Find the mistakes in the following code. Not all lines contain mistakes. Each line depends on the lines preceding it. Watch out for uninitialized pointers, NULL pointers, pointers to deleted objects, and confusing pointers with objects.

Answer:

Functional strategies are interdependent

Explanation:

Although functional strategies are usually formed separately, they are somewhat interrelated as a result of some factors.

First, we know that despite the fact that functional strategies can be formed in isolation, they still have to be in coordination with other functions. An example is that if an organization formulates a financial strategy, its implementation depends on more than just the finance function, but also on other functions. Also, from definition, we say that functional strategies are plans formulated by companies for human resources, sales, marketing, finance, and other functional areas. It supports line management and also both business strategy and corporate-level strategy, and hence it can be said that they are interdependent.

Answer:

Functional strategies are interdependent based of organizational strategies.

Explanation:

An organization is a group or encompasses a collection of departments, focused on assigned Target and objectives for each departments, to meet or achieve a general goal. Functional strategies are processes chosen by a department to execute a task.

Functional strategies are actually drafted independently in which departments, but the departmental goals are interrelated, making the their functional strategies interdependent to meet the organizational goals.

Answer:

Option A.

Explanation:

It is a business association working to protect your online privacy. Opa members agree to establish a User privacy Policy that is readable and understandable. So, the option of choosing who sees the data  is the provision is not available in the policy because It has data types policy gathered and how data collected is protected.

Answer:

Explanation:

public class time {

public static void main (String[]args) {

 //Step 1  we declare the variables

 int hours, minutes, seconds;

 hours = 17;

 minutes = 12;

 seconds = 00;

 //For checking

 System.out.println(hours+":"+minutes+":"+seconds);

 //Step 2 we make the operation for the seconds since midnight

 int secSinceMidNite;

 secSinceMidNite = ((hours*60)+minutes)*60 + seconds;

 System.out.println("Seconds since midnight = "+secSinceMidNite);

 //Step 3 we make the operation for the seconds remaining in day

 int secRemainingInDay, totalSecInDay;

 totalSecInDay = 24*60*60;

 secRemainingInDay = totalSecInDay - secSinceMidNite;

 System.out.println("Seconds remaining in day = "+secRemainingInDay);

 //Step 4 in the operation for percentage of day that has passed

 int percentOfDayPassed;  

 percentOfDayPassed = (secSinceMidNite*100)/totalSecInDay;

 System.out.println("Percentage of day that has passed = " +percentOfDayPassed+"%");

}

}

Answer:

Explanation:

In this case, the price of the RAM can rise because cost increase, assume the news of the Wall Street Journal, people with earning lower $80,000 they won't buy RAM because is too expensive, and people with over these earnings will buy less RAM, in addition, the incomes will fall, and the demand of RAM will fall too, but for the same reason the price could fall for the poor demand.

The code is in C.

We use the built-in functions to make the required calculations. These functions are already defined in C. We need to import math.h to be able to use the pow(), fabs(), and sqrt() functions

Comments are used to explain each line of the code

//main.c

//importing the required libraries

#include <stdio.h>

#include <math.h>

#include <stdlib.h>

int main(){

  //Declaring the variables x, y, z

  float x, y, z;

  //Getting inputs for x, y, z

  scanf("%f", &x);

  scanf("%f", &y);

  scanf("%f", &z);

  //Calculating the x to the power of z using the pow function

  double result1 = pow(x, z);

  //Calculating the x to the power of (y to the power of 2) using the pow function inside the another pow function

  double result2 = pow(x, pow(y, 2));

  //Calculating the absolute value of y using the fabs function

  double result3 = fabs(y);

  //Calculating the square root of (xy to the power of z) using the sqrt and pow functions

  double result4 = sqrt(pow(x * y, z));

  //Printing the results using prinntf("%0.2f") to get the two digits after decimal value

  printf("%0.2f\n", result1);

  printf("%0.2f\n", result2);

  printf("%0.2f\n", result3);

  printf("%0.2f\n", result4);

  return 0;

}

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The code takes three floating-point numbers as input (x, y, and z), computes the required expressions using the `pow()` function for exponentiation and the `fabs()` function for absolute value, and then prints the results with two digits after the decimal point using `printf()` formatting.

Here's a C code snippet that implements the required functionality:

#include <stdio.h>

#include <math.h>

int main() {

   double x, y, z;

   scanf("%lf %lf %lf", &x, &y, &z);

   double result1 = pow(x, z);

   double result2 = pow(x, pow(y, 2));

   double result3 = fabs(y);

   double result4 = sqrt(pow(x * y, z));

   printf("%0.2lf %0.2lf %0.2lf %0.2lf\n", result1, result2, result3, result4);

   return 0;

}

Final answer:

The task requires a Python code using a for loop to count down from a specified starting number, printing 'Ready!', each number on a new line, and 'Run!' at the end.

Explanation:

To write code that counts down from a given number and prints 'Ready!', followed by each number, and ending with 'Run!', we can use a for loop. Here is a sample Python code snippet that accomplishes this:

firstNumber = 3
print('Ready!')
for num in range(firstNumber, 0, -1):
   print(num)
   print('\n')
print('Run!')

This code starts by printing 'Ready!', then it enters a for loop that counts down from firstNumber to 1, printing each number followed by a newline. Finally, it prints 'Run!' after exiting the loop. Remember to replace firstNumber with the actual starting number you wish to count down from.

Answer:

def new_list_function(initial_list):

   new_list = initial_list*3

   return new_list

def main():

   initial_list = []

   while True:

     item = input("Enter value to be added to list: ")

     item = item.rstrip()

     if item.lower() == "exit" and "EXIT" and "Exit":

         break

     initial_list.append(item)

     new_list = new_list_function(initial_list)

   for item in new_list:

     print(item)

main()

Explanation:

Answer:

"Classification" is the correct answer to this question.

Explanation:

Classification is primarily a method of data processing, it makes easy for information to be separated and divided into a different business or personal goals by the data set demands.  

Final answer:

To solve the student's problem, input the current and last month's house prices, calculate the price change, compute the estimated mortgage, and correctly format the output presenting the figures.

Explanation:

To create a program that takes the current price and last month's price of a house as inputs, and outputs a summary of the price change and estimated monthly mortgage, follow these instructions:

Here's how the output should look like:

This house is $200000. The change is $-10000 since last month. The estimated monthly mortgage is $850.000000.

```python

current_price, last_month_price = map(int, input().split())

print(f'This house is ${current_price}. The change is ${last_month_price - current_price} since last month. The estimated monthly mortgage is ${(current_price * 0.051) / 12:.6f}.')

```

The program takes two integer inputs, representing the current house price and last month's price. It then uses a formatted string to output a summary, including the current price, the change since last month (calculated by subtracting the current price from last month's price), and the estimated monthly mortgage computed using the given formula. The use of f-strings in Python allows for concise and readable code, embedding expressions directly within the string.

The map function is employed to convert the input values into integers. The program calculates the change in price by subtracting the current price from last month's price. To ensure precise spacing and formatting, the f-string includes the required text and variable values in a structured manner. The estimated monthly mortgage is calculated using the provided formula and formatted as a floating-point value with six decimal places.

The code adheres to the assignment's emphasis on precision in spacing, punctuation, and newlines. By using f-strings and the specified formula, the program produces the required output with clarity and accuracy.

Answer:

The correct answer to the following question will be "True".

Explanation:

Therefore, the given statement is true.

Answer:

The method definition to this question as follows:

Method definition:

//method GetData

       public static void GetData(out int order, out int amount)//defining method GetData  

       {  

           String val1, val2;  //defining String variable

           Write("Enter order number ");  //message

           val1 = ReadLine();  //input value by user

           Write("Enter quantity ");  //message

           val2 = ReadLine();  //input value by user

           order = Convert.ToInt32(val1);  //convert value in integer and hold in order variable  

           amount = Convert.ToInt32(val2);  //convert value in integer and hold in amount variable

       }

Explanation:

In the above C# method definition code a method  GetData() is defined in which the GetData() method is a static method, in this method parameter two integer argument "order and amount" is passed, inside a method, two string variable "val1 and val2" is declared that is used to take input by the user and convert the value into integer and store this value in the function parameter variable.

Final answer:

The question concerns fixing errors in a C# code snippet, specifically with the GetData method call, constant declaration, and output formatting. After corrections, the code should work as intended, calculating the total price of an order.

Explanation:

The question pertains to an issue in a C# program where there are mistakes that need to be resolved to ensure the program runs correctly. Particularly, the errors are in the GetData method call and in the calculation of the total cost.

Firstly, the GetData method is meant to accept an order number and quantity which are not being assigned before the method is called. Secondly, there is an error in referring to the constant PRICE_EACH when calculating the total, as the variable in the calculation is misspelled as 'PRICEEACH'. In addition, the syntax errors like incorrect use of semicolons and missing closing parentheses in the WriteLine methods need to be corrected.

Here is the corrected version of the Main method:

static void Main()
{
int orderNum = 0, quantity = 0;
double total;
const double PRICE_EACH = 3.99;
// Assume GetData correctly assigns values to orderNum and quantity
GetData(orderNum, quantity);
total = quantity * PRICE_EACH;
WriteLine("Order #{0}. Quantity ordered = {1}", orderNum, quantity);
WriteLine("Total is {0}", total.ToString("C"));
}

Note that the pseudo-code for the GetData method implies there is additional logic required to populate the orderNum and quantity variables which is not provided.

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter num 1");

       double num1 = in.nextDouble();

       System.out.println("Enter num 2");

       double num2 = in.nextDouble();

       System.out.println("enter \"s\" for addition\t \"d\" for difference\t \"p\" for the product\t and \"q\" for the quotient");

       char op = in.next().charAt(0);

       if(op =='s'||op=='S'){

           double sum = num1+num2;

           System.out.println("The sum is "+sum);

       }

       else   if(op =='d'||op=='D'){

           double diff = num1-num2;

           System.out.println("The difference is "+diff);

       }

       else if(op =='p'||op=='P'){

           double prod = num1*num2;

           System.out.println("The product is "+prod);

       }

       else if(op =='q'||op=='Q'){

           double quo = num1/num2;

           System.out.println("The Quotient is "+quo);

       }

   }

}

Explanation:

MOHR-COULOMB FAILURE CRITERIA:

In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.

If you can not understand the below symbols see the attachment below

 f   f ()  

Where:      f = Shear Stress on Failure Plane  

       ´= Normal Stress on Failure Plane

 See the graph in the attachment

For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula:   shear stress =  f  c   tan 

Where,  

• f  is Shear Stress on Failure Plane

• c  is Cohesion

•  is Normal Total Stress on Failure Plane

•  is Friction Angle

To output the average and product of three floating-point numbers as rounded integers as well as floating-point numbers with two decimal points, we can use the Python string formatting expression. Given the inputs 10.3, 20.4, and 5.0, the average is rounded to 11 and the product is rounded to 1050 as integers. As floating-point numbers, formatted with two decimal places, the average is 11.90 and the product is 1050.60.

The average calculation is (10.3 + 20.4 + 5.0) / 3, which equals 11.9 when not rounded. For the integer part, we round 11.9 to 11. The product is 10.3 * 20.4 * 5.0, which equals 1052.6, rounded to 1050 as an integer. To format these as floating-point numbers using Python string formatting: '%0.2f' % 11.9 for the average and '%0.2f' % 1052.6 for the product, yielding 11.90 and 1050.60, respectively.

Answer:

C++ Program

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

void arrSelectSort(double *, int);

void showArrPtr(double *, int);

void showAverage(double, int);

int main()

{

 //dynamically allocate an array

 //acumulator

 //averge scores

 //number of test scores

 double *scores,                        

 total = 0.0;                  

//average;                              

int nScores;                      

   //Get how many test scores the users wants to enter.

cout << "How many test scores would you like to process?";

cin >> nScores;

//condition about the scores

scores = new double[nScores];

if (scores == NULL)

 return 0;

//Get the number of each test

cout << "Enter the test scores below.\n";

for (int count = 0; count < nScores; count++)

{

 cout << "Test score #" << (count + 1) << ": ";

 cin >> *(scores + count);

}

//total score operation

for (int count = 0; count < nScores; count++)

{

 total += *(scores + count);

}

showAverage(total, nScores);

//the array pointers

arrSelectSort(scores, nScores);

cout << "the ascending order is: \n";

showArrPtr(scores, nScores);

//free memory.

delete[] scores;

scores = 0;

return 0;

}

// bubble sort  

void arrSelectSort(double *array, int size)

{

int temp;

bool swap;

do

{

 swap = false;

 for (int count = 0; count < (size - 1); count++)

 {

  if (*(array + count) > *(array + count + 1))

  {

   temp = *(array + count);

   *(array + count) = *(array + count + 1);

   *(array + count + 1) = temp;

   swap = true;

  }

 }

} while (swap);

}

// sort function

void showArrPtr(double *array, int size)

{

for (int count = 0; count< size; count++)

 cout << *(array + count) << " ";

cout << endl;

}

// average function

void showAverage(double total, int nScores)

{

double average;

//average operation

average = total / nScores;

//Display the results.

cout << fixed << showpoint << setprecision(2);

cout << "Average Score: " << average << endl;

}

Answer:

The answer is explained below:

Explanation:

There are various modes in a computer that can be used as per the need.

The three modes provided in a compute are Standby, sleep and Hibernate.

Hibernate: Hibernate mode saves all the open windows and then shuts down the computer. It also saves more energy because the computer goes off completely. A computer needs more time to wake up from hibernation mode.

Sleep mode: Sleep mode means different things on different computers and operating systems. In windows it means standby. It the computer has been sleeping for  more than three hours then it hibernates automatically.  

Standby: Standby mode is for saving energy, it puts your computer into energy saving mode.

Shutdown: If you shut down a computer then all the software programs are closed and the computer turns off. The last program to be closed is operating system.

Fully awake mode means that the computer is running normally.

Answer:

There are four options for this question: A and D are correct.

A. By adding a mobile layout and assigning it to a profile.

B. By adding quick actions in the publisher section

C. By adding actions in the Salesforce1 action bar section.

D. By adding Visualforce page to the mobile cards section.

Explanation:

We can add a different view for the users instead of the standard web, we can use a mobil design and assign a different profile, addition, we can implement the visualforce page to create a new view, with this option we make a better and interesting user interface with interaction with different views.

Answer:

0.24 seg

Explanation:

We have 600 MB of data if we convert it to Gb we get 0.6Gb of data, the bandwidth is telling us that we can transfer 2.5 Gb of data per second if we assume that the data transfer is lineal we can apply the rule of three to solve the problem:

2.5 Gb -> 1 seg

0.6 Gb -> X

Applying the cross multiplication we get that X = 0.6 Gb* 1 seg / 2.5 Gb = 0.24 seg

The time required to transfer a 600-MB database over a DMA channel with a bandwidth of 2.5 GB/s is 0.24 seconds.

To calculate the transfer speed of a 600-MB database over a DMA channel with a bandwidth of 2.5 GB/s, you first need to convert the database size to the same unit as the bandwidth. In this case, 600 MB = 0.6 GB.

The time to transfer data over a channel is equivalent to the size of the data (in GB) divided by the bandwidth (in GB/s). Therefore, the time to transfer the 600-MB database would be 0.6 GB / 2.5 GB/s = 0.24 seconds.

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#SPJ3

Answer:

The Java code is given below with appropriate comments

Explanation:

import java.util.*;

class Main {

   static Set<String> set = new HashSet();

   static void printPerms(char ch[], int ind){

       //If end of string is reached, add it to set

       if(ind==ch.length){

           set.add(new String(ch));

           return;

       }

       for(int i=ind;i<ch.length;i++){

           //Only swap if lower case

           if((ch[i]>='a' && ch[i]<='z')&&((ch[ind]>='a' && ch[ind]<='z'))){

               char t  = ch[i];

               ch[i] = ch[ind];

               ch[ind] = t;

           }

           printPerms(ch,ind+1);

           if((ch[i]>='a' && ch[i]<='z')&&((ch[ind]>='a' && ch[ind]<='z'))){

               char t  = ch[i];

               ch[i] = ch[ind];

               ch[ind] = t;

           }

       }

   }

   public static void main(String[] args) {

       printPerms("aBbCc".toCharArray(),0);

       System.out.println(set);

   }

}

Final answer:

The question involves creating an algorithm to generate permutations of a given string without altering the positions of uppercase alphabets, a problem suitable for Computers and Technology at the college level.

Explanation:

The task requires generating all permutations of a given string while maintaining the original positions of the uppercase alphabets. This is typically a problem that can be approached algorithmically, falling under the category of Computers and Technology. To solve it, you would need to find permutations of the lowercase letters only and then insert them back into the string at the positions not occupied by uppercase letters.

One way to achieve this is to extract all lowercase letters and use a permutation algorithm, such as Heap's algorithm, to generate all permutations while the uppercase letters act as anchors, holding their respective positions fixed. As each permutation of the lowercase letters is generated, it's interlaced with the uppercase ones to construct a full-string permutation that meets the condition. This process is repeated until all permutations of the lowercase characters are exhausted.

The pH scale measures how acidic or basic a substance is. Human blood (pH 7.4) is basic, household ammonia (pH 11.0) is also basic, and cherries (pH 3.6) are acidic.

To compare the value of ph to 7.0, we can use an if-else statement in Python. We can assign the values to the variables neutral, base, and acid as follows:

Answer:

"knowledge management"  is the answer for the above question.

Explanation:

Answer:

   public static void printTotalInches(double num_feet, double num_inches){

       double inches = 12*num_feet;

       System.out.println("Total value in feets is: "+(inches+num_inches));

   }

This function is written in Java Programming Language. Find a complete program with a call to the function in the explanation section

Explanation:

public class ANot {

   public static void main(String[] args) {

//Calling the function and passing the arguments

   printTotalInches(5,8);

   }

   public static void printTotalInches(double num_feet, double num_inches){

       double inches = 12*num_feet;

       System.out.println("Total value in feets is: "+(inches+num_inches));

   }

}

Answer:

def calc_total_inches(num_feet, num_inches):

   return num_feet*12+num_inches

Explanation:

Answer:

Scripts for businesses are always followed exactly.

Explanation:

A computer script is a list of commands that are executed by a certain program or scripting engine. Scripts may be used to automate processes on a local computer.

Answer:

The correct answer to the following question will be "False".

Explanation:

Therefore, the given statement is false.

Answer:

360 msec

Explanation:

Data provided in the question:

Distance between the two hosts = 15,000 kilometer

= 1.5 × 10⁷ m    [ ∵ 1 km = 1000 m ]

Transmission rate, R = 5 Mbps = 5 × 10⁶ bits per second

Propagation speed over the link = 2.5 × 10⁸ meters/sec

Size of file to be sent = 1,500,000 bit

Now,

Propagation delay (dprop)

= Distance ÷ Speed

= ( 1.5 × 10⁷ ) ÷ (2.5 × 10⁸)

= 0.06 sec

= 60 msec           [ ∵ 1 sec = 1000 millisecond ]

Transmission delay (dtrans)

= Size of file ÷ Rate of transmission

= 1500000 ÷ ( 5 × 10⁶ )

= 0.3 sec

= 300 msec

Therefore,

Time required for transmitting the file

= Propagation delay + Transmission delay

= 60 msec + 300 msec

= 360 msec

Final answer:

The total time to send a 1,500,000-bit file from host A to host B over a distance of 15,000 kilometers at a rate of 5 Mbps is 0.36 seconds, which is the sum of the transmission time (0.3 seconds) and the propagation delay (0.06 seconds).

Explanation:

To calculate the time taken to send a 1,500,000-bit file from host A to host B separated by 15,000 kilometers at a rate of 5 Mbps, you need to consider both the transmission time and the propagation delay. The transmission time is the time required to push all the file's bits onto the wire and is given by the file size divided by the transmission rate. The second part is the propagation delay, which is the time it takes for the first bit to travel from the source to the destination.

The transmission time can be calculated as: Transmission Time = File size / Rate = 1,500,000 bits / (5 x 10⁶ bits/sec) = 0.3 seconds.

The propagation delay is the distance divided by the speed of light in the medium, which is: Propagation Delay = Distance / Speed of light = 15,000 km / (2.5 x 10⁸ m/s) = 0.06 seconds. Since the distance needs to be in meters, we convert it by multiplying by 1,000: Propagation Delay = 15,000,000 m / (2.5 x 10⁸ m/s) = 0.06 seconds.

The total time to send the file is the sum of transmission time and propagation delay: Total Time = Transmission Time + Propagation Delay = 0.3 s + 0.06 s = 0.36 seconds.

Answer:

import random

paswrd = input("Enter Pass: ")

while len(paswrd) < 8:

print('Password not long enough.')

paswrd = input("Enter Pass: ")

paswrd = paswrd.replace('e', '@')

paswrd = paswrd.replace('E', '@')

paswrd = paswrd.replace('s', '$')

paswrd = paswrd.replace('S', '$')

paswrd = paswrd.replace('t', '+')

paswrd = paswrd.replace('T', '+')

paswrd = paswrd.capitalize()

paswrd = paswrd + (str(random.randint(1,999)))

print(paswrd)

Explanation:

True, the newline character is generated by pressing the Enter or Return key and is used to signify the end of a line across various operating systems.

True, when working at the keyboard, the user generates a newline character by pressing the Enter or Return key. This action instructs the computer to move to the next line, and it's supported by the underlying ASCII character set which includes a 'carriage return' (CR) and a 'line feed' (LF) to represent the end of a line.

While different operating systems have their own conventions for line endings (Windows uses CRLF, Unix uses LF, and early Apple Mac used CR), the concept of the newline character is consistent across different platforms and is often represented by '\n' in text processing.

Answer:

.

Explanation:

The traditional waterfall method involves the breakdown of projects into

linear sequential phases. This method didn't give enough room for changes

to be made during testing stages.

The practitioners of alternative software development methods were not

satisfied with the traditional waterfall method due to other reasons such as:

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It should be noted that the practitioners of alternative software development methods not satisfied with the traditional waterfall method because;

The traditional waterfall method in software development can be regarded as a method which involves development of the projects base on linear sequential phases.

However, this method doesn't allow to make changes Incase their is an error during testing stages.

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Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

Final answer:

To represent 8 opcodes, 3 bits are required; for 10 registers, a minimum of 4 bits is needed. Therefore, if using a 32-bit instruction encoding, there would be 25 unused bits.

Explanation:

If we consider the scenario where there are 8 opcodes and 10 registers, we can figure out the minimum number of bits required for representing each by understanding how numbers are represented in binary.

Understanding these numbers helps with the basics of how computer instructions and machine code are structured, which is essential knowledge in computer architecture and programming.