The purpose of the ___________ is to provide sufficient notice to individuals whose personal information has been stolen so they can take appropriate actions in a timely manner to prevent further damage by the data thieves.

Answer:

The correct answer is: Organizing.

Explanation:

Management functions refer to the roles high-rank executives must play to handle businesses. Those functions are Planning, Organizing, Staffing, Directing, and Controlling. Organizing refers to the steps taken to create a structure in the organization. Managers should find the most optimal way to group the firm's resources to ensure efficiency and effectiveness. The process of organizing includes:

Answer:

The answer is "False".

Explanation:

CBIS is part of IT, it is a structured combination of programs, technologies and human resources for the distribution of timely, standardized, accurate and useful decision-making knowledge.

Answer:

yes ! you can see below.

Explanation:

EHR is a health record of a patient that gives information about the patient and securely authorized it. Electronic Health record allows medical professionals to enter data and update a new encounter.

DOC is a document used by Microsoft. DOC file is a file that contains formatted text, images, tables, graphs, and charts, etc.

Unstructured data is data that can be entered in free text format. Structured information is a type of data contain check boxes, images table, and other the user chooses from the given option.

As the DOC system contain free text format, then data in the EHR is structured.

The data sent from a DOS system to an EHR and populating an indexed field is typically considered structured data. EHR systems play a critical role in maintaining accessible and secure patient records, improving healthcare quality and efficiency while safeguarding privacy.

If data from a DOS system is electronically sent to an EHR (Electronic Health Record) or other Windows-based system via an interface to populate an indexed data field in the EHR, the data can be either structured or unstructured depending on the format it is sent and how it is handled by the receiving system. In this context, if the data populates a specific field within the EHR, it is typically considered to be structured data because it is organized in a predefined manner, making it easily searchable and analyzable within the system.

EHR systems are essential for maintaining accurate and accessible patient records. They ensure that in the event of a disaster, such as a hurricane, health information can be retrieved due to effective data backup solutions. Additionally, because EHRs are designed to be shared securely among healthcare providers, they facilitate improved coordination of care.

Overall, the transformation from paper-based records to EHRs serves to enhance the quality and efficiency of healthcare delivery, while also maintaining the privacy and security of personal health information under federal laws such as HIPAA.

Answer:

def max_magnitude(user_val1, user_val2):

if abs(user_val1) > abs(user_val2):

return user_val1

else:

return user_val2

if __name__ == '__main__':

n1 = int(input("Enter the first integer number: "))

n2 = int(input("Enter the second integer number: "))

print("The largest magnitude value of", n1, "and", n2, "is", max_magnitude(n1, n2))

Explanation:

Answer:

Software and Hardware virtualization.

Explanation:

Virtualization is a process or the ability of a system to run multiple operating systems and virtually using all the physical resources, as though they are individual systems.

Hardware virtualization allows for hardware components like the storage, CPU, memory etc to be virtually used by multiple virtual machines. Software virtualization uses software managers to run individual guest operating systems on virtual machines.

Answer:

The below code is pasted in the place of "/*Your solution goes here */"

while(numInsects<200) // while loop

       {

            System.out.print(numInsects+" "); // print statement

            numInsects=numInsects*2; // operation to print double.

       }

Output:

Explanation:

Using Python 3 programming, the code blocks below displays the required instructions. The program goes thus :

numInsects = int(input())

#takes input from the user on the number of insects

while numInsects < 200 :

#while loop checks if variable is below 200

print(numInsects, end=' ')

#displays the value with the cursor remaining on the same line

numInsects*=2

print(numInsects)

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Answer:

Option C.

Explanation:

Search engine use of pre-stored search that results is not mostly accurate.

Search engines shouldn't search the whole Internet each time when user requests for a search because It might be taken more time than the user might have expected and Many users were not involved in exploring the whole Internet.

Answer:

The code is as below. The solution is given in python and can be converted  to other programming language.

Explanation:

As the language is not identified, it is assumed that the requirement of the language is python

As the complete question is missing, here the link to complete question is given in the comments above.

From the complete question, it is given that the approximated solution is for x86 instruction. thus as the x86 instructions are for integers only thus the complete code is as follows: Here the code is given as

#Defining the function

def relerror(x):

   x=float(x);

   y=int(x)

   f_h=y**(0.72);

   f=x**(0.72);

   absol=abs(f_h-f);

   rel=absol/f;

   relp=(absol/f)*100;

   print('The relative error for',x,' as value of x when approximated as x86 routine is ',round(relp,2),'%')

   #Main program calling given function

x=input('Please enter a value in float')

relerror(x)

Answer:

False

Explanation:

Interfaces are similar to classes in Java, but they are not a type of class. A class defines the attributes and behaviours of objects, while interface contains the methods that shows the behaviours to be implemented by a class.

A method is one or more group of statements, it does not need to end with a semicolon. Methods in interfaces are abstract and for a class to contain these abstract method, it must be defined in the class.

An interface is a class that contains only the method headings and each method heading is terminated with a semicolon is a true statement.

An interface is known to be a kind of reference that is seen in Java. It is same to look the same with class.

It is known as a series of abstract methods that shows the description of the work that a specific object can do. Here, An interface is a class that has  only the method headings and the method heading is ended with a semicolon.

Learn more about interface from

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Answer:

Following is attached the solution of each part step-by-step. I hope it will help you!

Explanation:

Answer:

Following are the Pseudocode for the above problem:

Explanation:

Output:

Pseudocode Explanation:

Answer:

Program for the above question in python:

mass = float(input("Enter the mass in grams")) # It is used to take the mass as input.  

density = float(input("Enter the density grams per cm cube")) # It is used to take the input for the grams.

print("Volume ={:.2f}".format(mass/density)) #It is used to print the Volume.

Output:

Explanation:

To write a program that calculates and outputs the volume of an object using mass and density, you need to collect the mass and density from the user as input and use the formula volume = mass / density. Format the output to two decimal places using a print or format function that specifies the decimal precision.

To write a program that calculates and outputs the volume of an object using mass and density, you would need to collect the mass and density from the user as input. Then, you can use the formula volume = mass / density to calculate the volume. To format the output to two decimal places in most programming languages, you can use a print or format function that specifies the decimal precision. Here's an example in Python:

This program prompts the user to enter the mass and density, calculates the volume using the formula, and then formats the output to two decimal places using the '{:.2f}' format specifier.

https://brainly.com/question/20474319

#SPJ11

Answer:

string_class.h:

include <string>

using namespace std;

class string_class

{

private:

  string current_string;

public:

  string_class();

  string_class(string temp);

  bool palindrome();

  string replace_all(string Old, string New);

  friend ostream& operator<<(ostream& os,string_class& temp);

};

string_class.cpp:

#include "string_class.h"

#include<algorithm>

using namespace std;

string_class::string_class()

{

  this->current_string = "";

}

string_class::string_class(string temp)

{

  this->current_string = temp;

}

bool string_class::palindrome()

{

  string temp = this->current_string;

  reverse(temp.begin(), temp.end());

  if (temp == this->current_string)

      return true;

  return false;

}

string string_class::replace_all(string Old, string New)

{

  for (int i = 0; i < int(this->current_string.length()); i++)

  {

      string replace = "";

      for (int j = 0; j < int(Old.length()); j++)

          replace += this->current_string[i + j];

      if (replace == Old)

      {

          string final = "";

          for (int j = i + Old.length(); j < int(this->current_string.length()); j++)

              final += this->current_string[j];

          this->current_string = final;

      }

  }

  return this->current_string;

}

ostream& operator<<(ostream& co,string_class& temp)

{

  co << temp.current_string;

  return co;

}

test.cpp:

#include "string_class.h"

#include <iostream>

#include <string>

using namespace std;

int main()

{

  string_class s;

  cout << "**************" << endl

      << "Test#1: tesing default constructor and overloaded operator<< with chaining\n"

      << s << "1st blank line" << endl << s << "2nd blank line" << endl

      << "Test#1 Ended" << endl

      << "**************" << endl;

  string_class r("hello");

  cout << "**************" << endl

      << "Test#2: tesing explicit-value constructor and overloaded operator<< with chaining\n"

      << r << "1st blank line" << endl << r << "2nd blank line" << endl

      << "Test#2 Ended" << endl

      << "**************" << endl;

  cout << "**************" << endl

      << "Test#3: tesing palindrome\n"

      << "**************" << endl;

  string response = "Y";

  string ss;

  while (response == "Y" || response == "y")

  {

      cout << "Enter String: ";

      cin >> ss;

      string_class main_string(ss);

      if (main_string.palindrome())

      {

          cout << ss << " is a palindrome\n";

      }

      else

      {

          cout << ss << " is not a palindrome\n";

      }

      cout << "Would you like to try another string? (Y or N): ";

      cin >> response;

  }

  cout << "Test#3 Ended" << endl

      << "**************" << endl;

  cout << "**************" << endl

      << "Test#4: tesing replace_all\n"

      << "**************" << endl;

  response = "y";

  string current, old_substring, new_substring;

  while (response == "Y" || response == "y")

  {

      cout << "Enter value for current_string: ";

      cin >> current;

      string_class current_string(current);

      cout << "Enter old_substring: ";

      cin >> old_substring;

      cout << "Enter new_substring: ";

      cin >> new_substring;

      cout << "Current string = " << current << endl

          << "New string = " << current_string.replace_all(old_substring, new_substring)

          << endl;

      cout << "Would you like to try another string? (Y or N): ";

      cin >> response;

  }

  cout << "**************" << endl

      << "Test#4: tesing replace\n"

      << "**************" << endl;

  return 0;

}

Explanation:

Answer:

"Web browser" is the correct answer for the above question.

Explanation:

Answer:

 public static void main(String[] args)

 {

   int studentnumber = 123456;

   int divisor = 0;

   int chapter = (studentnumber%4)+2;

   switch(chapter) {

     case 2:

      divisor = 23;

      break;

     case 3:  

      divisor = 34;

       break;

     case 4:

      divisor = 38;

       break;

     case 5:  

      divisor = 46;

       break;

   }

   int exercise = (studentnumber % divisor) + 1;

  System.out.printf("Studentnumber %d divided by 4 plus 2 is chapter %d.\n", studentnumber, chapter);        

  System.out.printf("Studentnumber %d divided by %d is exercise %d.", studentnumber, divisor, exercise);  

 }

Explanation:

Above is just a bit of code to get you started with the first part. Hope you can figure out the rest.

Answer:

Increase the left and right margins.

Explanation:

Microsoft Excel is a spreadsheet application package from the Microsoft office package. It is a tool used for analysing and cleaning and/or organising information.

It's worksheets are made of cells located by columns or fields and rows or records. A collection of worksheets is called a workbook. An Excel file can be printed after use.

When a print layout is viewed and printed, and columns of the file is printed on another page. To avoid this, reduce the size of the columns and the size of the left and right margins and also decrease the scale value and change to a bigger paper printer size if required.

Answer:

Trap is a software interrupt that occurs when there is a system call, while hardware interrupt occurs when a hardware component needs urgent attention.

Explanation:

Interrupt is an input signal that disrupt the activities of a computer system, giving immediate attention to a hardware or software request.

In trap interrupt, the system activities are stop for a routine kernel mode operation, since it has a higher priority than the user mode. At the end of the interrupt, it switches control to the user mode.

The hardware interrupt is a signal from hardware devices like the input/output devices, storage and even peripheral devices that draws an immediate attention of the processor, stopping and saving other activities and executing the event with an interrupt handler.

Answer:

Option A and Option D are the correct options.

Explanation:

They decided to allow their users with a different perspective when viewing a Salesforce1 transaction records rather than the specific web edition. So, they accomplish the following scenario by adding and allocating a Mobile Design to a profile and by adding the following page to the mobile card section.

Explanation:

Virtualization can be defined as a virtual or software-based representation of virtual applications, storage, network and servers. Through this process it is possible to run a variety of different operating systems on the same physical server at the same time, which reduces information technology expenses, increases the speed and agility of the systems.

Some of the benefits of virtualization are:

Answer:

Following is the program in Java language:

import java.util.*;//import package

public class Main // main class

{

public static void main(String[] args) // main method

{

    String  firstname,lastname; // Declare the two String variables

    Scanner ob=new Scanner(System.in); // create a object of scanner //class

    System.out.println("Enter the first name:");  // Prompt the user for // enter the first name

   firstname=ob.nextLine();// Read in the first name by user

    System.out.println("Enter the last name:"); // Prompt the user for last //name

   lastname=ob.nextLine();// Read in the last name by user

   System.out.println("Hello " + firstname +' ' +lastname); // print the //firstname,lastname

}

}

Output:

Enter the first name:

San

Enter the last name:

ert

Hello San ert

Explanation:

Following are the description of program

Final answer:

The question asks for a program that reads an integer representing the number of words in a list, the words themselves, and a character, and then prints each word from the list that contains the character at least once. A sample Python script has been provided to illustrate how this can be achieved by iterating through the list and checking for the presence of the character in each word.

Explanation:

To create a program that reads an integer, a list of words, and a character, where the integer indicates the number of words in the list, and the output displays every word containing the specified character at least once, you would typically use a programming language like Python. The task involves iterating through the list of words and checking if each word contains the character. Here is a simple example in Python:

This script prompts the user to input the number of words, the words themselves, and the character to search for. It then prints out any word that contains the character.

Explanation:

What happens is that the security of a company's information and data system can be affected by its people because it is the organization's own employees who can leak sensitive information, for their own benefit or for the benefit of others. That is why it is extremely relevant that organizations should limit the level of access that each user has to their information system.

Adequate training in the use of these systems is essential for employees to use it properly, to correct system failures, and for top management to have adequate knowledge in the preparation of system security plans.

It is the security policies that will prevent unauthorized access and greater control over the security of important data and information, so it is important that any company with a data information system keeps itself up to date with the software and implements necessary security resources, in a way maintain security and always update and analyze the operation of technological equipment.

Answer:

The three types of technical information sources are:      

Vendor and manufacturer Web sites.

Technology-oriented Web sites and publications.

Professional society Web sites.              

Explanation:

Professional society Web sites provide most unbiased information.

These professional social websites are non profit companies as opposed to other sources of information that are profit making.

Social websites provides with the information that can help their members in a best way about getting information of their interest. This is done in an unbiased way because they do not work for some specific organizations or companies that want to sell their products or services.

Answer:

#include <iostream>

#include <stack>

#include <queue>

using namespace std;

bool checkfor(stack<int> &stk, int x){

   queue<int> q;

   bool flag = false;

   while(!stk.empty()){

       int p = stk.top();

       stk.pop();

       if(p == x){

           flag = true;

       }

       q.push(p);

   }

   while(!q.empty()){

       stk.push(q.front());

       q.pop();

   }

   while(!stk.empty()){

       q.push(stk.top());

       stk.pop();

   }

   // from queue to stack

   while(!q.empty()){

       stk.push(q.front());

       q.pop();

   }

   return flag;

}

int main(){

   stack<int> stk;

   // pushing data to stack

   stk.push(1);

   stk.push(3);

   stk.push(43);

   stk.push(2);

   stk.push(5);

   cout<<(checkfor(stk, 5)?"Found": "Not Found")<<'\n';

   cout<<(checkfor(stk, 10)?"Found": "Not Found")<<'\n';

   return 0;

}

Explanation:

Answer:

a) with Array

class array{

   int arrA[MAX],location,item,nA;

   int arrB[MAX],nB;

   int arr_merge[MAX+MAX],nM;

   public:

   array(){

      location=0;item=0;nA=0;

      nB=0;nM=0;

   }

   void init(); //initial data assignment  

void traverse(); //process is display (assumed)void insert();

   void del();

   void search();

   void sort();

   void merge();

};

void array :: del(){

    clrscr();

    int i;

    cout<<"\n\n*****Deleting Element*****\n";

    if(nA < 0){

   cout<<"\nArray is Empty\nDeletion Not Possible\n";

   goto end;

    }

    cout<<"\nEnter Location of deletion : ";

    cin>>location;

    location--;

    if(location<0 || location>=nA)

    {

   cout<<"\n\nInvalid Position\n";

   goto end;

    }

    cout<<"\nItem deleted is : "<<arrA[location];

    for(i=location;i<nA;i++){

    arrA[i] = arrA[i+1];

    }

    arrA[nA-1]=0;

    nA--;

end:

     getch();

}

void array :: search(){

    clrscr();

    int i,found=-1;

    cout<<"\n\n*****Searching Element*****\n";

    cout<<"\nEnter Item value to be search : ";

    cin>>item;

    for(i=0;i<nA;i++){

    if(arrA[i] == item){

       found=i+1;

       break;

    }

    }

    if(found==-1)

    cout<<"\nSearch NOT FOUND\n";

    else

    cout<<"\nSearch is FOUND at "<<found<<" location\n";

    getch();

}

void array :: sort(){

    clrscr();

    int i,j,temp;

    cout<<"\n\n*****Sorting Element*****\n";

    for(i=0;i<nA;i++){

   for(j=i;j<nA;j++){

     if(arrA[i] > arrA[j]){

        temp    = arrA[i];

        arrA[i] = arrA[j];

        arrA[j] = temp;

     }

   }

    }

   cout<<"\nData are Sorted\n";

   getch();

}

// b) with pointer

#include <stdio.h>

#include <conio.h>

#include <math.h>

#include <alloc.h>

void main()

{

char *a[10],dum[10],s;

int i,k,j,n;

clrscr();

printf("enter the no of std....");

scanf("%d",&n);

printf("enter the name of students ");

for(k=0;k<n;k++)

scanf("%s",a[k]);

for(i=1;i<n;i++)

{

for(j=1;j<n-i;j++)

{if(strcmp(a[j-1],a[j])>0)

 {strcpy(*dum,*a[j-1]);

  strcpy(*a[j-1],*a[j]);

  strcpy(*a[j],*dum);

}

}  }

for(i=0;i<n;i++)

printf("%s",a[i]);

getch();

}

c) with cursor implementations of lists.

#include<stdio.h>

#include<stdlib.h>

typedef struct Node  

{

       int data;

       struct Node *next;

}node;

void insert(node *pointer, int data)

{

       /* Iterate through the list till we encounter the last node.*/

       while(pointer->next!=NULL)

       {

               pointer = pointer -> next;

       }

       /* Allocate memory for the new node and put data in it.*/

       pointer->next = (node *)malloc(sizeof(node));

       pointer = pointer->next;

       pointer->data = data;

       pointer->next = NULL;

}

int find(node *pointer, int key)

{

       pointer =  pointer -> next; //First node is dummy node.

       /* Iterate through the entire linked list and search for the key. */

       while(pointer!=NULL)

       {

               if(pointer->data == key) //key is found.

               {

                       return 1;

               }

               pointer = pointer -> next;//Search in the next node.

       }

       /*Key is not found */

       return 0;

}

void delete(node *pointer, int data)

{

       /* Go to the node for which the node next to it has to be deleted */

       while(pointer->next!=NULL && (pointer->next)->data != data)

       {

               pointer = pointer -> next;

       }

       if(pointer->next==NULL)

       {

               printf("Element %d is not present in the list\n",data);

               return;

       }

       /* Now pointer points to a node and the node next to it has to be removed */

       node *temp;

       temp = pointer -> next;

       /*temp points to the node which has to be removed*/

       pointer->next = temp->next;

       /*We removed the node which is next to the pointer (which is also temp) */

       free(temp);

       /* Beacuse we deleted the node, we no longer require the memory used for it .  

          free() will deallocate the memory.

        */

       return;

}

void print(node *pointer)

{

       if(pointer==NULL)

       {

               return;

       }

       printf("%d ",pointer->data);

       print(pointer->next);

       }

}

Running Time:

a) 2 minute

b) 1 minutes  

c) 1 & half minutes

Explanation:

a) Initialize the array and traverse it by using for loop. Sort the array with the help of a temporary variable.  

b) Declare a pointer to the array and take the input from user using for loop.

c) Declare a Structure containing an integer and a pointer. Iterate through the list, allocate memory for the new node and insert the data in it.

Answer:

Detailed answer is provided in the explanation section

Explanation:

Conversion of ARMv8 machine code into ARMv8 Assembly Language instructions:

ARMv8 machine code ARMv8 Assembly Language

0x0000000080001294 : EB01001F                    CMP X0,X1

0x0000000080001298 : 5400006A

0x000000008000129C : 91000400

0x00000000800012A0 : 17FFFFFD

0x00000000800012A4 : D61F03C0

Answer:

Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!

Explanation:

```csharp

using System;

class ClassifiedAd

{

   // Fields

   private string category;

   private int numberOfWords;

   // Properties

   public string Category

   {

       get { return category; }

       set { category = value; }

   }

   public int NumberOfWords

   {

       get { return numberOfWords; }

       set { numberOfWords = value; }

   }

   public double Price

   {

       get { return numberOfWords * 0.09; } // Price calculated at nine cents per word

   }

}

class TestClassifiedAd

{

   static void Main(string[] args)

   {

       // Instantiate ClassifiedAd objects

       ClassifiedAd ad1 = new ClassifiedAd();

       ad1.Category = "Used Cars";

       ad1.NumberOfWords = 50;

       ClassifiedAd ad2 = new ClassifiedAd();

       ad2.Category = "Help Wanted";

       ad2.NumberOfWords = 80;

       // Display information about the ClassifiedAd objects

       Console.WriteLine("Classified Ad 1:");

       Console.WriteLine($"Category: {ad1.Category}");

       Console.WriteLine($"Number of Words: {ad1.NumberOfWords}");

       Console.WriteLine($"Price: ${ad1.Price}");

       Console.WriteLine("\nClassified Ad 2:");

       Console.WriteLine($"Category: {ad2.Category}");

       Console.WriteLine($"Number of Words: {ad2.NumberOfWords}");

       Console.WriteLine($"Price: ${ad2.Price}");

   }

}

```

1. ClassifiedAd Class:

  - This class represents a classified advertisement with three fields: `category`, `numberOfWords`, and a private field `price` (which is calculated internally).

  - Properties:

    - `Category`: This property has both a getter (`get`) and a setter (`set`) to allow getting and setting the category of the advertisement.

    - `NumberOfWords`: Similarly, this property has both a getter and a setter for getting and setting the number of words in the advertisement.

    - `Price`: This property only has a getter (`get`). It calculates the price based on the number of words (`numberOfWords * 0.09`), where each word costs nine cents.

2. TestClassifiedAd Class:

  - This is the main application class that demonstrates the use of `ClassifiedAd` objects.

  - Main Method:

    - It instantiates two `ClassifiedAd` objects (`ad1` and `ad2`) and assigns values to their properties (`Category` and `NumberOfWords`).

    - It then prints out information about each `ClassifiedAd` object:

      - Displays the category using `ad1.Category` and `ad2.Category`.

      - Displays the number of words using `ad1.NumberOfWords` and `ad2.NumberOfWords`.

      - Displays the calculated price using `ad1.Price` and `ad2.Price`.

3. Execution:

  - When you run the `TestClassifiedAd` application, it will output the category, number of words, and price for each of the two `ClassifiedAd` objects that were instantiated and configured.

4. Purpose:

  - This code demonstrates basic object-oriented principles such as encapsulation (using properties to access fields), calculation within properties, and object instantiation and usage in a simple console application.

Overall, the `ClassifiedAd` class encapsulates the data and behavior related to a classified advertisement, and the `TestClassifiedAd` application showcases the instantiation and usage of these objects with specific examples.

A program that reads a person's first and last names, separated by a space is shown below.

Given that;

Write a program that reads a person's first and last names, separated by a space.

Here's a solution in C++ that should do the trick:

#include <iostream>

#include <string>

using namespace std;

int main() {

 string firstName;

 string lastName;

 // Prompt user for input

 cout << "Please enter your first and last names, separated by a space: ";

 cin >> firstName >> lastName;

 // Output the last name, comma, first name

 cout << lastName << ", " << firstName << endl;

 return 0;

}

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Final answer:

To solve the programming exercise, include cin to read two strings representing the first and last name, then output them in 'Last name, First name' format using cout, followed by a newline.

Explanation:

To complete the coding exercise, you need to read in a person's first and last name and then display the last name followed by a comma, and then the first name. You can achieve this by using the cin to read the names and cout to output the result in the required format.

The program will look like this:

#include
#include
using namespace std;
int main() {
   string firstName;
   string lastName;
   // Reading the first and last name
   cin >> firstName >> lastName;
   // Output in 'Last name, First name' format
   cout << lastName << ", " << firstName << endl;
   return 0;
}

Simply include the code segment within the "/* Your solution goes here */" section in your program. When you run this code, it will prompt you to input a first and last name, and after you provide it, the program will print out the last name, a comma, and then the first name followed by a newline as specified in the exercise.

Answer:

Algorithm for the above problem:

Output:

Explanation:

This question is incomplete. The complete question is given below:

Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:

  A

 ABA

ABCBA

ABCDCBA

Answer:

#include <stdio.h>

void printTri(char asciiCharacter){

   // Row printer

//   for(int i = 65; i <= ((int)asciiCharacter); i++){

   int i = 65;

   while(i <= ((int)asciiCharacter)){

       int leftMargin = ((int)asciiCharacter) - i; +

       int j = 1;

       while(j <= leftMargin){

           printf(" ");

           j++;

       }

       int k = 65;

       while(k < ((int)i)){

           printf("%c",(char)k);

           k++;

       }

       int l = ((int)i);

       while(l >= 65){

           printf("%c",(char)l);

           l--;

       }

       printf("\n");

       i++;

   }

}

int main()

{

   for(;;){

       printf("Please enter a character between A and Z. Enter (!) to exit \n");

       char in;

//       scanf("%c",&in);

       in = getchar();

       getchar();

       printf("Printing Triangle for: %c \n",in);

       if(((int)in) >= 65 && ((int)in) <= 90){

           printTri(in);

           printf("\n");

       }else if(((int)in) == 33){

           break;

       } else {

           continue;

       }

   }

   return 0;

}

Explanation: