Solve for u. -24 = u ÷ 6

u = ____

Answer:

6 sq root 5

Step-by-step explanation:

Answer:

6sqrt(5)

Step-by-step explanation:

Both of these expressions are a number times the square root of 5. By definition, we can simply add the coefficients as these are like terms.

Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

[tex]a_1=12 \\ a_n=a_{n-1}+4.[/tex]

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

[tex]a_1=20\\ a_n=a_{n-1} - 5[/tex]

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

A line is graphed in the x-y plane and it will follow a path of straight line and equation for that is,  Y = (-3/2)X.

So option (C) is correct.

The equation of a straight line is a relationship between x and y coordinates, The equation of a straight line is y = mx + c, where m is the slope of the line and c is the y-intercept.

The net change in y coordinate is written as, Δy and the net change in x coordinate is written as, Δx.

m = change in y coordinate/change in x coordinate = Δy/Δx = y2-y1/x2-x1

In given graph,

Line is passing through the points (2, -3) & (-2 ,3)

Slope = -3-3/2-(-2)

Slope = -3/2

y = (-3/2) x + c  ____(i)

by putting point (2, -3) in  equation (i)

-3 = (-3/2) 2 + c

c = 0

Hence, The equation is  Y = (-3/2)X

To know more about the equation of line check:

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Answer:

200

Step-by-step explanation:

50 or more round up

49 and down you round to the last whole hundred or number

hope this helped please mark brainliest and rate

x = 3

Step-by-step explanation:

First we would simplify the left hand side of the equation by expanding the brackets

so 2(4-3x) = 8-6x and

5(2x-3) = 10x-15

This gives the left hand side as 8-6x+10x-15. So the overall equation becomes

8-6x+10x-15 = 20-5x.

Grouping the unknown values on one side and integers on one side of the equation gives us

8-15-20=6x-10x-5x (note the sign changes when numbers and unknown values are moved to the other side of the = sign

Solving further, -27 = -9x i.e x = -27/-9 = 3

Hence x = 3

Answer:

3

Step-by-step explanation:

Answer:

Your goal here is to get x by itself

-10x-1=11-9x Add 1 to each side

-10x-1+1=11+1-9x

-10x=12-9x Add 9x to each side

-10x+9x=12-9x+9x

-1x=12 Divide each side by -1

-1x/-1=12/-1

x=-12

Hope this helps ;)

Answer:

Step-by-step explanation:

$3,400*2.5%*3=$255

To calculate the simple interest on $3,400 at a 2.5% interest rate over 3 years, the formula I = P  imes r  imes t is used, which results in $255 of interest earned in that period.

To calculate the simple interest earned by a checking account with $3,400 at a 2.5% annual interest rate over 3 years, we use the formula for simple interest:

I = P times r times t

where:

Let's plug in the values:

I = $3,400 times 0.025 times 3

I = $85 times 3

I = $255

So, the account will earn $255 in simple interest over 3 years.

Answer: 1/4

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

i had the same question and 1/4 was right

Answer:

Explanation:

I will rewrite the table to understand how the process of solving using succesive approximations is.

Table:

x        f(x)      g(x)

0        - 5      - 6

1         - 3       - 5

2        - 1       - 2

3          1          3

Those are the points shown in the table.

Now you must continue the process of solving using successive approximations until you find the positive solution to the nearest tenth.

You need to determine whether a "guess" is closer or farther away of the solution.

The first row shows that g(x) is less than f(x) in 1 unit when x = 0 ( -6 - (-5) ) = -1.

The second raw shows that g(x) is less than g(x) in 2 units when x = 1 ( - 5 - (-3) ) = - 2

The third row shows that g(x) is is less than f(x) in 1 unit when x = 2 ( - 2 - (-1) ) = - 1.

The fourth row shows that g(x) is than f(x) in 2 units when x = 3 ( 3 - 1 = 2).

Hence, the trend changed form negative to positive, meaning that, since the functions are continous, there must be an intertemediate value of x (between x = 2 and x = 3) for which f(x) = g(x) and that is the solution.

Therefore, test x = 2.5

Test for x = 2.4

Now the difference is less than 0.1 and the solution to the nearest tenth is (2.4, - 0.2).

Answer:

answer is 2.7

Step-by-step explanation:

I got it right

The item most likely to be bought with an installment loan is A. A couch, as installment loans are used for significant purchases paid over time. Groceries, calculators, and school books are generally less expensive and paid for upfront.

The question posed is, "Which of these items are you most likely to buy with an installment loan?" The correct answer is A. A couch. Installment loans are typically used for larger purchases that require payment over time. These include items such as furniture, cars, and appliances.

On the other hand, groceries (B), calculators (C), and school books (D) are generally more affordable and are usually paid for upfront rather than through installment loans. Installment loans often come with interest, making them more suitable for more expensive items that cannot be paid for in full immediately.

It is essential to carefully consider the necessity and the ability to repay before taking out any loan, especially for substantial purchases like a couch, to avoid financial strain.

See picture for solution to your problem.

At the same rate, the bakery would sell approximately 10 loaves of bread for every 7 rolls.

The bakery sells 25 rolls for every 35 loaves of bread. To find out how many loaves of bread will be sold for every 7 rolls of bread, we need to use a simple proportion based on the given ratio. This can be set up as a fraction, 25 rolls/35 loaves = 7 rolls/x loaves, where x represents the number of loaves sold for every 7 rolls.

We can solve for x by cross-multiplying:

(25 rolls/35 loaves) = (7 rolls/x loaves),

so 25x = 35*7.

The next step is to divide both sides of the equation by 25 to solve for x:

x = (35*7)/25 = 9.8 loaves.

Therefore, the bakery would sell approximately 10 loaves of bread for every 7 rolls, given the same rate.

Answer:

[tex]a_1=7[/tex]

[tex]a_2=7\\a_3=10\\a_4=13\\a_5=16[/tex]

Step-by-step explanation:

The arithmetic series is [tex]S_{5}=\sum_{k=1}^5(1+3k)[/tex]

From the given series the general term of the series is [tex]a_k=1+3k[/tex]

When [tex]k=1[/tex], we substitute into the general formula to get:

[tex]a_1=1+3(1)=4[/tex]

When k=2, we get: [tex]a_2=1+3(2)=7[/tex]

When k=3, we substitute to get:

[tex]a_3=1+3(3)=10[/tex]

When k=4, we substitute to get:

[tex]a_4=1+3(4)=13[/tex]

When k=5, we get:

[tex]a_5=1+3(5)=16[/tex]

Answer:

a1= 4

a2=7

a3=10

a4=13

a5=16

s5=50

Step-by-step explanation

Answer:

a+8 x 2

Step-by-step explanation:

Lucy= a

Jacob= 8 + a

½ Jayne= Jacob or Jayne= 2 Jacob

½ Jayne= 8 + a

Jayne= (8+a)2

= 16 + 2a

(A)  4 sec the ball is in the air.

(B) Height of the ball = 49 ft.

(C) Yes, the ball is at its maximum height at 1.5 seconds.

Solution:

Given data:

[tex]h(t)=-16t^2+48t+64[/tex]

Initial velocity = 48 ft/s

Height = 64 ft

(A)  [tex]-16t^2+48t+64=0[/tex]

a = –16, b = 48, c = 64

We can solve it by using a quadratic formula,

[tex]$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{(48)^{2}-4 \times(-16)(64)}}{2(-16)}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{2304+4096}}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{6400}}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm 80}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 + 80}{-32},\frac{-48 - 80}{-32}[/tex]

[tex]$\Rightarrow t=-1,t=4[/tex]

Time cannot be in negative. So neglect t = –1

t = 4 sec

Hence, 4 sec the ball is in the air.

(B) When t = 1.5 sec,

[tex]h(1.5)=-16(1.5)^2+48(1.5)+64[/tex]

h(1.5) = 49 ft

(C) The maximum height occurs at the average of zeros.

Average = [tex]\frac{(-1+4)}{2}=1.5[/tex] sec

Yes, the ball is at its maximum height at 1.5 seconds.

Answer:

Part 1) [tex]z=121^o[/tex]

Part 2) [tex]x=59^o[/tex]

Part 3) [tex]y=49^o[/tex]

Part 4) [tex]w=72^o[/tex]

Step-by-step explanation:

step 1

Find the measure of angle z

we know that

The sum of exterior angles in a polygon is always equal to 360 degrees

so

[tex]z^o+(z+10)^o+(z-13)^o=360^o[/tex]

solve for z

[tex](3z-3)^o=360^o[/tex]

[tex]3z=363\\z=121^o[/tex]

step 2

Find the measure of angle x

we know that

[tex]z^o+x^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]121^o+x^o=180^o[/tex]

[tex]x=180^o-121^o=59^o[/tex]

step 3

Find the measure of angle y

we know that

[tex]y^o+(z+10)^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]y^o+(121+10)^o=180^o[/tex]

[tex]y=180^o-131^o=49^o[/tex]

step 4

Find the measure of angle w

we know that

[tex]w^o+(z-13)^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]w^o+(121-13)^o=180^o[/tex]

[tex]w=180^o-108^o=72^o[/tex]

Answer:

Andre scored 14 points in the game.

Step-by-step explanation:

Question :

Diego scored 9 points less than Andre in the basketball game. Noah scored twice as many points as Diego. If

Noah scored 10 points, how many points did Andre score?

Given:

Diego scored 9 points less than Andre in the basketball game.

Noah scored twice as many points as Diego.

Noah scored 10 points

To find Andre's points.

Solution:

Let Andre's score be = [tex]x[/tex] points

Then, Diego's points will be = [tex](x-9)[/tex] points

Noah's points will be = [tex]2(x-9)[/tex] points

Noah's points given = 10 points.

Thus, the equation can be given as:

[tex]2(x-9)=10[/tex]

Solving for [tex]x[/tex].

Dividing both sides by 2.

[tex]\frac{2(x-9)}{2}=\frac{10}{2}[/tex]

[tex]x-9=5[/tex]

Adding 9 both sides.

[tex]x-9+9=5+9[/tex]

∴ [tex]x=14[/tex]

Thus, Andre scored 14 points in the game.

The score of Andre and Diego is 14 and 9 points, respectively.

Given information:

Diego scores 9 points less than Andre in the basketball game.

Noah scores twice as many points as Diego.

Noah's score is 10 points.

Let x be the score of Diego.

So, the score of Andre will be x+9 and that of Noah will be [tex]2x[/tex].

Compare Noah's score to get the value of x as,

[tex]2x=10\\x=5[/tex]

So, Diego's score is 5 points.

Now, the score of Andre will be calculated as,

[tex]x+9=5+9\\=14[/tex]

Therefore, the score of Andre and Diego is 14 and 9 points, respectively.

For more details, refer to the link:

https://brainly.com/question/9132346

Answer:

98up-'[y;adsdsfsafafdespenol es mi amigos si

Step-by-step explanation:

Answer:

y =16

I have solved it . It's in the picture above. Hope it helps

Answer:

Step-by-step explanation:

Answer:

y=4x+8

Step-by-step explanation:

y-y1=m(x-x1)

y-(-8)=4(x-(-4))

y+8=4(x+4)

y=4x+16-8

y=4x+8

[tex]1\frac{1}{6}[/tex] cups of cheese should be used for [tex]\frac{2}{3}[/tex] of the recipe.

Step-by-step explanation:

Given,

Quantity of cheese used in recipe = [tex]1\frac{3}{4}\ cups = \frac{7}{4}\ cups[/tex]

Recipe to made = [tex]\frac{2}{3}[/tex]

Quantity to use in [tex]\frac{2}{3}[/tex] of recipe = [tex]\frac{2}{3}\ of\ quantity\ required\ for\ full\ recipe[/tex]

Quantity to use = [tex]\frac{2}{3}*\frac{7}{4}[/tex]

Quantity to use = [tex]\frac{7}{6} = 1\frac{1}{6}\ cups[/tex]

[tex]1\frac{1}{6}[/tex] cups of cheese should be used for [tex]\frac{2}{3}[/tex] of the recipe.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

Using the negative exponent rule move x^-2 to the numerator

Answer = 5x^2/y^5

Answer:

  392

Step-by-step explanation:

You want the value of the square of the length XY, given X and Y are outside and symmetrically opposite the center of a 10-unit square and each is 6 units and 8 units from the two nearest vertices.

The attached drawing shows the positions of points X and Y. Each is 4.8 units horizontally and 3.6 units vertically from the nearest vertex of the square. That means their locations relative to each other are ...

  horizontally: 2×4.8 +10 = 19.6 units

  vertically: 6.4 -3.6 = 2.8 units

The square of the distance between X and Y will be given by the Pythagorean theorem:

  XY² = 19.6² +2.8² = 384.16 +7.84

  XY² = 392

__

Additional comment

The locations of X and Y relative to the side of the square can be found using the "geometric mean" relations for a right triangle. Triangle QXP has side lengths 6, 8, 10, which are a multiple of the well-known {3, 4, 5} right triangle. So ∆QXP is a right triangle with a right angle at X.

The length QX is the geometric mean √(QA·QP), so we have ...

  6 = √(10·QA)
  36 = 10·QA
  QA = 3.6   ⇒   PA = 6.4

and

  XA = √(QA·PA) = √(3.6·6.4)
  XA = 4.8

The value of [tex]\( XY^2 \)[/tex] is 100.

Let's begin by visualizing the problem. We have a square PQRS with side length 10. Points X and Y are outside the square such that XQ = YS = 6 and XP = YR = 8. We need to find the square of the distance between X and Y, denoted as [tex]\( XY^2 \)[/tex].

To solve this, we can use the Pythagorean theorem. Let's consider triangle XPQ. Since PQRS is a square, angle PQX is a right angle. Therefore, triangle XPQ is a right-angled triangle with PQ as the hypotenuse and XQ and XP as the other two sides.

Using the Pythagorean theorem for triangle XPQ, we have:

[tex]\[ 8^2 = 6^2 + XQ^2 \][/tex]

[tex]\[ 64 = 36 + XQ^2 \][/tex]

[tex]\[ XQ^2 = 64 - 36 \][/tex]

[tex]\[ XQ^2 = 28 \][/tex]

Now, we have found the square of the distance XQ, which is [tex]\( 28 \)[/tex].

Similarly, for triangle YRQ, which is also a right-angled triangle with YR as one leg and YS as the other leg, and RQ as the hypotenuse, we can write:

[tex]\[ 8^2 = 6^2 + RQ^2 \][/tex]

[tex]\[ 64 = 36 + RQ^2 \][/tex]

[tex]\[ RQ^2 = 64 - 36 \][/tex]

[tex]\[ RQ^2 = 28 \][/tex]

We have found that [tex]\( RQ^2 = 28 \)[/tex], which is the same as [tex]\( XQ^2 \)[/tex].

Now, to find [tex]\( XY^2 \)[/tex], we need to consider the distance between points X and Y. Since X and Y are outside the square and their distances to the square are equal (XQ = YS and XP = YR), the line segment XY is parallel to side PQ of the square and is also equal to the side length of the square, which is 10.

Therefore, [tex]\( XY^2 \)[/tex] is simply the square of the side length of the square PQRS:

[tex]\[ XY^2 = PQ^2 \][/tex]

[tex]\[ XY^2 = 10^2 \][/tex]

[tex]\[ XY^2 = 100 \][/tex]

Yo sup??

6x^2+5x is a polynomial

-x^2+52 is also a polynomial

-7x^2+5/3x is not a polynomial as power of x is negative

x^2+5x^1/5 is not a polynomial as power of x is fraction

Hope this helps.

Answer: X = 27

Step-by-step explanation: The diagram shows two triangles with one triangle cut out from the other. A careful observation would reveal triangle BDR and triangle QDC.

Since line QC is parallel to line BR, that makes triangle QDC similar to triangle BDR. Also the ratio of lines QD and BQ is the same as the ratio of lines CD and RD. The same applies to lines QC and BR.

Therefore,

QD/BQ = CD/RC

Alternatively we can use the ratios,

QD/BD = CD/RD

Using the first ratios, we have

QD/BQ = CD/RC

39/26 = X/18

3/2 = X/18 {the left hand side has been reduced to it's simplest form}

If we cross multiply, we now arrive at

3 × 18 = 2X

54 = 2X

Divide both sides of the equation by 2

27 = X

Answer:

[tex]\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=-\log 4[/tex]

Step-by-step explanation:

[tex]\log 2-\log 8=\log\frac{2}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=\log 1-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \log 1=0[/tex]

Answer:

log(1/4)

log(2) + log (1/8)

30 m

Step-by-step explanation:

Step 1 :

Let x be the distance traveled.

Speed taken while going is given as 60mph.

Hence time taken for the onward journey =x/60

Speed for the return journey is 20mph

Hence time for the return journey is x/20

Step 2:

Total time is from 10 m to 2 pm. Deducting the 2 hours taken for lunch, time spent for the onward and return journey is 2 hrs

=> X/60 + x/20 = 2.

Solving for x we get x = 30

Hence the distance between the office and Valerie's is 30 m

Answer:

No; 14.7777777 or 14.78

Step-by-step explanation:

133 divided by 9 = 14.7777777

this rounds to 14.78

Hope this helped! :)

Answer:

no it does not it is 14.777777778

Answer:

$278

Step-by-step explanation:

There is an endowpayment policy with face of $25,000 with the annual premium $22.24 per $1000.

So, the annual premium of the endowpayment policy with face of $25,000 will be equal to [tex]\frac{25000}{1000}\times 22.24 = 556[/tex] dollars.

And the semi annual payment for this policy will be [tex]\frac{556}{2} = 278[/tex] dollars. (Answer)