which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Answer:

A) Be sure the task is understood.

Step-by-step explanation:

The principle "Make sure the mission is understood, performed, and achieved."

Another way we talk about this principle in the Navy is through the idea of "intrusive leadership." In some respects both "micromanagement" and "intrusive leadership" sound terrible.

Think about certain great managers and leaders you have had in your career yet again. Probability are they will be the ones who asked you those difficult questions, too.

They moved everyone to new technical levels, and eye for detail. When you said you knew what you were doing or when you announced the progress of a project, they didn't necessarily take it to face value.

Answer:

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex]    [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex]   [tex]\Rightarrow[/tex]  4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex]    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex]    [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex]   [tex]\Rightarrow[/tex]  4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex]    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

The money after 10 years is $ 13591.4091

Solution:

Given that,

If you have a bank account that is modeled by the following equation:

[tex]A = 5000e^{0.10t}[/tex]

To find: Money after 10 years

How much money would you have after 10 years

Substitute t = 10 in above given equation

[tex]A = 5000 \times e^{0.10 \times 10}\\\\A = 5000 \times e^{1}\\\\A = 5000 \times 2.71828\\\\A = 13591.4091[/tex]

Thus money after 10 years is $ 13591.4091

Answer:

  D. The second route, in 1.18 hours

Step-by-step explanation:

The appropriate relation is ...

  time = distance/speed

The time required on the first route is ...

  time1 = (40 mi)/(25 mi/h) = 40/25 h = 1.6 h

The time required on the second route is ...

  time2 = (65 mi)/(55 mi/h) = 65/55 h = 1 2/11 h ≈ 1.18 h

__

The second route requires a shorter time, so will get you there faster. The second route will get you there in 1.18 hours.

The statement "Every elementary row operation is​ reversible" is true because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement (Option A is correct).

The statement "Every elementary row operation is​ reversible" is true.

The correct choice is: A. True, because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement.

- Interchanging rows (row swapping) can be reversed by another interchange.

- Scaling a row by a non-zero scalar can be reversed by scaling it by the reciprocal of that scalar.

- Replacement operations (adding or subtracting multiples of one row from another) can also be reversed by adding or subtracting the same multiples in the opposite direction.

So, all three elementary row operations (replacement, interchanging, and scaling) are reversible, which makes option A the correct choice.

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The statement 'Every elementary row operation is reversible' is true. All the three types of elementary row operations, i.e., scaling, interchanging, and replacement, can be reversed using appropriate methods.

The statement 'Every elementary row operation is reversible' is indeed true. The three types of elementary row operations, i.e., scaling, interchanging, and replacement, are all reversible. Scaling can be reversed by multiplying the row by the reciprocal of the scale factor. Interchanging rows can be undone by simply interchanging them again. Replacement can be reversed by applying a replacement operation with the opposite sign.

For example, if you multiply a row by a factor of 3 (scaling), you can reverse this by multiplying the row by 1/3. If you interchange row 1 and row 2, you can reverse this by interchanging these two rows again. Finally, if you replaced row 1 by adding 2*row 2 to it, you could reverse this by replacing row 1 by subtracting the same 2*row 2 from it.

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To maximize the area of the Norman window, solve for the dimensions of the rectangle. Substitute the expression for 'h' in terms of 'w' into the area formula. Take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'.

To maximize the area of the Norman window, we need to find the dimensions of the rectangle. Let's denote the width of the rectangle as 'w' and the height as 'h'. The perimeter of the rectangle can be expressed as 2w + h + πh = 24 feet. Rearranging the equation, we have (2 + π)h + 2w = 24. Since we want to maximize the area, we can solve for 'h' in terms of 'w' using this equation.

Next, we can substitute the expression for 'h' in terms of 'w' into the area formula for the window, which is A = wh + (π/4)w^2. Simplifying this expression, we get A = (w(2 + πw))/4. To find the dimensions that maximize the area, we can take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'. This will give us the width of the rectangle. Once we have the width, we can substitute it back into the equation for 'h' to find the height.

By solving these equations, we can find the dimensions of the rectangle that will maximize the area of the Norman window, allowing in as much light as possible.

Answer: 20 feet

Step-by-step explanation:

in the attachment

The ladder reaches approximately 19.8 feet up the side of the house, as determined using the Pythagorean theorem.

The question is asking us to find the height the ladder reaches up the side of the house. This is a problem dealing with right triangles and can be solved using the Pythagorean theorem, which is a^2 + b^2 = c^2, where 'a' and 'b' are the shorter sides (base and height of the house) and 'c' is the hypotenuse (the ladder).

In this case, the ladder is 24 feet long (this is our c), and the base of the ladder is 13 feet from the house (this is our a). We are trying to find b (the height of the house the ladder reaches).

Substitute these values into the Pythagorean theorem and solve for 'b':

13^2 + b^2 = 24^2
b^2 = 24^2 - 13^2
b = sqrt(24^2 - 13^2)

So, the height that the ladder reaches up the side of the house is approximately 19.8 feet.

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Answer:

x = 0 , y = 0 , z = -3

Step-by-step explanation:

Solve the following system:

{x - 6 y + 4 z = -12 | (equation 1)

x + y - 4 z = 12 | (equation 2)

2 x + 2 y + 5 z = -15 | (equation 3)

Swap equation 1 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

x + y - 4 z = 12 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - (13 z)/2 = 39/2 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Multiply equation 2 by 2/13:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 7 y + (3 z)/2 = -9/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 14 y + 3 z = -9 | (equation 3)

Swap equation 2 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y - z = 3 | (equation 3)

Multiply equation 3 by -1:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by -14:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{2 x + 0 y+5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 5 × (equation 3) from equation 1:

{2 x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer: {x = 0 , y = 0 , z = -3

To solve the given system of equations, use the method of elimination to eliminate one variable at a time and solve for the remaining variables.

To solve the system of equations:

x - 6y + 4z = -12

x + y - 4z = 12

2x + 2y + 5z = -15

We can use the method of substitution or elimination. Let's use the method of elimination:

Therefore, the solution is x = -5, y = 4, and z = 1.

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Answer:

a.) 23

b.) y=14

c.) 23

d.) -23

e.) T=8

f.) f=1/8

Step-by-step explanation:

a.) general equation is Asin((2π/T))

A is the amplitude. It's A value is 23

b.)  Midline = vertical_shift = 14

c.) max = positive amplitude value = 23

d.) min = negative amplitude = -23

e.) Factor out 2π from your angular frequency to get the period.

ω = π/4 = (2π)/8 = (2π)/T

Period = 8

f.) Frequency is just the inverse of the period.

f = 1/T = 1/8

This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = [tex]\rho=1.28kg/m^3[/tex]

Area = A = 7.00 m × 12.0 m

Formula used :

[tex]\Delta P=\frac{1}{2}\times \rho \times v^2[/tex]

Now put all the given values in this formula, we get:

[tex]\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2[/tex]

[tex]\Delta P=1.11\times 10^3Pa[/tex]

Thus, the pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

Answer:

x=42

Step-by-step explanation:

x-12=30

x=30+12

x=42

To solve for x in this equation, we want to get x by itself on the left side of the equation. Since 12 is being subtracted from x, to get x by itself, we need to add 12 to the left side of the equation. If we add 12 to the left side, we must also add 12 to the right side.

On the left side, -12 and +12 cancel each other out so we are simply left with x. On the right side, 30 + 12 is 42 so we have x = 42.

It's important to understand that we can check our answer by substituting 42 back into the original equation.

So we have (42) - 12 = 30.

42 - 12 is 30 so we have 30 = 30 which is a true statement so our answer, x = 42, is correct.

Answer:

The required equation is [tex]4889=4850 +3n[/tex].

Step-by-step explanation:

Consider the provided information.

Melody has a new job recording for the All-Time Favorites record label.

She is paid a monthly base salary of $plus $3 for each CD sold.

Her pay stub for June indicates that she made $4,889 in that month.

Let n represents the number of CDs she sold.

Therefore, the required equation is [tex]4889=4850 +3n[/tex].

Answer:

Step-by-step explanation:

Please refer to the picture below

Answer:

  £100.32

Step-by-step explanation:

£88 + 14% × £88 = £88×(1 +0.14)

  = 1.14×£88

  = £100.32 . . . . using a calculator

£100.32 is £88 increased by 14%.

Final answer:

£100.32

Explanation:

To increase an amount by a certain percentage using the multiplier method, you can use the following steps:

Let's do the calculation:

Answer:

$774

Step-by-step explanation:

We have been given that from January to June, a company spent $60 per month on office supplies. In July the price of office supplies increased by 15% and remained the same for the rest of the year.

Let us find increased cost of supplies as shown below:

[tex]\text{Increased cost of supplies}=60+\frac{15}{100}\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+0.15\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+9[/tex]

[tex]\text{Increased cost of supplies}=69[/tex]

There are 6 months from January to June, so cost of supplies on these 6 months would be 6 times $60.

There are 6 months from July to December, so cost of these months would be 6 times $69.

Total cost will be equal to sum of these two amounts.

[tex]\text{Amount spent on office supply in the year}=6\times \$60+6\times \$69[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$60+\$69)[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$129)[/tex]

[tex]\text{Amount spent on office supply in the year}=\$774[/tex]

Therefore, $774 were spent on office supplies.

P(A) =0.54

P(B)= 0.68

P'(A)= 1-0.54 = 0.46

P'(B)= 1- 0.68 = 0.32

The probability of neither of both event will occur:

= P'(A)×P'(B)

=0.46 × 0.32

=0.1472

Answer:

1st it: g(2)=1/3(2)+1=0.67+1=1.67

2nd it: g^2(2)=1/3(1.67)+1=0.56+1=1.56

3rd it: g^3(2)=1/3(1.56)+1=0.52+1=1.52

Answer:

The first three iterations are 1.67, 1.56 and 1.52

Step-by-step explanation:

Given the function g(x)=1/3x+1

To get the first threw iteration with initial value of x = 2

First iteration at x= 2:

g(2) = 2/3+1

g(2) = (2+3)/3

g(2) = 5/3 = 1.67

Second iteration will be when x = g(2) = 5/3

g²(2) = g(5/3) = 1/3(5/3) + 1

g²(2) = g(5/3) = 5/9 + 1

g²(2) = g(5/3) = 14/9 = 1.56

Third iteration will be at when

x = g²(2) = 14/9

g³(2) = g(14/9) = 1/3(14/9) + 1

g³(2) = g(14/9) = 14/27 + 1

g³(2) = g(14/9) = 41/27 = 1.52

The first three iterations are 1.67, 1.56 and 1.52

What is the question that is being asked?

The location of the reflected post will be in the first quadrant at point (3, 2).

To reflect a point across the y-axis, we simply negate the x-coordinate while keeping the y-coordinate unchanged.

Given the point (-3, 2), when we reflect it across the y-axis, the x-coordinate becomes positive 3, while the y-coordinate remains 2. Therefore, the reflected point is (3, 2).

Since the original point (-3, 2) lies in the second quadrant (negative x, positive y), the reflected point (3, 2) will lie in the first quadrant (positive x, positive y).

Answer:

0.0223

Step-by-step explanation:

Given the following data x(1) = 377, n(1) = 422, x(2) = 431, n(2) = 518

The sample proportion is the number of success divided by the sample.

P(1) = x(1)/n(1) = 377/422 = 0.8934

P(2) = x(2)/n(2) = 431/518 = 0.8320

Formular for the standard error of the difference in sample proportions

S.E = √p(1)q(1)/n(1)+P(2)q(2)/n(2)

S.E = √p1(1-P1)/n1+P2(1-P2)/n2

By substitution we have that,

S.E = √0.8934(1-0.8934)/422+0.8320(1-0.8320)/518

S.E = 0.0223

The final velocity is 15.8 m/s in the forward direction

Step-by-step explanation:

An inelastic collision occurs when the two object after the collision stick together.

In any case, the total momentum of the system is conserved before and after the collision, in absence of external forces. Therefore, we can write:

[tex]p_i = p_f\\m u + MU = (m+M)v[/tex]

where in this problem:

m = 1300 kg is the mass of the small sedan

u = 20 m/s is the initial velocity of the small sedan

M = 7100 kg is the mass of the truck

U = 15 m/s is the initial velocity of the truck

v is the final combined velocity of the small sedan + truck

Here we have taken both the velocity of the sedan and the truck in the positive (forward) direction

Solving the equation for v, we find the final velocity:

[tex]v=\frac{mu+MU}{m+M}=\frac{(1300)(20)+(7100)(15)}{1300+7100}=15.8 m/s[/tex]

And since the sign is positive, this means that is direction is the same as the initial direction of the sedan and the truck, so forward.

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Answer:

1. 1.76x10^13,

2. 3.20x10^8,

3. 5.5x10^4

Step-by-step explanation:

Answer:

Step-by-step explanation:

GDP/POPULATION

1755x10^13/3.2x10^8 = .05484x10^5

=5.484x10^4

= 5.49x10^4

Answer:

a) Rate of brightness after t days = B(t) = 2.6 + 0.6sin(2×3.142 t /6.6)

b) 0.57

Step-by-step explanation:

Given

Number of days=6,6 days

Average brightness =2.6

B(t)= 2.6 + 0.6 sin (2× 3.142t/6.6)

b) B(1day) = 0.6 ×(2×3.142/6.6)cos (2×3.142/6.6)

B(1 day) = 0.6 × (6.248/6.6)cos 0.952

B(1 day) =0.6 × 0.952 ×0.9999

B(1day) = 0.5711

= 0.57

ANSWER:

1. How many possible combined page count and color choices are possible?

There are  3 choices for page size and 4 choices for color, and also, there are 3*4=12 possibilities to combine page size and color.

Number possibilities to combine and number of choices for size is: 12:3=4:1

Number of possibilities to combine and number of choices for color is 12:4=3:1

2. How does this number relate to the number of page size choices and to the number of color choices

There are 12 possibilities to combine size and color.

Number of possibilities to combine and number of choices for size is 4:1

Number of possibilities to combine and number of choices for color is 3:1

Answer:

We have 12 possibilities to combine page size and color.

Number of possibilities and number of choices is 12:4 that is 3:1

Step-by-step explanation:

have a nice day.

Answer:

True, the scores are not valid.

Step-by-step explanation:

The test supposed to be measuring intelligence. We can assume that the intelligence of most people relatively stable (will not change too much over a short amount of time), and can expect it should go upward with brain growth and education. But the test seems to give a huge decrease from the first and second results. Then the third result is a huge increase that even higher than the first test.  

We don't know the true value of the subject, but seeing the huge gap for every repetition we can tell that the test result lacks precision.

Answer:

Therefore, 32  is he total number of vehicles sold at the dealership last month.

Step-by-step explanation:

We know that the ratio of the number of sedans to the number of trucks to the number of vans sold at the dealership last month was 4:5:7, respectively. We have :

[tex]4:5:7 \implies 4x+5x+7x=16x[/tex]

Therefore, 16x is he total number of vehicles sold at the dealership last month.

We know that:

1) The number of vans sold at the dealership last month was between 10 and 20.

2) The number of sedans sold at the dealership last month was less than 10

We get:

[tex]10\leq 7x \leq 20\\\implies x=2\\\\\\4x\leq 10\\x=1 \, \vee \, x=2[/tex]

We know that x is a positive integer. In order to satisfy both conditions, this is possible only if x = 2.

We get [tex]16x=16\cdot 2=32[/tex]

Therefore, 32  is he total number of vehicles sold at the dealership last month.

Answer: 6x^13-1.5w+156x+13 is the answer to the first equation and is that another equation?

The expression 13 - 0.5w + 6x evaluates to 11 when substituting w=10 and x=1/2.

The problem is to evaluate the expression 13 - 0.5w + 6x given the values w=10 and x=1/2. Following the order of operations, we first substitute the given values into the expression.

13 - 0.5(10) + 6(1/2) = 13 - 5 + 3 = 11.

The result of the evaluated expression is 11.

Answer: Segments AB / A"B" = √13 / 2 x √13

Step-by-step explanation:

The Triangle's vertices are at points A(-3,3), B(1,-3) and C(-3,-3).

• The reflection over x = 1 shows vertices A, B and C below:

A(-3,3)→A'(5,3);

B(1,-3)→B'(1,3);

C(-3,-3)→C'(5,-3).

• The Dilation by a scale factor of 2 from the origin is expressed as:

(x,y)→(2x,2y)

Therefore,

A'(5,3)→A''(10,6);

B'(1,3)→B''(2,6);

C'(5,-3)→C''(10,-6)

The attachment below completed the calculations and shows the segment in a simple graph.

Answer:

The area of the rectangle TOUR is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

[tex]Area\ of\ a\ Rectangle=length\times width[/tex]

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

[tex]distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

Considering the rectangle TOUR the area formula will be:

Area of Rectangle TOUR = TO × OU

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices T and O as:

[tex]TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}[/tex]

Compute the distance between the vertices O and U as:

[tex]OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}[/tex]

Compute the area of rectangle TOUR as follows:

[tex]Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}[/tex]

Thus, the area of the rectangle TOUR is 80.00 unit².

Answer:

This answer is just here so you can give the other guy brainliest, as there can only be brainliest if there are two answers.

Step-by-step explanation:

Give that guy brainliest

Answer:

6 by 3

Step-by-step explanation:

a rectangle as 2 equal sides. so if we know that it is 6 by 3, then 6+6+3+3

=12+6=18

the area of a rectangle is base * height. so 6 * 3 = 18

Answer: the length is 6 inches and the width is 3 inches.

Step-by-step explanation:

Let L represent the length of the rectangular note card.

Let W represent the width of the rectangular note card.

The formula for determining the area of a rectangle is expressed as

Area = L × W

Area of the note card would be

LW = 18 - - - - - - - - - - - - 1

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

Perimeter of the note card would be

2(L + W) = 18

(L + W) = 9 - - - - - - - - - - - - 2

Substituting L = 9 - W into equation 1, it becomes

W(9 - W) = 18

9W - W² = 18

W² - 9W + 18 = 0

W² - 6W - 3W + 18 = 0

W(W - 6) - 3(W - 6) = 0

W - 6 = 0 or W - 3 = 0

W = 6 or W = 3

Substituting W = 3 into equation 1, it becomes

3L = 18

L = 18/3 = 6