Express 2.41 x 10^4 in a standard form

Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

[tex]a_1=12 \\ a_n=a_{n-1}+4.[/tex]

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

[tex]a_1=20\\ a_n=a_{n-1} - 5[/tex]

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

Yo sup??

6x^2+5x is a polynomial

-x^2+52 is also a polynomial

-7x^2+5/3x is not a polynomial as power of x is negative

x^2+5x^1/5 is not a polynomial as power of x is fraction

Hope this helps.

Answer:

200

Step-by-step explanation:

50 or more round up

49 and down you round to the last whole hundred or number

hope this helped please mark brainliest and rate

Answer:

not that hard sir

Step-by-step explanation:

do 7/8 x 5

Final answer:

Tarryn drives a total of 8.75 miles in a week to and from work, with each one-way trip being 7/8 mile and she works 5 days a week.

Explanation:

Calculating Total Distance Driven

Tarryn drives to and from work 5 days a week, with each trip being 7/8 mile. To calculate the total distance she drives in a week, we need to consider both the trip to work and the return trip. This will give us the daily round trip distance, which we will then multiply by the number of days she works in a week.

First, we calculate the daily round trip distance:

Round trip distance = Distance to work + Distance from work

Round trip distance = 7/8 mile + 7/8 mile

Round trip distance = 7/4 miles (or 1.75 miles)

Then, we calculate the total distance for the week:

Total weekly distance = Daily round trip distance × Number of workdays

Total weekly distance = 7/4 miles × 5 days

Total weekly distance = 35/4 miles (or 8.75 miles)

Therefore, Tarryn drives a total of 8.75 miles over the course of a 5-day workweek.

A line is graphed in the x-y plane and it will follow a path of straight line and equation for that is,  Y = (-3/2)X.

So option (C) is correct.

The equation of a straight line is a relationship between x and y coordinates, The equation of a straight line is y = mx + c, where m is the slope of the line and c is the y-intercept.

The net change in y coordinate is written as, Δy and the net change in x coordinate is written as, Δx.

m = change in y coordinate/change in x coordinate = Δy/Δx = y2-y1/x2-x1

In given graph,

Line is passing through the points (2, -3) & (-2 ,3)

Slope = -3-3/2-(-2)

Slope = -3/2

y = (-3/2) x + c  ____(i)

by putting point (2, -3) in  equation (i)

-3 = (-3/2) 2 + c

c = 0

Hence, The equation is  Y = (-3/2)X

To know more about the equation of line check:

https://brainly.com/question/2564656

#SPJ2

Answer:

[tex]\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=-\log 4[/tex]

Step-by-step explanation:

[tex]\log 2-\log 8=\log\frac{2}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=\log 1-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \log 1=0[/tex]

Answer:

log(1/4)

log(2) + log (1/8)

Answer:

$278

Step-by-step explanation:

There is an endowpayment policy with face of $25,000 with the annual premium $22.24 per $1000.

So, the annual premium of the endowpayment policy with face of $25,000 will be equal to [tex]\frac{25000}{1000}\times 22.24 = 556[/tex] dollars.

And the semi annual payment for this policy will be [tex]\frac{556}{2} = 278[/tex] dollars. (Answer)

4 pints of strawberries and 2 pints of blueberries are bought

Solution:

Let "a" be the pints of strawberries bought

Let "b" be the pints of blueberries cost

Cost per pint of strawberry = $ 1.60

Cost per pint of blueberry = $ 2.30

A shopper bought twice as many pints of strawberries as pints of blueberries

Therefore,

a = 2b --------- eqn 1

They spent a total of $11.00. Therefore we frame a equation as:

pints of strawberries bought x Cost per pint of strawberry + pints of blueberries cost x Cost per pint of blueberry = 11

[tex]a \times 1.60 + b \times 2.30 = 11[/tex]

1.6a + 2.3b = 11 --------- eqn 2

Substitute eqn 1 in eqn 2

1.6(2b) + 2.3b = 11

3.2b + 2.3b = 11

5.5b = 11

Divide both sides by 11

b = 2

Substitute b = 2 in eqn 1

a = 2(2)

a = 4

Thus 4 pints of strawberries and 2 pints of blueberries are bought

Answer:

3.45

Step-by-step explanation:

Its right on the quiz

Work is attached in the image provided.

8x + -4 > 12

8x > 16

x > 2

Hope this helps! ;)

Answer:8x + -4 > 12

8x > 16

x > 2

Step-by-step explanation:

See picture for solution to your problem.

At the same rate, the bakery would sell approximately 10 loaves of bread for every 7 rolls.

The bakery sells 25 rolls for every 35 loaves of bread. To find out how many loaves of bread will be sold for every 7 rolls of bread, we need to use a simple proportion based on the given ratio. This can be set up as a fraction, 25 rolls/35 loaves = 7 rolls/x loaves, where x represents the number of loaves sold for every 7 rolls.

We can solve for x by cross-multiplying:

(25 rolls/35 loaves) = (7 rolls/x loaves),

so 25x = 35*7.

The next step is to divide both sides of the equation by 25 to solve for x:

x = (35*7)/25 = 9.8 loaves.

Therefore, the bakery would sell approximately 10 loaves of bread for every 7 rolls, given the same rate.

Answer:

-8x+60

Step-by-step explanation:

3(-3x+20)+ 5(x/5)

Solve one term at a time

3(-3x+20)

-9x+60

Solve second term

5(x/5)

5x/5

X

Add both terms together

-9x+60+x

-9x+x+60

-8x+60

-8x+60

Step-by-step explanation:

3(-3x+20)+ 5(x/5)

Solve one term at a time

3(-3x+20)

-9x+60

Solve second term

5(x/5)

5x/5

X

Add both terms together

-9x+60+x

-9x+x+60

-8x+60

x = 3

Step-by-step explanation:

First we would simplify the left hand side of the equation by expanding the brackets

so 2(4-3x) = 8-6x and

5(2x-3) = 10x-15

This gives the left hand side as 8-6x+10x-15. So the overall equation becomes

8-6x+10x-15 = 20-5x.

Grouping the unknown values on one side and integers on one side of the equation gives us

8-15-20=6x-10x-5x (note the sign changes when numbers and unknown values are moved to the other side of the = sign

Solving further, -27 = -9x i.e x = -27/-9 = 3

Hence x = 3

Answer:

3

Step-by-step explanation:

Answer:

3,-2

Step-by-step explanation:

Answer:

ITS (-3,2)

Step-by-step explanation:

(A)  4 sec the ball is in the air.

(B) Height of the ball = 49 ft.

(C) Yes, the ball is at its maximum height at 1.5 seconds.

Solution:

Given data:

[tex]h(t)=-16t^2+48t+64[/tex]

Initial velocity = 48 ft/s

Height = 64 ft

(A)  [tex]-16t^2+48t+64=0[/tex]

a = –16, b = 48, c = 64

We can solve it by using a quadratic formula,

[tex]$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{(48)^{2}-4 \times(-16)(64)}}{2(-16)}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{2304+4096}}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm \sqrt{6400}}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 \pm 80}{-32}[/tex]

[tex]$\Rightarrow t=\frac{-48 + 80}{-32},\frac{-48 - 80}{-32}[/tex]

[tex]$\Rightarrow t=-1,t=4[/tex]

Time cannot be in negative. So neglect t = –1

t = 4 sec

Hence, 4 sec the ball is in the air.

(B) When t = 1.5 sec,

[tex]h(1.5)=-16(1.5)^2+48(1.5)+64[/tex]

h(1.5) = 49 ft

(C) The maximum height occurs at the average of zeros.

Average = [tex]\frac{(-1+4)}{2}=1.5[/tex] sec

Yes, the ball is at its maximum height at 1.5 seconds.

Answer:

y=4x+8

Step-by-step explanation:

y-y1=m(x-x1)

y-(-8)=4(x-(-4))

y+8=4(x+4)

y=4x+16-8

y=4x+8

To find the total weight of the hamburger in three packages, multiply the weight of one package by three. The total weight of the hamburger is 5 1/4 pounds.

The student's question involves finding the total weight of three packages of hamburger, each weighing 1 3/4 pounds.

To solve this problem, the weight of one package must be multiplied by the number of packages.

The calculation is: 1 3/4 pounds × 3, or in improper fraction form, (7/4) pounds × 3.

Multiplying the improper fraction by 3, we have:

The fraction 21/4 is equivalent to 5 1/4 when converted into a mixed number because 21 divided by 4 is 5 with a remainder of 1.

Therefore, Mary has a total of 5 1/4 pounds of hamburger across the three packages.

[tex]1\frac{1}{6}[/tex] cups of cheese should be used for [tex]\frac{2}{3}[/tex] of the recipe.

Step-by-step explanation:

Given,

Quantity of cheese used in recipe = [tex]1\frac{3}{4}\ cups = \frac{7}{4}\ cups[/tex]

Recipe to made = [tex]\frac{2}{3}[/tex]

Quantity to use in [tex]\frac{2}{3}[/tex] of recipe = [tex]\frac{2}{3}\ of\ quantity\ required\ for\ full\ recipe[/tex]

Quantity to use = [tex]\frac{2}{3}*\frac{7}{4}[/tex]

Quantity to use = [tex]\frac{7}{6} = 1\frac{1}{6}\ cups[/tex]

[tex]1\frac{1}{6}[/tex] cups of cheese should be used for [tex]\frac{2}{3}[/tex] of the recipe.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

Answer:

y =16

I have solved it . It's in the picture above. Hope it helps

30 m

Step-by-step explanation:

Step 1 :

Let x be the distance traveled.

Speed taken while going is given as 60mph.

Hence time taken for the onward journey =x/60

Speed for the return journey is 20mph

Hence time for the return journey is x/20

Step 2:

Total time is from 10 m to 2 pm. Deducting the 2 hours taken for lunch, time spent for the onward and return journey is 2 hrs

=> X/60 + x/20 = 2.

Solving for x we get x = 30

Hence the distance between the office and Valerie's is 30 m

Answer:

Explanation:

I will rewrite the table to understand how the process of solving using succesive approximations is.

Table:

x        f(x)      g(x)

0        - 5      - 6

1         - 3       - 5

2        - 1       - 2

3          1          3

Those are the points shown in the table.

Now you must continue the process of solving using successive approximations until you find the positive solution to the nearest tenth.

You need to determine whether a "guess" is closer or farther away of the solution.

The first row shows that g(x) is less than f(x) in 1 unit when x = 0 ( -6 - (-5) ) = -1.

The second raw shows that g(x) is less than g(x) in 2 units when x = 1 ( - 5 - (-3) ) = - 2

The third row shows that g(x) is is less than f(x) in 1 unit when x = 2 ( - 2 - (-1) ) = - 1.

The fourth row shows that g(x) is than f(x) in 2 units when x = 3 ( 3 - 1 = 2).

Hence, the trend changed form negative to positive, meaning that, since the functions are continous, there must be an intertemediate value of x (between x = 2 and x = 3) for which f(x) = g(x) and that is the solution.

Therefore, test x = 2.5

Test for x = 2.4

Now the difference is less than 0.1 and the solution to the nearest tenth is (2.4, - 0.2).

Answer:

answer is 2.7

Step-by-step explanation:

I got it right

Using the negative exponent rule move x^-2 to the numerator

Answer = 5x^2/y^5

Answer:

  392

Step-by-step explanation:

You want the value of the square of the length XY, given X and Y are outside and symmetrically opposite the center of a 10-unit square and each is 6 units and 8 units from the two nearest vertices.

The attached drawing shows the positions of points X and Y. Each is 4.8 units horizontally and 3.6 units vertically from the nearest vertex of the square. That means their locations relative to each other are ...

  horizontally: 2×4.8 +10 = 19.6 units

  vertically: 6.4 -3.6 = 2.8 units

The square of the distance between X and Y will be given by the Pythagorean theorem:

  XY² = 19.6² +2.8² = 384.16 +7.84

  XY² = 392

__

Additional comment

The locations of X and Y relative to the side of the square can be found using the "geometric mean" relations for a right triangle. Triangle QXP has side lengths 6, 8, 10, which are a multiple of the well-known {3, 4, 5} right triangle. So ∆QXP is a right triangle with a right angle at X.

The length QX is the geometric mean √(QA·QP), so we have ...

  6 = √(10·QA)
  36 = 10·QA
  QA = 3.6   ⇒   PA = 6.4

and

  XA = √(QA·PA) = √(3.6·6.4)
  XA = 4.8

The value of [tex]\( XY^2 \)[/tex] is 100.

Let's begin by visualizing the problem. We have a square PQRS with side length 10. Points X and Y are outside the square such that XQ = YS = 6 and XP = YR = 8. We need to find the square of the distance between X and Y, denoted as [tex]\( XY^2 \)[/tex].

To solve this, we can use the Pythagorean theorem. Let's consider triangle XPQ. Since PQRS is a square, angle PQX is a right angle. Therefore, triangle XPQ is a right-angled triangle with PQ as the hypotenuse and XQ and XP as the other two sides.

Using the Pythagorean theorem for triangle XPQ, we have:

[tex]\[ 8^2 = 6^2 + XQ^2 \][/tex]

[tex]\[ 64 = 36 + XQ^2 \][/tex]

[tex]\[ XQ^2 = 64 - 36 \][/tex]

[tex]\[ XQ^2 = 28 \][/tex]

Now, we have found the square of the distance XQ, which is [tex]\( 28 \)[/tex].

Similarly, for triangle YRQ, which is also a right-angled triangle with YR as one leg and YS as the other leg, and RQ as the hypotenuse, we can write:

[tex]\[ 8^2 = 6^2 + RQ^2 \][/tex]

[tex]\[ 64 = 36 + RQ^2 \][/tex]

[tex]\[ RQ^2 = 64 - 36 \][/tex]

[tex]\[ RQ^2 = 28 \][/tex]

We have found that [tex]\( RQ^2 = 28 \)[/tex], which is the same as [tex]\( XQ^2 \)[/tex].

Now, to find [tex]\( XY^2 \)[/tex], we need to consider the distance between points X and Y. Since X and Y are outside the square and their distances to the square are equal (XQ = YS and XP = YR), the line segment XY is parallel to side PQ of the square and is also equal to the side length of the square, which is 10.

Therefore, [tex]\( XY^2 \)[/tex] is simply the square of the side length of the square PQRS:

[tex]\[ XY^2 = PQ^2 \][/tex]

[tex]\[ XY^2 = 10^2 \][/tex]

[tex]\[ XY^2 = 100 \][/tex]

Answer: 1/4

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

i had the same question and 1/4 was right

Answer:

Step-by-step explanation:

Simple multiply both 8 and 12 by any number and then equivalent

Answer:

3/4 or 16/24 or 2/3

Step-by-step explanation:

Answer:

Part 1) [tex]z=121^o[/tex]

Part 2) [tex]x=59^o[/tex]

Part 3) [tex]y=49^o[/tex]

Part 4) [tex]w=72^o[/tex]

Step-by-step explanation:

step 1

Find the measure of angle z

we know that

The sum of exterior angles in a polygon is always equal to 360 degrees

so

[tex]z^o+(z+10)^o+(z-13)^o=360^o[/tex]

solve for z

[tex](3z-3)^o=360^o[/tex]

[tex]3z=363\\z=121^o[/tex]

step 2

Find the measure of angle x

we know that

[tex]z^o+x^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]121^o+x^o=180^o[/tex]

[tex]x=180^o-121^o=59^o[/tex]

step 3

Find the measure of angle y

we know that

[tex]y^o+(z+10)^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]y^o+(121+10)^o=180^o[/tex]

[tex]y=180^o-131^o=49^o[/tex]

step 4

Find the measure of angle w

we know that

[tex]w^o+(z-13)^o=180^o[/tex] ---> by supplementary angles (form a linear pair)

we have

[tex]z=121^o[/tex]

substitute

[tex]w^o+(121-13)^o=180^o[/tex]

[tex]w=180^o-108^o=72^o[/tex]

Answer: X = 27

Step-by-step explanation: The diagram shows two triangles with one triangle cut out from the other. A careful observation would reveal triangle BDR and triangle QDC.

Since line QC is parallel to line BR, that makes triangle QDC similar to triangle BDR. Also the ratio of lines QD and BQ is the same as the ratio of lines CD and RD. The same applies to lines QC and BR.

Therefore,

QD/BQ = CD/RC

Alternatively we can use the ratios,

QD/BD = CD/RD

Using the first ratios, we have

QD/BQ = CD/RC

39/26 = X/18

3/2 = X/18 {the left hand side has been reduced to it's simplest form}

If we cross multiply, we now arrive at

3 × 18 = 2X

54 = 2X

Divide both sides of the equation by 2

27 = X

Answer:

Step-by-step explanation: