Elena is cutting a 30-foot piece of ribbon for a craft project. She cuts off 7 feet, and then cuts the remaining piece into 9 equal lengths of x feet each.

Answer:

The two equivalent expression are  [tex]T=6(9.5+1.5)[/tex] and [tex]T=6\times9.5+6\times1.5[/tex].

The Total cost at state fair will be $66.

Step-by-step explanation:

Given:

Number of friends = 6

Cost for admission for each at the fair = $9.50

Cost of each person ride on Ferris wheel = $1.50

We need to find the two equivalent expressions and then find the total cost.

Solution:

Let the Total Cost be denote by 'T'.

So we can say that;

Total Cost will be equal to Number of friends multiplied by sum of Cost for admission for each at the fair and Cost of each person ride on Ferris wheel.

framing in equation form we get;

[tex]T=6(9.5+1.5)[/tex]

Now Applying Distributive property we get;

[tex]T=6\times9.5+6\times1.5[/tex]

Hence The two equivalent expression are [tex]T=6(9.5+1.5)[/tex] and [tex]T=6\times9.5+6\times1.5[/tex].

On Solving the above equation we get;

[tex]T=57+9= \$66[/tex]

Hence The Total cost to state fair will be $66.

Answer: e. The population median

Step-by-step explanation:

If repeated intervals are taken for each sample then the 90% of the intervals would actually have the population median in them. The other options like the sample mean, the sample median and the sample standard deviation and population will not be captured as only the population median is captured and confidence intervals can be interpreted in this way.

Answer:

X is greater than or equal to 15

Step-by-step explanation:

Final answer:

The inequality x >= 15 represents Samuel's goal of eating at least 15 grams of protein each day. Protein-rich foods like chicken breast and Greek yogurt are good sources of protein.

Explanation:

The inequality representing the situation is: x >= 15

To meet his goal of eating at least 15 grams of protein each day, Samuel should eat at least 15 grams of protein daily.

Examples of protein-rich foods include:

3 ounces of chicken breast: about 25 grams of protein

1 cup of Greek yogurt: approximately 20 grams of protein

Answer:

The 98% confidence interval for population proportion of people who refuse evacuation is {0.30, 0.33].

Step-by-step explanation:

The sample drawn is of size, n = 5046.

As the sample size is large, i.e. n > 30, according to the Central limit theorem the sampling distribution of sample proportion will be normally distributed with mean [tex]\hat p[/tex] and standard deviation [tex]\sqrt{\frac{\hat p (1-\hat p)}{n} }[/tex].

The mean is: [tex]\hat p=0.31[/tex]

The confidence level (CL) = 98%

The confidence interval for single proportion is:

[tex]CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }][/tex]

Here [tex]z_{(\alpha /2)}[/tex] = critical value and α = significance level.

Compute the value of α as follows:

[tex]\alpha =1-CL\\=1-0.98\\=0.02[/tex]

For α = 0.02 the critical value can be computed from the z table.

Then the value of [tex]z_{(\alpha /2)}[/tex] is ± 2.33.

The 98% confidence interval for population proportion is:

[tex]CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33][/tex]

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.  

Final answer:

The 98% confidence interval for the proportion of coastal residents who would evacuate is between approximately 67.49% and 70.51%. This reflects our confidence that the true proportion falls within this range, with only a 2% chance of being outside these bounds.

Explanation:

To estimate the proportion of coastal residents who would evacuate using a 98% confidence interval based on the available survey data, we look at the reported figure that 31% of the people will refuse to evacuate, which implies that 69% would evacuate. The sample size is 5046 adults. To calculate the 98% confidence interval for the true proportion, we use the formula for the confidence interval of a proportion:

Confidence interval = p ± Z*sqrt((p(1-p))/n)

where:

p is the sample proportion (0.69 in this case),

Z is the Z-score associated with the confidence level (2.326 for 98% confidence),

sqrt denotes the square root function,

n is the sample size.

Plugging the values into the formula, we get:

Confidence interval = 0.69 ± 2.326 * sqrt((0.69(1-0.69))/5046)

Performing these calculations:

Confidence interval = 0.69 ± 2.326 * sqrt(0.2141/5046)

Confidence interval = 0.69 ± 2.326 * sqrt(0.0000424451086)

Confidence interval = 0.69 ± 2.326 * 0.0065134

Confidence interval = 0.69 ± 0.015143

So the 98% confidence interval for the proportion of coastal residents who would evacuate is approximately 0.6749 to 0.7051, or 67.49% to 70.51%.

Interpreting this confidence interval at the 98% confidence level means that we can be 98% confident that the true proportion of all coastal residents in these high-risk areas who would evacuate falls between 67.49% and 70.51%. This does not mean that the true proportion is within this interval with 100% certainty, but rather that there's a 2% chance that the true proportion lies outside of this interval.

Answer:

We conclude that the statement B is true. The solution is also attached below.

Step-by-step Explanation:

As the inequality graphed on the number line showing that solution must be   < x    (-∞, 3] U [5, ∞)

So, lets check the statements to know which statement has this solution.

Analyzing statement A)

[tex]x^2-3x+5>\:0[/tex]

[tex]\mathrm{Write}\:x^2-3x+5\:\mathrm{in\:the\:form:\:\:}x^2+2ax+a^2[/tex]

[tex]2a=-3\quad :\quad a=-\frac{3}{2}[/tex]

[tex]\mathrm{Add\:and\:subtract}\:\left(-\frac{3}{2}\right)^2\:[/tex]

[tex]x^2-3x+5+\left(-\frac{3}{2}\right)^2-\left(-\frac{3}{2}\right)^2[/tex]

[tex]\mathrm{Complete\:the\:square}[/tex]

[tex]\left(x-\frac{3}{2}\right)^2+5-\left(-\frac{3}{2}\right)^2[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\left(x-\frac{3}{2}\right)^2+\frac{11}{4}[/tex]

So,

[tex]\left(x-\frac{3}{2}\right)^2>-\frac{11}{4}[/tex]

Thus,

[tex]x^2-3x+5>0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:\mathrm{True\:for\:all}\:x\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]

Therefore, option A) is FALSE.

Analyzing statement B)

(x + 3) (x - 5) ≥ 0

[tex]x^2-2x-15\ge 0[/tex]

[tex]\left(x+3\right)\left(x-5\right)=0[/tex]       [tex]\left(Factor\:left\:side\:of\:equation\right)[/tex]

[tex]x+3=0\:or\:x-5=0[/tex]

[tex]x=-3\:or\:x=5[/tex]

So

[tex]x\le \:-3\quad \mathrm{or}\quad \:x\ge \:5[/tex]

Thus,

[tex]\left(x+3\right)\left(x-5\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-3\quad \mathrm{or}\quad \:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-3]\cup \:[5,\:\infty \:)\end{bmatrix}[/tex]

Therefore, the statement B is true.

Solution is also attached below.

Analyzing statement C)

[tex]x^2+2x-15\ge 0[/tex]

[tex]\mathrm{Factor}\:x^2+2x-15:\quad \left(x-3\right)\left(x+5\right)[/tex]

So,

[tex]x\le \:-5\quad \mathrm{or}\quad \:x\ge \:3[/tex]

[tex]x^2+2x-15\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-5\quad \mathrm{or}\quad \:x\ge \:3\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-5]\cup \:[3,\:\infty \:)\end{bmatrix}[/tex]

Therefore, option C) is FALSE.

Analyzing statement D)

- 3 < x < 5

[tex]-3<x<5\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-3<x<5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-3,\:5\right)\end{bmatrix}[/tex]

Therefore, option D) is FALSE.

Analyzing statement E)

None of the above

The statement E) is False also as the statement B represents the correct solution.

Therefore, from the discussion above, we conclude that the statement B is true. The solution is also attached below.

Find the number that is [tex]\frac{1}{3}[/tex] of the way from [tex]\:2\frac{1}{6}[/tex] to [tex]\:5\frac{1}{4}[/tex].

Answer:

Therefore, [tex]\frac{37}{36}[/tex] is the number that is  [tex]\frac{1}{3}[/tex] of the way from  [tex]\:2\frac{1}{6}[/tex] to [tex]\:5\frac{1}{4}[/tex].

Step-by-step Explanation:

[tex]\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a\frac{b}{c}=\frac{a\cdot \:c+b}{c}[/tex]

So,

[tex]2\frac{1}{6}=\frac{13}{6}[/tex]

[tex]5\frac{1}{4}=\frac{21}{4}[/tex]

As the length from [tex]\frac{21}{4}[/tex] to [tex]\frac{13}{6}[/tex] is

[tex]\frac{21}{4}-\frac{13}{6}=\frac{37}{12}[/tex]

Now Divide [tex]\frac{37}{12}[/tex] into 3 equal parts. So,

[tex]\frac{37}{12}\div \:3=\frac{37}{36}[/tex]

As we have to find number that is [tex]\frac{1}{3}[/tex] of the way from  [tex]\:2\frac{1}{6}[/tex] to [tex]\:5\frac{1}{4}[/tex], it means it must have covered 2/3 of the way. As we have divided  [tex]\frac{37}{12}[/tex] into 3 equal parts, which is [tex]\frac{37}{36}[/tex]

Therefore, [tex]\frac{37}{36}[/tex] is the number that is  [tex]\frac{1}{3}[/tex] of the way from  [tex]\:2\frac{1}{6}[/tex] to [tex]\:5\frac{1}{4}[/tex].

Answer:

[tex]\left(2x+3\right)[/tex] is in the form [tex]dx+\:e[/tex].

Step-by-step Explanation:

Considering the expression

[tex]2x^2+11x+12[/tex]

Factor

[tex]2x^2+11x+12[/tex]

[tex]\mathrm{Break\:the\:expression\:into\:groups}[/tex]

[tex]\left(2x^2+3x\right)+\left(8x+12\right)[/tex]

[tex]\mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2+3x\mathrm{:\quad }x\left(2x+3\right)[/tex]

[tex]\mathrm{Factor\:out\:}4\mathrm{\:from\:}8x+12\mathrm{:\quad }4\left(2x+3\right)[/tex]

[tex]x\left(2x+3\right)+4\left(2x+3\right)[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}2x+3[/tex]

[tex]\left(2x+3\right)\left(x+4\right)[/tex]

Therefore, [tex]\left(2x+3\right)[/tex] is in the form [tex]dx+\:e[/tex].

Keywords: factor, ratio, solution

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Average speed: 8 feet/second. Total distance traveled: 32 feet. Total time: 4 seconds (from[tex]\( t = 1 \)[/tex] to[tex]\( t = 5 \)).[/tex]

To find the average speed of the car over the interval from[tex]\( t = 1 \) to \( t = 5 \),[/tex] we need to find the total distance traveled by the car during this time interval and then divide it by the total time taken.

Given the formula [tex]\( d = t^2 + 2t \)[/tex] for the distance from the crosswalk in terms of time [tex]\( t \),[/tex]  we'll find the distance at [tex]\( t = 1 \)[/tex]  and[tex]\( t = 5 \),[/tex]  and then subtract to find the total distance traveled:

1. At  [tex]\( t = 1 \):[/tex]

 [tex]\[ d_1 = (1)^2 + 2(1) = 1 + 2 = 3 \text{ feet} \][/tex]

2. At[tex]\( t = 5 \):[/tex]

 [tex]\[ d_5 = (5)^2 + 2(5) = 25 + 10 = 35 \text{ feet} \][/tex]

Now, the total distance traveled is [tex]\( d_5 - d_1 = 35 - 3 = 32 \)[/tex] feet.

The total time taken is [tex]\( t = 5 - 1 = 4 \)[/tex] seconds.

To find the average speed, divide the total distance by the total time:

[tex]\[ \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{32 \text{ feet}}{4 \text{ seconds}} = 8 \text{ feet/second} \][/tex]

So, the average speed of the car over the interval from [tex]\( t = 1 \) to \( t = 5 \) seconds is \( 8 \) feet per second.[/tex]

Answer:

option 2

52.1

Step-by-step explanation:

Peak season economy air fare: $526.30

30-day excrusion ship fare: $345.95

To know the percentage with respect, we only have to put the most expensive value divided by the smallest value multiplied by one hundred, this will tell us what percentage you have with each other

526.30 / 345.95 * 100 =

1.5213 * 100 =

152.13

Now to know only the percentage that increased, we have to subtract 100 that would be the base value

152.13 - 100 = 52.13

52.1

Answer:

Grand coffee cup = 1469 gm

Jumbo coffee cup = 60 gm

Step-by-step explanation:

Let x be the grande coffee cup and y be the jumbo coffee cup.

Solution:

From the first statement. They served 23 grande cups and 51 jumbo cups of the new coffee today, which equal a total of 36,846 grams.

So, the equation is.

[tex]23x+51y = 36846[/tex] ---------(1)

From the second statement. They served 58 grande cups and 68 jumbo cups of the new coffee tomorrow, which equal a total of 59460 grams.

[tex]58x+68y=59460[/tex] ----------(2)

Solve the equation 1 for x.

[tex]23x = 36846-51y[/tex]

[tex]x=\frac{36846}{23}-\frac{51}{23}y[/tex]

[tex]x=1602-\frac{51}{23}y[/tex] ---------(3)

Substitute [tex]x=1602-\frac{51}{23}y[/tex] in equation 2.

[tex]58(1602-\frac{51}{23}y)+68y=59460[/tex]

[tex]92916-\frac{51\times 58}{23}y+68y=59460[/tex]

[tex]-\frac{2958}{23}y+68y=59460-92916[/tex]

[tex]\frac{-2958+1564}{23}y=-33456[/tex]  

[tex]\frac{-1394}{23}y=-33456[/tex]

Using cross multiplication.

[tex]y=\frac{-23\times 33456}{-1394}[/tex]

[tex]y = 55.99[/tex]

y ≅ 60 gram

Substitute y = 60 in equation 3.

[tex]x=1602-\frac{51}{23}\times 60[/tex]

[tex]x=1602-\frac{3060}{23}[/tex]

[tex]x=1602-133.04[/tex]

[tex]x = 1469[/tex] grams

Therefore, grand coffee cup = 1469 gm and jumbo coffee cup = 60 gm

Final answer:

The answer explains how to calculate the amount of coffee required to make each size (grande and jumbo cups) based on the given information. Answer is 722 grams

Explanation:

The coffee required to make each size:

To ascertain the amount of coffee needed for a jumbo cup, we look at the data indicating 51 jumbo cups utilizing the same 36,846 grams. Dividing this total by the number of jumbo cups, we find that each jumbo cup requires approximately 722 grams of coffee.

Thus, the calculation yields 722 grams of coffee for each jumbo cup, confirming the final answer.

12 ways can one coin flip and one die roll be done.

'Die' is the singular version of the plural word 'dice.'

when we flip coin we got

Heads: 1,2,3,4,5,6

Tails:1,2,3,4,5,6

so total flips are 12 ways.

or  we can do in other way 6 × 2 = 12 ways

Therefore , 12 ways can one coin flip and one die roll be done.

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Answer:

0.08

Step-by-step explanation:

If 8% of drivers receive neither test, then the probability = 8/100 = 0.08

Final answer:

The probability that a randomly selected DWI suspect receives neither a breath test nor a blood test is 8%, determined by subtracting the combined probability of receiving at least one test (92%) from 1.

Explanation:

Calculating the Probability of Receiving Neither Test

To determine the probability that a DWI (driving while intoxicated) suspect receives neither a breath test nor a blood test, we can use the principle of inclusion-exclusion from probability theory. According to the police report, 82% receive a breath test, 34% receive a blood test, and 24% receive both tests.

Firstly, we need to find the probability of a suspect receiving at least one test. We add the probabilities of receiving each test and subtract the probability of receiving both tests to avoid double-counting:

P(Breath or Blood Test) = P(Breath) + P(Blood) - P(Both)
= 0.82 + 0.34 - 0.24
= 0.92

This means that 92% of DWI suspects receive at least one test. To find the probability that a suspect receives neither test, we subtract this value from 1 since the sum of the probabilities of all possible outcomes must equal 1:

P(Neither) = 1 - P(Breath or Blood Test)
= 1 - 0.92
= 0.08 or 8%

Hence, the probability that a randomly selected DWI suspect receives neither a breath test nor a blood test is 8%.

Answer:

Solution set {x|x<8}

Step-by-step explanation:

0.35x - 4.8<5.2- 0.9x

0.35x+0.9x<5.2+4.8

1.25x<10

x<10/1.25

x<8

Solution set {x|x<8}

Answer:

x < 8

Step-by-step explanation:

0.35x - 4.8 < 5.2- 0.9x

0.35x + 0.9x < 5.2 + 4.8

1.25x < 10

x < 10/1.25

x < 8

Answer:

C. x>0

Step-by-step explanation:

The given quotient is

[tex] \frac{ \sqrt{7 {x}^{2} } }{ \sqrt{3x} } [/tex]

Recall that the expression in the denominator should not be equal to zero.

Also the expression under the radical should be greater than or equal to zero.

This means that we should have:

[tex] \frac{7 {x}^{2} }{3x} \: > \: 0[/tex]

This implies that:

[tex]x \: > \: 0[/tex]

Option C is correct

Answer:

The required probability is [tex]P(x)=\frac{9}{128}[/tex] or [tex]P(x)=0.0703125[/tex].

Step-by-step explanation:

Consider the provided information.

A committee of 9 members is voting on a proposal. Each member casts a yea or nay vote. On a random voting basis,

The probability of yea or nay vote is equal, = [tex]\frac{1}{2}[/tex]

So, we can say that [tex]p=q=\frac{1}{2}[/tex]

Use the formula: [tex]P(x)=\binom{n}{x}p^xq^{n-x}[/tex]

Where n is the total number of trials, x is the number of successes, p is the probability of getting a success and q is the probability of failure.

We want proposal wins by a vote of 7 to 2, that means the value of x is 7.

Substitute the respective values in the above formula.

[tex]P(x)=\binom{9}{7}(\frac{1}{2})^7(\frac{1}{2})^{9-7}[/tex]

[tex]P(x)=\frac{9!}{7!2!}(\frac{1}{2})^7(\frac{1}{2})^{2}[/tex]

[tex]P(x)=\frac{8\times9}{2}\times(\frac{1}{2})^9[/tex]

[tex]P(x)=\frac{4\times9}{2^9}[/tex]

[tex]P(x)=\frac{9}{2^7}[/tex]

[tex]P(x)=\frac{9}{128}[/tex] or [tex]P(x)=0.0703125[/tex]

Hence, the required probability is [tex]P(x)=\frac{9}{128}[/tex] or [tex]P(x)=0.0703125[/tex].

Final answer:

The probability that a proposal wins by a 7 to 2 vote in a committee with 9 members is calculated using the binomial probability formula and is approximately 7.03%.

Explanation:

The question posed involves calculating the probability that a proposal wins by a vote of 7 to 2 in a committee with 9 members. We need to consider each vote as an independent 'yea' or 'nay' and find out the number of ways to get exactly 7 'yea' votes out of 9. This is a problem that can be solved using the binomial probability formula:

Binomial Probability Formula: P(X=k) = (n! / (k! * (n-k)!)) * p^k * (1-p)^(n-k), where 'n' is the total number of trials (or votes), 'k' is the number of successful outcomes need (yea votes), and 'p' is the probability of getting a yea vote. Since the voting is random, p = 0.5 assuming each member has an equal likely chance to vote yea or nay.

Plugging the values in, we get P(X=7) = (9! / (7! * 2!)) * 0.5^7 * 0.5^2. Calculating the factorials and powers of 0.5, the probability is:

P(X=7) = 36 * 0.5^9 = 36/512 = 0.0703125.

So, the probability that the proposal wins by a vote of 7 to 2 is approximately 7.03%.

Racheal can use the expression [tex]\(4 \frac{1}{2}\)[/tex] feet to find the total length of the two boards.

To find the total length of the two boards, Racheal needs to add the lengths of the two boards together.

The length of the first board is [tex]\(1 \frac{7}{12}\)[/tex] feet, and the length of the second board is [tex]\(2 \frac{11}{12}\)[/tex] feet.

To add these lengths together, we first need to convert them to improper fractions:

[tex]\[ 1 \frac{7}{12} = \frac{12}{12} + \frac{7}{12} = \frac{19}{12} \][/tex]

[tex]\[ 2 \frac{11}{12} = \frac{24}{12} + \frac{11}{12} = \frac{35}{12} \][/tex]

Now, to find the total length, we add the lengths of the two boards:

[tex]\[ \text{Total length} = \frac{19}{12} + \frac{35}{12} \][/tex]

To add fractions, we need a common denominator, which in this case is [tex]\(12\)[/tex].

[tex]\[ \text{Total length} = \frac{19}{12} + \frac{35}{12} = \frac{19 + 35}{12} = \frac{54}{12} \][/tex]

Now, we simplify the fraction:

[tex]\[ \text{Total length} = \frac{54}{12} = 4 \frac{1}{2} \][/tex]

So, Racheal can use the expression [tex]\(4 \frac{1}{2}\)[/tex] feet to find the total length of the two boards.

Answer:

A) [tex]d_{I}=2.5t[/tex]

B)[tex]d_{C}=4.5t[/tex]

C) d=200-7t

D) t=28.57s

Step-by-step explanation:

A) in order to solve this part of the problem, we must remember that velocity is the ratio between a displacement and the time it takes for a body to go from one point to the other. So we can write it like this:

[tex]v=\frac{x}{t}[/tex]

when solvin for the distance x, we get the formula to be:

[tex]x=vt[/tex]

We can use this to write the expression they are asking us for, so we get:

[tex]d_{I}=2.5t[/tex]

B) the procedure for part b is the same as the procedure for par A with the difference that Carolyn's speed is different. So by using the same formula with Carolyn's speed we get:

[tex]d_{C}=4.5t[/tex]

C)

In order to find the distance between Ian and Carolyn, we subtract the distances found on the previous two questions from the 200ft, so we get:

[tex]d=200-d_{I}-d_{c}[/tex]

we can further substitute the d's with the equations we found on the previos two parts of the problem, so we get:

[tex]d=200-2.5t-4.5t[/tex]

which simplififfes to the following:

d=200-7t

D) we can figure the seconds out by substituing the distance for 0 and solving for t, so we get:

0=200-7t

which can be solved for t, lke this:

-7t=-200

[tex]t=\frac{-200}{-7}=28.57[/tex]

Answer:

d: 99.7

Step-by-step explanation:

We know the mean is 1515. we know the standard devation is 15. both of 1560 and 1470 are both 3 standar devations away from the mean. on a table this would show almost all of the table. hence 99.7. Now im not 100% on this as i ahve the same question on a quiz but if i get it write i will add an answer or comment to this.

Percentage of buckets contain between 1470 and 1560 pieces of popcorn= 99.7%

percentage, a relative value indicating hundredth parts of any quantity. One percent (symbolized 1%) is a hundredth part; thus, 100 percent represents the entirety and 200 percent specifies twice the given quantity.

The following formula is a common strategy to calculate a percentage:

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Answer:

The answer to your question is letter A

Step-by-step explanation:

The first inequality is a circle with center (0,0) and radius 4, the inequality indicates that the solution must be greater than the radius (4) so the solutions are letters A and D.

The second inequality is the line, the solutions must be the numbers below the line, areas A and B.

The region where both inequalities cross is the solution  letter A.

Answer:

thats too long to read but good luck!

Step-by-step explanation:

Answer:

d.  His own

Step-by-step explanation:

John is the leader of the particular project team. He is in charge of delegating different tasks to his team members and also endure that everything is in order. He will also develop the necessary agenda and formulate the final report of the project. Therefore, the name that will be attached on the final tasks is his own.

Tom, the representative from top management, should be responsible for explaining the project's necessity, as his role allows him to address strategic concerns and ensure buy-in across the team.

In the context of the Joint Application Development (JAD) group, explaining the reason for the project, especially given the internal skepticism about its necessity, is a pivotal responsibility that typically falls onto someone influential and with comprehensive knowledge of the project's goals and business impact. In this scenario, Tom, as the representative from top management, is the most suitable member to address this point on the agenda. Tom's position allows him to articulate the strategic importance of the project to the organization, reassuring the rest of the team and potentially quelling any concerns about its necessity. It is critical that this explanation is conveyed convincingly to ensure buy-in from all members of the team.

It is advantageous for team members to take on tasks that align with their strengths, as suggested in the reference material, but also to challenge themselves and learn by undertaking tasks outside their usual domain, with the support of their colleagues. This approach fosters a collaborative environment and harnesses the diverse skill sets of the team members, leading to a more efficient and innovative project outcome. To help manage this process, tools like the Honeycomb Map encourage the distribution of responsibilities and help with project visualization and tracking.

Answer:

The answer to your question is letter C.

Step-by-step explanation:

[tex]\sqrt{50x^{3}}[/tex]     Find the prime factors of 50

                          50   2

                          25   5

                            5   5

                             1

               50 = 2 5²

[tex]\sqrt{5^{2} 2 x^{2} x} = 5 x\sqrt{2x}[/tex]

[tex]\sqrt{32x^{2}}[/tex]    Find the prime factors of 32

                         32   2

                          16   2

                           8   2

                           4   2

                           2   2

                            1

              32 = 2⁴2[tex]\sqrt{32x^{2}} = 2^{2} x\sqrt{2} = 4x\sqrt{2}[/tex]

Division                            [tex]5x\sqrt{2}\sqrt{x} / 4x\sqrt{2}[/tex]

Simplification                  [tex]\frac{5\sqrt{x}}{4}[/tex]

Answer:

C

Step-by-step explanation:

A P E x

Answer:

Therefore option A.) 0 is correct.

Step-by-step explanation:

The graph is attached.

The solution of the equations as seen from the intersection of the equations in the graph is (0,2).

Therefore x  = 0 is the solution which gives y = 2 for both equations.

Therefore option A.) 0 is correct.

The sequence of transformations is: reflect across the x-axis, rotate 180 degrees about the origin, and translate 4 units down.

The sequence of transformations that maps triangle ABC to triangle A'B'C' is:

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Answer:

The sample is a Simple Random sample.

explanation:

A simple random sample is the process where there is equal chance of selecting each member of a population to form a sample. in the example stated in the question there are equal chances of selecting every ticket among the five hundred ticket of the participant so as to form another set of ten tickets that win a prize.

Answer:

17 cm is the side length of the smallest square plate.

Step-by-step explanation:

Length of the square = l

Length of the diagonal = d

Length of chopstick = s = 24 cm

If chopstick is to be fitted along a diagonal . then length of the diagonal will be:

d = s = 24 cm

Applying Pythagoras Theorem :

[tex]l^2+l^2=(24 cm)^2[/tex]

[tex]2l^2=576 cm[/tex]

[tex]l^2=\frac{576}{2} cm^2[/tex]

[tex]l=\sqrt{\frac{576}{2} cm^2}=16,97 cm \approx 17 cm[/tex]

17 cm is the side length of the smallest square plate.

Final answer:

To determine the size of the smallest square plate that a 24-cm chopstick can fit diagonally on without overhang, the Pythagorean theorem is used, yielding a side length of approximately 16.97 cm.

Explanation:

The question asks for the side length of the smallest square plate on which a 24-cm chopstick can fit along a diagonal without any overhang. To find this, we can use the Pythagorean theorem in the context of a square. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In the case of a square, the hypotenuse is the diagonal, and the other two sides are equal, each being the side length of the square.

Let's denote the side length of the square as s. The diagonal (d) is then given as d = 24 cm. According to the Pythagorean theorem applied to a square, this can be written as √(2*s²) = d, because the diagonal divides the square into two equal right-angled triangles. Solving for s, we get s = √(d² / 2). Substituting 24 cm for d gives:

s = √(24² / 2)

s = √(576 / 2)

s = √(288)

s = 16.97 cm (approximately)

Therefore, the side length of the smallest square plate on which a 24-cm chopstick can fit along a diagonal without any overhang is approximately 16.97 cm.

Answer:

The family would have [tex]\frac34[/tex] of the watermelon for supper.

Step-by-step explanation:

Given:

Amount of watermelon in refrigerator = [tex]\frac14[/tex]

Amount of water melon brought form grocery store =[tex]\frac12[/tex]

We need to find the fraction of water melon family have for supper.

Solution:

Now we can say that;

the fraction of water melon family have for supper is equal to sum of Amount of watermelon in refrigerator and Amount of water melon brought form grocery store.

framing in equation form we get;

the fraction of water melon family have for supper = [tex]\frac14+\frac12[/tex]

Now taking LCM to make the denominator common we get;

the fraction of water melon family have for supper = [tex]\frac{1\times1}{4\times1}+\frac{1\times2}{2\times2}=\frac{1}{4}+\frac24[/tex]

Now denominators are common so we will solve for numerator we get;

the fraction of water melon family have for supper = [tex]\frac{1+2}{4}=\frac34[/tex]

Hence the family would have [tex]\frac34[/tex] of the watermelon for supper.

The equation to find the value of x in an isosceles triangle with a perimeter of 7.5 m and a side y measuring 2.1 m is 2x + 2.1 = 7.5. Solving for x, we find that x equals 2.7 meters.

To find the value of x for an isosceles triangle with a perimeter of 7.5 meters and the shortest side y measuring 2.1 meters, we can set up an equation. Since it's an isosceles triangle, the two equal sides are both x, and the perimeter is the sum of all sides: x + x + y = 7.5.

We can substitute y with 2.1 m to get 2x + 2.1 = 7.5. Solving for x, we subtract 2.1 from both sides to obtain 2x = 5.4, and then divide both sides by 2 to find x = 2.7 meters. This is the length of the two equal sides of the triangle.

This is based on the mathematical concept of geometric series, where in theoretical terms Mathias would never reach the door because he keeps moving half the remaining distance each time. Although, in practical terms, there comes a point where the remaining distance becomes negligible.

The situation you're describing is an example of a geometric series scenario in mathematics. In this case, where Mathias walks half the distance to the door each time, is often referred to as Zeno's paradox.

Zeno's paradox poses the question, how can one ever reach a destination if they are always traveling halfway there? Theoretically, Mathias is never able to fully reach the door, because no matter how small the remaining distance becomes, he is only allowed to cover half. Therefore, there will always technically be some distance remaining.

However, in practical terms, there would come a point where the distance remaining is so minuscule, it could be considered as Mathias having reached the door. For instance, if he started 10 meters away, after the first step he is 5 meters away, then 2.5 meters, then 1.25 meters, and so on. Eventually, this distance becomes negligible.

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Answer: 16 single crust apple pies and double crust apple pies were sold.

Step-by-step explanation:

Let x represent the number of single crust apple pies sold on a Friday.

Let y represent the number of double crust apple pies sold on a Friday.

The total number of pies sold on a busy Friday was 36. This means that

x + y = 36

Grandma's bakery sells single crust apple pies for $6.99 in double crust cherry pies for $10.99. The total amount that was collected that Friday was $331.64. This means that

6.99x + 10.99y = 331.74- - - ---- - - - -1

Substituting x = 36 - y into equation 1, it becomes

6.99(36 - y) + 10.99y = 331.74

251.64 - 6.99y + 10.98y = 331. 74 - 3 31.74

251.64 - 331.74

4y = 80

y = 80/4 = 20

x = 36 - y i= 36 - 20

x = 16

Answer:

Math will take over Ana's brain at 4.4 hours

Step-by-step explanation:

Exponential Grow

The population of the nanobots follows the equation  

[tex]p(t) = 5\cdot 2^t[/tex]

We must find the value of t such that the population of nanobots is 106 or more, that is

[tex]5\cdot 2^t\geq 106[/tex]

We'll solve the equation

[tex]5\cdot2^t= 106[/tex]

Dividing by 5

[tex]2^t= 106/5=21.2[/tex]

Taking logarithms

[tex]log(2^t)= log(21.2)[/tex]

By logarithms property

[tex]t\cdot log(2)= log(21.2)[/tex]

Solving for t

[tex]\displaystyle t=\frac{log21.2} {log2}[/tex]

[tex]t=4.4 \ hours[/tex]

Math will take over Ana's brain at 4.4 hours

It will take 5 hours for the nanobot population to reach 160, utilizing the equation p(t) = 5·[tex]2^t[/tex] and solving for t.

The problem involves determining how long it will take for the population of nanobots, which doubles each hour, to reach a specific number. The equation given for the population of nanobots at any time t is p(t) = 5·[tex]2^t[/tex], where t is the time in hours. We are tasked with finding the value of t when the population reaches or exceeds 160 nanobots.

To solve this, we set the equation equal to 160 and solve for t:

Dividing both sides by 5 gives:

To find t, we need to determine the power of 2 that equals 32. This can be expressed as 2⁵ = 32. Therefore, t = 5. It will take 5 hours for the population of nanobots to reach 160, at which point Ana will think of nothing but math.