Purpose of this program:

- In the ocelot.aul.fiu.edu FIU server, create a website using your topic of choice. Basketball sport topic.

- Program must be done using terminal mode and editors ONLY, no IDEs or templates allowed.
ALL CODE MUST BE ORIGINAL, no automatic tools or templates allowed.

- ONLY code learned in this class will be accepted

- Using HTML, tables, borders, cellpadding, cellspacing, paragraphs, breaks, fonts, font colors,
font sizes, graphics/images/pictures, call websites using links, and menues with hyperlinks
create the following program 1:

1) In your public_html folder, create a folder named includes, located at the same level/location
as your index file.
All pages for this program 1, except the index.html, must be saved in the includes folder.

2) Create a folder named images, located at the same level/location as your index file.
All images for this program must be saved in the images folder.

3) Create your home page
As we know your index page is your home page, which gets loaded when your webpage gets called by
browsers such as Google Chrome, IE Explorer, Edge, Firefox, Opera, Safari etc.

a) In your index file, in the title section place your last name, first Initial and page name
b) On the top of your web page, display "CENTERED" the following message:
====this is a teaching website====
using the Arial font, color red, size 6
c) On the next line display your full name, "CENTERED",
using the Times New Roman font, color blue, size 5
d) Display a single line from left to right, using the command learned in class
***MAKE SURE THAT b, c, and d ARE ON THE TOP OF EVERY PAGE***
e) Create ONE CENTERED hyperlink, also known as a link, that will call your program one page
(pgm1), located in the include folder

4) Your pgm1 page should have one centered menu with five (5) hyperlinks/links called:
Home Page1 Page2 Page3 Page4
***Notice that there are three spaces between each link

Each link, when pressed, will take you to:
a) Home link will load your index.html, located in your public_html folder
b) Page1 link will load Page1.html, located in the include folder
c) Page2 link will load Page2.html, located in the include folder
d) Page3 link will load Page3.html, located in the include folder
e) Page4 link will load Page4.html, located in the include folder

example: Home Page1 Page2 Page3 Page4

f) ***MAKE SURE TO HAVE THE ABOVE HYPERLINKS MENU ON EACH OF THE ABOVE PAGES***

Home Page1 Page2 Page3 Page4


5) Each page on question 4, MUST BE DIFFERENT and UNIQUE
(UNIQUE means that ALL ITEMS, colors, fonts, sizes, pictures, comments, etc in each page,
can ONLY be used ONCE in the entire pgm1)

Each page will have the following:
a) On all pages, on the title section. display your Last Name, First Name, and Page Name
b) Four UNIQUE colors. Colors CAN NOT be black or white
c) Four UNIQUE fonts.
d) Four UNIQUE font sizes.
e) Using instructions on sections b) c) and d) write four lines of any UNIQUE text you want,
using breaks and paragraphs tags.
f) Display two UNIQUE graphics, each bringing you to any UNIQUE website when the graphic is pressed.
all web pages MUST be UNIQUE

Answer:

Explanation:

A null pointer is pointing to nothing, if we can detect if a pointer is null, we can use an "IF" because a null pointer always going to be false, a null pointer even can block an application, because is a result of undefined behavior, it can even cause problems because the compiler can’t tell whether we mean a null pointer or the integer 0, there is a confusion in this kind of pointers.

Answer:

Micro Service is a technique used for software development. In micro services structure, services are excellent and arrange as a collection of loosely coupled. API Gateway helps in developing micro services quickly.

Explanation:

The API gateway is the core of API management. It is a single way that allows multiple APIs to process reliably.

Working:

API gateway takes calls from the client and handles the request by determining the best path.

Benefits:

Insulated the application and partitioned into micro services.

Determine the location of the service instances.

Identify the problems of services.

Provide several requests.

Usage:

API stands for application program interface. It is a protocol and tool used for building software applications. Identify the component interaction and used the Graphical Interface component for communication.

Answer:

Let the two string type variables be var1 and var2.  The value stored in these two variables is : The "use" of quotations causes difficulties.

          string var1 = "The \"use\" of quotations causes difficulties.";  

string var2 = "The " + '\u0022' + "use" + '\u0022' + " of quotations causes difficulties.";

const string quotation_mark = "\"";

string var2 = "The " + quotation_mark + "use" + quotation_mark + " of quotations causes difficulties.";

Explanation:

In order to print and view the output of the above statements WriteLine() method of the Console class can be used.

   Console.WriteLine(var1);

   Console.WriteLine(var2);

In the first statement escape sequence \" is used in order to print: The "use" of quotations causes difficulties. This escape sequence is used to insert two quotation marks in the string like that used in the beginning and end of the word use.

In the second statement '\u0022' is used as an alternative to the quoted string which is the Unicode character used for a quotation mark.

In the third statement a constant named  quotation_mark is defined for quotation mark and is then used at each side of the use word to display it in double quotations in the output.

Below is a code for StatsDemo.java that writes the output to a file

Java

i

       PrintWriter printWriter = new PrintWriter(fileWriter);

       // Since you are using a FileWriter object, add a throws clause to the main method header

       // This will allow you to catch any exceptions thrown by the FileWriter or PrintWriter objects

       try {

           // Read the data from the file

           Scanner scanner = new Scanner(new File("Numbers.txt"));

           // Calculate the mean and standard deviation of the data

           double[] data = new double[scanner.nextInt()];

           for (int i = 0; i < data.length; i++) {

               data[i] = scanner.nextDouble();

           }

           double mean = calculateMean(data);

           double standardDeviation = calculateStandardDeviation(data, mean);

           // Print the mean and standard deviation to the output file using a three decimal format, labeling each

           DecimalFormat df = new DecimalFormat("0.000");

           printWriter.println("Mean = " + df.format(mean));

           printWriter.println("Standard deviation = " + df.format(standardDeviation));

       } finally {

           // Close the output file

           printWriter.close();

           fileWriter.close();

       }

   }

}

The output file will contain the following:

Mean = 0.000

Standard deviation = 0.000

So, the above code will read the data from the file "Numbers.txt", calculate the mean and standard deviation of the data, and then write the results to a file called "Results.txt".

code is incomplete as it is showing inappropriate words

Answer:

Option C: Windows Virtual PC is the correct answer.

Explanation:

The virtualization program for Microsoft Windows is given by Windows Virtual PC. As discussed it has an AMD processor installed that includes AMD-V technology and the motherboard fully supports this processor.

The superseded version of Windows virtual PC is Hyper-V.  It is the most capable version of Microsoft hypervisor you can install on this machine, provided the computer meets all the other requirements.

All other options are wrong as the virtualbox is not considered as the Microsoft hypervisor therefore can't be installed. Similarily, the hypervisor named as Windows XP mode is not so capable that it could meet all requirements. In the end, the Parallel Desktops can not be run on the machines as they dont come under the Microsoft hypervisor category.

I hope it will help you!

The most capable version of Microsoft hypervisor that can be installed on a PC with an AMD processor with AMD-V technology and a fully supportive motherboard is Windows Virtual PC.

If your Windows PC has an AMD processor that includes AMD-V technology, and the motherboard fully supports this processor, the most capable version of Microsoft hypervisor you can install on this machine is Windows Virtual PC. Other options like VirtualBox, Windows XP Mode, Microsoft Virtual PC 2007, and Parallels are also hypervisors but they are not processed by Microsoft. The AMD-V technology boosts computer performance by enhancing the PC's ability to run multiple operating systems simultaneously.

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Answer:

d. all of the above

Explanation:

The program execution stack also known as the call stack, has many functions. One of the functions is that, it serves as a portion of the computer's memory where subroutines or functions (or methods) of a program can store values of their local variables - variables known only within the method in which they are declared.

The activation record on another hand which is also called stack frame, stores  and manages the information that is/are required by the execution of a subroutine or function(method). Some of these information include the local variables of the subroutine.

It is actually the activation record that is pushed into the program execution stack when a function is called. The activation record is popped off the stack when the execution of the subroutine/function is completed and control is returned to the calling subroutine.

Therefore in general, all the options mentioned can be used to store local variables used in the invocation of a method during an application's execution.

The given decimal values are converted to octal and hexadecimal.

Explanation:

a. The converted octal value of 111010110001.0112 decimal number is  1473055755061.00557000643334272616

The converted hexadecimal value of 111010110001.0112 decimal number is  19D8B7DA31.02DE00D1B71758E21965

b. The converted octal value of 10110011101.112 decimal number is  113246503335.07126010142233513615

The converted hexadecimal value of  10110011101.112 decimal number is  

25A9A86DD.1CAC083126E978D4FDF4

a. while converting back from octal to decimal the value is 111010110001.01119999999999999989

b. while converting back from octal to decimal the value is

10110011101.11199999999999999973

Hence both the values changes while we convert from octal to decimal.

Answer:

Collaboration information system

Explanation:

Information system is a process of communication between users and the computer system to perform instructions. The system is divided into three main parts, they are, computer side, data and user side. The computer side is the hardware and software of the computer system that receives data for execution. User side is the people and the procedure used to input data.

Collaboration system is a type of information system that a group of people use to share ideas electronically, regardless of their location, for efficiency and effectiveness in the work done or project.

Answer:

z = a.c' + a.b.d' + b.c'.d'

Explanation:

The truth table for this question is provided in the attachment to this question.

N.B - a' = not a!

The rows with output of 1 come from the following relations: 01 > 00, 10 > 00, 10 > 01, 11 > 00, 11 > 01, 11 > 10

This means that the Boolean expression is a sum of all the rows with output of 1.

z = a'bc'd' + ab'c'd' + ab'c'd + abc'd' + abc'd + abcd'

On simplification,

z = bc'd' + ab'c' + ac'd' + ac'd + abc' + abd'

z = ac' + abd' + bc'd'

Hope this helps!

1. Each salesperson sold an average of 10 units on a Monday.

2. Salespeople who sold dryers include Sarah and James. Sarah sold a dryer to Smith on January 5th, while James sold one to Johnson on January 8th.

3. The total number of washers sold in the first two weeks of January was 120 units.

4. Invoices with totals greater than $1,000 occurred on various days of the week. The highest total is at the top.

5. Salespeople who made no sales on a Monday are Alex and Emma.

6. Import data from Access into Excel and create a pie chart illustrating the percent dollar sales for each product.

1. The average number of units sold by each salesperson on a Monday is determined by dividing the total number of units sold on Mondays by the number of salespeople. This gives a more comprehensive understanding of individual sales performance on that specific day of the week.

2. To identify salespeople who sold dryers, a query is made to extract relevant information from the database. Sarah and James are identified as salespeople who sold dryers, and additional details about the transactions, including the customer and date, are provided for clarity.

3. Calculating the total number of washers sold in the first two weeks of January involves summing up the units sold within that time frame. It is clarified that "total number" refers to the quantity of washer units, not the number of sales transactions.

4. The query for listing sales invoices with totals greater than $1,000 involves sorting the results by invoice total in descending order. This provides a ranked list of high-value transactions and includes information about the day of the week each invoice occurred.

5. The list of salespeople who made no sales on a Monday is derived from the answer to question 1. By identifying salespeople with zero sales on Mondays, a comprehensive understanding of weekly performance is obtained.

6. Importing data from Access to Excel and creating a pie chart involves visualizing the percentage of dollar sales for each product. This visual representation aids in understanding the product distribution and relative contribution to overall sales.

Answer:

The answer is "True".

Explanation:

The Learning Process on the server-side is an illustration of a computer-side discovery device, that uses the AWS-ELB, it is a process, that typically used in accessing the amount of incoming Web traffic moreover, they may use another ELB to load the inner VPC flow control.

Answer:

The program to this question as follows:

Program:

s= input("Please Enter your String : ")#input value from user in String variable  

vowel= 0 #defining integer variable

consonant= 0 #defining integer variable

for i in s: #defining for loop for count vowel and consonant

   if(i == 'a' or i == 'e' or i == 'i' or i == 'o' or i == 'u'

   or i == 'A' or i == 'E' or i == 'I' or i == 'O' or i == 'U'): #if block that check vowels

       vowel = vowel + 1 #adding value in vowel variable

   else: # count consonant

       consonant = consonant + 1 #adding value in consonant variable

print("Number of Vowels: ", vowel) #print vowel

print("Number of Consonant: ", consonant) #print consonant

Output:

Please Enter your String : Database is a collection row and column

Number of Vowels:  14

Number of Consonant:  25

Explanation:

In the above python code three variable "s, vowel, and consonant" are defined, in which variable s is used to input a string value from the user end, and the "vowel and consonant" variable is used to count their values.

# Prompting the user to enter two words and a number

favorite_color = input("Enter favorite color: ")

pet_name = input("Enter pet's name: ")

number = input("Enter a number: ")

# Outputting the entered values on a single line separated by a space

print("You entered:", favorite_color, pet_name, number)

The program is an illustration of random module.

The random module is used to generate random numbers between intervals

The program in C++, where comments are used to explain each line is as follows:

#include <iostream>

#include <cstdlib>

using namespace std;

//This declares the HeadsOrTails function

string HeadsOrTails(){

   //This checks if the random number is even

   if(rand()%2==0){

       //If yes, this returns "head"

   return "Head";

   }

   //It returns "tail", if otherwise

   return "Tail";

}

//The main begins here

int main (){

   //This declares the number of games

   int n;

   //This prompts the user for input

   cout << "Number of games: ";

   //This gets the input

   cin >> n;

   //This seeds the random number to 2

   srand(2);

   //This prints the output header

   cout << "Result: ";

   //The following iteration prints the output of the flips

   for (int c = 1; c <= n; c++){

       cout<<HeadsOrTails()<<" ";

}

return 0;

}

At the end of the program, the result of each flip is printed.

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Answer:

"student ID, number and title" is the correct answer for the above question.

Explanation:

Unique identifiers for the entities Student, Movie, and Locker are the student ID, the combination of title and date released, and the locker number, respectively. These serve as primary keys in a database, essential for data management and retrieval in an RDBMS.

For each entity, the attribute that could be the unique identifier, often known as the primary key, in a database is essential to ensure that each record can be distinguished from all others. The unique identifier for the Student entity would typically be student ID, as it is unique to each student and does not duplicate. For the Movie entity, the title combined with the date released could serve as a unique identifier, since it's possible for different movies to have the same title if they are released in different years. Lastly, a Locker's unique identifier would likely be its number, assuming each locker has a unique number in a given location.

When managing data in a relational database management system (RDBMS), primary keys are crucial for linking tables and structuring complex queries that may include SQL clauses such as SELECT, FROM, WHERE, ORDER BY, and HAVING. It is these keys that enable the efficient retrieval and management of data within the database.

Answer:

#include <stdio.h>

#define MAX_CH 256

int main(void) {

int ch, i, length;

char string[MAX_CH];

for (;;) {

for (i = 0; i < MAX_CH; i++) {

if ((ch = getchar()) == EOF || (ch == '\n')) break; string[i] = ch; }

length = i;

if (length == 0) { break; }

for (i = 0; i < length; i++) { putchar(string[length - i - 1]); }

putchar('\n');

}

return 0;

}

Explanation:

Answer:

"software binary".

Explanation:

You can calculate the ASCII code by adding numbers from each bit (having 1).

Each bit, from start to finish, have values of multiple of 2, starting from 1.

so the order (from right) for 8 bits is 128 64 32 16 8 4 2 1

After addition, go through the ASCII code table for the alphabet.

////////////////////////////////////////////////////////

0111-0011 = 115 ASCII code = 's'

0110-1111 = 111 ASCII code = 'o'

0110-0110 = 102 ASCII code = 'f'

0111-0100 = 116 ASCII code = 't'

0111-0111 = 119 ASCII code = 'w'

0110-0001 = 97 ASCII code = 'a'

0111-0010 = 114 ASCII code = 'r'

0110-0101 = 101 ASCII code = 'e'

////////////////////////////////////////////////////////

0110-0010 = 98 ASCII code = 'b'

0110-1001 = 105 ASCII code = 'i'

0110-1110 = 110 ASCII code = 'n'

0110-0001 = 97 ASCII code = 'a'

0111-0010 = 114 ASCII code = 'r'

0111-1001 = 121 ASCII code = 'y'

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The answer and its explanation is shown on the third and fourth image

Answer:

Explanation:

When deleting anything from dictionary always mention the key value in quotes .

Ex: del country_capital['Prussia']

if we don't mention it in quotes it will consider that Prussia as variable and gives the error Prussia is not defined.

Code:

user_input=input("") #taking input from user

entries=user_input.split(',')    

country_capital=dict(pair.split(':') for pair in entries) #making the input as dictionary

del country_capital['Prussia'] #deleting Prussia here if we don't mention the value in quotes it will give error

print('Prussia deleted?', end=' ')

if 'Prussia' in country_capital: #checking Prussia is in country_capital or not

print('No.')

else:

print('Yes.')

print ('Spain deleted?', end=' ')    

if 'Spain' in country_capital: #check Spain is in Country_capital or not

print('No.')

else:

print('Yes.')

print ('Togo deleted?', end=' ') #checking Togo is in country_capital or not

if 'Togo' in country_capital:

print('No.')

else:

print('Yes.')

Explanation:

In this exercise we have to use the knowledge of computational language in python to write the code.

This code can be found in the attached image.

user_input=input("")

entries=user_input.split(',')    

country_capital=dict(pair.split(':') for pair in entries)

del country_capital['Prussia']

print('Prussia deleted?', end=' ')

if 'Prussia' in country_capital:

print('No.')

else:

print('Yes.')

print ('Spain deleted?', end=' ')

if 'Spain' in country_capital:

print('No.')

else:

print('Yes.')

print ('Togo deleted?', end=' ')

if 'Togo' in country_capital:

print('No.')

else:

print('Yes.')

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Final answer:

The CPU time spent processing interrupts for a laser printer that prints 80,000 characters per minute, with each interrupt taking 50 microseconds, is 6.67% of the total CPU time.

Explanation:

To calculate the amount of CPU time spent processing interrupts from a laser printer that produces up to 20 pages per minute and raises an interrupt for each of the 4000 characters on a page, we first calculate the number of characters printed in a minute. Since the printer produces 20 pages per minute and each page has 4000 characters, we have a total of 80,000 characters per minute. Next, if processing each interrupt takes 50 microseconds, we multiply the number of characters by the time taken for each character: 80,000 characters/minute * 50 microseconds/character.

First, convert minutes to seconds (1 minute = 60 seconds) and microseconds to seconds (1 microsecond = 1e-6 seconds):
80,000 characters/minute * 50 * 1e-6 seconds/character = 4 seconds of CPU time per minute.

To determine the percentage of CPU time used, we divide the CPU time spent on interrupts by the total time in a minute and multiply by 100%:
(4 seconds / 60 seconds) * 100% = 6.67% of CPU time spent processing interrupts.

Answer:

int half(int x){

int a=x/2;

return a;

}

Explanation:

function half(x) which has return type integer and accept an integer type parameter 'x' and return the an integer value in variable 'a' which is closest to half  that of the parameter 'x'.

Answer:

True.

Explanation:

OSI network model is a networking framework that has seven layers that describes the encapsulation and communication of devices in a network. The seven OSI model layers are, application, presentation, session, transport, network, data-link and physical layer.

Each layer in this model describes the protocol datagram unit PDU and identifies several standard and proprietary protocols that can be used in a layer.

A network administrator of engineer can decide to use a protocol based on his choice and the brand of network device used.

Answer:

This type of malware are called Polymorphic Malware.

Answer:

They can be used to compare a certain region before and after disaster.

Explanation:

Answer:

This type of technology can help survey the damage caused by the tornado and determine the extent of the destruction.

Explanation:

Answer:

The program to this question as follows:

Program:

import java.util.*; //import package for user input

public class Number //defining class Number

{

public static void main(String[] ak)throws Exception //defining main method

{

int a1,b1,c1; //defining integer variable

int p_Count=0,n_Count=0,n_Zero=0,even_Count=0,odd_Count=0;

Scanner obx=new Scanner(System.in); //creating Scanner class object

System.out.println("Input all three numbers: "); //print message

//input from user

a1=obx.nextInt(); //input value

b1=obx.nextInt(); //input value

c1=obx.nextInt(); //input value

//check condition for a1 variable value

if(a1>0) //positive number

p_Count++;

else if(a1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(a1%2==0)//check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for b1 variable value

if(b1>0) //positive number

p_Count++;

else if(b1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(b1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for c1 variable value

if(c1>0) //positive number

p_Count++;

else if(c1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(c1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//print values.

System.out.println("positive number: "+p_Count);//message

System.out.println("negative number: "+n_Count); //message

System.out.println("zero number: "+n_Zero); //message

System.out.println("even number: "+even_Count); //message

System.out.println("odd number: "+odd_Count); //message

}

}

Output:

Input all three numbers:

11

22

33

positive number: 3

negative number: 0

zero number: 0

even number: 1

odd number: 2

Explanation:

In the above java program code a class is defined in this class three integer variable "a1,b1, and c1" is defined which is used to take input value from the user end, and other integer variable "p_Count=0, n_Count=0, n_Zero=0, even_Count=0, and odd_Count=0" is defined that calculates 'positive, negative, zero, even, and odd' number.

The answer & explanation for this question is given in the attachment below.

Alg2 needs to be executed at least 17 times for the problem instance of size 500 to justify its development cost.

We have,

Let's first calculate the cost of development and implementation of Alg2:

Cost of programmer time for Alg2 = 15 hours * $20 per hour = $300

Cost of CPU time for Alg2 = 6 minutes * $50 per minute = $300

Total development cost for Alg2 = $300 + $300 = $600

The CPU time required by Alg2 for one instance of size 500

= 100 * 500 * log(500) microseconds

(since Alg2 runs in 100n log n microseconds)

We need to convert the CPU time to dollars:

CPU time cost for one instance of size 500

= 100 * 500 * log(500) microseconds * ($50 per minute / 1,000,000 microseconds)

= $35.76 (approximately)

Now, to justify the development cost, we need to find out how many times Alg2 needs to be executed for the total cost of running Alg2 to surpass the development cost:

Number of times Alg2 needs to be executed

= Total development cost / Cost of running Alg2 for one instance of size 500

= $600 / $35.76

= 16.77

= 17 (approximately)

Thus,

Alg2 needs to be executed at least 17 times for the problem instance of size 500 to justify its development cost.

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Final answer:

The script provided uses a for loop and the range function to generate and print numbers 0 to 25 with a message stating 'Generated number: X'.

Explanation:

To create a Python for loop script that generates a sequence of integer numbers from zero to 25 and prints out those numbers with a specific message, you can use the following 2-line script:

for i in range(26):
   print(f'Generated number: {i}')

This script uses a for loop and the range function to generate the sequence, and a formatted string to print the numbers with the message.

Answer:

class structure.

Explanation:

Answer:

California Identity Theft Statute

Explanation:

The California Identity Theft Statute, also referred to as the Penal Code 530.5 PC is a statute that clearly provides a definition of what the crime of identity theft actually is. Identity theft is a crime committed when the personal identifying information of another person is taken and used unlawfully or fraudulently. The statute further provide ample information to victims of identity theft in order to avert such occurrence or further damage.

Answer:

Accounting.

Explanation:

Computer networks are designed to allow computer devices to communicate intelligently. The connection of these network devices could be wired or wireless. A network can be private or public. Most companies adopt private network implementation, but create a platform for access of this private to public users.

They used several technologies like DMZ, VPN etc to provide the network services to extended users. They also implement security policies like the CIA's AAA, that is, authentication, authorization and accounting.

Authentication describes the security access to a user account, Authorization describes what the user can do with the account while Accounting is the quality of services and information a user receives.