What is the area of this figure? Enter your answer in the box. units² points on graph are (-2,3) (-4,5) (-5,3) (-3,-3) (4,-3) (3,4) (4,3) WILL MARK BRAINLIEST 50 POINTs

Answer:

Parallel lines do not intersect therefore the system of equations cannot have any solution. Therefore there no solutions to the given system of equations.

Step-by-step explanation:

Aaron and Blake both wrote down equation. Their equation has the same slope, But Aaron's y-intercept was negative and Blake's y-intercept was positive.

Therefore both equations will represent lines that are parallel.

Parallel lines do not intersect therefore the system of equations cannot have any solution.

Answer:

19

Step-by-step explanation:

If the scientist chooses 60 random eggs then the overall probability of selecting yellow eggs is 32%. So, there's a chance of he randomly collecting 60 eggs out of which 19 could be yellow.

(60/100) x 32 ~ 19...

The usual number of yellow dragon eggs expected in a sample of 60, given a 32% probability, is 19 when rounded to the nearest whole number.

The question at hand involves finding the expected number of yellow eggs in a sample size of 60, given a known probability of a yellow egg occurrence.

Since we know that 32% of the dragon eggs on planet Pern are yellow, we can calculate the usual number of yellow eggs in the samples by multiplying the sample size (60 eggs) by the probability of getting a yellow egg (0.32).

Therefore, the expected or usual number of yellow eggs in the sample would be 60 × 0.32 = 19.2.

Considering that we cannot have a fraction of an egg, the usual number of yellow eggs in samples of 60 eggs would typically be rounded to the nearest whole number, which is 19.

Final answer:

To calculate the number of floors a building can have for a given height, use the formula 'Number of Floors = h / 12', where 'h' is the total building height in feet and each floor is 12 feet tall.

Explanation:

To write an expression for the number of floors a building can have for a given building height, where each floor is 12 feet tall, we use the following formula:

Number of Floors = Total Building Height (in feet) / Height of One Floor (in feet)

Let 'h' represent the total height of the building in feet. Then the expression becomes:

Number of Floors = h / 12

For example, if a building has a height of 384 feet, the number of floors can be calculated as 384 feet / 12 feet per floor = 32 floors.

Answer:

5.42 hours

Step-by-step explanation:

Let x represent time taken to complete 300 miles.

We have been given that Bryce a previous winner of the contest, made a trip of 360 miles in a 6.5 hours.

We will use proportions to solve our given problem since rates are same for both distances.

[tex]\frac{\text{Distance covered}}{\text{Time taken}}=\frac{360\text{ Miles}}{6.5\text{ Hours}}[/tex]

Upon substituting our given values in above proportion, we will get:

[tex]\frac{300\text{ Miles}}{x}=\frac{360\text{ Miles}}{6.5\text{ Hours}}[/tex]

Cross multiply:

[tex]x\cdot 360\text{ Miles}=300\text{ Miles}\times6.5\text{ Hours}}[/tex]

[tex]x=\frac{300\text{ Miles}\times6.5\text{ Hours}}{ 360\text{ Miles}}[/tex]

[tex]x=\frac{300\times6.5\text{ Hours}}{360}[/tex]

[tex]x=5.41666\text{ Hours}\approx 5.42\text{ Hours}[/tex]

Therefore, it will take approximately 5.42 hours to travel additional 300 miles.

Answer:

  $30.88

Step-by-step explanation:

The account value is given by ...

  A = P(1 +r/n)^(nt)

where P is the principal invested, r is the annual interest rate, t is the number of years, n is the number of times interest is compounded per year.

The amount of interest earned is the account value less the initial investment:

  I = A - P = P(1 +r/n)^(nt) -P  = P((1 +r/n)^(nt) -1)

Filling in the given values, we get ...

  I = 500((1 +.03/12)^(12·2) -1) = 500(1.0025^24 -1) ≈ $30.88

The amount of interest earned is $30.88.

Answer:

Step-by-step explanation:

Given that  a school has 20 classes: 16 with 25 students in each, three with 100 students in each, and one with 300 students for a total of 1000 students.

a) Y = no of students in the class out of 20 selected at random

Y can take values as

Y          25     100    300   Total

freq      16        3          1       20

P(Y)     16/20   3/20   1/20     1

y*p      20        15       15       50

E(Y) = 50

b) X = size of student from which one student is taken at random

X                                    25       100    300     Total

No of classes                16           3         1         20

Total students          

(X*no of classes)           400    300    300     1000

P(x)                                 0.4      0.3       0.3          1

X*P                                 160       90      90       240

E(x) =240

c)   On an average,   a student at this school is in a class with 240 students. On average, a class at this school has 50 students.

i.e. expectation of number of students in a class is 50 while expectation of a student having students in the class is 240  

The volume of the square prism with a side of base decreasing at a rate of 7 km/min and height increasing at 10 km/min is decreasing at a rate of 344 cubic km/min.

In this problem, we're dealing with rates of change and the geometric properties of a square prism. A square prism can be characterized by the side length of its base (we'll call this length 's') and its height (h). The volume (V) of a square prism is given by the equation V = s^2 * h. We're told that the side length s is decreasing at a rate of 7 kilometers per minute (ds/dt = -7 km/min) and the height h is increasing at a rate of 10 kilometers per minute (dh/dt = 10 km/min).

To find the rate at which the volume is changing with respect to time, we can take the derivative of the volume equation with respect to time. Thus, dV/dt = 2*s*ds/dt*h + s^2*dh/dt. Substituting the given values, when s = 4 km and h = 9 km, we find: dV/dt = 2*4*(-7)*9 + 4^2*10 = -504 + 160 = -344 cubic kilometers per minute. Therefore, at the given instant, the volume of the square prism is decreasing at a rate of 344 cubic kilometers per minute.

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The rate of change of the surface area of the prism at that instant is -204 square kilometers per minute. Correct Option is Option C.

To solve this problem, let's first start by identifying the formula for the surface area (SA) of a square prism, which is given as [tex]2s^2 + 4sh[/tex] , where s is the side of the base and h is the height.

Now, let's find the rate of change of the surface area with respect to time, dSA/dt. We'll use the chain rule to differentiate the surface area formula:

1. Differentiate the given surface area formula:

[tex]SA = 2s^2 + 4sh[/tex]

[tex]d(SA)/dt = d(2s^2)/dt + d(4sh)/dt[/tex]

2. Apply the chain rule:

d(SA)/dt = 2 * 2s * (ds/dt) + 4 * (s * (dh/dt) + h * (ds/dt))

3. Plug in the given values: s = 4 km, ds/dt = -7 km/min, h = 9 km, dh/dt = 10 km/min:

d(SA)/dt = 4 * 4 * (-7) + 4 * (4 * 10 + 9 * (-7))

d(SA)/dt = -112 + 4 * (40 - 63)

d(SA)/dt = -112 + 4 * (-23)

d(SA)/dt = -112 - 92

d(SA)/dt = -204

The rate of change of the surface area of the prism at that instant is -204 square kilometers per minute. Correct Option is Option C.

Complete Question:- The side of the base of a square prism is decreasing at a rate of 7 kilometers per minute and the height of the prism is increasing at a rate of 10 kilometers per minute. At a certain instant, the base's side is 4 kilometers and the height is 9 kilometers. What is the rate of change of the surface area of the prism at that instant (in square kilometers per minute)? Choose 1 answer: A 204 B 148 C -204 D -148 The surface area of a square prism with base side 8 and height h is [tex]2s^2+4sh.[/tex]

Final answer:

The chicken quesadilla contains a total of 542 kilocalories, which is derived by summing the caloric contributions from protein, carbohydrate, and fat.

Explanation:

To calculate the number of kilocalories in a chicken quesadilla with 28 grams of protein, 40 grams of carbohydrate, and 30 grams of fat, we use the known caloric values for each macronutrient. Protein and carbohydrate each have 4 Calories per gram, while fat has 9 Calories per gram.

Protein: 28 grams × 4 Calories/gram = 112 Calories

Carbohydrate: 40 grams × 4 Calories/gram = 160 Calories

Fat: 30 grams × 9 Calories/gram = 270 Calories

Adding up these amounts, we have:

112 Calories (from protein) + 160 Calories (from carbohydrate) + 270 Calories (from fat) = 542 Calories

To convert Calories into kilocalories, we remember that 1 kilocalorie = 1 Calorie. Therefore, the chicken quesadilla contains 542 kilocalories.

Answer:

Option A) 1.68                

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

p = 15% = 0.15

Number of bags overfilled , x = 21

First, we design the null and the alternate hypothesis  

[tex]H_{0}: p = 0.15\\H_A: p > 0.15[/tex]

Formula:

[tex]\hat{p} = \dfrac{x}{n} = \dfrac{21}{100} = 0.21[/tex]

[tex]z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}[/tex]

Putting values, we get,

[tex]z = \dfrac{0.21-0.15}{\sqrt{\dfrac{0.15(1-0.15)}{100}}}\\\\z = 1.68[/tex]

Thus, the correct answer is

Option A) 1.68

To test the hypothesis H0: p = 0.15 versus Ha: p > 0.15, the test statistic is Z = 1.68.

To test the hypothesis H0: p = 0.15 versus Ha: p > 0.15, where p is the true proportion of overfilled bags, we can use the test statistic Z. The formula for the test statistic is Z = (P' - p) / √(p(1-p) / n), where P' is the sample proportion, p is the hypothesized proportion, and n is the sample size.

In this case, the sample proportion P' = 21/100 = 0.21, the hypothesized proportion p = 0.15, and the sample size n = 100.

Plugging these values into the formula, we get Z = (0.21 - 0.15) / √(0.15(1-0.15) / 100) = 1.68.

Therefore, the test statistic is Z = 1.68.

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Answer:

10cm/s²

Step-by-step explanation:

Acceleration is the change in velocity of an object with respect to time.

Given velocity v(x) to be x³-2x+6

Acceleration = ∆v/∆x

Differentiating the velocity function to get acceleration we have,

Acceleration = dv/dt = 3x²-2

Acceleration of the particle at x = 2 will give;

dv/dt @ x = 2 is 3(2)²-2

= 12-2 = 10cm/s²

Answer: The answer is Correlation because its a connection between 2 or more things, or interdependence of variable quantities. Plus its in the definition, it says the process of establishing a relationship or connection between 2 or more measures.

Answer:

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r/n)^ nt

Where

A represents the value after t years.

n represents the period for which the decrease in value is calculated

t represents the number of years.

P represents the value population.

r represents rate of decrease.

From the information given,

P = 23000

r = 8% = 8/100 = 0.08

n = 1

Therefore, the exponential decay function described in this situation is

A = 23000(1 - 0.08/n)1)^ 1 × t

A = 23000(0.92)^t

If A = 15000, then

15000 = 23000(0.92)^t

0.92^t = 15000/23000 = 0.6522

Taking log of both sides to base 10

Log 0.92^t = log 0.6522

tlog 0.92 = log 0.6522

- 0.036t = - 0.1856

t = - 0.1856/- 0.036

t = 5 years to the nearest year

The value of the car will be $15,000 after approximately 4 years.

To model the situation with an exponential decay function, we use the formula:

[tex]\[ V(t) = P \times (1 - r)^t \][/tex]

Given that the initial cost [tex]P[/tex] is $23,000 and the annual depreciation rate r is  8%, or 0.08 in decimal form, we can write the exponential decay function as:

[tex]\[ V(t) = 23000 \times (1 - 0.08)^t \][/tex]

[tex]\[ V(t) = 23000 \times (0.92)^t \][/tex]

To find out when the value of the car will be $15,000, we set [tex]V(t)[/tex] equal to $15,000 and solve for t.

[tex]\[ \frac{15000}{23000} = (0.92)^t \][/tex]

[tex]\[ 0.652173913043478 = (0.92)^t \][/tex]

Using a calculator, we find:

[tex]\[ t \approx \frac{\ln(0.652173913043478)}{\ln(0.92)} \approx 4.037 \][/tex]

Since we are looking for the time in whole years, we round to the nearest year:

[tex]\[ t \approx 4 \][/tex]

 Therefore, the value of the car will be $15,000 after approximately 4 years.

Answer:

[tex]\frac{3}{8}[/tex]  of a box of candy your friend eat.

Step-by-step explanation:

Given:

You and your friend are going to some candy.

You eat 3/4 of a box of candy.

Your friend eats 1/2 as much as you do.

Now, to find that how much of a box of candy does your friend eat.

Quantity of a box of candy you eat = [tex]\frac{3}{4}[/tex]

Quantity of candy your friend eat = [tex]\frac{1}{2} \ of\ \frac{3}{4}[/tex]

Now, to get how much the candy your friend eat we multiply 1/2 and 3/4:

= [tex]\frac{1}{2} \times \frac{3}{4}[/tex]

= [tex]\frac{3}{8}[/tex] .

Therefore, [tex]\frac{3}{8}[/tex]  of a box of candy your friend eat.

Answer:

75% increase

Step-by-step explanation:

Given:

Number of missed days of work before the management change = 4

Number of missed days of work after the management change = 7

So, increase in the number of missed days of work is given by subtracting the old number from the new number and is equal to:

Increase in missed number of days = 7 - 4 = 3 days

Now, the percent of this increase is calculated by dividing the increase by the old number and then multiplying the result by 100.

Percent of increase is given as:

[tex]Percent\ of\ increase=\frac{Increased\ value}{Old\ value}\times 100\\\\Percent\ of\ increase=\frac{3}{4}\times 100\\\\Percent\ of\ increase=0.75\times 100\\\\Percent\ of\ increase=75\%[/tex]

So, there is a 75% increase in the number of missed days of work after the change in the management.

Answer: $135.42

Step-by-step explanation:

Based on IRS tables, Mary is expected to receive 192 (16 years x 12 months) annuity payments. Her investment in the annuity is $70,000 and her return of capital for each annuity payment is $70,000/192 = $364.58. The return of capital portion of each annuity payment is not taxable (not included in gross income). Mary must include the excess received ($500.00 – 364.58) of $135.42 in her gross income.

To calculate how much of the first $500 payment Mary will include in her gross income, we need to determine the exclusion ratio. The exclusion ratio is the ratio of the investment in the annuity to the expected return. In this case, Mary will include $36.45 of the first $500 payment in her gross income.

To determine how much of the first $500 payment Mary will include in her gross income, we need to calculate the exclusion ratio. The exclusion ratio is the ratio of the investment in the annuity to the expected return. In this case, Mary paid $70,000 for the annuity and her life expectancy is 16 years, so the exclusion ratio is $70,000 / ($500/month * 12 months/year * 16 years) = 0.0729. To determine the amount she will include in her gross income, we multiply the monthly payment by the exclusion ratio: $500 * 0.0729 = $36.45. Therefore, Mary will include $36.45 of the first $500 payment in her gross income.

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Answer:

13π/2 m²/h

Step-by-step explanation:

Volume of a cylinder is:

V = πr²h

If h is a constant, then taking derivative of V with respect to time:

dV/dt = 2πrh dr/dt

Surface area of a cylinder is:

A = 2πr² + 2πrh

Taking derivative with respect to time:

dA/dt = (4πr + 2πh) dr/dt

Given that dV/dt = 10π, V = 80π, and h = 5, we need to find dA/dt.  But first, we need to find r and dr/dt.

V = πr²h

80π = πr² (5)

r = 4

dV/dt = 2πrh dr/dt

10π = 2π (4) (5) dr/dt

dr/dt = 1/4

dA/dt = (4πr + 2πh) dr/dt

dA/dt = (4π (4) + 2π (5)) (1/4)

dA/dt = 13π/2

The surface area of the cylinder is increasing at 13π/2 m²/h.

The required surface area of the cylinder is [tex]\frac{13}{2}[/tex] m²/h.

Given that,

The volume of the cylinder increase with the rate of 10π cubic meters per hour.

The height of the cylinder is fixed at 5 meters.

At a certain instant, the volume is 80π cubic meters.

We have to determine,

What is the rate of change of the surface area of the cylinder at that instant.

According to the question,

Height of cylinder = 5m

Volume of cylinder increase with rate =  10π cubic meters per hour.

At certain instant volume become =  80π cubic meters per hour.

Volume of cylinder is given as,

V = πr²h

Where h is a constant,

[tex]v = \pi r^{2} h\\\\80\pi = \pi r^{2}. (5)\\\\\frac{80\pi }{5\pi } = r^{2} \\\\r^{2} = 16\\\\r = 4[/tex]

Then,  taking derivative of V with respect to time:

[tex]\frac{dv}{dt} = 2\pi rh.\frac{dr}{dt} \\\\[/tex]

Where, dv\dt = 10π, V = 80π, and h = 5,

Then,

[tex]10\pi = 2\pi (4)(5). \frac{dr}{dt} \\\\10\pi = 40\pi \frac{dr}{dt} \\\\\frac{10\pi }{40\pi } = \frac{dr}{dt} \\\\\\\frac{dr}{dt} = \frac{1}{4}[/tex]

Then,

Surface area of a cylinder is define as,

[tex]A = 2\pi r^{2} + 2\pi rh\\\\\ \frac{da}{dt} = (4\pi r + 2\pi h)\frac{dr}{dt} \\\\\frac{da}{dt} = (4\pi (4) + 2\pi (5))\times\frac{1}{4} \\\\\frac{da}{dt} = \frac{26\pi }{4} \\\\\frac{da}{dt} = \frac{13\pi }{2}[/tex]

Hence, The required surface area of the cylinder is [tex]\frac{13}{2}[/tex] m²/h.

For more information about Surface area click the link given below.

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Answer:

20 >= x + y

Step-by-step explanation:

Given:

- The length of garden = x

- The width of the garden = y

- Total fence available = 40 ft

- Rectangular garden

Find:

(a) Write and inequality representing the fact that the total perimeter of thegarden is at most 40 ft.

(b) Sketch part of the solution set for this inequality that represents all possiblevalues for the length and with of the garden.

Solution:

- The perimeter of the rectangular garden is P at most 40 ft:

                              P >= 2*x + 2*y

                              40 >= 2*x + 2*y

                              20 >= x + y

- The sketch of the graph will be all points in the shaded region denoted by the inequality as follows:

                               y =< 20 - x

- See the triangular shaded region.

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since Rick has 40ft of fencing

Then, the perimeter cannot be more than 40ft if he decided to lay the block on a single layer and not on each other

Then if the length is x

And the breadth is y

Perimeter of a rectangle is 2(l+b)

Therefore,

Perimeter is less than or equal to 40ft

2(l+b)  ≤ 40

b.  2(l+b)≤ 40

Then divide both side by 2

l+b≤ 20.

Then l ≤ 20-b

Also, b ≤ 20-l

Check attachment for graph

Answer:

The height of the wall is 52.2 feet.

Step-by-step explanation:

Given:

From the figure shown, HT is the height of Carlos, 'V' is the position of mirror.

So, TV = 4 ft, VS = 36 ft, HT = 5.8 ft.

Let the height of the wall be 'x'. So, JS = 'x'

Now, consider the two triangles HTV and JVS

Statements                                                               Reasons

1. ∠ HTV ≅ ∠ JSV                                           Right angles are congruent

2. ∠ HVT ≅ ∠ JVS                                          Given in the figure

Therefore, ΔHTV and Δ JVS are similar triangles by AA postulate.

Now, from definition of similar triangles, corresponding sides of two similar triangles are in proportion to each other. Therefore,

[tex]\frac{HT}{JS}=\frac{TV}{VS}=\frac{HV}{JV}[/tex]

Considering the first two pair of fractions, we have:

[tex]\frac{5.8}{x}=\frac{4}{36}\\\\36\times 5.8=4\times x\\\\x=\frac{36\times 5.8}{4}\\\\x=9\times 5.8=52.2\ ft[/tex]

Therefore, the height of the wall is 52.2 feet.

Answer:

918

Step-by-step explanation:

Use distributive property.

(810) + (88) + (20) = 918

Answer:

918

Step-by-step explanation: hope it was helpful

Answer:

27° (as an integer)

Step-by-step explanation:

From the figure given;

DC = 8 units

BC = 4 units

We are required to determine m∠D

We need to use the appropriate trigonometric ratio;

In this case, DC is adjacent and BC is opposite to m∠D

Therefore, the appropriate trigonometric ratio is tangent;

That is;

Tan m∠D = BC ÷ DC

               = 4 ÷ 8

               = 0.5

Thus;

m∠D = Tan^-1 (0.5)

        = 26.57

         = 27 (as an integer)

Thus, m∠D is 27°

Answer: the distance from the base of the ladder from the building is 10 feet.

Step-by-step explanation:

The ladder forms a right angle triangle with the wall of the building and the ground.

The length of the ladder represents the hypotenuse of the right angle triangle.

The distance, h of the base of the ladder from the building represents the adjacent side of the triangle.

To determine h, we would apply

the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 60 = h/20

h = 20Cos60 = 20 × 0.5

h = 10 feet

Final answer:

To solve for the distance from the base of the ladder to the building, the cosine function is used because the scenario forms a right-angled triangle with the ground and the wall. By the equation cos(60°) = Base / Hypotenuse, with the ladder being the hypotenuse, the base is calculated to be 10 feet from the building.

Explanation:

The question involves using trigonometry to determine the distance from the base of the ladder to the building. When a ladder makes a 60° angle with the ground and its length is given (20 feet), this forms a right-angled triangle with the ground and the building's wall. To find the distance from the base of the ladder to the building, we can use the cosine function, which relates the adjacent side to the hypotenuse in a right-angled triangle.

Using the equation:

cos(60°) = Base / Hypotenuse

Here, the hypotenuse is the length of the ladder which is 20 feet. Therefore:

cos(60°) = Base / 20 feet

cos(60°) equals 0.5 when calculating in degrees. Consequently:

0.5 = Base / 20 feet

Multiplying both sides by 20 gives:

Base = 20 feet * 0.5

Base = 10 feet

Thus, the base of the ladder is 10 feet from the building.

Answer:

a) Specific volume of the air in balloon is [tex]14.96 ft^3/lbm[/tex]

b)The weight of the air within the balloon is 1,126.09 lbf.

Step-by-step explanation:

Mass of air, m = 35  lbm

Volume of the air = V

Diameter of balloon = d = 10 ft

radius of the balloon = r= 0.5 d = 5 ft

Volume of balloon = V

[tex]V=\frac{4}{3}\pr r^3[/tex]

[tex]V=\frac{4}{3}\times 3.14\times (5 ft)^3[/tex]

Specific volume of the air in balloon = S

[tex]S=\frac{V}{m}=\frac{\frac{4}{3}\times 3.14\times (5 ft)^3}{35 lbm}[/tex]

[tex]S=14.96 ft^3/lbm[/tex]

Specific volume of the air in balloon is [tex]14.96 ft^3/lbm[/tex]

[tex]lbf=32.174 lbm ft/s^2[/tex]

Weight of the air = W

Acceleration due to gravity = [tex]32.174 lbm ft/s^2[/tex]

Weight = m\times g[/tex]

[tex]W=35 lbm\times 32.174 lbm ft/s^2[/tex]

[tex]W=1,126.09 lbf[/tex]

The weight of the air within the balloon is 1,126.09 lbf.

Answer:

  tan(23° -21°) = (tan(23°) -tan(21°))/(1 +tan(23°)tan(21°))

Step-by-step explanation:

The formula for the tangent of the difference of angles is ...

  tan(a-b) = (tan(a) -tan(b))/(1 +tan(a)tan(b))

Filling in the values a=23° and b=21°, you get the formula shown above.

The expression for tan(23°−21°) in terms of the tangents of 23° and 21° is: tan(23°−21°) = (tan 23° - tan 21°) / (1 + tan 23° * tan 21°).

To express tan(23°−21°) in terms of the tangents of 23° and 21°, we can use the angle subtraction formula for tangent, which is:

tan(α - β) = (tan α - tan β) / (1 + tan α * tan β)

Applying this to tan(23°−21°), we get:

tan(23°−21°) = (tan 23° - tan 21°) / (1 + tan 23° * tan 21°)

We can't directly calculate the values from the given table since 23° and 21° are not listed. However, we understand the formula required to express tan(23°−21°) in terms of the tangents of these two angles.

Answer:

Step-by-step explanation:

Let u represent the unit price of the 100 lb container. Then u+.06 is the unit price of the 75 lb container.

The difference in prices is ...

  100u - 75(u+.06) = 55.50

  25u -4.50 = 55.50

  25u = 60

  u = 60/25 = 2.40

The cost of the 100 lb container is 100u = 240. The cost of the 75 lb container is $55.50 less: 240 -55.50 = 184.50.

The 100 lb container costs $240. The 75 lb container costs $184.50.

Answer: The amount she puts in a bag  = 0.912 pound.

Step-by-step explanation:

Given : Amount of red licorice purchased by Christy = 6.75 pounds

Amount of black licorice purchased by Christy  = 2.37 pounds

Total amount of licorice purchased by Christy =  6.75 + 2.37 pounds

= 9.12  pounds

Then, if she divides the total amount into 10 equal-sized bags  , the amount she put in a bag  = (Total amount of licorice purchased) ÷ 10

= 9.12  ÷ 10 = 0.912 pound

Hence, the amount she puts in a bag  = 0.912 pound.

Final answer:

To find how much licorice Christy needs to put into each of 10 bags, add the weights of red and black licorice and then divide by 10. She will need to put 0.912 pounds of licorice into each bag.

Explanation:

Christy purchased 6.75 pounds of red licorice and 2.37 pounds of black licorice. To find the total amount of licorice, we add the weight of the red and black licorice together:

Total weight of licorice = [tex]6.75 pounds + 2.37 pounds = 9.12 pounds.[/tex]

If she divides the total amount into 10 equal-sized bags, we divide the total weight by 10:

Weight per bag = [tex]9.12 pounds / 10 bags = 0.912 pounds per bag.[/tex]

Answer:

Therefore,

[tex]x=9\\\\y=7[/tex]

Step-by-step explanation:

Given:

D,E,F are the midpoints of side AB, BC,and AC such that

AB = 4x - 18

BC = 2x - 4

DF = x

FE = y

To Find:

x = ?

y = ?

Solution:

Midpoint Theorem:

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.  

E and F are Midpoint of Sides BC and AC, then

[tex]FE=\dfrac{1}{2}AB[/tex]        ......By Midpoint Theorem

Substituting the values we get

[tex]x=\dfrac{1}{2}(4x-18)=2x-9\\\\2x-x=9\\\\x=9[/tex]

Similarly,

D and Fare Midpoint of Sides AB and AC, then

[tex]DF=\dfrac{1}{2}BC[/tex]        ......By Midpoint Theorem

Substituting the values we get

[tex]y=\dfrac{1}{2}(2x-4)=x-2\\\\Substitute\ x=9\\\\y=9-2=7[/tex]

Therefore,

[tex]x=9\\\\y=7[/tex]

Answer:

a) 1

b) [tex]\frac{4}{3}[/tex]

c) = 1

Step-by-step explanation:

We are given the following in the question:

[tex]\cos \theta = \dfrac{6}{8}[/tex]

θ is in the IV quadrant.

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\sin \theta = \sqrt{1-\dfrac{36}{64}} = -\dfrac{2\sqrt7}{8}\\\\\tan \theta = \dfrac{\sin \theta}{\cos \theta} = -\dfrac{2\sqrt7}{6}\\\\\csc \theta = \dfrac{1}{\sin \theta} = -\dfrac{8}{2\sqrt7}[/tex]

Evaluate the following:

a)

[tex]\tan \theta\times \cot \theta =\tan \theta\times\dfrac{1}{\tan \theta} = 1[/tex]

b)

[tex]\csc \theta\times \tan \theta\\\\= -\dfrac{8}{2\sqrt7}\times -\dfrac{2\sqrt7}{6} = \dfrac{4}{3}[/tex]

c)

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\text{using the trignometric identity}[/tex]

Answer:

dA/dt = 16 square inches per second

Step-by-step explanation:

Width of rectangle is w

Height of rectangle is h

width = twice height

w = 2h

Area = wh = (2h)*h

A = 2h^2

Differentiating the equation with respect to time

dA/dt = 2+2h dh/dt

dA/dt = 4h dh/dt

According to the given situation when width is 4 inches

h = w/2

h = 2

Rate of change of A is  

dA/dt = wh dh/dt

dA/dt = 4(2)(2)

dA/dt = 16 square inches per second

The rate of change of the area of the rectangle with respect to time at the specified instant is 16 square inches per second.

The question asks for the rate of change of the area of a rectangle with respect to time, where the rectangle's width is twice its height, both width and height are functions of time and the rate at which height is increasing is given.

The area A of the rectangle is given by the formula A = w*h. Substituting w = 2h into the formula gives A = 2h². The rate of change of the area with respect to time (dA/dt) can be found by differentiating A with respect to time. By the chain rule this gives dA/dt = 2*2h(dh/dt) = 4h*dh/dt.

At the given instant, where the width is 4 inches (so the height is 2 inches) and the rate of change of the height is 2 inches per second, we have dA/dt = 4*2*2 = 16 square inches per second. Therefore, the rate of change of the area of the rectangle with respect to time at that instant is 16 square inches per second.

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Answer:12 packages.

Step-by-step explanation:

The agency has 2 cities,1 month and 6 airlines to choose from.(completion of the question)

Total package of the agency = 2cities×1 month × 6 airlines=12 packages.

Answer:

For a scaler variable, the Gaussian distribution has a probability density function of

p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×[tex]e^{\frac{-(x-u)^{2}}{2s^{2} } }[/tex]

The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ

Step-by-step explanation:

Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion  

From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ