Please answer this sample space question.

Answer:

The lower right graph.

Step-by-step explanation:

The value of d + e + f is 14

Solution:

Given that,

d = 20

e = -4

f = -2

We have to find the value of d + e + f

Substitute d = 20 and e = -4 and f = -2

Thus we get,

d + e + f = 20 + (-4) + (-2)

Remove the parenthesis

We know that, when we multiply negative sign with positive sign, we get negative sign as result

d + e + f = 20 - 4 - 2

d + e + f = 20 - 6

d + e + f = 14

Thus value of d + e + f is 14

Answer:

527, no mistakes this time

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

Answer:

3 is 14 less than 17

Step-by-step explanation:

17-3=14

Answer:

the answer is B 3 is 14 less than 17

hope it helps!

Answer:

3 3/7 or 24/7 mins

Step-by-step explanation:

Let total job = X

Jeff's rate = X/6

Bob's rate = X/8

Combined rate = X/6 + X/8

(4X × 3X)/24 = 7X/24

7X/24 = X/T

T = X ÷ (7X/24)

T = X × (24/7X)

T = 24/7 mins

Shortcut:

T = product of individual times/sum of individual times

T = (6×8)/(6+8)

T = 48/14

T = 24/7

T = 3 3/7 mins

Answer:

3 3/7 minutes or 3.4mins

Step-by-step explanation:

If Jeff washed husband car in 6 minutes and Bob washed the same car in 8 minutes , the time taken by both of them in washing the car ?

If Jeff washed the car in 6 minutes , in one minute, Jeff’s work = 1/6

If bob washed in 8mins, in one minute, bob’s work = 1/8

Add both together

1/6 + 1/8

Lcm of 6 and 8 Is 24

Divide the Lcm by the denominators and multiply the results by the numerator

We have 4+3 /24

7/24

Therefore time taken by both of them in Washing is 24/7

= 3 3/7 minutes 0r 3.4mins

Answer:

-3999944

Step-by-step explanation:

Answer:

w = 10

Step-by-step explanation:

Given

V = lwh ← substitute the given values

2000 = 10 × w × 20, that is

2000 = 200w ( divide both sides by 200 )

10 = w

Step-by-step explanation:

Let the smaller angle = x and

The larger angle = 10x + 15°

To find, the measure of each angle = ?

We know that,

The sum of two supplementary anges = 180°

∴ x + (10x + 15°) = 180°

⇒ x + 10x + 15° = 180°

⇒  11x = 180° - 15°

⇒  11x = 165°

Dividing both sides by 11, we get

[tex]\dfrac{11x}{11} =\dfrac{165}{11}[/tex]

⇒  x = 15°

∴ The smaller angle = 15° and

The larger angle = 10(15° ) + 15° = 165°

Answer:

B) 24 p-35

Step-by-step explanation:

Step :1

Apply distributive property  a.(b+c) = a.b+a.c

Given data 1+4(6 p-9)

                                 = 1+4.6 p - 4.9

multiply

                                 = 1+ 24 p - 36

subtracting

                                 = 24 p - 35

Answer:

6

Step-by-step explanation:

12/2=6

Answer:

6 touchdowns

Step-by-step explanation:

You just subtract the (2*3) from the 42 and get 36 than you divide by 6.

Standard form for a linear equation is Ax+By=C.

Problem: Write #y=3x-8 in standard form.

Subtract 3x from both sides of the equation.

−3x+y=−8

Multiply both sides by −1.

answer  ==>  3x−y=8

Answer:

The area of polygon JKLMNO is 48 square units

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the scale factor

we know that

If two figures are similar, the the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

Let

z ----> the scale factor

The scale factor of the dilation of polygon PQRSTU to polygon JKLMNO is

[tex]z=\frac{KJ}{QP}[/tex]

substitute the given values

[tex]z=\frac{4}{5}[/tex]

step 2

Find the area of polygon JKLMNO

we know that

If two figures are similar, the the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> area of polygon  JKLMNO

y ----> area of polygon PQRSTU

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]z=\frac{4}{5}[/tex]

[tex]y=75\ units^2[/tex]

substitute

[tex](\frac{4}{5})^{2}=\frac{x}{75}[/tex]

solve for x

[tex]x=(\frac{16}{25})75=48\ units^2[/tex]

therefore

The area of polygon JKLMNO is 48 square units

Answer:48units

Step-by-step explanation: I know

Answer:

Translate right 7 units (x+7)

Reflect over x-axis (-y) and translate down 6 units (-y - 6)

An

rawr raw

Step-by-step explanation:

Answer:

f(x+ 1) = 2x^2 + 5x + 3.

Step-by-step explanation:

We replace the x in the expression for f(x) by x+1:

f(x+1) = 2(x + 1)^2 + x + 1

= 2(x^2 + 2x + 1) + x + 1

= 2x^2 + 4x + 2 + x + 1

= 2x^2 + 5x + 3.

Answer:

18(p-2) and 2(9-18)

Step-by-step explanation:

r = 16/2 = 8 cm

C = 2π·r = 2×3.14×8 = 50.24 cm

Answer:

Step-by-step explanation:

42/7

= 8

Answer:

answer is b

Step-by-step explanation:

look at the picture

Answer:

the last one

Step-by-step explanation:

Answer:

Jamison is not correct

Step-by-step explanation:

According to the Fundamental Theorem of Algebra, an nth degree polynomial has n roots.

These roots comprises of real roots and imaginary roots.

The given function is

[tex]f(x) = {x}^{4} - {x}^{3} - 19 {x}^{2} - x - 20 [/tex]

Based on the Fundamental Theorem of Algebra, this function should have four roots.

The graph of the function only reveals real zeros and not the imaginary zeros.

So aside −4 and 5, there are two complex zeros

Jamison is incorrect; according to the Fundamental Theorem of Algebra, a fourth-degree polynomial will have four roots, which could include complex numbers. The zeros he observed are real, but the polynomial may also have complex zeros.

Jamison is not correct because the Fundamental Theorem of Algebra states that every non-zero, single-variable, degree n polynomial with complex coefficients has, counted with multiplicity, exactly n roots in the complex number system. The function ƒ(x) = x4 − x3 − 19x2 − x − 20 is a fourth-degree polynomial, therefore it will have four roots, not necessarily all distinct. Jamison has found two real zeros at −4 and 5. There could be additional complex zeros that were not visible on the graph. The theorem does not specify that all zeros must be real, only that there will be n zeros when including complex numbers.

Polynomials of the second order always have two roots in the complex number system, which explains why real polynomials without real roots (like x2 + 1) have complex roots i and −i. A polynomial of degree four such as the one Jamison is working with can be factored completely into four linear factors in the complex number system, leading to four complex roots. Therefore, it is possible that the remaining two roots of Jamison's polynomial are complex, which is consistent with the Fundamental Theorem of Algebra.

Answer:

Each side of the rhombus is 21 inches

Step-by-step explanation:

A rhombus has 4 equal sides: So all sides are the same

So you take the total perimeter and divide it by 4

84/4=21

Final answer:

The length of each side of a rhombus with a perimeter of 84 inches is 21 inches, calculated by dividing the total perimeter by the number of sides, which is four.

Explanation:

The question asks for the length of each side of a rhombus given its perimeter. The perimeter of a rhombus (or any polygon) is the total distance around the figure, and since all sides of a rhombus are equal in length, we can determine the length of one side by dividing the perimeter by the number of sides. A rhombus has four sides, so if the perimeter is 84 inches, the length of each side is the perimeter divided by four.

Here is the calculation for the length of each side:

Therefore, the length of each side of the rhombus is 21 inches.

Answer:

i think it is $38.70

Step-by-step explanation:

Answer:

1 & -1

Step-by-step explanation:

f(x) = g(x)

Find the inputs for which outputs are equal

Both outputs are 1 when x = -1

Both outputs are -7 when x = 1

Answer:

The answer is Y = 4.  Hope this helps.

Answer: y is 2/3, or the answer to the equation is 4

Step-by-step explanation:

it tells you what y is with y=2/3, so you need to plug that into the equation nto get 4, or just use 2/3 as your answer

Answer: 66

Step-by-step explanation:

6 laps

Answer:

because it can go overseas

Answer:

[tex]\huge\boxed{n=\log_35}[/tex]

Step-by-step explanation:

[tex]3^n=5\Rightarrow\log_33^n=\log_35\qquad\text{use}\ \log_ab^n=n\log_ab\\\\n\log_33=\log_35\qquad\text{use}\ \log_aa=1\\\\\boxed{n=\log_35}[/tex]