole = 43.8g

Then 1 mole = xg

x = (43.8*1)/0.378 = 115.87 = apprx 116

[CHO]n = 116

(12 + 1 + 16]n = 116

29n = 116

n = 116/29 = 4

The molecular formula is thus C4H4O4

Answer:

13.3 % by mass of NaCl

Explanation:

Solution is made of NaCl and water

Mass of NaCl = 23 g → Solute

Mass of H₂O = 150 g → Solvent

Total mass of solution = Solute + Solvent

23 + 150 = 173 g

Mass percent of NaCl → (Mass of solute / Mass of solution) . 100

(23g / 173g) . 100 = 13.3 g

The mass percent of NaCl in a solution made by dissolving 23.0 g of NaCl in 150.0 g of water is approximately 13.3%.

The mass percent of NaCl in a solution is found by dividing the mass of the solute (NaCl) by the total mass of the solution (solute plus solvent), and then multiplying by 100%.

For a solution made by dissolving 23.0 g of NaCl in 150.0 g of water, the total mass of the solution would be the mass of NaCl plus the mass of water, which is 23.0 g + 150.0 g = 173.0 g. The mass percent of NaCl is then calculated as:

So, the mass percent of NaCl in the solution is 13.3%.

Answer:

d. Localized.

Explanation:

You posted this question in the chemistry section. The whole exercise requires you to understand the terms in a chemical context. So let's look at the three terms: homogeneous, localized, and radicalized.

Homogeneous

A chemical substance is said to be homogeneous if the chemical composition is the same throughout. It means the substance must have the same states. For example, a mixture of undiluted orange juice forms a homogeneous solution once it is diluted in water. It means that there is perfect mixing to have a uniform liquid state.

Localized

The terminology is often applied to atoms or chemical structures, particularly metals and acids. For example, atoms have localized electrons in the orbitals. It means that the electron orbits in the region for 95 % of its time. Localized means belonging to one region. This applies to the religion.

Radical

The term applies to highly reactive atomic species, normally called ions. These elements seek electrons and are highly "reactive." The ions are called radicals in this sense.

Answer:

option (e), dichloromethane, methene chloride

Explanation:

(a)  [tex]CHCl_3[/tex]

Common name:  chloroform

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Three chlorine atoms are present.

Therefore, IUPAC name: Trichloromethane

(b)  [tex]CCl_4[/tex]

Common name:  Carbon tetrachloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Four chlorine atoms are present, chlorine atoms are named as prefixes.

Therefore, IUPAC name: tetrachloromethane

(c)  [tex]C_6H_5I[/tex]

Common name: Phenyl iodide

IUPAC name:

The given compound is an aryl halides. Aryl haildes are named as haloarenes. The prefix halo is placed before aromatic hydrocarbon. Here, prefix is iodo and aromatic hydrocarbon is benzene.

Therefore, IUPAC name of the compound is iodobenzene.

(d)  [tex]CH_3Cl[/tex]

Common name:  Methyl chloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

One chlorine atom is present.  

Therefore, IUPAC name: chloromethane

(e)  [tex]CH_2Cl_2[/tex]

Common name: Methylene chloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Two chlorine atoms are present, chlorine atoms are named as prefixes.

Therefore, IUPAC name: dichloromethane.

Therefore, the correct option is option (e), dichloromethane, methene chloride

Answer:

The aerobic cellular respiration of the glucose where glucose is converted to energy via four steps as follows

1. Glycolysis (glucose break down to pyruvic acid)

2. Link reaction

3. Krebs cycle

4. Electron transport chain, or ETC

The four pyruvic acid produces Four ATP, twenty NADH, and four [tex]FADH_{2}[/tex] molecules

Explanation:

When four pyruvic acid enters step two of the aerobic cellular respiration, they are converted by Oxidative decarboxylation into acetyl-CoA, four molecules of NADH and four molecule of CO2 are formed. This process is otherwise called the link reaction or transition  step, because it connects or links the Krebs cycle and glycolysis.

From the chemical reactions involved in cellular respiration of one glucose molecule, from two pyruvic acid molecules we have 2 ATP molecules, 10 NADH molecules, and 2 FADH2 molecules

Hence from four pyruvic acid molecules we have that the acetyl-CoA produced from the four pyruvic acid enters the the Krebs cycle and forms four ATP molecules, twenty NADH molecules, and four [tex]FADH_{2}[/tex] molecules.

In aerobic cellular respiration, four molecules of pyruvic acid will generate a total of four molecules of ATP, sixteen molecules of NADH (four from the conversion to Acetyl CoA, and twelve from the Krebs cycle) and four molecules of FADH2

In aerobic cellular respiration, pyruvic acid is converted into acetyl CoA. One molecule of pyruvic acid generates one molecule of NADH during this conversion so four molecules of pyruvic acid will yield four molecules of NADH. Acetyl CoA then enters the Krebs cycle, for each molecule of Acetyl CoA that goes through the Krebs cycle, three molecules of NADH, one molecule of FADH2, and one molecule of ATP is formed. Therefore, the four molecules of pyruvic acid would end up generating four molecules of ATP, twelve molecules of NADH and four molecules of FADH2 during the Krebs cycle (not including the NADH generated during the conversion to Acetyl CoA).

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Answer:

The answer is 671 litres of carbon dioxide is produced from 0.410 kg of hexane

Explanation:

We first write a balanced reaction for the complete combustion of hexane thus

The stoichiometry of the cumbustion of hexane in air is

2C6H14(g)+18O2(g)→12CO2(g)+14H2O(l) or

C6H14(g)+9O2(g)→6CO2(g)+7H2O(l)

From the above reaction it is observed that one mole of hexane burns completely in the presence of oxygen to produce 6 moles of carbon dioxide

Therefore we calculate the nuber of moles of hexane present in the sample thus

Mass hexane of sample = 0.41 kg

Molar nass of hexane = 86.18 g/mol

number of moles of hexane = (mass of hexane)/(molar mass of hexane) = (0.41×1000)/86.16 = 410/86.16 = 4.76 moles

As we have seen from the chemical reaction, 1 mole of H6H14 produces 6 moles of CO2 hence 4.76 moles of Hexane produces

4.76×6 moles of CO2 which is 28.55 moles of CO2

From the question we have the temperature and the pressure of the production of CO2 as

Temperature of reaction = 13° C converting to kelving gives= 13+273.15 = 286.15 K

and pressure = 1 atmosphere or 101325 Pa

13.0∘C=13.0∘C+273.15=286.15 K

The volume of the produced CO2 can be calculated using the combined ideal gas equation given by

P×V=n×R×T where

Here

P = Gas pressure (of CO2 )

V = Volume (of the CO2)

n = number of moles of gas (CO2) present

R = universal gas constant, equal to 0.0821 atm× L/(mol× K )

T = absolute temperature in Kelvin

Thus we have

1×V = 28.55×0.0821×286.15  or V  = 670.76L

Rounding up the answer to 3 significant digits we have

670.76L ≅ 671L

671 litres of carbon dioxide is produced from 0.410 kg of hexane

Answer: adhesion

Explanation:

Cohesion is the attraction between similar molecules. Example: Force of attraction between water molecules.

Thus hydrogen bond formed between the molecules of water due to the development of partial negative charge on oxygen and partial positive charge on hydrogen is cohesion.

Adhesion is the attraction between different molecules. Example: Force of attraction between HCl and water.

The hydrogen bond formed between H of HCl and O of water due to developments of partial positive and partial negative charge respectively is adhesion.

Final answer:

Using the 68-95-99.7 rule, the percentage of eggs weighing between 46.5 grams and 65.7 grams, given a mean weight of 51.3 grams and a standard deviation of 4.8 grams, is estimated to be between 95% and 99%.

Explanation:

The question asks us to calculate the percentage of eggs that weigh between 46.5 grams and 65.7 grams, given that the weights are normally distributed with a mean of 51.3 grams and a standard deviation of 4.8 grams. Utilizing the 68-95-99.7 rule (also known as the Empirical Rule), we can determine percentages for different ranges from the mean in a normal distribution.

Firstly, to find the specific range that includes 46.5g to 65.7g from our mean of 51.3g, we calculate the number of standard deviations each value is from the mean. However, without doing the math, we see that 46.5g is less than one standard deviation away (since one standard deviation is 4.8g), and 65.7g is significantly more than two but less than three standard deviations away.

According to the 68-95-99.7 rule, 68% of data falls within one standard deviation, 95% within two, and 99.7% within three. Thus, intuitively, without precise calculation, we can say that the percentage of eggs weighing between 46.5g and 65.7g would be a bit less than 99.7%, as the upper limit is not yet reaching three standard deviations from the mean but is beyond the two-standard deviation mark that covers 95% of the distribution. Thus, it's reasonable to conclude that approximately 95-99% of eggs will fall within this weight range.

Answer:

                    The elements that will be present after the burning of Ethanol are;

                  (i) Carbon

                   (ii)  Oxygen

                   (iii) Hydrogen

Explanation:

                    The balanced chemical equation for the burning of ethanol is as follow;

                            C₂H₅OH + 3 O₂ → 2 CO₂ + 3 H₂O

It can be observed in given balanced chemical equation that there three elements involved in this entire reaction. The elements that present in the reactant side are also found on the product side. It means that the elements have just rearranged going from reactant to product.

This means that this reaction is obeying Law of Conservation of Mass which states that mass can neither be created nor destroyed but it can be changed from one form to another hence, to keep the mass on both sides of the reaction balanced the same elements should be present on the product side too.

Answer: carbon, hydrogen, and oxygen only

Explanation: When a chemical reaction occurs, the atoms in the original set of substances are rearranged to form a new set of substances. The number of atoms of each element does not change.

The elements carbon, hydrogen, and oxygen are the only elements present in the original substances, so the only elements in the final substances after the reaction will be carbon, hydrogen, and oxygen, as well. The number of atoms of each element must be the same before and after the reaction.

Answer: False

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Example: [tex]CH_4[/tex] has similar molecular formula and empirical formula as the elements are already present in simplest of the ratios.

[tex]C_2H_2[/tex] has molecular formula of [tex]C_2H_2[/tex] but [tex]CH[/tex] as the empirical formula.

Answer: The unknown element is potassium.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

[tex]\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex] .....(1)

Mass of isotope 1 = 38.9637 amu

Percentage abundance of isotope 1 = 93.08 %

Fractional abundance of isotope 1 = 0.9308

Mass of isotope 2 = 39.9640 amu

Percentage abundance of isotope 2 = 0.012 %

Fractional abundance of isotope 2 = 0.00012

Mass of isotope 3 = 40.9618 amu

Percentage abundance of isotope 3 = 6.91 %

Fractional abundance of isotope 3 = 0.0691

Putting values in equation 1, we get:

[tex]\text{Average atomic mass of Z}=[(38.9637\times 0.9308)+(39.9640\times 0.00012)+(40.9618\times 0.0691)][/tex]

[tex]\text{Average atomic mass of Z}=38.85amu[/tex]

For the given options:

Option a: Average atomic mass of Sulfur = 32.065 amu

Option b: Average atomic mass of Potassium = 39.09 amu

Option c: Average atomic mass of Chlorine = 35.45 amu

Option d: Average atomic mass of Calcium = 40.078 amu

Option e: Average atomic mass of Argon = 39.94 amu

As, the average atomic mass of unknown element is near to the average atomic mass of potassium. So, the unknown element is potassium.

Hence, the unknown element is potassium.

The element with isotopes of masses 38.9637 amu, 39.9640 amu, and 40.9618 amu, and natural abundances of 93.08%, 0.012%, and 6.91% respectively, is Calcium (Ca).

To identify the element based on its isotopes, we need to calculate the average atomic mass of the element. This can be done by multiplying the mass of each isotope by its natural abundance (expressed as a decimal), and then summing up these products. In this case, the element with isotopes of masses 38.9637 amu, 39.9640 amu, and 40.9618 amu, and natural abundances of 93.08%, 0.012%, and 6.91% respectively, is Calcium (Ca). The average atomic mass of calcium can be calculated as follows:

(38.9637 amu * 0.9308) + (39.9640 amu * 0.00012) + (40.9618 amu * 0.0691) = 40.08 amu

Therefore, the element is calcium (Ca).

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In hemoglobin, a single amino acid change at position 6 from Glu to Val has major consequences on hemoglobin structure that makes the molecule defective leading to sickle cell anemia. Predict whether the following hypothetical change would or would not have a major effect at position 6. Briefly explain (1-2 sentences). Glu to Leu Hint: Look at the structures of the R groups and consider their chemical properties

The structure of the haemoglobin, hence the RBC won't be same as normal.

Both the leucine and glutamic acid are alpha amino acids which have an alpha carboxylic acid group and an alpha amino group. The variable in case of glutamic acid is propyl acid while the variable in case of leucine is isobutyl.

The glutamic acid is the normal amino acid of the 6th position of Beta chain of hemoglobin. Its an acid group, so can form bonds with another base inside the haemoglobin, or can form other hydrogen bonds. But the isobutyl group is an alkyl group. So it doesn't have that much effect in the recovering the structure, and sickle cell anemia prevails.

Answer:

The given chemical compound has 2 atoms of hydrogen and one atom of oxygen for each atom of carbon. The mass of CH2O is 12 + 2*1 + 16 = 30. The molecular weight of the compound is 180.18 which is approximately 180. This gives the molecular formula of the chemical compound as C6H12O6.

Explanation:

To calculate the percent composition of CH2O, determine the molar mass of each element and the total molar mass of the compound. The percent composition is approximately 40.0% Carbon, 6.7% Hydrogen, and 53.3% Oxygen.

To calculate the percent composition of CH2O, we will need to determine the molar mass of each element in the compound and the total molar mass of the compound. The molar masses from the periodic table are approximately 12.01 g/mol for Carbon (C), 1.01 g/mol for Hydrogen (H), and 16.00 g/mol for Oxygen (O).

First, let's calculate the total molar mass of CH2O: (1 × 12.01) + (2 × 1.01) + (1 × 16.00) = 12.01 + 2.02 + 16.00 = 30.03 g/mol.

Now, let's find the percent composition for each element:

The percent composition of CH2O is therefore approximately 40.0% Carbon, 6.7% Hydrogen, and 53.3% Oxygen.

Explanation:

Substances would be most likely to fall to the bottom of the beaker are CrPO4, Pb(OH)2.

All nitrates are soluble in water therefore, LiNO3 will be soluble. Also, sodium potassium salts are always soluble therefore, NaBr, KOH are soluble. Moreover. RbCl are generally soluble therefore, leaving the other two.

Answer and Explanation

The final reaction is the production of propane from Carbon and Hydrogen.

3C (s) + 4H2 (g) ---> C3H8 (g)

So, reverse eq. A,

3CO2 (g) + 4H20 (l) ---> C3H8 (g) + 502 (g)

Add 3 × eq. B,

3C (s) + 3O2 (g) ----> 3CO2 (g)

Add 4 × eq. C,

4H2 (g) + 2O2 (g) ---> 4H20 (l)

Writing them together,

3CO2 (g) + 4H20 (l) ---> C3H8 (g) + 502 (g)

+ 3C (s) + 3O2 (g) ----> 3CO2 (g)

+ 4H2 (g) + 2O2 (g) ---> 4H20 (l)

------------------------------------------------------------

3CO2 (g) + 4H20 (l) + 3C (s) + 3O2 (g) + 4H2 (g) + 2O2 (g) ---> C3H8 (g) + 502 (g) + 3CO2 (g) + 4H20 (l)

The compounds that exist on both sides cancel out and we're left with

3C (s) + 4H2 (g) ---> C3H8 (g)

So, mathematically, the final reaction can be written as:

(-eq. A + 3(eq. B) + 4(eq. C))

-A+3B+4C = 3C (s) + 4H2 (g) ---> C3H8 (g)

QED!

[tex]\[{3\text{C(s, graphite)} + 4\text{H2(g)} \rightarrow \text{C3H8(g)} + 5\text{O2(g)}} \][/tex]

This balanced equation shows the production of propane (C3H8) from its elements carbon and hydrogen gas.

To combine the given reactions to form the balanced chemical equation describing the production of propane (C3H8) from its elements carbon (C, as graphite) and hydrogen (H2), let's follow these steps:

Given reactions:

(a) [tex]\( \text{C3H8(g)} + 5\text{O2(g)} \rightarrow 3\text{CO2(g)} + 4\text{H2O(g)} \)[/tex]

(b) [tex]\( \text{C(s, graphite)} + \text{O2(g)} \rightarrow \text{CO2(g)} \)[/tex]

(c) [tex]\( \text{H2(g)} + \frac{1}{2}\text{O2(g)} \rightarrow \text{H2O(g)} \)[/tex]

We need to manipulate these reactions to combine them into one overall balanced equation that shows the formation of propane (C3H8) from carbon and hydrogen.

Step-by-Step Combination:

1. Reverse Reaction (a):

[tex]\( 3\text{CO2(g)} + 4\text{H2O(g)} \rightarrow \text{C3H8(g)} + 5\text{O2(g)} \)[/tex]

This is the reverse of reaction (a), which is necessary to show the formation of propane.

2. Multiply Reaction (b) by 3:

[tex]\( 3\text{C(s, graphite)} + 3\text{O2(g)} \rightarrow 3\text{CO2(g)} \)[/tex]

Multiply reaction (b) by 3 to balance the carbon atoms with the propane formation reaction.

3. Multiply Reaction (c) by 4:

[tex]\( 4\text{H2(g)} + 2\text{O2(g)} \rightarrow 4\text{H2O(g)} \)[/tex]

Multiply reaction (c) by 4 to balance the hydrogen atoms with the propane formation reaction.

4. Combine the Reactions:

Now, add the balanced reactions (reverse of (a), multiplied (b), and multiplied (c)) to get the overall balanced equation for the formation of propane:

[tex]\( 3\text{C(s, graphite)} + 3\text{O2(g)} + 4\text{H2(g)} + 2\text{O2(g)} \rightarrow 3\text{CO2(g)} + 4\text{H2O(g)} + 5\text{O2(g)} \)[/tex]

5. Simplify the Equation:

Combine like terms (oxygen on both sides):

[tex]\( 3\text{C(s, graphite)} + 3\text{O2(g)} + 4\text{H2(g)} \rightarrow 3\text{CO2(g)} + 4\text{H2O(g)} + 5\text{O2(g)} \)[/tex]

Answer: solutions that would be expected to contain the greatest number of solute particles (molecules or ions) is

1 L of 1.0 M NaCl

Answer:

Explanation:

from Bohr's equation,

E = -Z²R/n²

R = 13.6 eV

Z = atomic number of element

for 1s energy level n= 1

E = -(Z)² x (13.6)/(1)²

E = -13.6Z²

calculating the numerical for the 1s energy levels for He+ and Li2+

- for He+

E = -13.6 * (2)² = -54.4eV

- for Li2+

E = -13.6 * (3)² = -122.4eV