Speed cell wireless offers a plan of $40 for the first 400 minutes, and an additional $0.50 for every minute over 400. Let t represent the total talk time in minutes. Write a piecewise-defined function to represent the cost C(t)

Answer:

Yes, because −8c = 2(−4c) and −4c is an integer

Step-by-step explanation:

We want to determine whether [tex]-8c[/tex] is an even integer.

Recall that even integers are of the form: [tex]2n[/tex]

Let us see if we can rewrite the given expression in the form 2n, where n is an integer.

Let us factor 2 to get:

[tex]-8c=2(-4c)[/tex]

If -4c is an integer and we let m=-4c,then

[tex]-8c=2(m)=2m[/tex], where m is an integer.

Therefore the answer is Yes, because −8c = 2(−4c) and −4c is an integer

Answer:

  a. Slant asymptote with a slope of 5

Step-by-step explanation:

Dividing out the polynomials, you get ...

  [tex]\dfrac{5x^2-x+13}{x+10}=5x-51+\dfrac{523}{x+10}[/tex]

As the magnitude of x gets large, the fraction goes to zero, and the behavior matches the line ...

  y = 5x -51

This is a slant asymptote with a slope of 5 and a non-zero y-intercept.

It's 1.25 seconds, I just took the test and got 100% Good Luck!!! :)

Answer:

Type of music      Country  Rock & roll  Blues  

Observed number   11            17                 8      

Probabilities P(x)      11/36     17/36           8/36  

Step-by-step explanation:

The probabilities can be calculated as

P(x)= observed number of times/ Total number of times.

The probability distribution for the type of music restaurant playing is

Type of music   Country  Rock & roll  Blues  Total

Observed number 11            17                 8         36

Probabilities P(x)      11/36     17/36           8/36      1

Answer:

x = 28.5 minutes

Step-by-step explanation:

Let x be the time taken for finishing the bike race.

Given:

Ella finished a bike race = 37.6 minutes

Miranda finished the race sooner than Ella = [tex]9\frac{1}{10} = \frac{91}{10} = 9.1\ minutes[/tex]

We need to find the minutes did it take Miranda to finish the race.

Solution:

From the statement, Miranda finished the race 9.1 minutes sooner than Ella finished it while Ella finished the same bike race in 37.6 minutes.

So, time taken by Miranda to finish the race:

[tex]Mirianda\ finshed\ a\ bike\ race = (Ella\ finshed\ a\ bike\ race) - 9.1[/tex]

[tex]x=37.6-9.1[/tex]

x = 28.5 minutes

Therefore, Miranda finished the bike race in 28.5 minutes.

Answer:

[tex] \% Change = \frac{|28-32|}{32} *100 = 12.5\%[/tex]

(B) Decrease by 12.5%

Step-by-step explanation:

For this case we know that the revolution is proportional to the circumference.

And we know that the average number of revolutions of 32 inch tires for Tuesday is higher than the original value of 28 inch tires for Monday.

We know that we have x mi/hr, so we can select a value fo x in order to find the average revolutions with the following formula:

[tex] Avg = \frac{x}{mi}[/tex]

Let's say that we select a value for x for example x= 28*32 = 896, since this value is divisible by 32 and 28.

If we find the average revolutions per each case we got:

Tuesday:

[tex] Avg = \frac{896}{32}=28[/tex]

Monday:

[tex] Avg = \frac{896}{28}=32[/tex]

And then we can find the % of change like this:

[tex] \% Change= \frac{|Final-Initial|}{Initial} *100[/tex]

And if we replace we got:

[tex] \% Change = \frac{|28-32|}{32} *100 = 12.5\%[/tex]

Because we are assuming that the initial amount is the value for Monday and the final value for Tuesday.

So then the best answer for this case would be:

(B) Decrease by 12.5%

Answer:

The maximum of the sinusoidal function is 5.

Step-by-step explanation:

The maximum of the sinusoidal function is 5.

Answer:

4 pounds of strawberries and 5 pounds of apples are bought.

Step-by-step explanation:

Given:

Total number of pounds of fruit = 9 pounds

Total money spent = $16.35

Cost of 1 pound of strawberry = $1.60

Cost of 1 pound of apple = $1.99

Let 'x' pounds of strawberries and 'y' pounds of apples are bought.

So, as per question:

The sum of the pounds is 9. So,

[tex]x+y=9\\\\y=9-x----1[/tex]

Now, total sum of the fruits is equal to the sum of 'x' pounds of strawberries and 'y' pounds of apples. So,

[tex]1.60x+1.99y=16.35----2[/tex]

Now, plug in the 'y' value from equation (1) in to equation (2). This gives,

[tex]1.60x+1.99(9-x)=16.35\\\\1.60x+17.91-1.99x=16.35\\\\Combining\ like\ terms, we get:\\\\1.60x-1.99x=16.35-17.91\\\\-0.39x=-1.56\\\\x=\frac{-1.56}{-0.39}=4\ pounds[/tex]

Now, from equation 1, we have:

[tex]y=9-4=5\ pounds[/tex]

Therefore, 4 pounds of strawberries and 5 pounds of apples are bought.

If they were to win $30 they would expect to get $27 in profit.

If they were to win $10 they would expect $7.

If they were to win $0 they would expect $-3 in profit, so technically if they win nothing they lose money.

Hope I could help! :D

If player expect to get out of this game every time he/she plays then they would loose money.

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics.

The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The degree to which something is likely to happen is basically what probability means.

Given:

If a player rolls 2 dice and gets a sum of 2 or 12, he wins $30.

and, If they were to win $30, they would anticipate making a profit of $27.

Also, if they would anticipate $7 if they were to win $10.

So, if they were to win nothing, they would lose money because they would expect to make $-3 in profit.

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Answer:

Answer is (A) One-half times 14 times 57

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

we can use the variable c to represent the monthly cost

75+0.17x=c

Step-by-step explanation:

The expression shows the monthly cost for the phone if x represents the number of minutes if The cost for a cell phone service is $75 per month plus $0.17 per minute, is y = 75 + 0.17x.

An assertion that two mathematical expressions have equal values is known as an equation. An equation simply states that two things are equal. The equal to sign, or "=," is used to indicate it.

Given:

The cost for a cell phone service is $75 per month plus $0.17 per minute,

Write the equation as shown below,

Total cost = Cost for a month + per minute charge × total use in minutes,

Assume the total cost is y, and the use of minute is x then,

y = 75 + 0.17 × x

y = 75 + 0.17x

Thus,  the monthly cost for the phone is 75 + 0.17x.

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Answer:

The max altitude you can operate an sUAS on these given conditions is 1400ft AGL.

Step-by-step explanation:

Final answer:

The sUAS can fly at a maximum altitude of 1,100 feet AGL when inspecting a tower with a top at 1,000 feet AGL, assuming it stays within 100 feet of the tower as per 14 CFR Part 107.

Explanation:

In accordance with 14 CFR Part 107, specifically considering sUAS (small Unmanned Aircraft Systems) operations around structures, there are specific altitude regulations. When a drone operator is inspecting a tower, and the drone is within 100 feet laterally of the structure, the drone can operate above the standard 400 feet above ground level (AGL) limit. For a tower with a top at 1,000 feet AGL, the sUAS can fly at a maximum altitude of 1,100 feet AGL, assuming it stays within 100 feet of the structure. This is possible because the regulations allow the sUAS to fly 400 feet above the structure's uppermost limit when it is within a close radius of the structure.

Answer:

Option A:    [tex]$ \frac{\textbf{2}}{\textbf{9}} $[/tex]

Step-by-step explanation:

Given there are 10 cards viz: 1, 2, 3, 4, . . . , 10

We find the probability of drawing two cards less than six, without replacing the first card.

Draw 1:

There are 5 cards with value less than 6. 1, 2, 3, 4, 5

The total number of cards is 10.

The probability of the number being less than 6 = [tex]$ \frac{number \hspace{1mm} of \hspace{1mm} cards \hspace{1mm} less \hspace{1mm} than \hspace{1mm} 6}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards} $[/tex]

[tex]$ = \frac{5}{10} $[/tex]

Draw 2:

We are again drawing a card without replacing the card that was drawn earlier. This makes the total number of cards 9.

Also, the number of cards less than 6 will now be: 4.

Therefore, probability of drawing a number less than 6 without replacing

[tex]$ = \frac{4}{9} $[/tex]

Since, both draw 1 and draw 2 are happening we multiply the two probabilities. We get

[tex]$ \textbf{P} \hspace{1mm} \textbf{=} \hspace{1mm} \frac{\textbf{5}}{\textbf{10}} \hspace{1mm} \times \hspace{1mm} \frac{\textbf{4}}{\textbf{9}} $[/tex]

[tex]$ \therefore P = \frac{\textbf{2}}{\textbf{9}} $[/tex]

Hence, OPTION A is the required answer.

Answer: p=11

Step-by-step explanation:

12p+7)139

-7 -7

12p)132

÷12 ÷12

P)11

Answer:

p= 11

Step-by-step explanation:

1 2p + 7 > 1 39​

collection of like term

12p > 139 - 7

12p > 132

Divide both side by the coefficient of p

12p/12 > 132/12

p = 11

Answer:

SinƟ  = 12/37

CosƟ    =35/37

TanƟ = 12/35

Step-by-step explanation:

The diagram of the triangle is attached

Using SOH CAH TOA

SinƟ = Opposite/Hypotenuse

SinƟ  = 12/37

CosƟ= adjacent/Hypo tenuse

CosƟ    =35/37

TanƟ=Opposite/Adjacent

TanƟ = 12/35

Answer:

The answer is x = -6.6

Step-by-step explanation:

Answer:

X= -6.6

Step-by-step explanation:

Just do 13.8 - 20.4. It will equal -6.6.

Answer:

615 children tickets

195 adults tickets

Step-by-step explanation:

Let the number of children’s tickets be c and the number of adult tickets be a.

Children’s ticket is $3 and adult’s is $5 for a total of $2,820. This means:

3c + 5a = 2,280

This is the first equation.

The number of children’s tickets sold is 30 more than 3 times that of the adults. This means

c = 3a + 30.

This is equation ii. We now substitute ii into I to yield:

3(3a+ 30) + 5a = 2,820

9a + 90 + 5a = 2,820

14a + 90 = 2,820

14a = 2820 - 90

14a = 2730

a = 2730/14 = 195 tickets

c = 3a + 30

c = 3(195) + 30 = 615

Final answer:

By setting up a system of equations based on the total sales and the relationship between the number of adult and children's tickets sold, we can solve to find that Galen sold 130 adult tickets and 420 children's tickets for the church's carnival which is 195.

Explanation:

The question involves finding the number of children's and adult tickets sold by Galen for a church's carnival, given the total sale amount and the price of each ticket type. To solve this, we can set up a system of equations based on the information provided:

Let x be the number of adult tickets sold and y be the number of children's tickets sold. The problem statements can be translated into two equations:

Substituting the second equation into the first gives us:

3(3x + 30) + 5x = 2820

Solving for x, we find that Galen sold 130 adult tickets. Using the relationship between x and y, we then find that 420 children's tickets were sold.

14x= 2730

x=195.

Answer:

Distance = 44 m

Change in position = 0 m

Step-by-step explanation:

Given:

Running around the house covering a total length of 44 m and reaching the same position where you started.

So, initial position is same as final position.

Change in position is given as:

Change = Final position - Initial position

Now, since, final position = Initial position.

So, Change in position = 0 m

Now, distance is the total length of the path covered. So, you started from your initial position and ran around the house covering a path length of 44 m before reaching the same starting position.

Therefore, the distance is equal to the path length and hence is equal to 44 meters

Answer:

X+y=237Litres

Step-by-step explanation:

Let a be mixture of milk and water.

Let x =milk

Let y= water

z = x+y

Final volume of mixture =63litres + z

5/12(3+z))+60=8/15(63-z)

z =x+y= 237litres

The value of [tex]x+y[/tex] is 237 liters.

Given information:

A 63 liter mixture contains milk and water in a ratio of 4:5.

Let the initial amount of water be a. So, the amount of milk will be [tex]63-a[/tex].

The initial mixture can be written as,

[tex]\dfrac{63-a}{a}=\dfrac{4}{5}[/tex]

The initial amount of water and milk will be,

[tex]\dfrac{63-a}{a}=\dfrac{4}{5}\\315-5a=4a\\9a=315\\a=35\\63-a=28[/tex]

x liters of milk and y liters of water are added to the mixture, resulting in a milk to water ratio of 7:5.

The mixture, now, can be written as,

[tex]\dfrac{28+x}{35+y}=\dfrac{7}{5}\\140+5x=245+7y[/tex]

60 liters of the mixture are drained and replaced with 60 liters of water, resulting in a milk to water ratio of 7:8.

Draining will release the amount of water and milk in the ratio 7:5 which is its concentration. So, 35 liters of milk and 25 liters of water will be drained.

The final mixture can be written as,

[tex]\dfrac{28+x-35}{35+y-25+60}=\dfrac{7}{8}\\\dfrac{x-7}{y+70}=\dfrac{7}{8}\\8x-56=7y+490[/tex]

Solve for x and y as,

[tex]140+5x=245+7y\\8x-56=7y+490\\3x-196=245\\x=147\\y=90[/tex]

So, the value of [tex]x+y[/tex] will be,

[tex]x+y=147+90\\=237[/tex]

Therefore, the value of [tex]x+y[/tex] is 237 liters.

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To figure this out, use the acronym SOHCAHTOA to determine which trigonometric function to use.

8 is opposite to <R and 3 is adjacent to <R so we use tangent.

Set up the following equation: tan(x)=8/3

Find the inverse (aka. tan^-1): x=69.44

So your answer is <R=69.4 degrees

Hope this helped!

Answer:

sin 80

Step-by-step explanation:

Answer:

P=0.00564

Step-by-step explanation:

From Exercise we have  52 cards.

We calculate the number of combinations to draw 5 cards from a deck of 52 cards. We get

{52}_C_{5}=\frac{52!}{5!(52-5)!}=2598960

We now count the number of favorable combinations:

{13}_C_{1} · {48}_C_{2}= 13 · \frac{48!}{2!(48-2)!}=14664

Therefore, the probabilitiy is

14664/2598960=0.00564

P=0.00564

Answer:

x = 0.8 Mi

Step-by-step explanation:

for x = 4224 ft we can use the factor (1 Mi/5280 ft)

then

x = 4224 ft (1 Mi/5280 ft) = 0.8 Mi

Answer:

The vertex of the function is at point (-4,-1).

Step-by-step explanation:

Given function:

[tex]f(x)=(x+4)^2-1[/tex]

Solution:

The vertex form of a function is given by:

[tex]f(x)=a(x-h)^2+k[/tex]

where [tex](h,k)[/tex] is the vertex of the function. At this point the function has the maximum or minimum value.

Writing the given function in the vertex form.

[tex]f(x)=(x-(-4))^2+(-1)[/tex]

On comparing the above function with the standard form we find that:

[tex]a=1\\h=-4\\k=-1[/tex]

Thus, the vertex of the function is at point (-4,-1)

The vertex of the function f(x)= (x + 4)² - 1 is at the point (-4,-1) by comparing it with the vertex form of a quadratic function f(x) = a(x - h)² + k.

The function given is in the vertex form of a quadratic function, which is f(x) = a(x - h)² + k. In this form, the vertex of the graph of the function is at the point (h, k). For f(x)=(x + 4)² - 1, you can see that h is -4 and k is -1. Therefore, the vertex of the graph of the function is at the point (-4,-1).

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Answer:

Weinstein, McDermott, and Roediger (2010) conducted an experiment to evaluate the effectiveness of different study strategies.

One part of the study asked students to prepare for a test by reading a passage.

In one condition, students generated and answered questions after reading the passage.

In a second condition, students simply read the passage a second time.

All students were then given a test on the passage material and the researchers recorded the number of correct answers.

a. Identify the dependent variable for this study:

   The dependent variable for this study is effectiveness.    

b. Is the dependent variable discrete or continuous?

   The dependent variable is discrete.

c. What scale of measurement (nominal, ordinal, interval, or ratio) is used to measure the dependent variable?

   The scale of measurement is ratio scale.

Step-by-step explanation:

a) To identify the dependent variable you need to find the item, circumstance, concept, sense, time frame, or any category in an specific scientific research, that is going to be measured. In this particular case, the dependent variable measured is the effectiveness of the different study strategies used based by the number of correct answers on a test. This variable could be influenced by independent variables also.

b) The method by which we obtain the resulting values make the difference between a discrete variable and a continuous variable. If measuring is the used method, then it is a continuous variable, but if counting is the utilized method to get the correct number of correct answers, as it is stated in this case, then it is a discrete, finite and countable.

c) The measurements´ accuracy are given by the different scales or levels and they are classified as:

- Nominal

- Ordinal

- Interval

- Ratio

Interval and ratio scales data are similiar is also known as called metric, sharing units, and represent quantiy., therefore the scale of measurement used in this study is ratio scale.

Answer:

The correct answer is compress the graph closer to the x axis

reflect the graph over the x axis

translate the graph to the right

Step-by-step explanation:

I just took the test

The correct answer is (A)(C)(G) because to transform the graph, we first reflect it over the x-axis, then translate it to the right, and finally compress it closer to the x-axis.

To determine the transformations applied to the graph of [tex]\( f(x) = \sqrt[3]{x} \)[/tex] to obtain the graph of [tex]\( g(x) = -\frac{1}{2} \sqrt[3]{x-9} \)[/tex], let's analyze each component of the transformation step-by-step.

Given [tex]\( f(x) = \sqrt[3]{x} \)[/tex] and [tex]\( g(x) = -\frac{1}{2} \sqrt[3]{x-9} \)[/tex], the transformations are as follows:

1. Horizontal Shift:

The term [tex]\( x-9 \)[/tex] inside the function indicates a horizontal shift.

Specifically, it shifts the graph to the right by 9 units.

2. Vertical Compression and Reflection:

The coefficient [tex]\( -\frac{1}{2} \)[/tex] outside the cube root function indicates a vertical transformation.

The negative sign reflects the graph over the x-axis.

The factor [tex]\( \frac{1}{2} \)[/tex] compresses the graph closer to the x-axis.

The complete question is:

Which transformations have been performed on the graph of [tex]f(x)=\sqrt[3]{x}[/tex] to obtain the graph of [tex]g(x)= -\frac{1}{2} \sqrt[3]{x-9}[/tex] ?

A. reflect the graph over the x-axis.

B. translate the graph down.

C. translate the graph to the right.

D. translate the graph up.

E. stretch the graph away from the x-axis.

F. translate the graph to the left.

G. compress the graph closer to the x-axis.

Answer:

Hence,

The measure of ∠A is 60.065°

[tex]\m\angle A= 60.065[/tex]

Step-by-step explanation:

Given:

ΔABC is a Right Angle Triangle at ∠ B = 90°

BC = Opposite side to ∠A = 13 unit

AC = Hypotenuse  = 15 unit  

To Find:

m∠A = ?  

Solution:

In Right Angle Triangle ABC ,Sine Identity,

[tex]\sin A= \dfrac{\textrm{side opposite to angle A}}{Hypotenuse}\\[/tex]

Substituting the values we get

[tex]\sin A= \dfrac{BC}{AC}=\dfrac{13}{15}=0.8666\\\angle A=\sin^{-1}(0.8666)\\m\angle A= 60.065\°[/tex]

Hence,

The measure of ∠A is 60.065°

[tex]\m\angle A= 60.065[/tex]

Answer:

4(√2.5)x

Step-by-step explanation:

Let each side of the dragonal be P

Bringing out a Triangle out of the rhombus we have a right angle triangle with the base of x/2 and height of 3/2x.

And the hypothenus is P.

Applying Pythagoras theorem we have

p ^2= (1.5x)^2+(0.5X)^2

p ^2= 2.25X^2 +0.25X^2

P = (√2.5) X

Since the Rhombus consist of 4 triangles . The perimeter can best be expressed as 4 x the perimeter of the triangle.

P= 4(√2.5)x.

The longer diagonal of a rhombus is three times the length of the shorter diagonal. The expression that gives the perimeter of the rhombus cannot be determined with the information provided.

The perimeter of a rhombus can be found by adding the lengths of all four sides. In this case, the longer diagonal of the rhombus is three times the length of the shorter diagonal, which is represented by x. So, the shorter diagonal is x and the longer diagonal is 3x.

Since the longer diagonal of a rhombus creates two congruent right triangles, we can use the Pythagorean theorem to find the length of its sides. The Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. So, for one of the right triangles, the hypotenuse is 3x and the two sides are x. Using the Pythagorean theorem, we have:

x² + x² = (3x)²

2x² = 9x²

2 = 9

This equation is not true, which means that x cannot be the length of the shorter diagonal.

Therefore, since the given information is incorrect, we cannot find the expression that gives the perimeter of the rhombus.

Answer:

All statements are correct for two congruent triangles

Step-by-step explanation:

If two triangles are congruent than the rules states that

Triangles are congruent when all corresponding sides and interior angles are congruent. The triangles will have the same shape and size, but one may be a mirror image of the other.

As the fig shows two triangle

Δ PQR

Δ LMN

All three corresponding sides of triangle are congruent

all three corresponding  angles are congruent

Both triangle are of same size

Both are of same shape

hence all the statements are CORRECT

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Answer:

D. Isosceles trapezoid

Step-by-step explanation:

Answer: The answer is D. Isosceles trapezoid