PLEASE HELP ASAP Which equation BEST models the data shown in the scatterplot below?

A. y=3x+10

B. y=3x+60

C. y=4x+5

D. y=4x+35

Answer:

3 is 14 less than 17

Step-by-step explanation:

17-3=14

Answer:

the answer is B 3 is 14 less than 17

hope it helps!

r = 16/2 = 8 cm

C = 2π·r = 2×3.14×8 = 50.24 cm

Answer

5 fries per minute

Step-by-step explanation:

To work out this question, you would need to divide 70 by 14. This would give you the rate of fries he eats per minute as 14 divided by 14 = 1.

Dracula's fry-eating rate is 5 fries per minute.

The subject of this question is Dracula's fry-eating rate. In mathematics, we often deal with rates, which are a measure of how something changes over time.

In this case, we are being asked to find how many fries Dracula eats per minute. This can be found by dividing the total number of fries he ate by the total time he took.

Given, Dracula ate 70 fries in 14 minutes.

To find the fry-eating rate, we need to divide the total fries by the total minutes. That is, fry-eating rate = total fries / total time.

So, the fry-eating rate = 70 fries / 14 minutes = 5 fries per minute. Therefore, Dracula's fry-eating rate is 5 fries per minute.

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Answer:

$110,5

Step-by-step explanation:

If 6 pounds costs $39, then 17 pounds (11+6) will cost $110,5

The solution can be found using famous math rule called "Rule of three".

In this case we have an unknown quantity  [tex]\left \{ {{6=39}\atop {17=?}} \right.[/tex]  where  ? can be found multiplying $39 x 17 (new quantity) and dividing by the first quantity, [tex]? = \frac{39x17}{6}[/tex]

Answer: 659,500 is the initial value

Step-by-step explanation:

Answer:

18(p-2) and 2(9-18)

Step-by-step explanation:

Answer:

a.i) 1 piece = 20 days

   1 day= 1/20 piece =0.05 of a piece

a.ii) 0.05*5 =0.25

a.iii) 0.05*10 =0.5 done.

so if the total is 1, 0.5 is half, so he has 0.5 work left

b.i)1 piece=12 days

4 days = 1/3 = 0.3333333333 of his work

b.ii)1/4=0.25

so 12*0.25 = 3 days

c.i)1/3 = 6 days

1 (work)= 6*3 = 18 days

c.ii) 1/18 = 1 day = 0.05555555555

c.iii) 0.5 since 9/18 = 1/2 = 0.5

d.i) 1 hour= 60 mins

whole tank = 60 mins

20 mins = 60/20 = 1/3 of a tank

if capacity = 1500L

1500 = 60 mins

1500/3 = 20 mins

=500 Liters

Answer:

f(x+ 1) = 2x^2 + 5x + 3.

Step-by-step explanation:

We replace the x in the expression for f(x) by x+1:

f(x+1) = 2(x + 1)^2 + x + 1

= 2(x^2 + 2x + 1) + x + 1

= 2x^2 + 4x + 2 + x + 1

= 2x^2 + 5x + 3.

Answer:

What table below

Step-by-step explanation:

The independent variable is what you change

The dependent variable is what you measure

So the money he earns per hour seems like a constant, and it won't change. Therefore the dependent variable would be the amount of money he earns.

The number of hours he works can be changed, so the independent variable would the number of hours he works/babysits

If you start at (6, 7) and you move up 2 units, you will end at point (6, 9) as shown in the image attached below.

In Mathematics and Euclidean Geometry, the translation a geometric figure upward means adding a digit to the value on the positive y-axis of the pre-image;

g(x) = f(x) + k

In this exercise, we would apply a translation of 2 units up to the point (6, 7), in order to determine the coordinates of its image as follows;

(x, y)                   →                  (x, y + 2)

A (6, 7)               →    (6, 7 + 2) = (6, 9).

So, if you start at (6, 7) and you move up 2 units, you will end at point (6, 9) as shown in the image attached below.

Answer:

The graph shows that a consistent time to go from resting position to point A, then back to resting, then to point B, then back to resting, and so on is 0.75 seconds.

To bounce from resting to point A then point B and back to resting is 3 seconds.

The question pertains to the period of oscillation in a simple harmonic motion scenario involving a weight and a spring. The period is calculated using the formula T = 2π√(m/k). The student asks how long it takes for the weight to complete one full oscillation cycle, which can be calculated using mass and spring constant.

The students asked about the period of oscillation for a weight attached to a spring. In physics, especially concerning simple harmonic motion (SHM), the period is the time it takes for one full cycle of motion: moving in one direction, reversing, and returning to the starting point. To find the period of a mass-spring system, we use the formula T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. This formula is derived from the motion equations that describe SHM.

For example, if you have a mass of 0.750 kg attached to a spring with a spring constant of 150 N/m, you would calculate the period using the mass (m) and the spring constant (k) from Hooke's Law. Similarly, when a spring exerts an upward force of 2.00 mg at the lowest point, this is due to the spring force being equal to the gravitational force at that point (mg) and also providing the restoring force needed for SHM (another mg).

Understanding SHM and its principles such as spring constant, and force of gravity are critical in solving these types of physics problems. These concepts explain how an attached weight on a spring moves in the absence of friction and other forces, such as air resistance.

Answer:

[tex]His\ average\ speed\ to\ trip\ there\ =45\ mph\\\\His\ average\ speed\ in\ return\ trip=45-9=36\ mph\\\\His\ average\ speed\ during\ whole\ trip=40\ mph[/tex]

Step-by-step explanation:

[tex]Let\ distance\ from\ one\ side=d[/tex]

Trip:

[tex]Let\ speed\ when\ he\ was\ going=x\ mph\\\\Time\ taken=4\ hours\\\\distance=d\\\\distance=speed\times time\\\\d=x\times 4\\\\d=4x\ ...................................eq(1)[/tex]

Return Trip:

[tex]Speed=x-9\ \ \ \ \ (as\ it\ is\ 9\ mph\ slower)\\\\Time\ taken=5\ hours\\\\Distance=d\\\\Distance=speed\times time\\\\Distance=5\times (x-9)\\\\d=5x-45\ ........................................eq(2)[/tex]

[tex]from\ eq(1)\ and\ eq(2)\\\\5x-45=4x\\\\5x-4x=45\\\\x=45\ mph\\\\from\ eq(1)\\\\d=4\times 45=180\ miles[/tex]

[tex]Average\ speed\ during\ whole\ trip=\frac{total\ distance}{total\ time}=\frac{2\times 180}{5+4}=\frac{360}{9}=40\ mph[/tex]

[tex]His\ average\ speed\ to\ trip\ there\ =45\ mph\\\\His\ average\ speed\ in\ return\ trip=45-9=36\ mph\\\\His\ average\ speed\ during\ whole\ trip=40\ mph[/tex]

Answer:

Step-by-step explanation:

Mean = ∑x/ N

91 = ∑x / 150

∑x = 150 * 91 = 13650

x= 6825 and y = 6825

Answer:

the last one

Step-by-step explanation:

Answer:

The answer is Y = 4.  Hope this helps.

Answer: y is 2/3, or the answer to the equation is 4

Step-by-step explanation:

it tells you what y is with y=2/3, so you need to plug that into the equation nto get 4, or just use 2/3 as your answer

Answer:

No i dont think so

Step-by-step explanation:

Because 16:4 isn't an equivilent ratio to 1:4

The value of d + e + f is 14

Solution:

Given that,

d = 20

e = -4

f = -2

We have to find the value of d + e + f

Substitute d = 20 and e = -4 and f = -2

Thus we get,

d + e + f = 20 + (-4) + (-2)

Remove the parenthesis

We know that, when we multiply negative sign with positive sign, we get negative sign as result

d + e + f = 20 - 4 - 2

d + e + f = 20 - 6

d + e + f = 14

Thus value of d + e + f is 14

Answer:

  10

Step-by-step explanation:

Consider the triangle consisting of the segment from the center of the sphere to the center of the circle, a radius of the circle, and the radius of the sphere to the other end of the radius of the circle. The given leg dimensions of that right triangle are 6 and 8, so the Pythagorean theorem tells you the hypotenuse (radius of the sphere) is ...

  √(6²+8²) = √(36+64) = √100 = 10

The radius of the sphere is 10 units.

_____

You may recognize this as a 3-4-5 right triangle scaled by a factor of 2.

In this case, the radius of the sphere is 10 units.

The distance from the center of the sphere to the plane is given as 6 units.

According to the Pythagorean theorem, we have:

[tex]\[ r^2 = d^2 + r'^2 \][/tex]

[tex]\[ r^2 = 6^2 + 8^2 \][/tex]

[tex]\[ r^2 = 100 \][/tex]

 Taking the square root

[tex]\[ r = \sqrt{100} \][/tex]

r = 10

 The radius of the sphere is 10 units.

Answer:

x = 2 and x = 2

Step-by-step explanation:

Using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]

Given

[tex]log_{x}[/tex] 8 = 3 ⇒ 8 = x³

Note 8 = 2³ = x³  ⇒ x = 2

Given

[tex]log_{5}[/tex] 25 = x ⇒ 25 = [tex]5^{x}[/tex]

25 = 5² = [tex]5^{x}[/tex] ⇒ x = 2

To solve for L, you need to isolate/get the variable "L" by itself in the equation:

S = 2HW + 2HL + 2WL    Subtract 2HW on both sides

S - 2HW = 2HW - 2HW + 2HL + 2WL

S - 2HW = 2HL + 2WL    Take out the "L" in 2HL and 2WL

S - 2HW = L(2H + 2W)    Now divide (2H + 2W) to get "L" by itself

[tex]\frac{S-2HW}{2H +2W} =\frac{L(2H+2W)}{2H+2W}[/tex]

[tex]\frac{S-2HW}{2H+2W} =L[/tex]

I think you can stop here, but if you need or want to simplify:

[tex]\frac{S}{2H+2W} -\frac{HW}{H+W} =L[/tex]     which looks longer so I don't know if you need to do this

To solve for 'L' in the given equation, we subtract 2HW and 2WL from each side, then divide each side by 2H. The solution is L = (S - 2HW - 2WL) / 2H.

We are given the equation S= 2HW + 2HL + 2WL and we are asked to solve for L. To do this, we will need to isolate L on one side of the equation. Here are the steps:

So the value of L in terms of the other variables in the equation is (S - 2HW - 2WL) / 2H.

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Answer:

The area of polygon JKLMNO is 48 square units

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the scale factor

we know that

If two figures are similar, the the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

Let

z ----> the scale factor

The scale factor of the dilation of polygon PQRSTU to polygon JKLMNO is

[tex]z=\frac{KJ}{QP}[/tex]

substitute the given values

[tex]z=\frac{4}{5}[/tex]

step 2

Find the area of polygon JKLMNO

we know that

If two figures are similar, the the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> area of polygon  JKLMNO

y ----> area of polygon PQRSTU

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]z=\frac{4}{5}[/tex]

[tex]y=75\ units^2[/tex]

substitute

[tex](\frac{4}{5})^{2}=\frac{x}{75}[/tex]

solve for x

[tex]x=(\frac{16}{25})75=48\ units^2[/tex]

therefore

The area of polygon JKLMNO is 48 square units

Answer:48units

Step-by-step explanation: I know

Answer:

$37.5

Step-by-step explanation:

(25/50) x 75 = 37.5

$25/50  .... each apple cost $0.5

0.5 x 75 = 37.5

The correct answer is 75 apples would cost $37.50.

To solve this problem, we first need to determine the cost per apple when 50 apples cost $25. We can calculate this by dividing the total cost by the number of apples:

Cost per apple = Total cost / Number of apples

Cost per apple = $25 / 50 apples

Cost per apple = $0.50 per apple

Now that we know the cost per apple is $0.50, we can calculate the cost for 75 apples by multiplying the cost per apple by the number of apples:

Cost for 75 apples = Cost per apple * Number of apples

Cost for 75 apples = $0.50 * 75

Cost for 75 apples = $37.50

Therefore, 75 apples would cost $37.50.

Volume of the small truck = 554.54 cubic ft

Solution:

Given data:

Length of the small truck = [tex]11\frac{1}{13}[/tex] ft

Width of the small truck = [tex]7\frac{5}{12}[/tex] ft

Height of the small truck = [tex]6\frac{3}{4}[/tex] ft

Volume of the small truck = length × width × height

                                           [tex]$=11\frac{1}{13}\times7\frac{5}{12}\times 6\frac{3}{4}[/tex]

Let us change the mixed fraction into improper fraction.

                                          [tex]$=\frac{11\times 13 + 1}{13}\times\frac{7 \times 12 + 5}{12}\times \frac{6 \times 4 + 3}{4}[/tex]

                                          [tex]$=\frac{144}{13}\times\frac{89}{12}\times \frac{27}{4}[/tex]

                                          [tex]$=\frac{7209}{13}[/tex]

                                          = 554. 54 cubic ft

Volume of the small truck = 554.54 cubic ft

Answer:

The lower right graph.

Step-by-step explanation:

Answer:

40) D

41) -56.33

Step-by-step explanation:

40)

Equation #1) 1 centimeter = 2.5 meters on the drawing

Equation #2) Length of the cafeteria on the drawing = 12.25 cm

Actual length:

Multiply both sides of equation #1 by 12.25 to get the actual length of the cafeteria

1(12.25) = 2.5(12.25)

12.25 cm = 30.625 meters

D

41)

[tex]\frac{0.5\left(8\ +\ 3.2\right)}{-0.1}+\ \frac{3}{\left(-2.7\ -\ 6.3\right)}[/tex]

Start with multiplication inside the parenthesis

[tex]\frac{4\ +\ 1.6}{-0.1}+\ \frac{3}{\left(-2.7\ -\ 6.3\right)}[/tex]

Add/Subtract

[tex]\frac{5.6}{-0.1}+\ \frac{3}{-9}[/tex]

Simplify

[tex]-56+\left(-0.33\right)[/tex]

[tex]-56 - 0.33[/tex]

Hope this helps ツ

Answer:

40

Step-by-step explanation:

4 x 10= 40

PlZ add brainliest.

Answer:

40 is the answer to this question

Answer:

answer is b

Step-by-step explanation:

look at the picture

Standard form for a linear equation is Ax+By=C.

Problem: Write #y=3x-8 in standard form.

Subtract 3x from both sides of the equation.

−3x+y=−8

Multiply both sides by −1.

answer  ==>  3x−y=8

Answer:

527, no mistakes this time

Step-by-step explanation:

Answer:

  Volume of the pet carrier   [tex]=2702.5[/tex] cubic inches

Step-by-step explanation:

The Pet carrier in the image is in the shape of a cuboid

The volume of a cuboid can be found by the formula

         volume of cuboid= [tex]Length*Breadth*Height[/tex]

Given:

Length = 20 inches,                          Breadth=[tex]11\frac{3}{4} =\frac{(11*4)+3}{4}=\frac{47}{4}[/tex] inches,                          

Height=[tex]11\frac{1}{2}=\frac{23}{2}[/tex] inches

Volume of the pet carrier:

                                          [tex]=20*\frac{47}{4}* \frac{23}{2}\\\\= 5*47*\frac{23}{2} \\\\=5*47*11.5\\[/tex]

                                         [tex]=2702.5[/tex] cubic inches

Volume of the pet carrier   [tex]=2702.5[/tex] cubic inches