Answer:
Group Policy Object (GPO)
Explanation:
A Group Policy Object is simply known as a collection of setting that are created by system administrators using the Microsoft Management Console Group Policy Editor. This method is usually associated with one or sometimes more than one Active Directory containers, which includes organizational units, domains, and sites.
Create detailed pseudocode for a program that calculates how many days are left until Christmas, when given as an input how many weeks are left until Christmas. Use variables named weeks and days.
Answer:
Following are the Pseudocode for the above problem:
Explanation:
Declare weeks and days As Variables Output: "Enter the input for weeks are left until Christmas."Set weeks = user answerSet days = weeks *7Output: “The days left until Christmas is ” Output: days.Output:
If the user inputs 2 then the output is "The days left until Christmas is 14"If the user inputs 3 then the output is "The days left until Christmas is 21"Pseudocode Explanation:
Pseudocode is the solution to any problem which is written in the form of the English language.The only difference between the algorithm and Pseudocode is that the algorithm is only written in English and the Pseudocode is written in the form of input and output.
An interface is a class that contains only the method headings and each method heading is terminated with a semicolon. True False
Answer:
False
Explanation:
Interfaces are similar to classes in Java, but they are not a type of class. A class defines the attributes and behaviours of objects, while interface contains the methods that shows the behaviours to be implemented by a class.
A method is one or more group of statements, it does not need to end with a semicolon. Methods in interfaces are abstract and for a class to contain these abstract method, it must be defined in the class.
An interface is a class that contains only the method headings and each method heading is terminated with a semicolon is a true statement.
What is interface?An interface is known to be a kind of reference that is seen in Java. It is same to look the same with class.
It is known as a series of abstract methods that shows the description of the work that a specific object can do. Here, An interface is a class that has only the method headings and the method heading is ended with a semicolon.
Learn more about interface from
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Give state diagrams of DFAs that recognize the following languages.
In all parts, the alphabet is {0, 1}.
(a) {w|w begins with a 1 and ends with a 0}
(b) {w|w contains at least three 1s}
(c) {w|w contains the substring 0101, i.e., w = x0101y for some strings x, y}
Answer:
Following is attached the solution of each part step-by-step. I hope it will help you!
Explanation:
What is a method whereby new problems are solved based on the solutions from similar cases solved in the past?
Answer:
"Case-Based Reasoning" is the answer for the above question.
Explanation:
Case-Based Reasoning is a process of decision-making theory in which the new problems were solved based on the previously solved problem.It is used in artificial intelligence and robots. This helps to make any AI and robots to do the work and take decisions on its own.The theory is used to make any computer that behaves like humans. It can take decisions like a human. The above question asked about the method by which the new problem is solved on behalf of the old problem. Hence the answer is "Case-Based Reasoning".What are the design concepts and assumptions behind a class, an object and the relationship between them? What are the roles methods and static fields play in OOP?
Answer:
Object-oriented programming (OOP) is a procedural language and based on classes associated with an object. Without classes and object relationship OOP is not possible. According to program's design concept classes provide abstraction and encapsulation with the help of object. Object have states and behaviors like cat has states like name, color and cat has also behaviors like wagging the tail, eating, jumping etc. A class forms template or blueprints for these states and behaviors because different cats have different behaviors and states.
Methods provide a way for encapsulation and accessing private class members with public methods and static fields are sometimes best alternative for global variable. We can use static field when it same for all and shared by all objects of that class and it can save memory because we do not have to initialize it for each object
Final answer:
In Object-Oriented Programming (OOP), a class is a blueprint for creating objects, while an object is an instance of a class. The relationship between a class and an object is that a class defines the structure of an object. Methods in OOP are used to perform actions or computations, while static fields are shared among all objects of a class.
Explanation:
Design Concepts and Assumptions in OOP:
In Object-Oriented Programming (OOP), a class is a blueprint for creating objects, while an object is an instance of a class. The design concept behind a class is to define the common characteristics and behaviors that objects of that class will have. Assumptions made when designing a class include creating a hierarchy of classes to represent different levels of abstraction and encapsulating data and behaviors within the class.
Relationship between Class and Object:
In OOP, the relationship between a class and an object is that a class defines the structure (attributes and behaviors) of an object, while an object is an instance of a class that can be created and manipulated using the defined structure.
Roles of Methods and Static Fields in OOP:
In OOP, methods are functions or behaviors associated with an object or class, which are used to perform certain actions or computations. They define how objects or classes interact with each other and with the outside world. Static fields, on the other hand, are variables or data that are shared among all objects of a class. They hold values that are common to all instances of the class and can be accessed without creating an object.
An alternative to hexadecimal notation for representing bit patterns is dotted decimal notation in which each byte in the pattern is represented by its base ten equivalent. In turn, these byte representations are separated by periods. For example, 12.5 represents the pattern 0000110000000101 (the byte 00001100 is represented by 12, and 00000101 is represented by 5), and the pattern 100010000001000000000111 is represented by 136.16.7. Represent each of the following bit patterns in dotted decimal notation. 0000111100001111 001100110000000010000000 0000101010100000
Answer:
Represent each of the following bit patterns in decimal notation.
Process for conversion:
1. Divide the bit pattern into equal parts.
2. Every digit represent by base 2 with different powers from 0 to 7.
3. Then match the binary number to respective digits of base 2.
4. Neglect numbers that represent by 0 and add numbers that represent by 1.
5. Then place dot between results obtained from different parts.
Part 1: Answer = 15.15
Part 2: Answer=51.0.128
Part 3: Answer=10.160
See attachment for each part
Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. The output of the program is every word in the list that contains the character at least once. Assume at least one word in the list will contain the given character. Assume that the list of words will always contain fewer than 20 words.
Final answer:
The question asks for a program that reads an integer representing the number of words in a list, the words themselves, and a character, and then prints each word from the list that contains the character at least once. A sample Python script has been provided to illustrate how this can be achieved by iterating through the list and checking for the presence of the character in each word.
Explanation:
To create a program that reads an integer, a list of words, and a character, where the integer indicates the number of words in the list, and the output displays every word containing the specified character at least once, you would typically use a programming language like Python. The task involves iterating through the list of words and checking if each word contains the character. Here is a simple example in Python:
# Read the integerThis script prompts the user to input the number of words, the words themselves, and the character to search for. It then prints out any word that contains the character.
Two co-workers at Nortel came up with an idea for renting software over the Internet. Nortel's top management liked the idea and set up a special division called Channelware devoted to taking the idea and making a new product. The establishment of a new company and assigning the employees in the division the task of making an idea a reality requires which management function?
Answer:
The correct answer is: Organizing.
Explanation:
Management functions refer to the roles high-rank executives must play to handle businesses. Those functions are Planning, Organizing, Staffing, Directing, and Controlling. Organizing refers to the steps taken to create a structure in the organization. Managers should find the most optimal way to group the firm's resources to ensure efficiency and effectiveness. The process of organizing includes:
Identification of activities Grouping of activities Assigning of responsibilities Granting authority Establishing relationships
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".
Full Question
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal
#include <iostream>
#include <cmath>
using namespace std;
int main() {
double targetValue;
double sensorReading;
cin >> targetValue;
cin >> sensorReading;
if (/* Your solution goes here */) {
cout << "Equal" << endl;
} else {
cout << "Not equal" << endl;
} return 0;
}
Answer:
if (abs(targetValue - sensorReading) <= 0.0001)
Explanation:
Replace
if (/* Your solution goes here */) {
With
if (abs(targetValue - sensorReading) <= 0.0001)
Two values are considered to be close enough if the difference between the values is 0.0001
Splitting the codes into bits;
abs
targetValue - sensorReading
<=
0.0001
The keyword abs is to return the absolute value of the expression in bracket.
This is needed because the expression in the bracket is expected to return a positive value.
To do this the absolute keyword is required.
targetValue - sensorReading returns the difference between the variables
<= compares if the difference falls within range that should be considered to be close enough
0.0001 is the expected range
What are the differences between a trap (aka software interrupt) and an interrupt (hardware interrupt)? What is the use of each function
Answer:
Trap is a software interrupt that occurs when there is a system call, while hardware interrupt occurs when a hardware component needs urgent attention.
Explanation:
Interrupt is an input signal that disrupt the activities of a computer system, giving immediate attention to a hardware or software request.
In trap interrupt, the system activities are stop for a routine kernel mode operation, since it has a higher priority than the user mode. At the end of the interrupt, it switches control to the user mode.
The hardware interrupt is a signal from hardware devices like the input/output devices, storage and even peripheral devices that draws an immediate attention of the processor, stopping and saving other activities and executing the event with an interrupt handler.
Describe how to scan a stack S containing to see if it contains a particular value x using only a queue Q and a constant number of reference variables. The stack contains n values and Q is initially empty. When the process finishes, the elements of S must be in their original order. [Preferred Language in C++]
Answer:
#include <iostream>
#include <stack>
#include <queue>
using namespace std;
bool checkfor(stack<int> &stk, int x){
queue<int> q;
bool flag = false;
while(!stk.empty()){
int p = stk.top();
stk.pop();
if(p == x){
flag = true;
}
q.push(p);
}
while(!q.empty()){
stk.push(q.front());
q.pop();
}
while(!stk.empty()){
q.push(stk.top());
stk.pop();
}
// from queue to stack
while(!q.empty()){
stk.push(q.front());
q.pop();
}
return flag;
}
int main(){
stack<int> stk;
// pushing data to stack
stk.push(1);
stk.push(3);
stk.push(43);
stk.push(2);
stk.push(5);
cout<<(checkfor(stk, 5)?"Found": "Not Found")<<'\n';
cout<<(checkfor(stk, 10)?"Found": "Not Found")<<'\n';
return 0;
}
Explanation:
Check the top of stack for relevant value and insert that into queue.Take value from front of queue and push it to stack after the stack is empty. Now empty queue and push values to stack.Create an application named TestClassifiedAd that instantiates and displays at least two ClassifiedAd objects. A ClassifiedAd has fields for a Category (For example, Used Cars and Help Wanted), a number of Words, and a price. Include properties that contain get and set accessors for the category and number of words, but only a get accessor for the price. The price is calculated at nine cents per word.
Answer:
Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!
Explanation:
```csharp
using System;
class ClassifiedAd
{
// Fields
private string category;
private int numberOfWords;
// Properties
public string Category
{
get { return category; }
set { category = value; }
}
public int NumberOfWords
{
get { return numberOfWords; }
set { numberOfWords = value; }
}
public double Price
{
get { return numberOfWords * 0.09; } // Price calculated at nine cents per word
}
}
class TestClassifiedAd
{
static void Main(string[] args)
{
// Instantiate ClassifiedAd objects
ClassifiedAd ad1 = new ClassifiedAd();
ad1.Category = "Used Cars";
ad1.NumberOfWords = 50;
ClassifiedAd ad2 = new ClassifiedAd();
ad2.Category = "Help Wanted";
ad2.NumberOfWords = 80;
// Display information about the ClassifiedAd objects
Console.WriteLine("Classified Ad 1:");
Console.WriteLine($"Category: {ad1.Category}");
Console.WriteLine($"Number of Words: {ad1.NumberOfWords}");
Console.WriteLine($"Price: ${ad1.Price}");
Console.WriteLine("\nClassified Ad 2:");
Console.WriteLine($"Category: {ad2.Category}");
Console.WriteLine($"Number of Words: {ad2.NumberOfWords}");
Console.WriteLine($"Price: ${ad2.Price}");
}
}
```
1. ClassifiedAd Class:
- This class represents a classified advertisement with three fields: `category`, `numberOfWords`, and a private field `price` (which is calculated internally).
- Properties:
- `Category`: This property has both a getter (`get`) and a setter (`set`) to allow getting and setting the category of the advertisement.
- `NumberOfWords`: Similarly, this property has both a getter and a setter for getting and setting the number of words in the advertisement.
- `Price`: This property only has a getter (`get`). It calculates the price based on the number of words (`numberOfWords * 0.09`), where each word costs nine cents.
2. TestClassifiedAd Class:
- This is the main application class that demonstrates the use of `ClassifiedAd` objects.
- Main Method:
- It instantiates two `ClassifiedAd` objects (`ad1` and `ad2`) and assigns values to their properties (`Category` and `NumberOfWords`).
- It then prints out information about each `ClassifiedAd` object:
- Displays the category using `ad1.Category` and `ad2.Category`.
- Displays the number of words using `ad1.NumberOfWords` and `ad2.NumberOfWords`.
- Displays the calculated price using `ad1.Price` and `ad2.Price`.
3. Execution:
- When you run the `TestClassifiedAd` application, it will output the category, number of words, and price for each of the two `ClassifiedAd` objects that were instantiated and configured.
4. Purpose:
- This code demonstrates basic object-oriented principles such as encapsulation (using properties to access fields), calculation within properties, and object instantiation and usage in a simple console application.
Overall, the `ClassifiedAd` class encapsulates the data and behavior related to a classified advertisement, and the `TestClassifiedAd` application showcases the instantiation and usage of these objects with specific examples.
Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:
This question is incomplete. The complete question is given below:
Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:
A
ABA
ABCBA
ABCDCBA
Answer:
#include <stdio.h>
void printTri(char asciiCharacter){
// Row printer
// for(int i = 65; i <= ((int)asciiCharacter); i++){
int i = 65;
while(i <= ((int)asciiCharacter)){
int leftMargin = ((int)asciiCharacter) - i; +
int j = 1;
while(j <= leftMargin){
printf(" ");
j++;
}
int k = 65;
while(k < ((int)i)){
printf("%c",(char)k);
k++;
}
int l = ((int)i);
while(l >= 65){
printf("%c",(char)l);
l--;
}
printf("\n");
i++;
}
}
int main()
{
for(;;){
printf("Please enter a character between A and Z. Enter (!) to exit \n");
char in;
// scanf("%c",&in);
in = getchar();
getchar();
printf("Printing Triangle for: %c \n",in);
if(((int)in) >= 65 && ((int)in) <= 90){
printTri(in);
printf("\n");
}else if(((int)in) == 33){
break;
} else {
continue;
}
}
return 0;
}
Explanation:
Inside the printTri function, print spaces, characters in order as well as characters in reverse order.Inside the main function, take the character as an input from user then print the triangle by validating first to ensure that the character lies between a to z alphabets.Write a program that fills half the canvas with circles in a diagonal formation.
Have Tracy draw circles along the width of the canvas on the bottom row. Have the number of circles decrease by 1 on each iteration until there is only 1 circle on the top row.
Answer:
Explanation:
function draw()
{
var ctx = document.getElementById("myCanvas").getContext("2d");
var counter = 0;
for (var i=0;i<6;i++)
{
for (var j=0;j<6;j++)
{
//Start from white and goes to black
ctx.fillStyle = "rgb(" + Math.floor(255-42.5*i) + "," + Math.floor(255-42.5*i) +
"," + Math.floor(255-42.5*j) + ")";
ctx.beginPath();
if (i === counter && j === counter)
{
//creates the circles
ctx.arc(25+j*50,30+i*50,20,0,Math.PI*2,true);
ctx.fill();
//creates a border around the circles so white one will be vissible
ctx.stroke();
}
}
counter++;
}
}
draw();
If 2 bits of a byte are in error when the byte is read from ECC memory, can ECC detect the error? Can it fix the error?
Answer:
Explanation:
Error-correcting code memory (ECC memory) these kinds of memories can detect and correct errors but only in single bit of the byte, in this case, if there is more than one bit, for example, two bits, the ECC memory can detect the error but cannot fix it, there are some memories without ECC can detect errors but not correct it.
Write a loop that prints each country's population in country_pop. Sample output with input: 'China:1365830000,India:1247220000,United States:318463000,Indonesia:252164800': United States has 318463000 people. India has 1247220000 people.
Answer:
Hi there! This question is good to check your understanding of loops. To illustrate, I have implemented the answer in Python and explained it below.
Explanation:
Assuming user input for the country and population list as provided in the question, we can write the python script "country_pop.py" and run it from the command line. First we prompt user for the input, after which we split the country-population list which is separated or delimited with a comma into an array of country-population list. We then create a hash of country and its corresponding population by further splitting the country-population combo into a hash, and finally, printing the resultant hash as the output.
country_pop.py
def add_country_pop(country, population):
countrypop_hash[country]=population
countrypop_hash = {}
input_string = input("Enter country population list: ")
print(input_string)
countrypop_array = input_string.split(",")
for country in countrypop_array:
country_pop = country.split(':')
pop_country = country_pop[0]
population = country_pop[1]
add_country_pop(pop_country, population)
print(country + ' has ' + population + ' people')
Output
> country_pop.py
Enter country population list: China:1365830000,India:1247220000,United States:318463000,Indonesia:252164800
China:1365830000,India:1247220000,United States:318463000,Indonesia:252164800
China:1365830000 has 1365830000 people
India:1247220000 has 1247220000 people
United States:318463000 has 318463000 people
Indonesia:252164800 has 252164800 people
Answer:user_input = input()
entries = user_input.split(',')
country_pop = {}
for pair in entries:
split_pair = pair.split(':')
country_pop[split_pair[0]] = split_pair[1]
# country_pop is a dictionary, Ex: { 'Germany':'82790000', 'France':'67190000' }
for country,pop in country_pop.items():
print(f'{country} has {pop} people.')
Explanation:
List three types of technical information sources that an IS professional might use when researching a new storage technology and selecting specific products that incorporate that technology. Which information?
Answer:
The three types of technical information sources are:
Vendor and manufacturer Web sites.
Technology-oriented Web sites and publications.
Professional society Web sites.
Explanation:
Professional society Web sites provide most unbiased information.
These professional social websites are non profit companies as opposed to other sources of information that are profit making.
Social websites provides with the information that can help their members in a best way about getting information of their interest. This is done in an unbiased way because they do not work for some specific organizations or companies that want to sell their products or services.
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 200. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 16, print:16 32 64 128 import java.util.Scanner;public class InsectGrowth {public static void main (String [] args) {int numInsects;Scanner scnr = new Scanner(System.in);numInsects = scnr.nextInt(); // Must be >= 1/* Your solution goes here */}}
Answer:
The below code is pasted in the place of "/*Your solution goes here */"
while(numInsects<200) // while loop
{
System.out.print(numInsects+" "); // print statement
numInsects=numInsects*2; // operation to print double.
}
Output:
If the user gives inputs 16 then the output is 16 32 64 128.If the user gives inputs 25 then the output is 25 50 100.Explanation:
The above code is in java language in which the code is pasted on the place of "Your solution" in the question then only it can work.Then the program takes an input from the user and prints the double until the value of double is not 200 or greater than 200.In the program, there is while loop which checks the value, that it is less than 200 or not. If the value is less the operation is performed otherwise it terminates.Using Python 3 programming, the code blocks below displays the required instructions. The program goes thus :
numInsects = int(input())
#takes input from the user on the number of insects
while numInsects < 200 :
#while loop checks if variable is below 200
print(numInsects, end=' ')
#displays the value with the cursor remaining on the same line
numInsects*=2
print(numInsects)
Learn more : https://brainly.com/question/12483071
Search engines do not search the entire Web every time a user makes a search request, for all the following reasons EXCEPT a. It would take longer than the user could wait. b. The Web is too complex to be searched each time. c. It is more efficient to use pre-stored search results. d. Most users are not interested in searching the entire Web.
Answer:
Option C.
Explanation:
Search engine use of pre-stored search that results is not mostly accurate.
Search engines shouldn't search the whole Internet each time when user requests for a search because It might be taken more time than the user might have expected and Many users were not involved in exploring the whole Internet.
What is virtualization? What are the benefits we can have with it?
Explanation:
Virtualization can be defined as a virtual or software-based representation of virtual applications, storage, network and servers. Through this process it is possible to run a variety of different operating systems on the same physical server at the same time, which reduces information technology expenses, increases the speed and agility of the systems.
Some of the benefits of virtualization are:
Reduced hardware costsEasy backup and restoration of complete servers Reduction of electricity consumptionFaster deployment of new machinesWrite a function max_magnitude() with two integer input parameters that returns the largest magnitude value. Use the function in a program that takes two integer inputs, and outputs the largest magnitude value.
Ex: If the inputs are:
5 7
the function returns:
7
Ex: If the inputs are:
-8 -2
the function returns:
-8
Note: The function does not just return the largest value, which for -8 -2 would be -2. Though not necessary, you may use the absolute-value built-in math function.
Your program must define and call a function:
int MaxMagnitude(int userVal1, int userVal2)
code------------------------
#include
using namespace std;
/* Define your function here */
int main() {
/* Type your code here */
return 0;
}
Answer:
def max_magnitude(user_val1, user_val2):
if abs(user_val1) > abs(user_val2):
return user_val1
else:
return user_val2
if __name__ == '__main__':
n1 = int(input("Enter the first integer number: "))
n2 = int(input("Enter the second integer number: "))
print("The largest magnitude value of", n1, "and", n2, "is", max_magnitude(n1, n2))
Explanation:
A ________ is a software application that can be used to locate and display Web pages, including text, graphics, and multimedia content. Group of answer choices proxy server Webcam keylogger Webmaster Web browser
Answer:
"Web browser" is the correct answer for the above question.
Explanation:
A web browser is a software of the computer system which is used to display the page of the internet which is also called the website.It can help to display because it interprets the HTML language and the network pages or websites are written in the form of HTML language.There are so many examples of web browsers, like safari, chrome e.t.c.The above question asked about the software which is used to display the content of the website which is a web browser. Hence web browser is the correct answer while the other option is not correct because:-The webcam is used to capture the image, the keylogger is used for security and the webmaster is not used in the client machine.How can this be accomplished by Universal Containers?
Universal containers wants to provide a different view for its users when they access an Account record in Salesforce1 instead of the standard web version.
A. By adding a mobile layout and assigning it to a profile.
B. By adding quick actions in the publisher section
C. By adding actions in the Salesforce1 action bar section.
D. By adding Visualforce page to the mobile cards section.
Answer:
Option A and Option D are the correct options.
Explanation:
They decided to allow their users with a different perspective when viewing a Salesforce1 transaction records rather than the specific web edition. So, they accomplish the following scenario by adding and allocating a Mobile Design to a profile and by adding the following page to the mobile card section.
Write programs to insert, delete, and locate an element on a sorted list using a. array, b. pointer, and c. cursor implementations of lists. What is the running time of each of your programs?
Answer:
a) with Array
class array{
int arrA[MAX],location,item,nA;
int arrB[MAX],nB;
int arr_merge[MAX+MAX],nM;
public:
array(){
location=0;item=0;nA=0;
nB=0;nM=0;
}
void init(); //initial data assignment
void traverse(); //process is display (assumed)void insert();
void del();
void search();
void sort();
void merge();
};
void array :: del(){
clrscr();
int i;
cout<<"\n\n*****Deleting Element*****\n";
if(nA < 0){
cout<<"\nArray is Empty\nDeletion Not Possible\n";
goto end;
}
cout<<"\nEnter Location of deletion : ";
cin>>location;
location--;
if(location<0 || location>=nA)
{
cout<<"\n\nInvalid Position\n";
goto end;
}
cout<<"\nItem deleted is : "<<arrA[location];
for(i=location;i<nA;i++){
arrA[i] = arrA[i+1];
}
arrA[nA-1]=0;
nA--;
end:
getch();
}
void array :: search(){
clrscr();
int i,found=-1;
cout<<"\n\n*****Searching Element*****\n";
cout<<"\nEnter Item value to be search : ";
cin>>item;
for(i=0;i<nA;i++){
if(arrA[i] == item){
found=i+1;
break;
}
}
if(found==-1)
cout<<"\nSearch NOT FOUND\n";
else
cout<<"\nSearch is FOUND at "<<found<<" location\n";
getch();
}
void array :: sort(){
clrscr();
int i,j,temp;
cout<<"\n\n*****Sorting Element*****\n";
for(i=0;i<nA;i++){
for(j=i;j<nA;j++){
if(arrA[i] > arrA[j]){
temp = arrA[i];
arrA[i] = arrA[j];
arrA[j] = temp;
}
}
}
cout<<"\nData are Sorted\n";
getch();
}
// b) with pointer
#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <alloc.h>
void main()
{
char *a[10],dum[10],s;
int i,k,j,n;
clrscr();
printf("enter the no of std....");
scanf("%d",&n);
printf("enter the name of students ");
for(k=0;k<n;k++)
scanf("%s",a[k]);
for(i=1;i<n;i++)
{
for(j=1;j<n-i;j++)
{if(strcmp(a[j-1],a[j])>0)
{strcpy(*dum,*a[j-1]);
strcpy(*a[j-1],*a[j]);
strcpy(*a[j],*dum);
}
} }
for(i=0;i<n;i++)
printf("%s",a[i]);
getch();
}
c) with cursor implementations of lists.
#include<stdio.h>
#include<stdlib.h>
typedef struct Node
{
int data;
struct Node *next;
}node;
void insert(node *pointer, int data)
{
/* Iterate through the list till we encounter the last node.*/
while(pointer->next!=NULL)
{
pointer = pointer -> next;
}
/* Allocate memory for the new node and put data in it.*/
pointer->next = (node *)malloc(sizeof(node));
pointer = pointer->next;
pointer->data = data;
pointer->next = NULL;
}
int find(node *pointer, int key)
{
pointer = pointer -> next; //First node is dummy node.
/* Iterate through the entire linked list and search for the key. */
while(pointer!=NULL)
{
if(pointer->data == key) //key is found.
{
return 1;
}
pointer = pointer -> next;//Search in the next node.
}
/*Key is not found */
return 0;
}
void delete(node *pointer, int data)
{
/* Go to the node for which the node next to it has to be deleted */
while(pointer->next!=NULL && (pointer->next)->data != data)
{
pointer = pointer -> next;
}
if(pointer->next==NULL)
{
printf("Element %d is not present in the list\n",data);
return;
}
/* Now pointer points to a node and the node next to it has to be removed */
node *temp;
temp = pointer -> next;
/*temp points to the node which has to be removed*/
pointer->next = temp->next;
/*We removed the node which is next to the pointer (which is also temp) */
free(temp);
/* Beacuse we deleted the node, we no longer require the memory used for it .
free() will deallocate the memory.
*/
return;
}
void print(node *pointer)
{
if(pointer==NULL)
{
return;
}
printf("%d ",pointer->data);
print(pointer->next);
}
}
Running Time:
a) 2 minute
b) 1 minutes
c) 1 & half minutes
Explanation:
a) Initialize the array and traverse it by using for loop. Sort the array with the help of a temporary variable.
b) Declare a pointer to the array and take the input from user using for loop.
c) Declare a Structure containing an integer and a pointer. Iterate through the list, allocate memory for the new node and insert the data in it.
A palindrome is a word or phrase that reads the same both backward and forward. The word ""racecar"" is an example. Create an algorithm (sequence of steps) to determine if a word or phrase is a palindrome. Try several different words or phrases to ensure your algorithm can detect the existence of a palindrome properly.
Answer:
Algorithm for the above problem:
Take a string from the user input.store the input string on any variable.Reverse the string and store it on the other variable.Compare both strings (character by character) using any loop.If all the character of the string matched then print that the "Input string is a palindrome".Otherwise, print "The inputted string is not a palindrome."Output:
If the user inputs "ababa", then it prints that the "Input string is palindrome"If the user inputs "ababaff", then it prints that the "Input string is not palindrome"Explanation:
The above-defined line is a set of an algorithm to check the number is palindrome or not.It is defined in English because the algorithm is a finite set of instructions written in any language used to solve the problem. The above algorithm takes input from the user, compare that string with its reverse and print palindrome, if the match is found.Assume that the data on a worksheet consume a whole printed page and two columns on a second page. You can do all of the following except what to force the data to print all on one pageIncrease the left and right margins.
Answer:
Increase the left and right margins.
Explanation:
Microsoft Excel is a spreadsheet application package from the Microsoft office package. It is a tool used for analysing and cleaning and/or organising information.
It's worksheets are made of cells located by columns or fields and rows or records. A collection of worksheets is called a workbook. An Excel file can be printed after use.
When a print layout is viewed and printed, and columns of the file is printed on another page. To avoid this, reduce the size of the columns and the size of the left and right margins and also decrease the scale value and change to a bigger paper printer size if required.
If data from a DOS system is electronically sent to an EHR or other Windows-based system via an interface to populate an indexed data field in the EHR, after the data is in the EHR is it structured or unstructured?
Answer:
yes ! you can see below.
Explanation:
EHR is a health record of a patient that gives information about the patient and securely authorized it. Electronic Health record allows medical professionals to enter data and update a new encounter.
DOC is a document used by Microsoft. DOC file is a file that contains formatted text, images, tables, graphs, and charts, etc.
Unstructured data is data that can be entered in free text format. Structured information is a type of data contain check boxes, images table, and other the user chooses from the given option.
As the DOC system contain free text format, then data in the EHR is structured.
The data sent from a DOS system to an EHR and populating an indexed field is typically considered structured data. EHR systems play a critical role in maintaining accessible and secure patient records, improving healthcare quality and efficiency while safeguarding privacy.
If data from a DOS system is electronically sent to an EHR (Electronic Health Record) or other Windows-based system via an interface to populate an indexed data field in the EHR, the data can be either structured or unstructured depending on the format it is sent and how it is handled by the receiving system. In this context, if the data populates a specific field within the EHR, it is typically considered to be structured data because it is organized in a predefined manner, making it easily searchable and analyzable within the system.
EHR systems are essential for maintaining accurate and accessible patient records. They ensure that in the event of a disaster, such as a hurricane, health information can be retrieved due to effective data backup solutions. Additionally, because EHRs are designed to be shared securely among healthcare providers, they facilitate improved coordination of care.
Overall, the transformation from paper-based records to EHRs serves to enhance the quality and efficiency of healthcare delivery, while also maintaining the privacy and security of personal health information under federal laws such as HIPAA.
I need help in creating a Java Program; To calculate the chapter from which you solve the programming exercise, below are the requirements;
• Divide the integer number representing your student ID by 4, consider the remainder and increment it by 2. The result you obtain represents the chapter number, and it should be either 2, 3 , 5 or 6.
* Depending on the chapter number obtained above, consider the following rules in calculating the problem number to solve:
• If the chapter number is 2, divide your student ID by 23, consider the remainder and increment it by 1. The result you obtain represents the number of the programming exercise you will solve for online discussions, which should be from chapter 2.
• If the chapter number is 3, divide your student ID by 34, consider the remainder and increment it by 1. The result you obtain represents the number of the programming exercise you will solve for online discussions, which should be from chapter 3.
• If the chapter number is 4 (you need to go to chapter 6), divide your student ID by 38, consider the remainder and increment it by 1. The result you obtain represents the number of the programming exercise you will solve for online discussions, which should be from chapter 6.
• If the chapter number is 5, divide your student ID by 46, consider the remainder and increment it by 1. The result you obtain represents the number of the programming exercise you will solve for online discussions, which should be from chapter 5.
*After calculating the number of the chapter, and the number of the programming exercise to solve, ask the user to enter the page number where the specific problem is located in the textbook. Display the requirement for the programming exercise using the following format: "Please solve programming exercise … (include here the number of the exercise) from chapter … (include here the number of the chapter), from page … (include here the page number)."
Answer:
public static void main(String[] args)
{
int studentnumber = 123456;
int divisor = 0;
int chapter = (studentnumber%4)+2;
switch(chapter) {
case 2:
divisor = 23;
break;
case 3:
divisor = 34;
break;
case 4:
divisor = 38;
break;
case 5:
divisor = 46;
break;
}
int exercise = (studentnumber % divisor) + 1;
System.out.printf("Studentnumber %d divided by 4 plus 2 is chapter %d.\n", studentnumber, chapter);
System.out.printf("Studentnumber %d divided by %d is exercise %d.", studentnumber, divisor, exercise);
}
Explanation:
Above is just a bit of code to get you started with the first part. Hope you can figure out the rest.
In BitTorrent, if Alice provides chunks to Bob throughout a 30-second interval, Bob will return the favor and provide chunks to Alice in the same interval only if she is one of the top four neighbors to Bob during this interval.
True or False?
False, as it is not necessary for Bob to return the chunks to Alice in the same interval in Bit Torrent.
Explanation:
This can be done, if Alice is at the top neighbors list of Bob.Then Bob needs to send a message to Alice.This scenario can occur even if Alice not provide the chunks in the 30 second interval to BobHence, the answer for the given question might be False. As this is a case of may or may not happen.Create a new program called Time.java. From now on, we won’t remind you to start with a small, working program, but you should. 2. Following the example program in Section 2.4, create variables named hour, minute, and second. Assign values that are roughly the current time. Use a 24-hour clock so that at 2pm the value of hour is 14. 3. Make the program calculate and display the number of seconds since midnight. 4. Calculate and display the number of seconds remaining in the day. 5. Calculate and display the percentage of the day that has passed. You might run into problems when computing percentages with integers, so consider using floating-point. 6. Change the values of hour, minute, and second to reflect the current time. Then write code to compute the elapsed time since you started
Answer:
Explanation:
public class time {
public static void main (String[]args) {
//Step 1 we declare the variables
int hours, minutes, seconds;
hours = 17;
minutes = 12;
seconds = 00;
//For checking
System.out.println(hours+":"+minutes+":"+seconds);
//Step 2 we make the operation for the seconds since midnight
int secSinceMidNite;
secSinceMidNite = ((hours*60)+minutes)*60 + seconds;
System.out.println("Seconds since midnight = "+secSinceMidNite);
//Step 3 we make the operation for the seconds remaining in day
int secRemainingInDay, totalSecInDay;
totalSecInDay = 24*60*60;
secRemainingInDay = totalSecInDay - secSinceMidNite;
System.out.println("Seconds remaining in day = "+secRemainingInDay);
//Step 4 in the operation for percentage of day that has passed
int percentOfDayPassed;
percentOfDayPassed = (secSinceMidNite*100)/totalSecInDay;
System.out.println("Percentage of day that has passed = " +percentOfDayPassed+"%");
}
}