Answer:
Accounting.
Explanation:
Computer networks are designed to allow computer devices to communicate intelligently. The connection of these network devices could be wired or wireless. A network can be private or public. Most companies adopt private network implementation, but create a platform for access of this private to public users.
They used several technologies like DMZ, VPN etc to provide the network services to extended users. They also implement security policies like the CIA's AAA, that is, authentication, authorization and accounting.
Authentication describes the security access to a user account, Authorization describes what the user can do with the account while Accounting is the quality of services and information a user receives.
Achieving a degree in computer forensics, information technology, or even information systems can provide a strong foundation in computer forensics. A degree supplemented by a ________ provides greater competencies in the field and makes a candidate even more marketable to a potential employer.
A degree supplemented by a Certifications provides greater competencies in the field and makes a candidate even more marketable to a potential employer.
Explanation:
Computer forensics is field of digital evidences.In a civil or Criminal case computer forensics technology is used to study the digital evidences(like retrieval of deleted files,encrypted files,usage of various disk)
Using 8-bit bytes, show how to represent 56,789. Clearly state the byte values using hexadecimal, and the number of bytes required for each context. Simply indicate the case if the code is not able to represent the information.
Answer:
a) 56789₁₀ = 11011110111010101₂ (unsigned integer)
b) 56789₁₀ = 0000000011011110111010101₂ (Two's complement)
c) 56789₁₀ = 01010110011110001001 (BCD)
d) 56789₁₀ = ÝÕ (ASCII)
e) 56789₁₀ = 0 - 1000 1110 - 101 1101 1101 0101 0000 0000 (IEEE single precision)
Explanation:
a) 56789₁₀ = (1 × 2¹⁵) + (1 × 2¹⁴) + (0 × 2¹³) + (1 × 2¹²) + (1 × 2¹¹) + (1 × 2¹⁰) + (0 × 2⁹) + (1 × 2⁸) + (1 × 2⁷) + (1 × 2⁶) + (0 × 2⁵) + (1 × 2⁴) + (0 × 2³) + (1 × 2²) + (0 × 2¹) + (1 × 2⁰) = 11011110111010101₂
This requires 2 bytes - 16 bits and hexadecimal byte value of DDD5.
2) since the number is positive, the two's complement is just that same binary number with a signed 0 to indicate positive number in front.
56789₁₀ = 0000000011011110111010101₂
This requires 3 bytes - 24 bits and hexadecimal byte value of 11DDD5.
c) BCD
This converts each single bit in the base-10 to binary.
5 = 0101, 6 = 0110, 7 = 0111, 8 = 1000, 9 = 10001, then combined, we have
56789₁₀ = 01010110011110001001 (BCD)
It's an historic code.
This requires 3 bytes - 24 bits and hexadecimal byte value of 56789.
d) ASCII
This uses symbols to represent the numbers.
56789₁₀ = ÝÕ (ASCII)
This requires 1 byte - 8 bits.
e) IEEE single precision
Step 1, convert to base 2
56789₁₀ = 11011110111010101₂
Step 2, normalize the binary,
11011110111010101₂ =11011110111010101 × 2⁰ = 1.1011110111010101 × 2¹⁵
Sign = 0 (a positive number)
Exponent (unadjusted) = 15
Mantissa (not normalized) = 1.1011110111010101
Step 3, Adjust the exponent in 8 bit excess/bias notation and then convert it from decimal (base 10) to 8 bit binary
Exponent (adjusted) = Exponent (unadjusted) + 2⁽⁸⁻¹⁾ - 1 = 15 + 2⁽⁸⁻¹⁾ - 1 = (15 + 127)₁₀ = 142₁₀
Exponent (adjusted) = 142₁₀ = 1000 1110₂
Step 4, Normalize mantissa, remove the leading (the leftmost) bit, since it's allways 1 (and the decimal point, if the case) then adjust its length to 23 bits, by adding the necessary number of zeros to the right:
Mantissa (normalized) = 1.101 1101 1101 0101 0000 0000 = 101 1101 1101 0101 0000 0000
Therefore,
56789₁₀ = 0 - 1000 1110 - 101 1101 1101 0101 0000 0000
This requires 4 bytes - 32 bits and hexadecimal byte value of 8E5DD500.
Hope this helps!
How should this be accomplished? Business users have requested that the Salesforce Administrator allow agents to view a list of cases in the console while agents work through their cases. This will allow agents to identify urgent cases that need to be worked on.
A. Enable the list to be pinned in the console. This allows users to view the list alongside the case view in the console
B. Configure the Case list under custom console components so users can view the list view along with the case view.
C. Build a custom VisualForce page with the list view and assign it to the console sidebar.
D. Recommend opening the case list view in a separate browser tab and use the window alongside the case view.
Answer:
A)
Explanation:
Enable the list to be pinned in the console. This allows users to view the list alongside the case view in the console
java Problem: The TARDIS has been infected by a virus which means it is up to Doctor Who to manually enter calculations into the TARDIS interface. The calculations necessary to make the TARDIS work properly involve real, imaginary and complex numbers. The Doctor has asked you to create a program that will evaluate numerical expressions so that he can quickly enter the information into the TARDIS. Details:
Answer:
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.HashMap;
import java.util.Scanner;
import java.util.concurrent.SynchronousQueue;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public lass Test
{
public static void main(String[] args) {
FileReader fr;
try {
fr = new FileReader("expression.txt");
Scanner sc=new Scanner(fr);
while(sc.hasNextLine())
{
String line=sc.nextLine();
pareseString(line);
pareseString(line);
}
} catch (FileNotFoundException e) {
e.printStackTrace();
}
pareseString("6 * 3+2i");
pareseString("2 - 3");
}
public static ComplexNumber add(ComplexNumber c1, ComplexNumber c2) {
return new ComplexNumber(c1.getRealNumber() + c2.getRealNumber(), c1.getImaginaryNumber() + c2.getImaginaryNumber());
}
public static ComplexNumber substract(ComplexNumber c1, ComplexNumber c2) {
return new ComplexNumber(c1.getRealNumber() - c2.getRealNumber(), c1.getImaginaryNumber() - c2.getImaginaryNumber());
}
public static ComplexNumber multiply(ComplexNumber c1,ComplexNumber c2) {
ComplexNumber c3 = new ComplexNumber();
c3.setRealNumber( c1.getRealNumber() * c2.getRealNumber() - c1.getImaginaryNumber() * c2.getImaginaryNumber());
c3.setImaginaryNumber( c1.getRealNumber() * c2.getImaginaryNumber() - c1.getImaginaryNumber() * c2.getRealNumber());;
return c3;
}
public static ComplexNumber divide(ComplexNumber c1,ComplexNumber c2) {
ComplexNumber c3 = new ComplexNumber();
c3.setRealNumber( c1.getRealNumber() / c2.getRealNumber() - c1.getImaginaryNumber() / c2.getImaginaryNumber());
c3.setImaginaryNumber( c1.getRealNumber() / c2.getImaginaryNumber() - c1.getImaginaryNumber() / c2.getRealNumber());;
return c3;
}
public static void pareseString(String line)
{
String [] strArr=line.split(" ");
String cn1=strArr[0];
String operation=strArr[1];
String cn2=strArr[2];
ComplexNumber c1=validation(cn1);
ComplexNumber c2=validation(cn2);
if(c1!=null && c2!=null)
{
switch (operation) {
case "+":
System.out.println(add(c1, c2));
break;
case "-":
System.out.println(substract(c1, c2));
break;
case "*":
System.out.println(multiply(c1, c2));
break;
case "/":
System.out.println(divide(c1, c2));
break;
}
}
}
private static ComplexNumber validation(String comp) {
String numberNoWhiteSpace = comp.replaceAll("\\s","");
Pattern patternA = Pattern.compile("([-]?[0-9]+\\.?[0-9]?)([-|+]+[0-9]+\\.?[0-9]?)[i$]+");
Pattern patternB = Pattern.compile("([-]?[0-9]+\\.?[0-9]?)$");
Pattern patternC = Pattern.compile("([-]?[0-9]+\\.?[0-9]?)[i$]");
Matcher matcherA = patternA.matcher(numberNoWhiteSpace);
Matcher matcherB = patternB.matcher(numberNoWhiteSpace);
Matcher matcherC = patternC.matcher(numberNoWhiteSpace);
double realNumber=0.0;
double imaginaryNumber=0.0;
ComplexNumber cn=null;
if (matcherA.find()) {
realNumber = Double.parseDouble(matcherA.group(1));
imaginaryNumber = Double.parseDouble(matcherA.group(2));
cn=new ComplexNumber(realNumber, imaginaryNumber);
} else if (matcherB.find()) {
realNumber = Double.parseDouble(matcherB.group(1));
imaginaryNumber = 0;
cn=new ComplexNumber(realNumber, imaginaryNumber);
} else if (matcherC.find()) {
realNumber = 0;
imaginaryNumber = Double.parseDouble(matcherC.group(1));
cn=new ComplexNumber(realNumber, imaginaryNumber);
}
return cn;
}
}
class Number
{
private double realNumber;
public Number(double realNumber) {
this.realNumber= realNumber;
}
public Number() {
this.realNumber= realNumber;
}
public double getRealNumber() {
return realNumber;
}
public void setRealNumber(double realNumnber) {
this.realNumber = realNumnber;
}
@Override
public String toString() {
return this.getRealNumber()+"";
}
@Override
public boolean equals(Object obj) {
if(obj instanceof Number)
{
Number cn=(Number)obj;
return this.getRealNumber()==cn.getRealNumber();
}
return false;
}
}
class ComplexNumber extends Number
{
public double getImaginaryNumber() {
return imaginaryNumber;
}
public void setImaginaryNumber(double imaginaryNumber) {
this.imaginaryNumber = imaginaryNumber;
}
double imaginaryNumber;
public ComplexNumber(double realNumnber,double imaginaryNumber) {
super(realNumnber);
this.imaginaryNumber=imaginaryNumber;
}
public ComplexNumber() {
super();
}
@Override
public String toString() {
return this.getRealNumber()+"+"+this.getImaginaryNumber()+"i";
}
@Override
public boolean equals(Object obj) {
if(obj instanceof ComplexNumber)
{
ComplexNumber cn=(ComplexNumber)obj;
return this.getRealNumber()==cn.getRealNumber() && cn.getImaginaryNumber()==this.getImaginaryNumber();
}
return false;
}
}
Explanation:
Create the add method, that takes object c2 as parameter.
Create the subtract method, followed by the methods to multiply and divide.
Create a regular expression that matches complex number with BOTH real AND imaginary parts.
Answer:
tell him to do it himself and call him lazy
(i know im a genius)
Examine the following declarations and definitions for the array-based implementations for the Stack and Queue ADTs. Assume that exception class PushOnFullStack and class PopOnEmptyStack have been defined and are available. Read the following code segment and fill in blank #6.
class StackType
{
public:
StackType();
void Push(StackItemType item);
void Pop();
private:
int top;
ItemType items[MAX_STACK];
};
void StackType::StackType()
{
top = -1;
}
void StackType::Push(ItemType item)
{
__________________ // 1
___________________; // 2
__________________; // 3
___________________; // 4
}
class QueType
{
public:
// prototypes of QueType operations
// go here
private:
int front;
int rear;
ItemType items[MAX_QUEUE];
}
void QueType::QueType()
{
front = MAX_QUEUE - 1;
rear = MAX_QUEUE - 1;
}
Boolean QueType::IsEmpty()
{
return (rear == front);
}
void QueType::Enqueue(ItemType item)
{
____________________; // 5
____________________; // 6
}
[1] rear = (rear +1) % MAX_QUEUE
[2] items[rear] = item
[3] rear = (rear % MAX_QUEUE) + 1
[4] items[front] = item
Answer:
The codes for the respective blanks are given below with appropriate comments for better understanding
Explanation:
FOR 1 TO 4
Void StackType::Push(ItemType item)
{
if(top == MAX_STACK - 1) // means stack is full so we need to throw the PushOnFullStack exception
throw PushOnFullStack ; // You can use this class and appropriate method to deal with exception like printing that stack is full so can not push the current item
top ++ ;// increment the top to accumulate the next item
items[top] = item; // put the item into the place identified
}
FOR 5 AND 6
Void Quetype::enqueue(itemType item)
{
if (rear==MAX_QUEUE && front==0) // queue is full so can not enqueue
//Handle the queue full exception here, may be print this
}else
{
items[rear] = item;
rear ++;
}
IN PYTHON
Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integers that follow. Then, get the last value from the input, and output all integers less than or equal to that value.
Answer:
Python program is given below
Explanation:
def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):
print("The integers that are less than or equal to", upper_threshold, "are:")
for value in user_values:
if value < upper_threshold:
print(value)
def get_user_values():
n = int(input("Enter the number of integers in your list: "))
lst = []
print("Enter the", n, "integers:")
for i in range(n):
lst.append(int(input()))
return lst
if __name__ == '__main__':
userValues = get_user_values()
upperThreshold = int(input("Enter the threshold value: "))
output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)
The question is about writing a Python program that filters a list of integers, outputting only those less than or equal to the last integer in the list, based on user input.
Python Program to Filter Integers
To write a Python program that filters integers from a list based on a specific condition, you'll first need to capture user input. Since the user will indicate the number of integers followed by the integers themselves, you can use a loop to collect these values. Afterward, you can compare each integer to the last value obtained from the input and output all integers less than or equal to this last value.
Here's an example code:
num_of_integers = int(input())
integers_list = []
for _ in range(num_of_integers):
integers_list.append(int(input()))
threshold = integers_list[-1]
for value in integers_list[:-1]:
if value <= threshold:
print(value)
This program stores all integers in a list, then iterates over the list except the last element and prints out those integers that are less than or equal to the last value in the list.
Write a function listLengthOfAllWords which takes in an array of words (strings), and returns an array of numbers representing the length of each word.
Answer:
public static int[] listLengthOfAllWords(String [] wordArray){
int[] intArray = new int[wordArray.length];
for (int i=0; i<intArray.length; i++){
int lenOfWord = wordArray[i].length();
intArray[i]=lenOfWord;
}
return intArray;
}
Explanation:
Declare the method to return an array of ints and accept an array of string as a parameterwithin the method declare an array of integers with same length as the string array received as a parameter.Iterate using for loop over the array of string and extract the length of each word using this statement int lenOfWord = wordArray[i].length();Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;Return the Integer ArrayA Complete Java program with a call to the method is given below
import java.util.Arrays;
import java.util.Scanner;
public class ANot {
public static void main(String[] args) {
String []wordArray = {"John", "James", "David", "Peter", "Davidson"};
System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));
}
public static int[] listLengthOfAllWords(String [] wordArray){
int[] intArray = new int[wordArray.length];
for (int i=0; i<wordArray.length; i++){
int lenOfWord = wordArray[i].length();
intArray[i]=lenOfWord;
}
return intArray;
}
}
This program gives the following array as output: [4, 5, 5, 5, 8]
What is true after the following statements in a C program have been executed? int* intPointer; intPointer = (int*) 500; *intPointer = 10;
Answer:
The answer to this question as follows:
Explanation:
In the given code an integer pointer variable "intPointer" is declared, this variable holds an integer type value, which is "500". In the next step, the pointer variable initialized a value with 10, which is illegal, because in pointer we hold the address of variable, not the value, that's why it will give segmentation fault. This fault will arise when the common condition triggering crashed systems, it often linked to the main script, that Safeguards are triggered by a program, that tries to read or write an illegal place in storage.To connect a Visual Basic 2012 application to data in a database, use the ____ Wizard. a. Database Source Connection b. Database Source Configuration c. Data Source Connection d. Data Source Configuration
Answer:
Option(d) i. e "Data Source Configuration" is the correct answer for the given question.
Explanation:
In the ADO.Net of Visual basic 2012 when we want to create the dataset we used the Data Source Configuration wizard. The Data Source Configuration wizard helps to connect with the database in the visual basic of the 2012 application. The Following are the step when we want to create the Dataset.
Select the project which will we have to connect with the database After Selecting the project open the wizard of Data Source Configuration.After selecting the wizard to choose the new data source as well as the database type of the data-source.Finally, configure the appropriate database file.In the Budget Details sheet, if you wish to autofill with the formula, you must use a ______ reference for the LY Spend Total cell in your formula in order to calculate what percentage of the Total is Gasoline.
A. Absolute B. Circular C. Linking D. Relative
Answer:
The answer is A.Absolute reference.
Explanation:
Absolute reference is a cell reference whose location remains constant when the formula is copied.
Identify two entities and 2 of their attributes from the given scenario.
Book.com is an online virtual store on the Internet where customers can browse the catalog and select products of interest.
Bookstore and BookSearch are the two entities for the given scenario.
Explanation:
For the given Book.com virtual store, there can be two entities like Bookstore and BookSearch.Bookstore can have all the details of the books in the virtual store. hence the attributes can be Bookstore attributes: bookname, Authorname, Publisher, Publishedyear, Agegroup, category.BookSearch entity can be used to search the books in the virtual store.Booksearch attributes: bookname, category, bookid, authorname.You are installing a webcam in the screen bezel of your laptop. Prior to disassembling the laptop, what other devices in the screen bezel should you be aware of? (Select all that apply.)a. Microphoneb. Inverterc. Touchpadd. WI-FI antenna
Answer:
a. Microphone
d. Wi-Fi antenna
Explanation:
The wifi antenna , is present in the screen bezel , and the two cables are connected to the motherboard and the wifi adapter .
Hence , we need to be aware of the wifi antenna , before installing the webcam .
Microphone , as in most of the laptop , the microphone is present just near the screen bezel , and hence , need to be aware of before the installation process of the webcam .
Answer:
The correct option is WIFI antenna.
Patrick Rowe is a manager at a software firm. Jack Blair, Patrick's team member, is facing technical issues with software system. While communicating with Blair, Rowe used an impersonal statement to talk about the issue. Which of the following did Patrick say? A. "Why did you not tell me you did not know how to resolve such problems?" B. "This new software system has been giving us problems for a while now." C. "You will attend a training seminar on the new software system next week." D. "You should really know how to operate this new phone system by now." E. "Sam Todd has worked on this system before and will be able resolve the problem."
Answer:
B. "This new software system has been giving us problems for a while now."
Explanation:
Of all the given, answer B is the only impersonal statement. Passive voice is used and it is highly effective in remaining professional while communicating from a managerial role. By using an impersonal statement, the employee (Jack Blair) won't get offended by any means. Although he isn't personally mentioned in the answer E, he may feel guilt because there is someone else that is able to resolve the problem.
Design a class named Triangle that extends GeometricObject:import java.util.Scanner;abstract class GeometricObject {private String color = "white";private boolean filled;private java.util.Date dateCreated;/** Construct a default geometric object */protected GeometricObject() {}/** Construct a geometric object with color and filled value */protected GeometricObject(String color, boolean filled) {dateCreated = new java.util.Date();this.color = color;this.filled = filled;}/** Return color */public String getColor() {return color;}/** Set a new color */public void setColor(String color) {this.color = color;}/** Return filled. Since filled is boolean ,* the get method is named isFilled */public boolean isFilled() {return filled;}/** Set a new filled */public void setFilled(boolean filled) {this.filled = filled;}/** Get dateCreated */public java.util.Date getDateCreated() {return dateCreated;}@Overridepublic String toString() {return "created on " + dateCreated + "\ncolor: " + color +" and filled: " + filled;}/** Abstract method getArea */public abstract double getArea();/** Abstract method getPerimeter */public abstract double getPerimeter();}The Triangle class contains:Three double data fields named side1, side2, and side3A default constructor that creates a triangle with three sides of length 1.0A constructor that creates a triangle with specified values for side1, side2, and side3Accessor methods for all three data fieldsA method called getArea() that returns the area of a triangleA method named getPerimeter() that returns the perimeter of the triangleA method named toString() that returns the string description of the triangle in the following format: "Triangle: side1 = " + side1 + " side2 = " + side2 + " side3 = " + side3;Test your Triangle class in a Drive program (in the same file) that prompts the user to enter the three sides of the triangle, the color, and whether or not the triangle is filled. The program should create a Triangle object with these sides and set the color and filled properties. Then, it should display the area, perimeter, color, and filled value .
Answer:
Hi there Collegebound! The implementation of the Triangle class and the Drive program is below. Copy the code below into the file Triangle.java and then compile it with the command: "javac Triangle.java". To run the program, type the command: "java Drive". You should see the following result if you test with the same inputs:
$java Drive
Enter side 1 of the triangle:
1
Enter side 2 of the triangle:
1
Enter side 3 of the triangle:
1
Enter color of the triangle:
orange
Enter if triangle is filled:
true
Area of Triangle is: 0.4330127018922193
Perimeter of Triangle is: 3.0
Color of Triangle is: orange
Triangle is filled: true
Explanation:
import java.lang.Math;
import java.util.Scanner;
public class Triangle extends GeometricObject {
double side1, side2, side3;
protected Triangle() {}
protected Triangle(double s1, double s2, double s3) {
this.side1 = s1;
this.side2 = s2;
this.side3 = s3;
}
public double getSide1() {
return side1;
}
public double getSide2() {
return side2;
}
public double getSide3() {
return side3;
}
public double getArea() {
/* use Heron's formula */
double s = (this.side1 + this.side2 + this.side3) / 2;
double area = Math.sqrt(s*((s-this.side1)*(s-this.side2)*(s-this.side3)));
return area;
}
public double getPerimeter() {
return side1+side2+side3;
}
@Override
public String toString() {
return "Triangle: side1 = " + side1 + " side2 = " + side2 + " side3 = " + side3;
}
}
class Drive {
public static void main(String args[]) {
double side1, side2, side3;
System.out.println("Enter side 1 of the triangle: ");
Scanner scan = new Scanner(System.in);
side1 = scan.nextDouble();
System.out.println("Enter side 2 of the triangle: ");
scan = new Scanner(System.in);
side2 = scan.nextDouble();
System.out.println("Enter side 3 of the triangle: ");
scan = new Scanner(System.in);
side3 = scan.nextDouble();
System.out.println("Enter color of the triangle: ");
scan = new Scanner(System.in);
String color = scan.next();
System.out.println("Enter if triangle is filled: ");
scan = new Scanner(System.in);
Boolean isFilled = scan.nextBoolean();
Triangle triangle = new Triangle(side1, side2, side3);
triangle.setColor(color);
triangle.setFilled(isFilled);
System.out.println("Area of Triangle is: " + triangle.getArea());
System.out.println("Perimeter of Triangle is: " + triangle.getPerimeter());
System.out.println("Color of Triangle is: " + triangle.getColor());
System.out.println("Triangle is filled: " + triangle.isFilled());
}
}
Final answer:
A Triangle class in Java entails creating a subclass of GeometricObject with fields for its sides, methods to calculate its area and perimeter, and an overridden toString method. Test the class with a program that gathers user inputs to instantiate a triangle and display its attributes.
Explanation:
The student's question pertains to the construction of a Triangle class in Java that extends a given GeometricObject abstract class. To design this class, one must include three data fields representing the sides of the triangle, constructors for default and specified values, accessor methods for the sides, a method to calculate the area of the triangle, a method to calculate the perimeter, and an override of the toString method to describe the triangle.
The test program will prompt the user for inputs regarding the sides, color, and fill of the triangle and will use this information to create a Triangle object and display its attributes.
Example Implementation:
public class Triangle extends GeometricObject {
private double side1 = 1.0, side2 = 1.0, side3 = 1.0;
public Triangle() {}
public Triangle(double side1, double side2, double side3) {
this.side1 = side1;
this.side2 = side2;
this.side3 = side3;
}
// Accessor methods
public double getSide1() {
return side1;
}
public double getSide2() {
return side2;
}
public double getSide3() {
return side3;
}
// Area calculation using Heron's formula
public double getArea() {
double s = (side1 + side2 + side3) / 2;
return Math.sqrt(s * (s - side1) * (s - side2) * (s - side3));
}
// Perimeter calculation
public double getPerimeter() {
return side1 + side2 + side3;
}
// Description of Triangle
Override
public String toString() {
return "Triangle: side1 = " + side1 + " side2 = " + side2 + " side3 = " + side3;
}
}
To test the Triangle class, one can implement a Driver program within the same file that uses a Scanner to collect user input, initializes a Triangle object, sets its attributes, and finally prints the area, perimeter, color, and filled status.
The first step in accessing database information is to establish a ____ with the database. a. pipeline b. dialog c. connection d. data exchange path\
Answer:
C
Explanation:
To access any database you of course need to establish a connection with it, which then proceeds to the user verification process of the data implemented.
What does Web content mining involve? a. Analyzing the PageRank and other metadata of a Web page b. Analyzing the pattern of visits to a Web site c. Analyzing the universal resource locator in Web pages d. Analyzing the unstructured content of Web pages
Answer:
d. Analyzing the unstructured content of Web pages
Explanation:
Web page mining is referred to that mining that is used to extract the data or information from the web page. The main focus behind the web page mining is to discover all useful information from web pages.
The main objective of web page mining the unstructured data or content of the web pages.
All the other three option are not related with web content mining, so the correct option is D
Name a piece of software you often use where it is easy to produce an error. Explain ways you could improve the interface to better prevent errors.
To prevent errors in spreadsheet software, improve the interface by providing clear input validation, formula assistance, error messages, data validation, version control, incorporating user testing and feedback.
What is the software?One piece of software that often involves errors is spreadsheet software, such as Microsoft Excel.
These errors can range from simple calculation mistakes to more complex issues in formulas, references, and data input.
To improve the interface and prevent errors in spreadsheet software, consider the following suggestions:
Provide clear validation messages when users input data that doesn't match the expected format or range.Highlight cells with errors using distinct colors or indicators to quickly catch mistakes.Offer an auto-complete or suggestion feature for formulas and functions to prevent typos and syntax errors.Learn more about software here: https://brainly.com/question/28224061
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Microsoft Excel is a software where it is easy to make errors due to its complex nature. Improvements could be made to the interface such as effective tool-tips, a simplified menu, a comprehensive help guide, and an 'undo' button.
Explanation:A piece of software I often use where it is easy to produce an error is Microsoft Excel. The complex, multifunctional nature of Excel means that users can easily input incorrect formulae or make errors in data entry.
To improve the interface, Microsoft could improve tool-tips that explain the function of each tool more effectively, simplify the menu by grouping related functions together and develop a more comprehensive and easily accessible help guide. Also, adding an 'undo' button that has more stages would be helpful, as errors could be quickly rectified.
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A computer system uses passwords that are six characters and each character is one of the 26 letters (a-z) or 10 integers (0-9). Uppercase letters are not used. Let A denote the event that a password begins with a vowel (either a, e, i, o, u) and let B denote the event that a password ends with an even number (either 0, 2, 4, 6, or 8). Suppose a hacker selects a password at random. Determine the following probabilities. Round your answers to four decimal places (e.g. 98.7654).
Question continuation
Determine the following probabilities:
a. P(A)
b. P(B)
c. P(A ∩ B)
d. P(A ∪ B)
Answer:
a. P(A) = 0.1389
b. P(B) = 0.1389
c. P(AnB) = 0.0193
d. P(AuB) = 0.2585
Explanation:
Given
Password length = 6
Letters (a-z) = 26
Integers (0-9) = 10
Total usable characters = 26 + 10 = 36
a. P(A) = Probability that a password begins with vowel (a,e,i,o,u)
Probability = Number of required outcomes/ Number of possible outcomes
Number of required outcomes = Number of vowels = 5
Number of possible outcomes = Total usable characters = 36
P(A) = 5/36
P(A) = 0.13888888888
P(A) = 0.1389
b. P(B) = Probability that the password ends with an even number (0,2,4,6,8)
Probability = Number of required outcomes/ Number of possible outcomes
Number of required outcomes = Number of even numbers = 5
Number of possible outcomes = Total usable characters = 36
P(B) = 5/36
P(B) = 0.13888888888
P(B) = 0.1389
c. P(AnB)
This means that the probability that a password starts with a vowel and ends with an even number
P(AnB) = P(A) and P(B)
P(AnB) = P(A) * P(B)
P(AnB) = 5/36 * 5/36
P(AnB) = 25/1296
P(AnB) = 0.01929012345
P(AnB) = 0.0193 ----_---- Approximately
d. P(AuB)
This means that the probability that a password either starts with a vowel or ends with an even number
P(AuB) = P(A) or P(B)
P(AuB) = P(A) + P(B) - P(AnB)
P(AuB) = 5/36 + 5/36 - 25/1296
P(AuB) = 335/1296
P(AuB) = 0.25848765432
P(AuB) = 0.2585 ----_---- Approximately
Final answer:
Calculating the probability of events A and B for passwords satisfying specific conditions.
Explanation:
A denote the event that a password begins with a vowel and B denote the event that a password ends with an even number. The total number of possible passwords is 36^6 (26 letters + 10 integers). To determine the probability of A, we calculate the number of passwords that start with a vowel (5 vowels) followed by any character (36 options) for the remaining 5 characters. Similarly, to find the probability of B, we consider passwords that end with an even number (5 options) and any character for the other 5 places.
Probability of A = (5 * 36^5) / 36^6
Probability of B = (5 * 36^5) / 36^6
Give the 16-bit 2's complement form of the following 8-bit 2's complement numbers: (a) OX94 (b) OXFF (c) OX23 (d) OXBCWhich of the following 16-bit 2's complement numbers can be shortened to 8 bits and maintain their values?(a) OX00BA(b) OXFF94(c) OX0024(d) OXFF3C
Answer:
Answer is provided in the explanation section
Explanation:
Convert 8-bit 2’s complement form into 16-bit 2’s complement form.
First write value in binary then check for 8 th bit value. If it is positive the upper 8 bits will be zero otherwise will be 1s.
8-bit number Binary of number Insert 8 bits 16-bit number
0X94 1001-0100 1111-1111-1001-0100 0XFF94
0XFF 1111-1111 1111-1111-1111-1111 0XFFFF
0X23 0010-0011 0000-0000-0010-0011 0X0023
0XBC 1011-1100 1111-1111-1011-1100 0XFFBC
Which of the following 16-bit 2’s complement form can be shortened to 8-bits?
16-bit number 8-bit number
0X00BA 0XBA
0XFF94 MSB bits are not zero so we can’t truncate it to 8-bit No
0X0024 0X24
0XFF3C MSB bits are not zero so we can’t truncate it to 8-bit No
Decide what factors are important in your decision as to which computer to buy and list them. After you select the system you would like to buy, identify which terms refer to hardware and which refer to software.
Answer and explanation:
When buying a computer, there are a few factors that sould be taken into account. Those could be the following ones:
Bulkiness (hardware)Operating system (software)Processor (CPU) (hardware)RAM (Random Access Memory) (hardware)Hard drive (hardware)When deciding which computer to buy, important factors to consider are price, performance, operating system, usage, portability, and brand and support. Hardware refers to physical components, while software refers to programs and applications.
Explanation:When deciding which computer to buy, there are several factors to consider. These include:
Price: Determine your budget and choose a computer within that range.Performance: Consider the processor, memory, and storage capacity of the computer. Higher specifications usually result in better performance.Operating System: Decide whether you prefer Windows, macOS, or Linux based on your needs and preferences.Usage: Determine the purpose of the computer. Are you planning to use it for gaming, programming, video editing, or just basic tasks?Portability: Decide whether you need a desktop or a laptop based on your mobility requirements.Brand and Support: Research different brands and read reviews to ensure good customer support and reliability.After selecting the system you would like to buy, you should identify which terms refer to hardware and which refer to software. Hardware refers to the physical components of a computer, such as the hard drive, processor, memory, and motherboard. Software refers to the intangible programs or applications that run on the computer, such as operating systems, utilities, and applications.
Enables businesses and consumers to share data or use software applications directly from a remote server over the Internet or wirelessly rather than having that data file or program reside on a personal computer
Answer:
Cloud Computing
Explanation:
Cloud Computing is basically an infrastructure to deliver various computing resources and services to the users online (via Internet). These resources include networks, applications, servers, databases, software, storage etc.
These services are mostly utilized by organizations for recovery and backup of data, using virtual hardware and other computing resources such as desktops, memory etc. Cloud computing is also used for developing software, for securing data by providing with access control and for storing bulk of data.
The benefits of cloud computing are as following:
Because of cloud computing the customers do not have to buy hardware or install software on their computer which might be very costly to maintain and update. Servers and data centers are provided by cloud service providers and experts are available for managing the services and resources.
These services are scalable and can be adjusted as per the users requirements.
Cloud computing offers a variety of protocols, tools, and access controls that improve security and protects confidential data, applications, and networks against security threats and attacks. It also provides with data backup, disaster recovery.
Give an efficient algorithm to find all keys in a min heap that are smaller than a provided value X. The provided value does not have to be a key in the min heap. Evaluate the time complexity of your algorithm
Answer:
The algorithm to this question as follows:
Algorithm:
finding_small_element(element,Key xa) //defining method that accepts parameter
{
if (element.value>= xa) //check value
{
//skiping node
return;
}
print(element.value);//print value
if (element.left != NULL) //check left node value
{
finding_small_element(element.left,xa); //using method
}
if (element.right != NULL) //check right node value
{
finding_small_element(element.right,xa); //using method
}
}
Explanation:
In the above pre-order traversing algorithm a method "finding_small_element" is defined, that accepts two parameter, that is "element and ax', in which "element" is node value and ax is its "key".
Inside this if block is used that check element variable value is greater then equal to 0. In the next step, two if block is defined, that check element left and the right value is not equal to null, if both conditions are true, it will check its right and left value. In this algorithm, there is no extra need for traversing items.Final answer:
An efficient algorithm to find keys in a min heap smaller than a given value X is to use DFS, starting at the root and adding each key less than X to a result list, with the time complexity being O(n) in the worst case.
Explanation:
Finding Keys Smaller Than X in a Min Heap
To find all keys in a min heap that are smaller than a provided value X, we can use a depth-first search (DFS) algorithm. Since a min heap is a complete binary tree where the key at the root is less than or equal to the keys in its children, and this property applies recursively to subtrees, we can traverse the min heap efficiently with the following approach:
Start at the root of the min heap.If the current node's key is greater than or equal to X, return, as all keys in the subtree rooted at the current node will also be greater than or equal to X (due to heap property).If the current node's key is smaller than X, add it to the result list.Recursively apply this logic to the left and right children of the current node.The time complexity of this algorithm is O(n), where n is the number of elements in the min heap, because in the worst case, we might have to visit every node. However, thanks to the properties of the min heap, we can often avoid exploring all nodes, making the algorithm more efficient in practice than O(n).
Gwen recently purchased a new video card, and after she installed it, she realized she did not have the correct connections and was not able to power the video card.
What connector(s) should Gwen look for when purchasing a new power supply? (Select all that apply.)
a.8-pin PCI-E connector
b.Molex connector
c.24 pin connector
d.SATA connector
e.P4 MB connector
f.6-pin PCI-E connector
Answer:
A. 8-pin PCI-E connector.
F. 6-pin PCI-E connector.
Explanation:
The video card is a peripheral hardware component in a computer system that is used to run videos and graphic files, providing the required memory, runtime and bandwidth.
The PCI-e or peripheral component interconnect express is a connector or expansion slot used specifically for adding and powering video cards on a computer system.
Investigate the functions available in PHP, or another suitable Web scripting language, to interpret the common HTML and URL encodings used on form data so that the values are canonicalized to a standard form before checking or further use.
Answer:
Answer explained below
Explanation:
Solution:
Some of the PHP functions used to interpret common HTML and URL encodings are as follows:
urlencode:
This function is used for encoding a string to be used in a query part of a URL and this is used as a convenient way to pass variables to the next page of a web form.
urldecode(): Same as urlencode() but in a reverse way. It is used to decode URL-encoded string
htmlentities(): This PHP function is used to convert all applicable characters to HTML entities
html_entity_decode(): This function converts HTML entities to characters and it is the reverse form of htmlentities() function.
________ programming is a method of writing software that centers on the actions that take place in a program.
Answer: Procedural software
Explanation:
Procedural software programming is the programming mechanism that functions through splitting the data and functions of the program.This programming focuses on subroutines or action for functioning as per call of procedure.
It can carry out computation through steps in linear manner or top-to-bottom manner.These steps consist of data ,subroutines, routines and other variable and functions for working.An ATM allows a customer to withdraw a maximum of $500 per day. If a customer withdraws more than $300, the service charge is 4% of the amount over $300. If the customer does not have sufficient money in the account, the ATM informs the customer about the insufficient funds and gives the customer the option to withdraw the money for a service charge of $25.00. If there is no money in the account or if the account balance is negative, the ATM does not allow the customer to withdraw any money. If the amount to be withdrawn is greater than $500, the ATM informs the customer about the maximum amount that can be withdrawn. Write an algorithm that allows the customer to enter the amount to be withdrawn. The algorithm then checks the total amount in the account, dispenses the money to the customer, and debits the account by the amount withdrawn and the service charges, if any. (9)
Answer:
maxWithdraw = 500; //Initialise maximum withdrawal amount
Charges = 0; // Initialise Charges
Input Amount; //Customer input amount to withdraw
Get AvailableAmount; // System reads customer available amount
if (Amount >= 300)
{
Charges = (Amount -300) * 0.04; //Calculate charges when amount to withdraw is greater than or equal to 300
}
if (AvailableAmount <= 0)
{
Amount = 0; //Initialise amount to 0 if customer balance is less than or equal to 0
}
if (AvailableAmount < Amount) {
Print “You do not have sufficient funds";
Charges = 25;
}
if (Amount > 500) {
Print "Maximum withdrawal amount is $500"
}
if (Charges > 0) {
AvailableAmount -= Amount;
AvailableAmount-= Charges);
}
if (Charges = 0) {
AvailableAmount -= Amount; }
Dispense Cash.
Convert each of the following 8-bit numbers to hexadecimal and then to octal a) 10011101 b) 00010101 c) 11100110 d) 01101001
a) 10011101₂ = 9D₁₆ or 235₈
b) 00010101₂ = 15₁₆ or 025₈
c) 11100110₂ = E6₁₆ or 346₈
d) 01101001₂ = 69₁₆ or 151₈
Explanation:An hexadecimal is a group of 4bits while an octal is a group of 3 bits. They are represented in the table below;
Table for conversion;
Octal => binary
0 => 000
1 => 001
2 => 010
3 => 011
4 => 100
5 => 101
6 => 110
7 => 111
Hexadecimal => binary
0 => 0000
1 => 0001
2 => 0010
3 => 0011
4 => 0100
5 => 0101
6 => 0110
7 => 0111
8 => 1000
9 => 1001
A => 1010
B => 1011
C => 1100
D => 1101
E => 1110
F => 1111
(a)
(i) Convert 10011101 to hexadecimal
Step 1: Starting from the right, split the number into groups of 4s as follows;
1001 1101
Step 2: Convert each of the groups into its equivalent hexadecimal using the table above;
1001 = 9
1101 = D
Step 3: Put them together;
1001 1101₂ = 9D₁₆
(ii) Convert 10011101 to octal
Step 1: Starting from the right, split the number into groups of 3s as follows;
10 011 101
Step 2: The last group (10) in the result of step 1 above has only 2 bits. Therefore, add zero to its left to make it 3 bits as follows;
010 011 101
Step 3: Convert each of the groups into its equivalent octal using the table above;
010 = 2
011 = 3
101 = 5
Step 4: Put them together;
10 011 101₂ = 235₈
(b)
(i) Convert 00010101 to hexadecimal
Step 1: Starting from the right, split the number into groups of 4s as follows;
0001 0101
Step 2: Convert each of the groups into its equivalent hexadecimal using the table above;
0001 = 1
0101 = 5
Step 3: Put them together;
0001 0101₂ = 15₁₆
(ii) Convert 00010101 to octal
Step 1: Starting from the right, split the number into groups of 3s as follows;
00 010 101
Step 2: The last group (00) in the result of step 1 above has only 2 bits. Therefore, add zero to its left to make it 3 bits as follows;
000 010 101
Step 3: Convert each of the groups into its equivalent octal using the table above;
000 = 0
010 = 2
101 = 5
Step 4: Put them together;
00 010 101₂ = 025₈
(c)
(i) Convert 11100110 to hexadecimal
Step 1: Starting from the right, split the number into groups of 4s as follows;
1110 0110
Step 2: Convert each of the groups into its equivalent hexadecimal using the table above;
1110 = E
0110 = 6
Step 3: Put them together;
1110 0110₂ = E6₁₆
(ii) Convert 11100110 to octal
Step 1: Starting from the right, split the number into groups of 3s as follows;
11 100 110
Step 2: The last group (11) in the result of step 1 above has only 2 bits. Therefore, add zero to its left to make it 3 bits as follows;
011 100 110
Step 3: Convert each of the groups into its equivalent octal using the table above;
011 = 3
100 = 4
110 = 6
Step 4: Put them together;
11 100 110₂ = 346₈
(d)
(i) Convert 01101001 to hexadecimal
Step 1: Starting from the right, split the number into groups of 4s as follows;
0110 1001
Step 2: Convert each of the groups into its equivalent hexadecimal using the table above;
0110 = 6
1001 = 9
Step 3: Put them together;
0110 1001₂ = 69₁₆
(ii) Convert 01101001 to octal
Step 1: Starting from the right, split the number into groups of 3s as follows;
01 101 001
Step 2: The last group (01) in the result of step 1 above has only 2 bits. Therefore, add zero to its left to make it 3 bits as follows;
001 101 001
Step 3: Convert each of the groups into its equivalent octal using the table above;
001 = 1
101 = 5
001 = 1
Step 4: Put them together;
01 101 001₂ = 151₈
Write a program that uses a two dimensional array to store the highest and lowest temperatures for each month of the calendar year. The temperatures will be entered at the keyboard. This program must output the average high, average low, and highest and lowest temperatures of the year. The results will be printed on the console. The program must include the following methods:
Answer:
Java program is explained below with appropriate comments
Explanation:
Temperature.java
import java.util.Scanner;
public class Temperatures {
public static Scanner keyboard = new Scanner(System.in);
private static int highTemperature, lowTemperature,averageHigh, averageLow;
private static int index;//keeps track of months
private static int indexOfHighestTemp=0, indexOfLowestTemp=0;
private static int[][] highAndLowTemps = new int [12][2];//array for highs and lows
private static String[] months = new String[12];//array of monthss
public static void main(String[] args) {
inputTempForYear();
calculateAverageHigh(highAndLowTemps);
calculateAverageLow(highAndLowTemps);
findHighestTemp(highAndLowTemps);
findLowestTemp(highAndLowTemps);
//outputs results
System.out.println("Average High: "+averageHigh);
System.out.println("Average Low: "+averageLow);
System.out.println("Highest Temp and Month: "+highAndLowTemps[indexOfHighestTemp][0]+" "+months[indexOfHighestTemp]);
System.out.println("Lowest Temp and Month: "+highAndLowTemps[indexOfLowestTemp][1]+" "+months[indexOfLowestTemp]);
}
private static void inputTempForMonth(int[][] highAndLowTemps)
{
System.out.println("Input the high temperature for "+months[index]+":");
highTemperature = keyboard.nextInt();//inputs months high temp
highAndLowTemps[index][0]=highTemperature;
System.out.println("Input the low temperature for "+months[index]+":");
lowTemperature = keyboard.nextInt();//inputs months low temp
highAndLowTemps[index][1]=lowTemperature;
}
private static int[][] inputTempForYear()
{
months[0]="January";
months[1]="Febuary";
months[2]="March";
months[3]="April";
months[4]="May";
months[5]="June";
months[6]="July";
months[7]="August";
months[8]="September";
months[9]="October";
months[10]="November";
months[11]="December";//fills month array
for (index=0;index<=11;index++)//fills array with highs and lows
{
inputTempForMonth(highAndLowTemps);
}
return highAndLowTemps;
}
private static int calculateAverageHigh(int[][] highAndLowTemps)
{
for(int i=0;i<=11;i++)//finds sum of high temps
{
averageHigh=averageHigh+highAndLowTemps[i][0];
}
averageHigh/=12;//calculates average
return averageHigh;
}
private static int calculateAverageLow(int[][] highAndLowTemps)
{
for(int i=0;i<=11;i++)//finds sum of low temps
{
averageLow=averageLow+highAndLowTemps[i][1];
}
averageLow/=12;//calculates average
return averageLow;
}
private static int findHighestTemp(int[][] highAndLowTemps)
{
double max=highAndLowTemps[0][0];
int indexHigh;//index for highest
for(indexHigh=0;indexHigh<11;indexHigh++)//find highest high temp
{
if(highAndLowTemps[indexHigh][0]>max)
{
max=highAndLowTemps[indexHigh][0];
indexOfHighestTemp=indexHigh;
}
}
return indexOfHighestTemp;
}
private static int findLowestTemp(int[][] highAndLowTemps)
{
double min=highAndLowTemps[0][1];
int indexLow;//index for lowest
for(indexLow=0;indexLow<11;indexLow++)//finds lowest low temp
{
if(highAndLowTemps[indexLow][1]<min)
{
min=highAndLowTemps[indexLow][1];
indexOfLowestTemp=indexLow;
}
}
return indexOfLowestTemp;
}
}
Create a list of student names from area code 203 along with the number of years since they registered (show 2 decimal places on all values).
Sort the list on the number of years from highest to lowest and then on student name.
NOTE that the calculated number of years will vary from the expected results depending on when the query is run.
Answer:
Answer is provided in the explanation section
Explanation:
1. For testing this query, first create a table:
CREATE TABLE STUDENT (NAME CHARACTER(25), ROLLNO int PRIMARY KEY, AREACODE int, REGD_YEAR date)
2. Insert some data for checking the query
insert into student values(101,'Mark',203,'03-12-1997')
insert into student values(106,'Zack',204,'06-18-1992')
insert into student values(104,'Jess',203,'01-11-1995')
3. Select query for creating a list of student names from area code 203
SELECT NAME AS "Student Name", AREACODE, REGD_YEAR
FROM STUDENT
WHERE AREACODE LIKE '203%'
ORDER BY “REGD_YEAR“,”Student Name”;
2.Consider the following algorithm and A is a 2-D array of size ???? × ????: int any_equal(int n, int A[][]) { int i, j, k, m; for(i = 0; i < n; i++) for( j = 0; j < n; j++) for(k = 0; k < n; k++) for(m = 0; m < n; m++) if(A[i][j]==A[k][m] && !(i==k && j==m)) return 1 ; return 0 ; } a. What is the best-case time complexity of the algorithm (assuming n > 1)? b. What is the worst-case time complexity of the algorithm?
Answer:
(a) What is the best case time complexity of the algorithm (assuming n > 1)?
Answer: O(1)
(b) What is the worst case time complexity of the algorithm?
Answer: O(n^4)
Explanation:
(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1) .
(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).