A sample of N2 gas is collected over water at 20o C and pressure of 1 atm. The volume collected is 250 Liters. What mass of N2 is collected?

Answers

Answer 1

Answer : The mass of nitrogen gas collected is, 290.9 grams

Explanation :

To calculate the mass of nitrogen gas we are using ideal gas equation:

[tex]PV=nRT\\\\PV=\frac{w}{M}RT[/tex]

where,

P = pressure of nitrogen gas = 1 atm

V = volume of nitrogen gas = 250 L

T = temperature of nitrogen gas = [tex]20^oC=273+20=293K[/tex]

R = gas constant = 0.0821 L.atm/mole.K

w = mass of nitrogen gas = ?

M = molar mass of nitrogen gas = 28 g/mole

Now put all the given values in the ideal gas equation, we get:

[tex](1atm)\times (250L)=\frac{w}{28g/mole}\times (0.0821L.atm/mole.K)\times (293K)[/tex]

[tex]w=290.9g[/tex]

Therefore, the mass of nitrogen gas collected is, 290.9 grams.


Related Questions

What is the ratio of hydrogen atoms (HH) to oxygen atoms (OO) in 2 LL of water? Enter the simplest whole number ratio in order of hydrogen to oxygen, respectively. Express your answer as two integers, separated by a comma (e.g., 3,4).

Answers

Answer: 2, 1

Explanation:

Water has a formula as H2O.

Meaning it contains 2 atoms of Hydrogen and one atom of oxygen. No matter the volume of water, it will always contain 2 atoms of Hydrogen and one atom of oxygen. The ratio of hydrogen to oxygen in a water molecule is (2, 1)

Convert using the relation ship below

Answers

Answer:

25.33125KPa

Explanation:

From the above,

1atm = 101.325KPa

0.25atm = (0.25atm x 101.325KPa) / 1atm = 25.33125KPa

Therefore, 0.25atm = 25.33125KPa

Olympic cyclists fill their tires with helium to make them lighter. Assume that the volume of the tire is 860 mL , that it is filled to a total pressure of 120 psi , and that the temperature is 26°C. Also, assume an average molar mass for air of 28.8 g/mol.
Calculate the mass of air in an air filled tire.
Calculate the mas of helium in a helium-filled tire.
What is the mass difference between the two?

Answers

Answer:

The mass of air is 8.245 g

The mass of helium is 1.145 g

The difference is 7.1 g

Explanation:

Total mass (air and helium) = PVM/RT

P is total pressure in the tire = 120 Psi = 120/14.696 = 8.17 atm

V is volume of the tire = 860 mL = 860 cm^3

M is the total molar mass of air and helium = 28.8 + 4= 32.8 g/mol

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature = 26°C = 26+273 = 299 K

Total mass = 8.17×860×32.8/82.057×299 = 9.39 g

Mass of air = mass fraction of air × total mass = 28.8/32.8 × 9.39 = 8.245 g

Mass of helium = total mass - mass of air = 9.39 - 8.245 = 1.145 g

Difference = 8.245 - 1.145 = 7.1 g

Final answer:

To calculate the mass of air in an air-filled tire, you can use the ideal gas law equation PV = nRT. The mass of air in the tire is 142.57 g. To calculate the mass of helium in a helium-filled tire, use the same equation and the molar mass of helium. The mass of helium in the tire is 19.84 g. The mass difference between the two is -122.73 g, indicating that the helium-filled tire is lighter than the air-filled tire.

Explanation:

To calculate the mass of air in an air-filled tire, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the volume from mL to L and the temperature from Celsius to Kelvin. So, the volume is 0.860 L, and the temperature is 26 + 273 = 299 K.

Next, we rearrange the ideal gas law equation to solve for n, the number of moles: n = PV / RT. Substituting the values, we get n = (120 psi x 0.860 L) / (0.0821 L.atm/mol.K x 299 K) = 4.96 moles.

The molar mass of air is given as 28.8 g/mol, so the mass of air in the tire is 4.96 moles x 28.8 g/mol = 142.57 g.

To calculate the mass of helium in a helium-filled tire, we can follow the same steps as above, but use the molar mass of helium (4 g/mol) instead. Substituting the values, we get n = (120 psi x 0.860 L) / (0.0821 L.atm/mol.K x 299 K) = 4.96 moles.

So, the mass of helium in the tire is 4.96 moles x 4 g/mol = 19.84 g.

To find the mass difference between the two, we subtract the mass of air from the mass of helium: 19.84 g - 142.57 g = -122.73 g. The negative sign indicates that the helium-filled tire is lighter than the air-filled tire by 122.73 g.

: How does the solubility of a solid in a liquid depend on temperature? How is this temperature dependence exploited to purify solids through recrystallization?

Answers

Answer:

Explanation:

Solubility of many solid in a solvent increases with increase in temperature. Increase in temperature increases kinetic energy of the solute, increasing collision and weakens the intermolecular force within the solute. This makes the solute dissolve faster in their solvents.

During recrystallization, more solutes are added to the solvent at higher temperature so that a supersaturated solution is produced on cooling. As the solution cools the over saturated solute begins to precipitate out of the solution.

Recrystallization is a form of purification if solid, as the crystalline solids continue to precipitate it reject impurities are comes out as a purer solid

How many solutions does an equation have when the variable adds out and the final sentence is false?

Answers

Answer:

None solution

Explanation:

When the variable adds out and the final sentence is false you have arrived to a contradiction, also called absurd, meaning that the starting equality was a wrong assumption that could never be true. Thus, the equation has no solutions.

An example of such situation is this equation:

x + 3 = x + 9

To solve it, you use the subtraction property of the equalities: subtract both x and 3 from both sides:

x - x = 9 - 30 = 6

The variable added out and the final sentences 0 = 6 is false. That means that none value of x satisfies the original equation and it has no solutions.

Answer:

It has 0 solutions

Explanation:

Which is the appropriate term for an alloimmune disease in which maternal blood and fetal blood are antigenically incompatible?

Answers

Answer:

Erythroblastosis fetalis

Explanation:

Erythroblastosis fetalis, occurs when there is an antigenic incompatibility between a mother and her fetus.  When an antigen present in the fetus and absent in the mother crosses the placenta into the maternal circulation, maternal antibodies are produced, causing her body to sense the fetus as a foreign body to be combated. The antibodies return to the fetal circulation and result in red blood cell destruction.

This incompatibility could be in varying forms including:

Rhesus incompatibilityABO incompatibility (blood group)Minor blood group incompatibility

On a hot sunny day, you get out of the swimming pool and sit in a metal chair, which is very hot. Would you predict that the specific heat of the metal is higher or lower than that of water? Explain.

Answers

Answer:

The specific heat capacity of the metal is lower than that of the water as explained as follows

Explanation:

The heat capacity is a measure of propensity of a given object or matter to undergo an increase or decrease in its temperature when subject a given amount of heat, in other words, for a given mass of the substance, it is the amount of heat required to be added to cause it to have a unit temperature change

The specific heat capacity of a material or substance is the amount of heat required to be supplied to raise the temperature of a unit mass of that by one degree Celsius. It is the ratio of the heat capacity of a specimen of a substance divided by the mass of the specimen

Both the water of the swimming pool, the swimmer and the metal chair are all exposed to the same amount of heat from the sun, however the heat required to raise the water temperture by one degree Celsius is higher than heat required to raise the temperature of the metal chair by one degree hence the chairs temperature is higher than the water temperature as shown in the following equation

ΔH = m₁ × C₁ × ΔT₁ = m₂ × C₂ × ΔT₂

Where ΔH =  Heat or energy supplied from the sun

m₁  = mass of water in the swimming pool

C₁  = Specific heat capacity of the water in the swimming pool

ΔT₁ = Change in temperature of the swimming pool and

m₂  = mass of metal chair

C₂  = Specific heat capacity of the metal chair material

ΔT₂ = Change in temperature of the metal chair

Where ΔH is the same for both the chair and swimming pool with the chair being hotter than the swimming pool with an asumed temperature change of 1.5 times that of the swimming pool and assuming the same mass of both the swimming pool and the chair are measured we have

m₁ × C₁ × 1.5ΔT₂ = m₁ × C₂ × ΔT₂ then cancelling like terms we have

1.5C₁ = C₂

Hence the heat capacity of the swimming pool water is 1.5 times that of the metal chair

Final answer:

On a hot sunny day, when you sit in a metal chair and it feels very hot, it indicates that the metal has a lower specific heat than water.

Explanation:

The specific heat of a material is a measure of the amount of heat energy required to raise the temperature of a given mass of the material by a certain amount. In this case, when you sit in a metal chair on a hot sunny day and it feels very hot, it indicates that the metal has a lower specific heat than that of water.

Metal is generally a good conductor of heat, which means it can rapidly transfer heat energy from the surroundings to your body when in contact. Water, on the other hand, has a higher specific heat and is a poor conductor of heat, so it takes longer to heat up and cool down.

The specific heat of metal depends on the type of metal. Different metals have different specific heat values.

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The masses of reactants is always greater than the masses of the products in a chemical reaction, because the products are combined together. TRUE FALSE

Answers

Answer: False

Explanation: the masses of reactants are always the same as the products in order to conform to the law of conservation of mass.

Answer:   False

Explanation:

In a chemical reaction atoms are not created or destroyed, only rearranged.

No change in mass

PLEASE HELP!! WILL MARK BRAINLIEST


Answer the following questions using the data below:


Data :Trial 1 :Trial 2

Mass of empty crucible with lid: 26.679 grams 26.698 grams

Mass of Mg metal, crucible, and lid: 26.934 grams 27.051 grams

Mass of MgO, crucible, and lid: 27.097 grams 27.274 grams


Balanced Chemical Equation for reaction: 2 MG(s) + O2(g) = 2 MGO(s)


Mass of magnesium for each trial:

Trial 1: 0.255g

Trial 2: 0.353g


Actual yield of magnesium oxide for each trial:

Trial 1: 0.418g

Trial 2: 0.576g


Question 1: Calculate the theoretical yield of MgO for each trial:


Question 2: Determine the percent yield of MgO for your experiment for each trial:


Question 3: Determine the average percent yield of MgO for the two trials:

Answers

Answer:

The answer to your question is below

Explanation:

                                         Trial 1                   Trial 2

mass of Mg                      0.255 g                0.353 g

mass of MgO                   0.418 g                 0.576 g

Chemical reaction

                                2Mg(s)    +  O₂(g)     ⇒   2MgO(s)

Question 1.

Atomic mass of Mg = 24.31 x 2 = 48.62 g

Molecular mass of MgO = 2(24.31 + 16) = 80.62 g

Trial 1

                          48.62 g of Mg ----------------- 80.62 g of MgO

                          0.255 g            ----------------   x

                          x = (0.255 x 80.62)/48.62

                          x = 0.422 g of MgO

Trial 2                48.62 g of Mg ----------------- 80.62 g of MgO

                          0.353 g            ----------------   x

                          x = (0.353 x 80.62)/48.62

                          x = 0.585 g of MgO

Question 2

Trial 1          

Percent yield = 0.418/0.422 x 100 = 99%

Trial 2

Percent yield = 0.576/0.585 x 100 = 98.5%

Question 3

Average = (99 + 98.5)/2

              = 98.75%

WHAT IS THE DEFINITION FOR ISOTOPES, WHAT ARE EXAMPLES OF ISOTOPES, WHAT ARE NON EXAMPLES OF ISOTOPES AND WHAT ARE EXAMPLES OF ISOTOPES?
WILL MAKE BRAINLIEST (THE FIRST PERSON TO ANSWER CORRECTLY)

Answers

Final answer:

Isotopes are versions of a chemical element with different neutron numbers. Examples are Hydrogen-1, 2, and 3. Non-examples would be different elemental atoms.

Explanation:

Isotopes are variants of a particular chemical element which differ in neutron number, and consequently in nucleon number. All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom.

Examples of isotopes include Hydrogen-1 (Protium), Hydrogen-2 (Deuterium), and Hydrogen-3 (Tritium) - all are isotopes of hydrogen but have different numbers of neutrons. Non-examples of isotopes would be atoms of different elements, like a helium atom (2 protons) compared with a hydrogen atom (1 proton).

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What is the basic form for the names of ionic compounds containing a metal that forms more than one type of ion?

Answers

Answer:

Metal (appropriate charge on metal) nonmetal-ide

Explanation:

1) Write the name of transition metal as shown on the Periodic Table.

2) Write the name and charge for the non-metal.

          Use the total charge on the non-metal (or polyatomic ion) find the charge on the transition metal.

3) After the name for the metal, write its charge as a Roman Numeral in parentheses. Example: Iron (II) chloride.

You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several different temperatures.
The sphere can expand or shrink to any volume without changing the pressure of the gas inside.
As a result of your experiment, you find that the volume (V) of the gas divided by its temperature (T) is always equal to 1.75.
What would the volume (V) of the gas be at a temperature of 300K? (assume the unit for volume is liters)
Show your work and answer the question with a clear statement. Show each step of your calculations for full points. After showing your calculations, answer the question with a clear statement.

Please help

Answers

Volume of the gas is 525 L.

Explanation:

It is given that the volume of the gas divided by the temperature is 1.75.

V/T = 1.75

As per the Charles law, volume is proportional to the temperature.

V ∝ T

V/T = constant

Now we have to find V, and T is given as 300 K.

So plugin the values as,

V/300 = 1.75

Rearranging the equation to get V as,

V = 1.75×300

  = 525 L

A wooden cylinder 30.0 cm high floats vertically in a tub of water (density =1:00g/cm3).The Top of the cylinder is 13.5cm above the surface of the liquid. What is the density of the wood?

Answers

Explanation:

When the cylinder floats on the water the upstream pressure force acts on the wooden cylinder determines the thickness of the wooden cylinder.

When the cylinders float on the gas, the force of the upward thrust correlates to the weight of the water.

Answer is 5.3 X 10 − 3  k g / m 3

Material density is the correlation between the material's mass as well as how much room (volume) it occupies. A material is determined by the density of either the atoms, their size, and how they can be organised.

A tank of methane gas contains 2.8 m³ of the gas at 20°C. The tank has a pressure-release valve that releases gas into a secondary tank that will hold 0.2m³ of gas if the pressure rises.

At what Celsius temperature will the methane fill both tanks?

Answers

Answer:

The answer to your question is T2 = 20.93°K

Explanation:

Data

Volume 1 = V1 = 2.8 m³

Temperature 1 = T1 = 20°C

Volume 2 = V2 = 0.2 m³

Temperature 2 = T2 = ?

Process

To solve this problem use Charles' law

               [tex]\frac{V1}{T1} = \frac{V2}{T2}[/tex]

Solve for T2

               T2 = [tex]\frac{T1V2}{V1}[/tex]

1.- Convert temperature to °K

T1 = 20 + 273 = 293°K

2.- Substitute values

               T2 = [tex]\frac{(293)(0.2)}{2.8}[/tex]

3.- Simplify

               T2 = [tex]\frac{58.6}{2.8}[/tex]

4.- Result

               T2 = 20.92°K

Final answer:

The question seeks the temperature at which methane gas, initially at 2.8 m³ and 20°C, will expand to fill an additional 0.2 m³ tank, by applying Charles's Law to relate volume and temperature of a gas under constant pressure.

Explanation:

The question, "At what Celsius temperature will the methane fill both tanks?", involves understanding the principles of gas laws, specifically Charles's Law which relates volume and temperature of a gas at constant pressure. Given the initial volume of methane gas is 2.8 m³ at 20°C, and it will be released into a secondary tank of volume 0.2 m³ if the pressure increases, we're essentially looking for the temperature at which the total volume of 3.0 m³ (2.8 m³ + 0.2 m³) is achieved at constant pressure.

Charles's Law states that V1/T1 = V2/T2, where V refers to volume and T refers to temperature in Kelvin. To find the desired temperature, we first convert the initial temperature to Kelvin (20°C + 273.15 = 293.15 K), then solve for T2 while using the total volume as V2. Without going into the numerical solving part (since the specific question doesn't require it), the concept demonstrates the application of Charles's Law in determining the temperature that leads to the expansion of methane gas to fill both tanks.

Use the drop-down menus to match each part of the scenario to the correct scientific practice. Akira records the speed of a reaction, first without a catalyst, and then with a catalyst. Akira creates a reaction without a catalyst, then repeats the reaction with a catalyst. Akira turns in a written lab report to his science teacher. Akira wonders, "Will adding a catalyst speed up this chemical reaction?" Akira writes in his notes that adding a catalyst sped up the chemical reaction because the catalyst lowered the activation energy needed to start the reaction.

Answers

Answer:

1)collecting data

2)performing an investigation

3)communicating results

4)asking a question

5)providing explanation

Explanation:

Scenario 1 is matched with collecting data. Scenario 2 is matched with performing an investigation. Scenario 3 is matched with communicating results. Scenario 4 is matched with asking a question. Scenario 5 is matched with providing explanation for the given scientific practice using catalyst.

A catalyst is a material that speeds up a chemical reaction without being consumed or irreversibly transformed in the process. It promotes the process by giving a lower activation energy alternate reaction pathway. The activation energy is the smallest amount of energy required for a chemical reaction to take place. A catalyst permits the reaction to occur more rapidly and efficiently by decreasing the energy barrier.

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The density of gold is 19.3g/mL. If you have a 9.00 g piece of gold, what volume will it occupy (in milliliters)

Answers

Answer:

The answer to your question is volume = 0.47 ml

Explanation:

To solve this problem use the formula of density, that relates the mass and volume.

Data

density = 19.3 g/ml

mass = 9.0 g

volume = ?

Formula

density = [tex]\frac{mass}{volume}[/tex]

Solve for volume

volume = [tex]\frac{mass}{density}[/tex]

Substitution

Volume = 9 / 19,3

Simplification and result

Volume = 0.47 ml

Final answer:

To determine the volume a 9.00 g piece of gold occupies, divide the mass of gold by its density (19.3g/mL), which calculates to approximately 0.4663 mL.

Explanation:

The question asks to find the volume occupied by a 9.00 g piece of gold, given that the density of gold is 19.3g/mL. To find the volume, we use the formula density = mass/volume, which can be rearranged to find volume as volume = mass/density.

Given:

Mass of gold = 9.00 g

Density of gold = 19.3 g/mL

Applying the values into the formula gives

volume = 9.00 g / 19.3 g/mL

, which equals approximately 0.4663 mL.

Therefore, a 9.00 g piece of gold will occupy about 0.4663 milliliters.

Describe the differences among primitive, igneous, sedimentary, and metamorphic rock, and relate these differences to their origins.

Answers

Answer:

Rocks are the aggregate of minerals. There are three distinct categories of rocks, namely the sedimentary, metamorphic and the igneous rocks.

The sedimentary rocks are formed from the deposition, compaction, and lithification of soft sediments that are transported from one place to another by the agents such as wind, water, and ice. For example, Sandstone and Shale. The metamorphic rocks are derived from the previously existing sedimentary, igneous or other metamorphic rocks, due to the influence of extremely high pressure as well as temperature conditions. For example, Quartzite and Marble. The igneous rocks are those rocks that are formed from the cooling and crystallization of magma. For example, Granite and Diorite.

All these three types of rocks are formed by different processes and their mode of origins are also different.

Determine the magnitude of the acceleration experienced by an electron in an electric field of 664 N/CN/C .

Answers

Answer:

[tex]a=-1.17\times 10^{14} \hspace{3}\frac{m}{s^2}[/tex]

Explanation:

A charged particle that is in a region where there is an electric field, experiences a force equal to the product of its charge by the intensity of the electric field:

[tex]F_e=q*E[/tex]

If the electric field is uniform, the force is constant and so is the acceleration. Applying the equations of uniformly accelerated rectilinear motion, we obtain the velocity of the particle at any time or after having moved a certain distance:

[tex]a=\frac{qE}{m}[/tex] (1)

Where:

[tex]E=Electric\hspace{3}field\hspace{3}strength=664\frac{N}{C} \\q=Electric\hspace{3}charge\hspace{3}of\hspace{3}the\hspace{3}particle\\m=Mass\hspace{3}of\hspace{3}the\hspace{3}particle[/tex]

The electric charge and the mass of the electron are known constants:

[tex]q=-1.6\times 10^{-19} C\\m=9.1\times 10^{-31} kg[/tex]

So, replacing this data in the equation (1) :

[tex]a=\frac{(-1.6\times 10^{-19})*(664) }{9.1\times 10^{-31} } =-1.167472527\times 10^{14} \approx -1.17\times 10^{14} \hspace{3}\frac{m}{s^2}[/tex]

The minus sign is due to the fact that the charge is negative, therefore it experiences a force in the opposite direction to the field.

How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lower the temperature to 335.0 K? The following physical data may be useful.

Hvap = 33.9 kJ/molHfus = 9.8 kJ/mol
Cliq = 1.73 J/g

Answers

Answer : The energy removed must be, -34.67 kJ

Solution :

The process involved in this problem are :

[tex](1):C_6H_6(l)(425.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(2):C_6H_6(l)(353.0K)\rightarrow C_6H_6(s)(353.0K)\\\\(3):C_6H_6(s)(353.0K)\rightarrow C_6H_6(s)(335.0K)[/tex]

The expression used will be:

[tex]\Delta H=[m\times c_{p,l}\times (T_{final}-T_{initial})]+m\times \Delta H_{fusion}+[m\times c_{p,s}\times (T_{final}-T_{initial})][/tex]

where,

[tex]\Delta H[/tex] = heat available for the reaction = [tex]4.50\times 10^3kJ=4.50\times 10^6J[/tex]

m = mass of benzene = 125 g

[tex]c_{p,s}[/tex] = specific heat of solid benzene = [tex]1.51J/g.K[/tex]

[tex]c_{p,l}[/tex] = specific heat of liquid benzene = [tex]1.73J/g.K[/tex]

[tex]\Delta H_{fusion}[/tex] = enthalpy change for fusion = [tex]9.8kJ/mole=9800J/mole=\frac{9800J/mole}{78g/mole}J/g=125.64J/g[/tex]

Molar mass of benzene = 78 g/mole

Now put all the given values in the above expression, we get:

[tex]\Delta H=[125g\times 1.73J/g.K\times (353-425)K]+125g\times -125.64J/g+[125g\times 1.51J/g.K\times (335-353)K][/tex]

[tex]\Delta H=-34672.5J=-34.67kJ[/tex]

Therefore, the energy removed must be, -34.67 kJ

Which of the following statements about enzymes is false? A. they increase the rate of chemical reactions. B.They function as chemical catalysts. C. They are monomers used to build proteins. D. They regulate virtually all chemical reactions in a cell

Answers

Final answer:

The false statement about enzymes is C: Enzymes are monomers used to build proteins. In fact, enzymes are proteins, but they aren't monomers. The monomers for proteins are amino acids.

Explanation:

The statement about enzymes that is false is C: Enzymes are monomers used to build proteins. In reality, enzymes are proteins themselves, but they are not monomers. A monomer is a molecule that can be bonded to other identical molecules to form a polymer. In the case of proteins, the monomers are the amino acids, not enzymes. Option A, B and D are correct. Enzymes do indeed increase the rate of chemical reactions (A), function as chemical catalysts (B) and regulate virtually all chemical reactions in a cell (D).

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Final answer:

The incorrect statement about enzymes is that they are monomers used to build proteins. Instead, enzymes are complex proteins made up of amino acids, which are the monomers. Enzymes act as catalysts, accelerating chemical reactions and playing vital roles in cellular metabolism.

Explanation:

The false statement about enzymes is: C. They are monomers used to build proteins. This is incorrect as enzymes are not monomers, but are typically complex proteins, which are themselves composed of monomers called amino acids. Here are the explanations for each option: A. Enzymes do increase the rate of chemical reactions by reducing activation energy, allowing reactions to proceed under physiologically tolerable conditions. B. They absolutely function as chemical catalysts, accelerating chemical reactions in cells. C. Enzymes are not monomers, they are typically complex proteins made up of amino acids, which are the monomers. D. Enzymes do regulate virtually all chemical reactions in a cell, playing a central role in cellular metabolism by catalyzing essential biochemical reactions.

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Convertible bonds are examples of: a. Securities that have characteristics of both debt and equity b. Non-recurring items c. Assets d. Treasury stock

Answers

Answer:

a. Securities that have characteristics of both debt and equity

Explanation:

A convertible bond is a debt security that can be converted into a certain number of shares and this can be done during specific times in the life of the bond. According to this, convertible bonds are examples of securities that have characteristics of both debt and equity as they are a type of debt that pays interest but can be turned into shares.

What is the magnitude of the force required to accelerate an electron of mass 9.1×10–31 kg from rest to a speed of 2.0×107 m/s for a distance of 0.50 cm?

Answers

Answer:

[tex]3.64\times 10^{-14} N[/tex] is the magnitude of the force required to accelerate an electron of given mass.

Explanation:

Initial velocity of the electron = u

Final velocity of the electron = v = [tex]2.0\times 10^7 m/s[/tex]

Acceleration of the electron = a =?

Distance covered by electron= s = 0.50 cm =  0.005 m ( 1 cm = 0.01 m)

Using third equation of motion :

[tex]v^2-u^2=2as[/tex]

[tex](2.0\times 10^7 m/s)-0^2=2\times a\times 0.005 m[/tex]

[tex]a=4\times 10^{16} m/s^2[/tex]

Mass of an electron = [tex]m=9.1 \times 10^{-31} kg[/tex]

Force on moving electron = F

[tex]F = m\times a[/tex]

[tex]=9.1 \times 10^{-31} kg\times 4\times 10^{16} m/s^2=3.64\times 10^{-14} N[/tex]

[tex]3.64\times 10^{-14} N[/tex] is the magnitude of the force required to accelerate an electron of given mass.

The magnitude of the force required to accelerate an electron is [tex]3.64 \times 10^{-18}N[/tex]

According to Newton's second law, the formula for calculating the required force is expressed as:

F = mam is the mass of the body = [tex]9.1 \times 10^{-31} kg[/tex]a is the acceleration of the body

Get the required acceleration;

[tex]v^2=u^2+2as\\(2.0 \times 10^7)^2=0^2+2(0.005)a\\4.0 \times 10^{14}=0.01a\\a=4.0\times 10^{12}m/s^2[/tex]

Geet the magnitude of the force required:

[tex]F=9.1\times 10^{-31} \times 4.0 \times 10^{12}\\F=36.4 \times 10^{-19}N\\F=3.64 \times 10^{-18}N[/tex]

Hence the magnitude of the force required to accelerate an electron is [tex]3.64 \times 10^{-18}N[/tex]

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A 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12.6 cm/s. After the collision, the 11.7 g marble moves to the right at 23.7 cm/s. Find the velocity of the 27.3 g marble after the collision. Answer in units of cm/s.

Answers

Answer:

The answer to this is

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Explanation:

To solve the question, let us list out the given variables and their values

Mass of first marble m1 = 27.3g

Velocity of the first marble v1 = 21.0 cm/s

Mass of second marble m2 = 11.7g

Velocity of the second marble v2 = 12.6 cm/s

After collision va1 = unknown and va2 = 23.7 cm/s

From Newton's second law of motion, force = rate of change of momentum produced

Hence m1v1 + m2v2 = m1va1 + m2va2 or

va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Which example shows a chemical change?

A evaporating water

B. melting ice

C. rust

D cutting pap​

Answers

Rust is a chemical change.

The correct answer would be C, a

chemical change.

WHICH IS NOT A PROPERTY OF GOLD?

A. COMMON
B. MELLABLE
C. GOOD REFLECTOR OF HEAT
D. GOOD CONDUCTOR OF ELETRICITY

Answers

Answer:

The answer to your question is A. Common

Explanation:

Properties of metals

Gold is a metal and as a metal is silvery looking, has a high density, relatively soft and easily deformed, good conductor of heat and electricity.

From this information we can conclude that letter B, C and D are properties of gold and the answer is A. Common

Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1."
__H2O2 → __H2O+__O2

Answers

Answer:

2H2O2-----2H2O+O2

Explanation:

This is because theres the same number of atoms of each element on both sides

Which of the following is an example of erosion?

ions in water reacting with rocks
plant roots splitting rocks apart
wind blowing sand against a rock
a glacier carving a valley

Answers

Answer:

The answer is a!

Explanation:

Hope this helps!

What is the [HPO42-]/[H2PO4-] ratio in an acetate buffer at pH 7.20? (The pKa for dihydrogenphosphate is 7.10.)

Answers

Answer:

[tex]\frac{[HPO_4^{2-}]}{[H_2PO_4^{-}]}=1.26[/tex]

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

pH=pKa+log[base]/[acid]

For the equilibrium buffer of dihydrogen phosphate, pKa = 7.10

pH = 7.20

[tex]pH=pKa+\log\frac{[base]}{[acid]}[/tex]

[tex]7.20=7.10+\log\frac{[HPO_4^{2-}]}{[H_2PO_4^{-}]}[/tex]

[tex]\log\frac{[HPO_4^{2-}]}{[H_2PO_4^{-}]}=0.10[/tex]

[tex]\frac{[HPO_4^{2-}]}{[H_2PO_4^{-}]}=1.26[/tex]

Final answer:

The [HPO42-]/[H2PO4-] ratio in an acetate buffer at pH 7.20 is approximately 1.26, calculated using the equation pH = pKa + log ([A-]/[HA]) and the provided pKa for dihydrogenphosphate.

Explanation:

To calculate the [HPO42-]/[H2PO4-] ratio in an acetate buffer at pH 7.20, we can use the equation pH = pKa + log ([A-]/[HA]). In this case, the pKa for dihydrogenphosphate is 7.10. Given that pH = 7.20, we can rewrite this as log ([HPO42-]/[H2PO4-]) = pH - pKa = 7.20 - 7.10 = 0.1. The anti-logarithm of 0.1 gives us around 1.26. Therefore, the [HPO42-]/[H2PO4-] ratio is approximately 1.26.

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The increasing concentration of a chemical as it moves through the links in a food chain is called ________.

Answers

Answer: Biological Magnification

Explanation:

Organisms acquire toxic substance from the environment along with nutrients and water. Some of the toxins are metabolized and excreted, but others accumulate in specific tissues, especially fat. One of the reasons accumulated toxins are particularly harmful is that the become more concentrated in successive trophic level of the food web, this is the process of biological magnification.

Magnification occurs because the biomass at any given level is produced from a must larger biomass ingested from the level below. Thus the top-level carnivores tend to be the organism most severely affected by toxic compounds in the environment.

Examples of toxins that demonstrate biology magnification are chlorinated hydrocarbons, and many pesticides.

Jackie goes camping in the Nowhere mountains and brings a few pots and pans to cook. On top of Nowhere mountain (at 3,000 feet above sea level), Jackie realizes her soup cooks much faster than at her house in Austin, TX (at sea level). Explain why this is.

Answers

This is because of the low pressure at the mountains.

Explanation:

The air pressure or atmospheric pressure is defined as the amount of pressure exerted by the air column of the atmosphere above in the atmosphere per unit area. This air pressure is inversely proportional to the height of the land above sea level. As we go up in the atmosphere, the pressure of Air decrease.

As Jackie goes in the mountains for his picnic, the pressure of air at the mountains is much lower than at her house in Austin, because Austin is at sea level. So water will boil much faster owing to low pressure. Thus, water is boiling at lower temperature. And this low temperature is easily and quickly achievable. So Austin seems that her soup is ready much faster. But the veggies and meat won't be fully cooked at that temperature. So although the soup seems to be ready, it isn't.

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