Answer:
D
Explanation:
the answer is d because gravitational force is what allows them to rotate
hope this was helpful
a child pulls on a string that is attached to a car. if the child does 80.2 J of work while pulling the car 25.0 m, with what force is the child pulling?
Answer:
F = 3.20 N
Explanation:
Given:
Work done by child = 80.2 j
Distance that the car moves = 25.0 m
We need to find the force acting on the car.
Solution:
Using work done formula as.
[tex]W = F\times d[/tex]
Where:
W = Work done by any object.
F = Force (push or pull)
d = distance that the object moves.
Substitute [tex]W = 80.2\ J\ and\ d =25.0\ m[/tex] in work done formula.
[tex]80.2 = F\times 25[/tex]
[tex]F=\frac{80.2}{25}[/tex]
F = 3.20 N
Therefore, force acting on the car F = 3.20 N
. A car moves forward up a hill at 12 m/s with a uni-
form backward acceleration of 1.6 m/s2.
a. What is its displacement after 6.0 s?
b. What is its displacement after 9.0 s?
A) Displacement after 6.0 s 43.2 m uphill.
B) Displacement after 9.0 s 43.2 m uphill.
Explanation:
A car moving upwards in a hill is [tex]12 ms^{-1}[/tex].
Its uniform backward acceleration is [tex]-1.6ms^{-2}[/tex]. (since backward acceleration is a negative acceleration, it is mentioned in negative)
We need to find the displacement of the car after some time.
Using the equation of the motion formula, we know can identify the displacement.
D=[tex]vt+\frac{1}{2} at^2[/tex].
a) Displacement after 6.0 seconds,
D = [tex]12(6.0)+\frac{1}{2}(-1.6)(6.0)^2[/tex].
=[tex]72+\frac{1}{2} (36)(-1.6).[/tex]
=[tex]72+\frac{1}{2}(-57.6).[/tex]
=72-28.8.
D=43.2 m.
b) Displacement after 9.0 seconds,
D= [tex]12(9.0)+\frac{1}{2}(-1.6)(9.0)^2[/tex].
=[tex]108+\frac{1}{2} (81)(-1.6).[/tex]
=[tex]108+\frac{1}{2}(-129.6).[/tex]
= 108-64.8.
D=43.2 m.
The car's displacement after 6.0 s is 14.4 m and after 9.0 s is 43.2 m.
To find the displacement of the car after a given time, we can use the equation:
Displacement (d) = Initial velocity (v) * time (t) + (1/2) * acceleration (a) * time^2
a. After 6.0 s:
Initial velocity (v) = 12 m/s
Acceleration (a) = -1.6 m/s^2 (negative because it's a backward acceleration)
Substituting the values into the equation:
d = (12 m/s) * (6.0 s) + (1/2) * (-1.6 m/s^2) * (6.0 s)^2 = 72 m - 57.6 m = 14.4 m
b. After 9.0 s:
Using the same equation and substituting the new time, we can calculate the displacement:
d = (12 m/s) * (9.0 s) + (1/2) * (-1.6 m/s^2) * (9.0 s)^2 = 108 m - 64.8 m = 43.2 m
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If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?
Answer: 2200J
Explanation:
M = 44kg
V = 10m/s
K.E =?
K.E = 1/2MV2 = 1/2 x 44 x (10)^2
K.E = 22 x 100
K.E = 2200J