Answer:
Therefore the correct option is a.) The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 catfish in the river.
Step-by-step explanation:
i) Let p = 0.47
ii) therefore q = 1 - 0.47 = 0.53
iii) sample size, n =25
iii) standard deviation = [tex]\sqrt{\frac{p \times q}{n} } = \sqrt{\frac{0.47 \times 0.53}{25} } = 0.0998[/tex]
Therefore the correct option is
a.) The standard deviation is 0.0998. The 10% condition is met because it
is very likely there are more than 250 catfish in the river.
The standard deviation of the sampling distribution of the sample proportion is 0.0998. To determine whether the 10% condition is met, the total population of catfish should be at least 10 times the sample size.
Explanation:The question asks about determining the standard deviation of the sampling distribution of the proportion of catfish in a river and if the 10% condition is met for the sampling distribution to be approximately normal. First, to calculate the standard deviation of the sampling distribution of the sample proportion (p-hat), we use the formula √[(p(1-p))/n], where p is the population proportion and n is the sample size. In this case, p = 0.47, so 1 - p = 0.53, and n = 25. The standard deviation is then √[(0.47*0.53)/25], which is approximately 0.0998.
Next, the 10% condition checks whether we can consider the population large enough that the sample size doesn't affect the population proportion notably when taking without replacement. This condition states that the sample size, n, should be no more than 10% of the population. If there are indeed more than 250 fish in the river (10 times the sample size), we can be confident that the 10% condition is met. If not, the condition is not met.
Therefore, the correct response would state the standard deviation and appropriately evaluate whether the 10% condition is met based on the estimated number of catfish in the river.
What are the terms in the expression, 2 + 6 + 10b – 8a?
The terms in the expression 2 + 6 + 10b - 8a are 2, 6, 10b, and -8a, where 2 and 6 are constants, and 10b and -8a are variable terms.
Explanation:The terms in the expression 2 + 6 + 10b – 8a are 2, 6, 10b, and –8a. A term is a single mathematical expression which can be a number, a variable, or numbers and variables multiplied together. Here, the numbers 2 and 6 are called constant terms because they don’t change, 10b is a variable term which means it has a number (coefficient) and a variable (b), and similarly, –8a is a variable term with a negative coefficient and the variable a.
What is 50/400 simplified
Step-by-step explanation:
[tex] \frac{50}{400} = \frac{5}{40} = \frac{1}{8} = 0.125[/tex]
Which value is an output of the function? -6,-2,4,7
Without knowing the function itself, it's impossible to definitively say which of the values (-6,-2,4,7) is an output. Any of these numbers could potentially be an output depending on the function.
Explanation:In the context of this question, an output of a function refers to the result you get after substituting an input (or value from the domain) into the function. For example, if we have a function f(x) = x+2, and we input the value 3 (from our domain), our output (or range) will be 5. Unless we know the actual function, it's difficult to determine which of the listed values (-6,-2,4,7) is an output because any of these could potentially be an output depending on the function. Thus, without additional context, the statement 'Which value is an output of the function?' cannot be definitively answered.
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The output of a function is -6.
The output of a function is the value that the function produces when a certain input is given. In the table above, the function is f(x). We are given that x can be any of the values -6, -2, 4, or 7. We want to know which of the values -6, -2, 4, 7, or 12 is an output of the function.
To find out, we can look at the table. We see that the only value in the table that is an output of the function is -6. This is because when we plug in x = -6 into the function, we get f(x) = -6.
Therefore, the answer is -6.
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What is -3(x + 4)+15 = 6 - 4x
Answer:
1/3
Step-by-step explanation:
Answer:
x = 3
Step-by-step explanation:
1. Expand.
−3x − 12 + 15 = 6 − 4x
2. Simplify −3x − 12 + 15 to −3x + 3.
−3x + 3 = 6 − 4x
3. Subtract 3 from both sides.
−3x = 6 − 4x − 3
4. Simplify 6 − 4x − 3 to −4x + 3.
−3x=−4x+3
5. Add 4x to both sides.
−3x + 4x = 3
6. Simplify -3x + 4x to x.
x = 3
Use the distributive property to write an expression
that is equivalent to 45 + 30x. Please help!! ;0
Answer:
15(3+2x)
Step-by-step explanation:
Factor out the 15.
11. Solve 10 + 6(–9 - 4x) = 10(x - 12) + 8.
0
O A. X = -6
B. x = 17
OC. x= -18
D. X = 2
0
Answer:
Step-by-step explanation:
10 + 6(-9 - 4x) = 10(x - 12) + 8
10 - 54 - 24x = 10x - 120 + 8
-44 - 24x = 10x - 112
-24x - 10x = -112 + 44
-34x = -68
x = -68/-34
x = 2 <====
Perimeter and area for these 2 please! Give explanation! BIG POINTS
Answer: For the figure on the left {c}, the Area is 30m (squared) and the Perimeter is 46m.
For the figure on the right {d}, the Area is 32cm (squared) and the Perimeter is 34cm
Step-by-step explanation: (Please refers to the attached diagram)
We shall start with the diagram on the left. The first thing is to break it down into regular shapes, such as rectangles, squares, etc. The dotted line that runs from point C to point G divides the figure into two rectangles which are ABCG {or X} and GDEF {or Y}. Line AG measures 10m since it’s the same length as line BC. Similarly line GF measures 2m since it’s the same length as line DE. So rectangle “X” has dimensions;
L = 10, W = 1
Area of a rectangle = L x W
Area = 10 x 1
Area = 10m
Similarly rectangle Y has dimensions L= 10m and W = 2m
Hence area of rectangle “Y” is computed as
Area = L x W
Area = 10 x 2
Area = 20m
Area of the entire figure is derived as
Area of rectangle X + Area of rectangle Y, which is
10m + 20m = 30m {squared)
The perimeter of rectangle X is given as Perimeter = 2(L + W)
Perimeter = 2(10 + 1)
Perimeter = 2(11)
Perimeter = 22m
Also, perimeter of rectangle Y is derived as
Perimeter = 2(L + W)
Perimeter = 2(10+ 2)
Perimeter = 2(12)
Perimeter = 24m
Therefore the perimeter of the entire figure is derived as
Perimeter of rectangle X + perimeter of rectangle Y, which is
22m + 24m and that equals 46m
For the second figure on the right side of the page, we shall also break it down with the dotted lines that runs from point E to point G. That leaves us with rectangle ABGF {or P} and rectangle EGCD {or Q}.
Rectangle “P” has dimensions L= 4 and W = 2
Area of rectangle P = 4 x 2
Area of rectangle P = 8cm
Similarly area of rectangle Q is given as Area of Q = 8 x 3
Area of Q = 24cm
Area of the entire figure is derived as
Area of P + Area of Q,
8cm + 24cm
= 32cm {squared}
To compute the perimeter of rectangle P
Perimeter of a rectangle = 2(L + W)
Perimeter of rectangle P = 2(4 + 2)
Perimeter of rectangle P = 2(6)
Perimeter of rectangle P= 12cm
Similarly Perimeter of rectangle Q = 2(L + W)
Perimeter of rectangle Q = 2(8 + 3)
Perimeter of rectangle Q = 2(11)
Perimeter of rectangle Q = 22cm
Hence, perimeter of the entire figure is derived as perimeter of rectangle P + perimeter of rectangle Q which equals
12cm + 22cm and that equals
34cm.
In a certain chemical, the ratio of zinc to copper is 3 to 11. A jar of the chemical contains 473 grams of copper. How many grams of zinc does it contain?
Answer:
[tex]\large \boxed{\text{129 g}}[/tex]
Step-by-step explanation:
We can use ratio and proportion to solve this problem.
Let x = the mass of Zn
[tex]\begin{array}{cccl}\dfrac{\text{Zn}}{\text{Cu}} & = & \dfrac{3}{11} & \\\\\dfrac{x}{473} & = & \dfrac{3}{11} & \text{Substituted the mass of Cu}\\\\x & = & \dfrac{3\times473}{11} &\text{Multiplied each side by 473} \\\\ & = &\mathbf{129} & \text{Simplified}\\\end{array}\\\text{The mass of Zn is $\large \boxed{\textbf{129 g}}$}[/tex]
Check:
[tex]\begin{array}{rcl}\dfrac{129}{473} & = &\dfrac{3}{11} \\\\\dfrac{3}{11} & = & \dfrac{3}{11} \\\end{array}[/tex]
OK
Simplify the expression: 2/3 divided by - {1/6 - 8/6}
Answer:
4/7
Step-by-step explanation:
1/6-8/6=-7/6
-[1/6-8/6]=7/6
---------------------
(2/3)/(7/6)=(2/3)(6/7)=12/21=4/7
Shane spends 48% of her income on cruises.if she makes $68,000 per year,how much does she spend on cruises?
Answer:
She spend $32,640 on cruises.
Step-by-step explanation:
Given:
Shane spends 48% of her income on cruises.
If she makes $68,000 per year.
Now, to find the money she spend on cruises.
Shane makes income per year = $68,000.
Percent Shane spends of her income on cruises = 48%.
Now, to get the income she spends on cruises:
48% of $68,000.
[tex]=\frac{48}{100} \times 68000[/tex]
[tex]=0.48\times 68000[/tex]
[tex]=\$32,640.[/tex]
Therefore, she spend $32,640 on cruises.
Which line segment is a radius of circle F?
A F⎯⎯⎯⎯⎯
AB⎯⎯⎯⎯⎯
BE⎯⎯⎯⎯⎯
AC⎯⎯⎯⎯
Answer:
A F because it is right i took the test
Find the Derived Function
a) [tex]\frac{dy}{dx} = \frac{1-3lnx}{x^4}[/tex]
b) [tex]\frac{dy}{dx} = \frac{-2}{3\sqrt[3]{1-x} }[/tex]
Explanation:
a) [tex]y=\frac{lnx}{x^3}[/tex]
[tex]y = \frac{lnx}{\sqrt[3]{x} }[/tex]
[tex]y = lnx. x^-3[/tex]
Differentiating the above equation in terms of x
[tex]\frac{dy}{dx} = \frac{1}{x} \times x^-3 - 3lnx\times x^-^4\\\frac{dy}{dx} = \frac{1}{x^4} - \frac{3lnx}{x^4} \\\frac{dy}{dx} = \frac{1-3lnx}{x^4} \\[/tex]
b) [tex]y = \sqrt[3]{1-x^{2} }[/tex]
Differentiating the above equation in terms of x
[tex]y = \sqrt[3]{(1-x)^{2} } \\\frac{dy}{dx} = (1-x)^\frac{2}{3} \\\frac{dy}{dx} = \frac{2}{3}\times (1-x)^\frac{-1}{3} \times -1\\\frac{dy}{dx} = \frac{-2}{3\sqrt[3]{1-x} }[/tex]
Thus,
a) [tex]\frac{dy}{dx} = \frac{1-3lnx}{x^4}[/tex]
b) [tex]\frac{dy}{dx} = \frac{-2}{3\sqrt[3]{1-x} }[/tex]
What number decreased by 77 equals negative 18
Answer:
59
Step-by-step explanation:
77+(-18)=59
Check:
59-77=(-18)
Hoped this helped !
Cheers, Z.
Answer:
59
Step-by-step explanation:
59-77=-18
77+-18=59
36x - 8y2 when x=3 an y= -6
Hey there!
First off, I’m going to assume that the 2 in the second term is an exponent. If it isn’t, let me know and I’ll fix the answer.
Anyways, let’s start by plugging the values for the variables into the equation.
36(3)-8(-6)^2
Square -6
108-8(36)
Multiply.
108-288
Subtract.
-180
Your answer is -180.
Hope this helps!
The tree diagram represents an experiment consisting of two trials.
P(A and C) = [?]
The probability defined as P(A and C) is the probability of P(A) × P(B) = (0.6 × 0.3) = 0.18
The probability of A ; P(A) from the tree diagram is 0.6
The probability of B ; P(B) from the tree diagram is 0.3
The probability, P(A and B) equals ;
P(A) × P(B) = 0.6 × 0.3 = 0.18
Therefore, probability of A and B is 0.18
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The probability of P(A and C) would be 0.18. To understand, check the calculations below.
ProbabilityThe probability is recounted as the proportion of outcomes favorable upon the total possibilities.
What information do we have from the tree diagram:
P(A) = 0.6
P(B) = 0.3
so,
we know that,
P(A and C) = P(A) × P(B)
= 0.6 × 0.3
= 0.18
Therefore, the probability of A and C is 0.18.
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There are
170
170170 deer on a reservation. The deer population is increasing at a rate of
30
%
30%30, percent per year.
Write a function that gives the deer population
P
(
t
)
P(t)P, left parenthesis, t, right parenthesis on the reservation
t
tt years from now.
Answer:
So, we divide
1
by
5
6
→
1
÷
5
6
→
1
⋅
6
5
→
6
5
⇒
1
1
5
=
1.2
So, there are
1
1
5
number of
5
6
's in
1
Step-by-step explanation:
the function that gives the deer population \( P(t) \) on the reservation t years from now is:
[tex]\[ \boxed{P(t) = 170 \times (1.30)^t} \][/tex]
To write a function that gives the deer population [tex]\( P(t) \)[/tex] on the reservation t years from now, where the population is increasing at a rate of 30% per year, we'll use the formula for exponential growth:
[tex]\[ P(t) = P_0 \times (1 + r)^t \][/tex]
Where:
- [tex]\( P(t) \)[/tex] is the population after t years,
- [tex]\( P_0 \)[/tex] is the initial population (in this case, 170),
- r is the annual growth rate (in decimal form), and
- t is the number of years.
Given that the population is increasing at a rate of 30% per year, we have [tex]\( r = 0.30 \)[/tex].
Substituting the given values into the formula, we get:
[tex]\[ P(t) = 170 \times (1 + 0.30)^t \][/tex]
Simplifying further:
[tex]\[ P(t) = 170 \times (1.30)^t \][/tex]
Therefore, the function that gives the deer population \( P(t) \) on the reservation t years from now is:
[tex]\[ \boxed{P(t) = 170 \times (1.30)^t} \][/tex]
The complete Question is given below:
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year. Write a function that gives the deer population P(t) on the reservation t years from now.
The fuel gauge in Nick's car says that he has 26 miles to go until his tank is empty he passed a fuel station 19 miles ago and the sign says that there is a town only 8 miles ahead if he takes a chance and drives ahead to the town and there isn't fuel station any more does he have enough fuel to go back to the last station
Answer:
No
Step-by-step explanation:
The distance from Nick's current spot to the town ahead and back to this spot is 2·8 = 16 miles. Additionally, it is 19 miles back to the gas station, so a total of 35 miles to the gas station via the town ahead. Nick does not have enough gas for that.
If there is no gas in the town ahead, there will need to be a station within 18 miles further on, or Nick will be walking 9 miles to the station he just passed.
H E L P
Factor -6m + 9.
a. -6( m - 3)
b. -6( m + 9)
c. -3(2 m - 3)
d. -3(2 m + 3)
Answer:
c
Step-by-step explanation:
-6m + 9
-3(2m - 3)
Answer:
I think it's c sorry if I am wrong.
Step-by-step explanation:
Vicki would like to estimate the probability of tails coming up fewer than 2 times in 3 coin flips.
To do this, she has a computer randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. The results of 15 trials are shown in the table.
110 111 000 011 000
010 101 100 000 000
111 101 110 101 111
What is Vicki's estimated probability, based on this simulation?
Answer:
0.4
Step-by-step explanation:
Vicki has a computer randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. The results of 15 trials are shown in the table.
110 111 000 011 000
010 101 100 000 000
111 101 110 101 111
Vicki would like to estimate the probability of tails (1) coming up fewer than 2 times (must be 0 or 1 digit 1 in record). All such seuences are marked in bold int the above table. There are 6 such trails. Hence, Vicki's estimated probability, based on this simulation is
[tex]\dfrac{6}{15}=\dfrac{2}{5}=0.4[/tex]
♡ The Question ♡
-What is Vicki's estimated probability, based on this simulation?
* ୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Answer ♡
-The answer would be 0.4, but if you're looking for it in fraction-form it would be 2/5! So your answer is 2/5!
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Explanation/Step-By-Step ♡
-No Explanation/Step-By-Step provided!
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ Tips ♡
-No Tips provided!
I would like to know the answer to the following question
(((10-9)+2)-3)
Work from the inside set of parentheses to the outside at:
(()10-9)+2)-3)
10-9 = 1
1+ 2 = 3
3-3 = 0
The answer is 0
(((10 - 9)+2)-3)
((1+2)-3)
(3-3)
The answer is 0.
⭐ Answered by Hyperrspace (Ace) ⭐
⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐
⭐ If you have questions, leave a comment, I'm happy to help! ⭐
For this right triangle shown, what is the sine of angle C?
A)
15
7
B)
15
8
C)
17
7
D)
17
8
E)
7
8
Answer:
8.212°
Step-by-step explanation:
Hypotenuse^2=base^2+perp^2
(8)^2=(7)^2+(perp)^2
64=49+(perp)^2
64/49=perp^2
1.306=perp^2
Now taking sq root on both sides
Perp=√1.306
Perp=1.142
Sin C=opposite/hypotenuse
Sin C=1.142/8
Sin C=0.14285
C=Sin^-1 0.14285
C=8.212°
Answer:
correct answer is B
Step-by-step explanation:
usatestprep
What is 1/4 * 4x + 8
Answer:
2
Step-by-step explanation:
do like terms
1/4 x 8 = 2
divide un-like terms
4x ÷ 8 = 2
What is the probability that a randomly chosen positive factor of 72 is less than 10?
and
A list consists of all possible three-letter arrangements formed by using the letters A, B, C, D, E, F, G, H such that the first letter is D and either the second or third letter is A. If no letter is used more than once in an arrangement and one three-letter arrangement is randomly selected from the list, what is the probability that the arrangement selected will be DCA?
Problem 1
S = sample space = set of all possible outcomes
S = set of positive factors of 72
S = {1,2,3,4,6,8,9,12,18,24,36,72}
n(S) = number of items in sample space
n(S) = 12
E = event space = set of outcomes we want to happen
E = set of factors of 72 such that they are less than 10
E = {1,2,3,4,6,8,9}
n(S) = number of items in event space
n(S) = 7
P(E) = probability get a value in set E (that is also in set S as well)
P(E) = probability we get a positive factor of 72 that is less than 10
P(E) = n(E)/n(S)
P(E) = 7/12
Answer: 7/12============================================
Problem 2
[tex]\begin{array}{ccl}S & = & \text{Sample Space}\\\\S & = & \{\\ & & ~~DAB, DAC, DAE, DAF, DAG, DAH\\ & & ~~DBA, DCA, DEA, DFA, DGA, DHA\\ & & \}\end{array}[/tex]
n(S) = 12
E = event space
E = {DCA}
n(E) = 1
P(E) = probability we get an item in set S that is in set E also
P(E) = probability we get DCA from set S listed above
P(E) = n(E)/n(S)
P(E) = 1/12
Answer: 1/12please answer this if you can thank you :))
Answer:
The variable that has the highest power is considered to be the degree of polynomials in an algebraic equation.
A column:
1) [tex]4x^3[/tex] .
The degree is 3.
2)[tex]x^2+4[/tex].
The degree is 2.
3) [tex]x-2[/tex]
The degree is 1.
B column:
1) [tex]2x^2+1[/tex]
The degree is 2.
2) [tex]x^2-x[/tex]
The degree is 2.
3) [tex]x^3-5x^2+1[/tex]
The degree is 3.
A×B columns:
While Multiplying two terms in a equation, if the variables are same then multiply the constant value and sum the exponent value.
1) [tex](4x^3)(2x^2+1)[/tex].
=[tex]8x^5+4x^3.[/tex]
The degree is 5.
2) [tex](x^2+4)(x^2-x)[/tex].
=[tex]x^4-x^3+4x^2-4x[/tex].
The degree is 4.
3) [tex](x-2)(x^3-5x^2+1)[/tex].
[tex]=x^4-5x^3+x-2x^3+15x^2-3.\\=x^4-7x^3+15x^2+x-3.[/tex]
The degree is 4.
In 2000, the average price of a football ticket for a Minnesota Vikings game was $48.28. During the next 20 years, the price increased an average of 6% each year. Write a model giving the annual price p (in dollars) of a ticket t in years after 2000.
[tex]y = 48.28(1.06)^t[/tex] is the model giving the annual price p (in dollars) of a ticket t in years after 2000 is found
Solution:
Given that,
In 2000, the average price of a football ticket for a Minnesota Vikings game was $48.28
During the next 20 years, the price increased an average of 6% each year
The increasing function is given by:
[tex]y = a(1+r)^t[/tex]
Where,
y is the value after t years
t is the number of years
a is the initial value
r is rate of increase in decimal
From given,
a = 48.28
[tex]r = 6 \% = \frac{6}{100} = 0.06[/tex]
Substituting the values we get,
[tex]y = 48.28(1+0.06)^t\\\\y = 48.28(1.06)^t[/tex]
Thus the model giving the annual price p (in dollars) of a ticket t in years after 2000 is found
what is 67,456 divided by 32 and tell me how
Answer:
2108
Step-by-step explanation:
Divide 67,456 by 32, using long division.
1) How many times 32 go into 67? (2 times, with a remainder of 3)
2) Bring down the 4.
3) How many times does 32 go into 34? (1 time, with a remainder of 2)
4) Bring down the 5
5) How many times does 32 go into 25? (0 times, so write 0)
6) Bring down the 6.
7) How many times does 32 go into 256? ( 8 times, no remainder)
8) Your answer is 2108
Every Halloween, trick-or-treaters love going to Erica's house to see her spooky decorations and get some of her delicious caramel chews.
There is a proportional relationship between the number of kids in a group, x, and the total number of caramel chews Erica gives to that group, y.
x (kids) y (caramel chews)
2 6
4 12
5 15
6 18
Write an equation for the relationship between x and y.
y=
Answer:
[tex]y=3x[/tex]
Step-by-step explanation:
Let
x ----> the number of kids in a group
y ----> the total number of caramel chews Erica gives to that group
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]
Find the value of the constant of proportionality k
take a ordered pair from the data in the table and determine the value of k
For x=2, y=6 ----> [tex]k=\frac{y}{x}[/tex] ----> [tex]k=\frac{6}{2}=3\ caramels/kid[/tex]
therefore
[tex]y=3x[/tex]
Find the absolute value of a-b-c^2 when a=4, b=-3, and c=10
Answer:-93
Step-by-step explanation:4-(-3)-10²
4+3-100
7-100
=-93
determine whether the realtionship between the circumference of a circle and its diameter is a direct variation. if so, identify the constant of porportionatlity. justify your response
Step-by-step explanation:
Let the radius of a circle be r
The circumference of a circle is(C) [tex]=2\pi r[/tex]
[tex]=\pi d[/tex] [∵2r =d= diameter]
Therefore [tex]C = \pi d[/tex]
Since the value of [tex]\pi[/tex] is always constant. Here the diameter and the circumference are the variables.
So, [tex]C \propto d[/tex]
Therefore the constant of proportionality is [tex]\pi[/tex]
5x6+(5+7) = please help
Answer:
Step-by-step explanation:5×6=30 and 5+7=12
Then is 30+12=42
The answer is 42
I believe the answer is 42.