Incomplete question as the car's speed is missing.I have assumed car's speed as 6.0m/s.The complete question is here
An amusement park ride consists of a car moving in a vertical circle on the end of a rigid boom of negligible mass. The combined weight of the car and riders is 6.00 kN, and the radius of the circle is 15.0 m. At the top of the circle, (a) what is the force FB on the car from the boom (using the minus sign for downward direction) if the car's speed is v 6.0m/s
Answer:
[tex]F_{B}=-5755N[/tex]
Explanation:
Set up force equation
∑F=ma
∑F=W+FB
[tex]\frac{mv^{2} }{R}=W+F_{B}\\ F_{B}=\frac{mv^{2} }{R}-W\\F_{B}=\frac{(W/g)v^{2} }{R}-W\\F_{B}=\frac{(6000N/9.8m/s^{2} )(6m/s)^{2} }{(15m)}-6000N\\F_{B}=-5755N[/tex]
The minus sign for downward direction
In the circuit described by the diagram, which pair of resistors is connected in parallel?
*answer choices attached*
Option 4 ( R2 and R3 ) is the correct answer.
Explanation:
In the below given diagram, we can see a circuit diagram that has four resistors such as R1, R2, R3, and R4.The opening of the circuit is noted as "a" and the ending is noted as "b".By observing the above diagram, we can clearly see that R2 and R3 are the pair of resistors that are connected in a parallel manner.Where all the other resistors such as R1 and R4 are neither connected in parallel nor in series.Hence we can conclude that Resistor R2 and R3 are the ones that are connected in parallel.
Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If they grab each other as they collide, the combined speed of the two players just after the collision would be:
Answer:
2 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before collision = total momentum after collision
mu+m'u' = V(m+m') .................................Equation 1
Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.
Making V the subject of the equation,
V = (mu+m'u')/(m+m')................ Equation 2
Note: Taking the direction of the first player as positive.
Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),
Substituting into equation 2
V = [(75×6)+(100×(--8))]/(75+100)
V = (450-800)/175
V = 350/175
V = - 2 m/s.
Note: The negative signs tells that the combined speed is in the direction of the second player.
Hence the combined speed of the two players = 2 m/s
Final answer:
The question involves using the conservation of momentum to calculate the combined speed of two football players after they collide and cling together. By applying the formula (m1*v1 + m2*v2) / (m1 + m2), the resulting velocity can be obtained, considering the direction of the players' velocities.
Explanation:
The question involves a physical interaction between two football players, which is described by the conservation of momentum, a fundamental concept in physics. When two objects, in this case football players, collide and stick together, the total momentum before the collision equals the total momentum after the collision, provided no external forces act on the system. The formula to find the combined velocity just after the collision is derived from the conservation of momentum principle: (m1*v1 + m2*v2) / (m1 + m2), where m1 and m2 are the masses and v1 and v2 are the velocities of the two players respectively.
Therefore, to find the combined speed of the two players just after the collision, we would use their given masses and initial speeds: (75kg*6m/s + 100kg*-8m/s) / (75kg + 100kg). The negative sign indicates that the second player is running in the opposite direction. After solving, we'd get the resulting velocity, which represents the speed and direction of the two players immediately after the collision.
Here is a simple example. The inhabitants of a small island begin exporting beautiful cloth made from a rare plant that grows only on their island. Seeing how popular the small quantity that they export has been, they steadily raise their prices. A clothing maker from New York, thinking that he can save money by "cutting out the middleman," decides to travel to the small island and buy the cloth himself. Ignorant of the local custom of offering strangers outrageous prices and then negotiating down, the clothing maker accepts (much to everyone's surpise) the initial price of 400 tepizes/m2. The price of this cloth in New York is 120 dollars/yard2.If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.
Answer:
He lost $53,240.60
Explanation:
In order to solve this problem, we must start by determining how many dollars he spent for the [tex]500m^{2}[/tex] of cloth. We can determine this by doing the following conversion:
[tex]500m^{2}*\frac{400 tepizes}{m^{2}}*\frac{\$0.625}{1 tepiz}=\$125,000[/tex]
Next, we need to figure out what is the price of the [tex]500m^{2}[/tex] of coth is in New York:
[tex]500m^{2}*\frac{1yd^{2}}{(0.9144m)^{2}}*\frac{\$120}{1 yard^{2}}=\$71,759.40[/tex]
so now we subtract the two amounts so we get:
$125,000-$71,759.40=$53,240.60
A metal alloy rod is submerged 22 cm below the surface of a fresh water pool by steel cables tied 10cm from each end. It has a length of 110 cm, a mass of 2 kg and a uniform square cross sectional area of 7 cm2. Because its density is not uniform its center of mass is located 49 from the left end.
1.) What is the force of tension in the left cable?
2.) What is the force of tension in the right cable?
Answer:
force of tension in the left cable = 7.66N
force of tension in the right cable = 5.074N
Explanation:
The detailed step and calculation is as shown in the attachment.
Put the items below in correct sequence for using wind to generate electricity.
1 - A generator converts mechanical energy into electrical energy.
2 - Wind turns the wind turbine blade.
3 - A gear box transfers mechanical energy to a generator.
4 - Electricity is transferred to the grid.
Answer:
2- 3 - 1- 4
Explanation:
Extracting energy from the wind is known as wind energy. Wind energy is are a renewable source of energy.
Energy can be extracted from the wind by following different steps.
1) Wind will turn the wind turbine blade.
2) Then the mechanical energy from the wind turbine blade is transferred to the generator.
3) The generator will convert mechanical energy into electrical energy.
4) the electrical energy produced is then transferred to the grid.
Hence, the sequence of Power generation is
2- 3 - 1- 4
Centripetal force Fc acts on a car going around a curve. If the speed of the car were twice as great, the magnitude of the centripetal force necessary to keep the car moving in the same path would be
Answer:
We need 4 times more force to keep the car in circular motion if the velocity gets double.
Explanation:
Lets take the mass of the car = m
The radius of the arc = r
[tex]F=\frac{m\times v^2}{r}[/tex]
Given that speed of the car gets double ,v' = 2 v
Then the force on the car = F'
[tex]F'=\frac{m\times v'^2}{r}[/tex] ( radius of the arc is constant)
[tex]F'=\frac{m\times (2v)^2}{r} [/tex]
[tex]F'=4\times \frac{m\times v^2}{r}[/tex]
We know that [tex]F=\frac{m\times v^2}{r}[/tex]
Therefore F' = 4 F
So we can say that we need 4 times more force to keep the car in circular motion if the velocity gets double.
The magnitude of centripetal force will become four times with the twice the greater speed of car.
Given data:
The magnitude of centripetal force on car is, Fc.
The force acting on any object undergoing the motion around the circular path, such that the motion is balanced is known as centripetal force. It is also known as the center-seeking force. And the expression for the centripetal force is given as,
Fc = mv²/r
Here,
m is the mass of car.
v is the speed of car.
r is the radius of circular track.
If the speed of car is twice as great, then the new centripetal force is given as,
F'c = m(2v)²/r
F'c = 4 × mv²/r
F'c = 4 × Fc
Thus, we can conclude that the magnitude of centripetal force will become four times with the twice the greater speed of car.
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If the fundamental frequency of a violin string is 440 HzHz, what is the frequency of the second harmonic?
Answer:
880Hz
Explanation:
A violin string is an example of an open pipe. An open pipe is open at both ends.
The fundamental frequency is the first harmonic.In an open pipe the second harmonic is twice the fundamental frequency.
Hence, second harmonic = 2Fo
Fo=440Hz
Second harmonic = 2*440Hz
Second harmonic = 880Hz
A uniform solid disk with a mass of 24.3 kg and a radius of 0.364 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk, as the drawing illustrates. (a) What is the net torque produced by the two forces? (Assume counterclockwise is the positive direction.)(b) What is the angular acceleration of the disk? rad/s2
To find the net torque, we multiply the radius by each force, and then add them taking the direction into account. Then, we divide the net torque by the moment of inertia (which we find by substituting the given mass and radius values into the formula for a uniform solid disk) to find the angular acceleration.
Explanation:To solve this question, we need to calculate the net torque ('t') which is the product of the radius and the force applied perpendicular to it, and then use that value to find the angular acceleration ('a', represented as rad/s2). This involves the physics concept of Newton's second law applied to rotation.
Step 1: Calculate net torque. The applied forces are perpendicular to the radius and friction is negligible, so the torque due to each force is t = rF. The total torque is the sum of the torques due to the two forces applied, taking into account that the 90.0 N force is in the counterclockwise direction and the 125 N force is in the clockwise direction (-125 N). The net torque would therefore be t = r(90 N) - r(125 N) = 0.364m(90 N) - 0.364m(125 N).
Step 2: Calculate angular acceleration. Angular acceleration is the net torque divided by the moment of inertia ('I') of the disk. The moment of inertia for a uniform solid disk is 0.5mr2. We can substitute m = 24.3 kg and r =0.364 m to find I. The angular acceleration is therefore a = t/I.
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The net torque produced by the two forces is 12.74 N·m and the angular acceleration of the disk is 7.90 rad/s². The calculation involved determining the torque from each force and then using the moment of inertia for a solid disk to find the angular acceleration.
(a) Net Torque Calculation
To calculate the net torque, we use the formula:
Torque (τ) = Force (F) x Radius (r) x sin(θ)
Assuming both forces are applied tangentially (θ = 90° or sin(90°) = 1), we have:
Torque from 90.0 N force:
τ₁ = 90.0 N x 0.364 m x 1 = 32.76 N·m (clockwise, so negative)
Torque from 125 N force:
τ₂ = 125 N x 0.364 m x 1 = 45.5 N·m (counterclockwise, so positive)
The net torque is:
Net Torque = τ₂ - τ₁ = 45.5 N·m - 32.76 N·m = 12.74 N·m
(b) Angular Acceleration Calculation
First, we need the moment of inertia (I) for a solid disk, given by:
I = 0.5 x Mass (m) x Radius² (r²)
For this disk:
I = 0.5 x 24.3 kg x (0.364 m)² = 1.612 kg·m²
Next, using the net torque (τ) to find angular acceleration (α):
α = τ / I
Substituting the values:
α = 12.74 N·m / 1.612 kg·m² = 7.90 rad/s²
Conclusion:
The net torque produced by the two forces is 12.74 N·m, and the angular acceleration of the disk is 7.90 rad/s².
A 0.60 Kilo gram basketball poses on the rim of a basketball hoop that is 3.0 m high find the potential energy of the ball there (use G=10 N/KG.)
Answer:
18Joules
Explanation:
Potential Energy = mass * gravity * height
PE = 0.6 * 10 * 3
PE = 18Joules
What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperature is held constant?
Answer: 9.0 atm
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.
[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.
We are given:
[tex]P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL[/tex]
Putting values in above equation, we get:
[tex]3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm[/tex]
Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm
Since you've determined that the power supply is a 700W dual rail, what does that make the maximum output power?
700 makes the maximum output power.
Explanation:
In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft.
A joule is equal to one Newton-meter, which is the amount of work needed to move a 1 Newton force a distance of 1 meter. When you divide work by time, you get power, measured in units of joules per second. This is also called a Watt. 1 Watt = 1 Joule Sec. This is the formula to calculate output power.
The maximum output power of a 700W dual rail power supply is 700W. 'Dual rail' refers to how the power is distributed, it does not increase the total output.
Explanation:Having determined that the power supply is a 700W dual rail, this refers to the maximum amount of power that the power supply can output. The power supply's maximum output power is its total capacity, which in this case is 700W. It's important to remember that 'dual rail' refers to the way the power is distributed and doesn't increase the overall power. Simply put, a dual rail power supply divides its power between two ‘rails’ or circuits, but the maximum output power remains 700W.
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Why is designing a successful service operation often more difficult than a successful design of a tangible product?
A. Strong element of customer involvement
B. Lack of computer-aided design
C. Tangible products are more personalized
D. More challenging inventory considerations
Answer:
A. Strong element of customer involvement
Explanation:
A service operation involves managing and performing the activities that are necessary to deliver services at a good level of quality to customers. Service operation tends to be more difficult than a successful design of a tangible product because the process involves high customer contact because customers are consumers of the product but in the case of the services, they are also part of its production and this is more difficult to control. According to this, the answer is that a successful service operation is more difficult because it has a strong element of customer involvement.
A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. What was the trumpet players' initial frequency?
Frequency of trumpet wire = 445 Hz
Explanation:
The given frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5
It can be either 445 or 435
Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .
If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .
If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .
Thus the initial frequency of wire is 445 Hz
To find the initial frequency of the trumpet player, we can use the concept of beat frequency. The initial frequency is either 442 Hz or 438 Hz.
Explanation:To find the initial frequency of the trumpet player, we can use the concept of beat frequency. The beat frequency is the difference between the frequencies of two sounds, in this case, the trumpet player's note and the tuning fork. Initially, the trumpet player hears 5 beats per second. After adjusting the length of her trumpet, she hears 3 beats per second. The change in beat frequency is 5 - 3 = 2 Hz. Since the tuning fork remains at 440 Hz, the initial frequency of the trumpet player can be calculated by adding or subtracting the beat frequency from the tuning fork frequency. In this case, the initial frequency is either 440 + 2 = 442 Hz or 440 - 2 = 438 Hz.
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A 1.00 cm diameter plastic sphere, used in a static electricity demonstration, has a charge of 22.6 pC uniformly distributed on its surface. What is the potential at its surface (or just barely above it)?
Answer:
Electric potential, V = 40.68 volts
Explanation:
Given that,
Charge on the sphere, [tex]q=22.6\ pC=22.6\times 10^{-12}\ C[/tex]
Diameter of the plastic sphere, d = 1 cm
Radius, r = 0.5 cm
We need to find the electric potential at its surface. The potential at a surface is given by :
[tex]V=\dfrac{kq}{r}[/tex]
[tex]V=\dfrac{9\times 10^9\times 22.6\times 10^{-12}}{0.5\times 10^{-2}}[/tex]
V = 40.68 volts
So, the electric potential at its surface is 40.68 volts. Hence, this is the required solution.
To prepare 400 ml of a 40% (w/v) solution of sodium bicarbonate, how many grams of solute are needed?
Answer : The mass of solute needed are, 40 grams.
Explanation :
As we are given that 40 % (w/v) solution of sodium bicarbonate (solute) that means 40 grams of sodium bicarbonate present in 100 mL of solution.
Now we have to calculate the mass of solute needed.
As, 100 mL of solution needs mass of solute = 10 g
So, 400 mL of solution needs mass of solute = [tex]\frac{400mL}{100mL}\times 10g=40g[/tex]
Thus, the mass of solute needed are, 40 grams.
To prepare a 400 ml of 40% (w/v) solution of sodium bicarbonate, multiply the percentage (40%) by the total volume (400 ml) and divide by 100. You will need 160 grams of sodium bicarbonate for this solution.
Explanation:To prepare 400 ml of a 40% (w/v) solution of sodium bicarbonate, you need to understand the meaning of (w/v). It stands for weight/volume, and it means that for every 100 ml of solution, you have the given percentage in grams of the solute. So, for a 40% (w/v) solution, 100 ml of the solution will contain 40 grams of sodium bicarbonate. Therefore, we need to calculate the amount of sodium bicarbonate for 400 ml of solution:
First, determine the total weight of sodium bicarbonate needed for 100 ml: 40 grams (from the definition of 40% w/v).Next, because you need 400 ml, which is four times the amount of 100 ml, you multiply the amount needed for 100 ml by 4.This results in 40 grams x 4 = 160 grams.To prepare a 400 ml of 40% (w/v) sodium bicarbonate solution, you would need 160 grams of sodium bicarbonate.
every computer consists of physical components and non physical components the non physical component of a computer that understand how to work with the physical components are referred to as_________
Answer:
C. software
Explanation:
software, is a collection of data or computer instructions that tell the computer how to work. This is in contrast to physical hardware, from which the system is built and actually performs the work.
Answer:gbji
Explanation:
hbbju
_____________ is an excessive current relative to normal operating current, but one that is confined to the normal conductive path provided by the conductors, circuit components, and loads of the distribution system. A(n) _________ is a current that flows outside the normal conducting path. One generally accepted definition of _______is when a phase or ungrounded conductor comes in contact with, or arcing current flows between, another phase conductor, neutral, or ground.
Answer:
Overload current, short-circuit current and short circuit
Explanation:
Overload current is an excessive current relative to normal operating current, but one that is confined to the normal conductive path provided by the conductors, circuit components, and loads of the distribution system.
A short-circuit current is a current that flows outside the normal conducting path.
One generally accepted definition of short circuit is when a phase or ungrounded conductor comes in contact with, or arcing current flows between, another phase conductor, neutral, or ground.
Two identical small metal spheres are separated by 1.00 × 105 m and exert an 18.9-N repulsive force on each other. A wire is connected between the spheres and then removed. The spheres now repel each other, exerting a 22.5-N force. Assume both charges are positive.
1. Determine the total charge of this system.
q =______ (units)
2. Determine the charges of the spheres before the connection.
q1, q2 = ______ C
Answer:
(a). The total charge of this system is 10 C.
(b). The charges of the spheres before the connection is 5 C and 4.2 C.
Explanation:
Given that,
Distance [tex]r= 1.00\times10^{5}\ m[/tex]
Force = 22.5 N
The two spheres are connected for a moment by a wire. After this, charge is re-distributed equally, and each sphere now has a charge
We need to calculate the charge
Using formula of electric force
[tex]F=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
Here, charge is equal
Put the value into the formula
[tex]22.5=\dfrac{9\times10^{9}\times q^2}{(1.00\times10^{5})}[/tex]
[tex]q^2=\dfrac{22.5\times(1.00\times10^{5})^2}{9\times10^{9}}[/tex]
[tex]q=\sqrt{\dfrac{22.5\times(1.00\times10^{5})^2}{9\times10^{9}}}[/tex]
[tex]q=5\ C[/tex]
(a). We need to calculate the total charge of this system
We have the charge of each sphere after re-distribution.
We know that the charge is distributed equally.
Therefore, the total charge of the system is
[tex]q+Q=2q=2\times5=10\ C[/tex]
(b). We need to calculate the charge of the spheres before the connection
Using formula of electric force
[tex]F=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
Put the value into the formula
[tex]18.9=\dfrac{9\times10^{9}\times q_{1}\times q_{2}}{(1.00\times10^{5})}[/tex]
[tex]q_{2}=\dfrac{18.9\times(1.00\times10^{5})^2}{9\times10^{9}\times5}[/tex]
[tex]q_{2}=4.2\ C[/tex]
Hence, (a). The total charge of this system is 10 C.
(b). The charges of the spheres before the connection is 5 C and 4.2 C.
Two workers push on a wooden crate. One worker push with a force of 543 N and the other with a force of 333 N. The mass of the wooden crate is 206 kg. What is the acceleration of the crate?
Answer:
[tex]a=4.2524\ m.s^{-2}[/tex]
Explanation:
Given:
two workers push a crate.
Force by first worker, [tex]F_1=543\ N[/tex]force by second worker, [tex]F_2=333\ N[/tex]mass of crate, [tex]m=206\ kg[/tex](Assuming that both the workers push in the same direction.)
We know that,
Acceleration is given as:
[tex]a=\frac{F}{m}[/tex]
[tex]a=\frac{F_1+F_2}{m}[/tex]
[tex]a=\frac{543+333}{206}[/tex]
[tex]a=4.2524\ m.s^{-2}[/tex]
Can an object have kinetic and potential energy at the same time
Answer:
An object can have both kinetic and potential energy at the same time.
Explanation:
For example, an object which is falling, but has not yet reached the ground has kinetic energy because it is moving downwards, and potential energy because it is able to move downwards even further than it already has.
Final answer:
An object can have both kinetic and potential energy at the same time, such as a ball thrown in the air. The sum of these two types of energy in a closed system remains constant unless non-conservative forces are present.
Explanation:
Yes, an object can indeed have kinetic and potential energy at the same time. Consider a ball thrown upward; at any point in its trajectory, except the peak, the ball will have both kinetic energy due to its motion and potential energy due to its height above the ground. To address whether the sum of kinetic energy and potential energy can change without work being done on the object: In a closed system where no external work is applied, the sum of kinetic and potential energies remains constant because of the conservation of mechanical energy. However, if non-conservative forces like friction are involved, they can convert mechanical energy into thermal energy, thus decreasing the total mechanical energy without any external work being performed.
The plates of a parallel-plate capacitor have constant charges of +Q and?Q. Do the following quantities increase, decrease, or remain the same as the separation of the plates is increased?
A) the electric field between the plates
B) the potential difference between the plates
C) the capacitance
D) the energy stored in the capacitor
Explanation:
(A) Electric field for the parallel plate capacitor is given by :
[tex]E=\dfrac{\sigma}{2\epsilon_o}[/tex]
It is clear that the electric field does not depend on the separation of the plates.
(B) The relation between the electric field and the electric potential is given by :
[tex]V=Ed[/tex]
d is the separation between plates. So, if the separation of the plates is increased, the potential difference increases.
(C) The capacitance of the parallel plate capacitor is given by :
[tex]C=\dfrac{A\epsilon_o}{d}[/tex]
So, the capacitance decreases when the separation of the plates is increased.
(D) The energy stored in the capacitor is given by :
[tex]E=\dfrac{1}{2}CV^2[/tex]
[tex]E=\dfrac{1}{2}C(Ed)^2[/tex]
So, the energy stored in the capacitor is increased when the separation of the plates is increased.
Answer:
a)constant
b)constant
c)constant
d) constant
Explanation:
a)
The electric field between the plates remain constant. The Electric field between the plates is given as:
[tex]E=\frac{\sigma}{\epsilon}[/tex]
where:
[tex]\sigma=[/tex] surface charge density
[tex]\epsilon=[/tex] permittivity of the material between the plates
b)
The potential difference between the plates is related as:
[tex]V=\frac{Q}{C}[/tex]
and
[tex]E=\frac{V}{d}[/tex]
where:
d = distance between the plates
Therefore the potential difference remains constant when the capacitor plates distance remains constant.
c)
the capacitance:
[tex]C=\frac{Q}{V}[/tex]
When the charge and potential difference is constant then the capacitance also remains constant.
d)
Energy stored in a capacitor:
[tex]U=\frac{1}{2} C.V^2[/tex]
Since capacitance and potential difference are constant therefore potential difference is also constant.
Squid use jet propulsion for rapid escapes. A squid pulls water into its body and then rapidly ejects the water backward to propel itself forward. A 1.5 kg squid (not including water mass) can accelerate at 20 m/s2 by ejecting 0.15 kg of water.?
Answer:
a. FTh = 30 N
b. Fw = 30 N
c. a = 200 m/s2
Explanation:
See full explanation in the picture. Please rate as brainliest
The magnitude of squid thrust force, magnitude of force on the water and the acceleration experienced by the water is required.
The magnitude of squid thrust force and magnitude of force on the water is 30 N.
The acceleration is [tex]200\ \text{m/s}^2[/tex]
Newton's Lawsm = Mass
a = Acceleration
m = 1.5 kg
a = [tex]20\ \text{m/s}^2[/tex]
Thrust force
[tex]F=ma\\\Rightarrow F=1.5\times 20\\\Rightarrow F=30\ \text{N}[/tex]
The magnitude of squid thrust force will be equal to the magnitude of force on the water from the third law of motion.
F = 30 N
m = 0.15 kg
Acceleration is given by
[tex]a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{30}{0.15}\\\Rightarrow a=200\ \text{m/s}^2[/tex]
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The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x-ray photon by a line 1 inch long, how long a line (in feet) must you draw to represent the wavelength of visible light?
Answer:
458.33 ft
Explanation:
We are given that
Wavelength of of an x- ray photon=1 in
Wavelength of of an x- ray photon==[tex]\frac{1}{12}[/tex]ft
1 in=[tex]\frac{1}{12}[/tex]feet
We have to find the length of line (in feet) drawn by you to represent the wavelength of visible light.
According to question
Wavelength of visible light=[tex]5500\times \frac{1}{12}[/tex] ft
Wavelength of visible light[tex]=\frac{5500}{12}[/tex]ft
Wavelength of visible light=458.33 ft
Hence, the 458.33 ft line must drawn by you to represent the wavelength of visible light.
Answer:
458.33 ft
Explanation:
I had the same question once
A 12-volt automotive circuit has a current of 3 amps. Technician A says the electric power in this circuit is 36 watts. Technician B says the electric power in this circuit is 4 watts. Who is right?
Answer:
Technician A is right.
Explanation:
Given that,
Voltage of circuit, V = 12 volt
Current in the circuit, I = 3 A
Technician A says the electric power in this circuit is 36 watts. Technician B says the electric power in this circuit is 4 watts. We need to say that which technician is correct.
The power of any circuit is given by :
[tex]P=V\times I[/tex]
[tex]P=12\ V\times 3\ A[/tex]
P = 36 watts
So, technician A is right. Hence, this is the required solution.
The power in an electric circuit is calculated by multiplying the voltage by the current. Therefore, in a 12-volt circuit with a current of 3 amps, the power would be 36 watts. This confirms the statement made by Technician A, making him correct.
Explanation:In the context of electric circuits, the power is determined by multiplying the voltage across the circuit by the current flowing through it. This relationship is captured in the formula P = IV, where P represents power, I represents current, and V represents voltage.
In this particular case, given a 12-volt circuit with a current of 3 amps, the calculation becomes P=12V * 3A. Accordingly, the power in this circuit would be 36 watts, validating Technician A's statement. Therefore, in this instance, Technician A is correct and Technician B is incorrect.
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In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward at 2 m/s and the other cart rolls leftward at 1 m/s. After the carts collide, they couple (attach together) and roll together with a speed of __________. Ignore resistive forces.a. 0.5 m/s
b. 0.33 m/s
c. 0.67 m/s
d. 1.0 m/s
e. none of these
Answer:
The correct answer is option a.
Explanation:
Conservation of momentum :
[tex]m_1u_1+m_2u_2=m_1v_1+m_1v_2[/tex]
Where :
[tex]m_1, m_2[/tex] = masses of object collided
[tex]u_1,u_2[/tex] = initial velocity before collision
[tex]v_1,v_2[/tex] = final velocity after collision
We have :
Two equal-mass carts roll towards each other.
[tex]m_1=m_2=M[/tex]
Initial velocity of [tex]m_1=u_1=2 m/s[/tex]
Initial velocity of [tex]m_2=u_2=-1 m/s[/tex] (opposite direction)
Final velocity of [tex]m_1=v_1=v[/tex] (same direction )
Final velocity of [tex]m_2=v_2=v[/tex] (same direction)
[tex]M\times 2 m/s+M(-1 m/s)=Mv+Mv[/tex]
[tex]1 m/s=2v[/tex]
v = 0.5 m/s
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The speed of the carts after their collision is 0.5 m/s.
Using the principle of conservation of momentum, the combined carts will have a speed of 0.5 m/s after their collision. This is because their total momentum prior to the collision is conserved during the collision and is equal to their total momentum post the collision.
Explanation:This is a question about the principle of conservation of linear momentum in physics. Before the collision, the total momentum of the system (two carts) is the sum of their individual momenta. Since they have equal mass, we can write the total momentum as momentum of cart 1 + momentum of cart 2 = total momentum, or (mass x velocity of cart 1) + (mass x -velocity of cart 2) = total momentum. Since one cart is moving rightward and the other is moving leftward, we take the velocity of the leftward moving cart, cart 2, as negative. Thus, we have (mass x 2 m/s) - (mass x 1 m/s) = total momentum, hence the total momentum comes out to be mass x 1 m/s.
After the collision, the two carts couple and move with a common speed which we denoted as V. According to the conservation of linear momentum law, the total momentum before collision must be equal to the total momentum after the collision, which gives us mass x 1 m/s = 2 x mass x V (since the total mass after the collision becomes 2 times the mass of one cart), solving this gives V = 0.5 m/s.
Therefore, the combined carts will have a speed of 0.5 m/s after the collision. So, the answer to your question is a. 0.5 m/s.
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Two wires, each of length 1.3 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 640 Hz. However, the same frequency of 640 Hz is the third harmonic on wire B. Find the speed at which the individual waves travel on each wire.
Answer:
Explanation:
Given
Length of each wire [tex]L=1.3\ m[/tex]
On wire A second harmonic frequency is given by
[tex]f_2_{a}=2\times (\frac{v}{2L})[/tex]
where f=frequency
v=velocity of wave
L=length of wire
[tex]v_a=f_2\times L[/tex]
[tex]v_a=640\times 1.3=832\ m/s[/tex]
For wire B third harmonic is given by
[tex]f_3_{b}=3\times (\frac{v}{2L})[/tex]
[tex]v_b=\frac{2L}{3}\cdot f_3_{b}[/tex]
[tex]v_b=\frac{2\times 1.3}{3}\times 640=554.66\ m/s[/tex]
A proton with kinetic energy of 1.16×105 eV is fired perpendicular to the face of a large plate that has a uniform charge density of σ = +6.60 μC/m2. What is the magnitude of the force on the proton?
Answer:
force on the proton = 5.96 × [tex]10^{-14}[/tex] N
Explanation:
given data
kinetic energy = 1.16 ×[tex]10^{5}[/tex] eV
charge density of σ = +6.60 μC/m²
solution
we get here force on the proton that is express as
F = qE ....................1
here q is charge on proton i.e = 1.6 × [tex]10^{-19}[/tex] C
and E is electric field due to charge i.e E = [tex]\frac{\sigma }{2*\epsilon_o }[/tex]
so put the value in equation 1 we get
force on the proton = 1.6 × [tex]10^{-19}[/tex] × [tex]\frac{6.60*10^{-6}}{2*8.85*10^{-12}}[/tex]
force on the proton = 5.96 × [tex]10^{-14}[/tex] N
Final answer:
The magnitude of the force on the proton is 1.19 × 10-13 N.
Explanation:
In order to find the magnitude of the force on the proton, we can use the formula F = qE, where F is the force, q is the charge of the proton, and E is the electric field. First, we need to convert the charge density from μC/m² to C/m², which gives us σ = 6.60 × 10-6 C/m². Since the electric field is uniform, we can use the equation E = σ/ε₀, where ε₀ is the electric constant.
Plugging in the values, we have E = (6.60 × 10-6 C/m²) / (8.85 × 10-12 C²/N·m²), which gives us E = 7.46 × 10^5 N/C. Now, we can find the force using F = qE.
F = (1.60 × 10-19 C)(7.46 × 10^5 N/C) = 1.19 × 10-13 N.
When we look at an object that is 1,000 light-years away we see it _________.
a. as it is right now, but it appears 1,000 times dimmer
b. as it was 1,000 light-years ago
c. as it was 1,000 years ago
d. looking just the same as our ancestors would have seen it 1,000 years ago
Answer:
c. as it was 1,000 years ago
Explanation:
since the object is one thousand light years away, it means what ever light is comes from the object (is reflected off the object) would take 1,000 years to get to us, meaning we would be seeing the object as it was 1,000 years ago.
The forces exerted by earth and a skier become an action reaction force pair when the skier accelerates while earth doesnt seem to move at all. expalin why the skier accelerates whu,e tthe earth doesn't seem to move at all?
Explanation:
We know from newton's 2nd law that F= m/a. That is force directly proportional to mass and inversely proportional to acceleration. F is same for the skier and Earth but mass is different for both. m for earth is way larger than the m for skier. So, for constant Force , a of Earth must very small as compared with a of the skier.
Skiers and skateboarders accelerate due to action-reaction force pairs in accordance with Newton's third law, but the Earth's immense mass leads to negligible acceleration, rendering its movement imperceptible.
Explanation:Understanding Force and Acceleration
When discussing the action-reaction force pair between the Earth and a skier, Newton's third law of motion is essential. This law states that for every action, there is an equal and opposite reaction. When the skier accelerates, the force exerted on them by the Earth (gravity) is met with an equal and opposite force exerted by the skier back onto the Earth. The reason the Earth does not seem to move while the skier accelerates is due to the massive difference in mass between the Earth and the skier. Since acceleration is calculated as force divided by mass (F = ma), the much larger mass of the Earth compared to the skier results in a negligible acceleration of the Earth. This is similar to why stationary skater A does not move when pushing skater B; if skater A has more contact with the surface or better frictional grip, they may not move significantly despite exerting force.
Furthermore, when objects like a skateboarder jump off a building, both the Earth and the skateboarder exert mutual forces on each other. Despite experiencing the same total change of momentum, the Earth's massive size means its acceleration is imperceptible, while the skateboarder moves considerably more.
A hill that has a 28.1% grade is one that rises 28.1 m vertically for every 100.0 ml of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?
Answer:
[tex]\theta=15.70^\circ[/tex]
Explanation:
A right triangle is formed, in which the vertical elevation is the opposite cathetus and the horizontal distance is the adjacent cathetus, since we know these two values, we can calculate the angle of inclination using the definition of tangent:
[tex]tan\theta=\frac{opp}{adj}\\\theta=arctan(\frac{opp}{adj})\\\theta=arctan(\frac{28.1m}{100m})\\\theta=15.70^\circ[/tex]