Answer:
1)
[tex]H_0: p_1-p_2=0\\\\H_a: p_1-p_2>0[/tex]
2) z=3.164
3) Critic value z₀=1.282.
4) P=0.00078
5) The correct answer is: "Since the p-value is less than the given value of alpha, there is sufficient evidence to reject H_0"
Step-by-step explanation:
5.1) Being:
p₁: proportion of men who keep track of the deadlines in their head
p₂: proportion of women who keep track of the deadlines in their head
If we want to test if p₁ is larger than p₂, the null hypothesis and the alternative hypothesis should be:
[tex]H_0: p_1-p_2=0\\\\H_a: p_1-p_2>0[/tex]
In this way, if we reject the null hypothesis, it can be claimed that p₁ is larger than p₂.
5.2) Compute the test statistic for the test.
First, we have to estimate a proportion as if the null hypothesis is true. This means the average of proportion of the samples taken from men and women, weighted by the sample size.
[tex]\bar p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{500*0.54+500*0.44}{500+500}= 0.49[/tex]
Then, we used this average to estimate the standard error
[tex]s=\sqrt{\frac{p(1-p)}{n_1}+{\frac{p(1-p)}{n_2}}}=\sqrt{\frac{0.49(1-0.49)}{500}+{\frac{0.49(1-0.49)}{500}}}=\sqrt{0.0004998+0.0004998}\\\\s= 0.0316[/tex]
Lastly, we calculate the statistic z
[tex]z=\frac{p_1-p_2}{s}=\frac{0.54-0.44}{0.0316}=\frac{0.10}{0.0316}=3.164[/tex]
5.3) Give the rejection region for the test, using α = 0.10
For a one-tailed test with α = 0.10, the z value to limit the rejection region is z=1.282.
For every statistic larger than 1.282, the null hypothesis should be rejected.
5.4) Find the p-value for the test.
The p-value for a z=3.164 is P=0.00078 (corresponding to the area ot the standard normal distribution for a z larger than 3.164).
5.5) Choose the correct answer below.
The correct answer is: "Since the p-value is less than the given value of alpha, there is sufficient evidence to reject H_0"
The difference between the proportions is big enough to be statistically significant and enough evidence to reject the null hypothesis.
A consumer products company found that 44% of successful products also received favorable results from test market research, whereas 13% had unfavorable results but nevertheless were successful. That is, P(successful product and favorable test market) = 0.44 and P(successful product and unfavorable test market) = 0.13. They also found that 32% of unsuccessful products had unfavorable research results, whereas 11% of them had favorable research results, that is P(unsuccessful product and unfavorable test market) = 0.32 and P(unsuccessful product and favorable test market) = 0.11.
Find the probabilities of successful and unsuccessful products given known test market results, that is, P(successful product given favorable test market), P(successful product given unfavorable test market), P(unsuccessful product given favorable test market), and P(unsuccessful product given unfavorable test market).
Answer:
0.800.2890.200.711Step-by-step explanation:
Given:
[tex]P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11[/tex]
The rule of total probability states that:
[tex]P(A) = P(A\cap B) + P(A\cap B^{c})[/tex]
Compute the individual probabilities as follows:
[tex]P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57[/tex]
[tex]P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43[/tex]
[tex]P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55[/tex]
[tex]P(F^{c})=1-P(F)\\=1-0.55\\=0.45[/tex]
Conditional probability of an event A given B is:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]
Compute the value of [tex]P(S|F)[/tex]:[tex]P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80[/tex]
Compute the value of [tex]P(S|F^{c})[/tex][tex]P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289[/tex]
Compute the value of [tex]P(S^{c}|F)[/tex][tex]P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20[/tex]
Compute the value of[tex]P(S^{c}|F^{c})[/tex][tex]P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711[/tex]
The probability of successful product given favorable test market is 0.80, and the probability of successful product given unfavorable test market is 0.29. The probability of unsuccessful product given favorable test market is 0.20, and the probability of unsuccessful product given unfavorable test market is 0.71.
Explanation:To solve this, we first need to determine the total probability of each market test outcome. The probability that the market test is favorable (P(favorable test market)) can be found by summing the probabilities of a successful product with a favorable test market and an unsuccessful product with a favorable test market. Therefore, P(favorable test market) = 0.44 + 0.11 = 0.55. Similarly, P(unfavorable test market) = 0.13 + 0.32 = 0.45.
To find the conditional probabilities, we use the formula P(A|B) = P(A and B) / P(B):
P(successful product given favorable test market) = P(successful product and favorable test market) / P(favorable test market) = 0.44 / 0.55 = 0.80.P(successful product given unfavorable test market) = P(successful product and unfavorable test market) / P(unfavorable test market) = 0.13 / 0.45 = 0.29.P(unsuccessful product given favorable test market) = P(unsuccessful product and favorable test market) / P(favorable test market) = 0.11 / 0.55 = 0.20.P(unsuccessful product given unfavorable test market) = P(unsuccessful product and unfavorable test market) / P(unfavorable test market) = 0.32 / 0.45 = 0.71.Learn more about Conditional Probability here:https://brainly.com/question/32171649
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Use the geometric definition of the cross product and the properties of the cross product to make the following calculations. (a) ((i⃗ +j⃗ )×i⃗ )×j⃗ = (b) (j⃗ +k⃗ )×(j⃗ ×k⃗ ) = (c) 4i⃗ ×(i⃗ +j⃗ ) = (d) (k⃗ +j⃗ )×(k⃗ −j⃗ ) =
Answer:
Step-by-step explanation:
we know
[tex]\vec{i}\times \vec{j}=\vec{k}[/tex]
[tex]\vec{j}\times \vec{k}=\vec{i}[/tex]
[tex]\vec{k}\times \vec{i}=\vec{j}[/tex]
(a)[tex]\left [ \left ( \hat{i}+\hat{j}\right )\times \hat{i}\right ]\times \hat{j}[/tex]
[tex]=\left [ \hat{i}\times \hat{i}+\hat{j}\times \hat{i}\right ]\times \hat{j}[/tex]
[tex]=\left [ 0-\hat{k}\right ]\times \hat{j}[/tex]
[tex]=\hat{i}[/tex]
(b)[tex]\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{j}\times \hat{k}\right )[/tex]
[tex]=\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{i}\right )[/tex]
[tex]=\hat{k}+\hat{j}[/tex]
(c)[tex]4\hat{i}\times \left ( \hat{i}+\hat{j}\right )[/tex]
[tex]=4\hat{i}\times \hat{i}+4\hat{i}\times \hat{j}[/tex]
[tex]=0+4\hat{k}[/tex]
(d)[tex]\left ( \hat{k}+\hat{j}\right )\times \left ( \hat{k}-\hat{j}\right )[/tex]
[tex]=\hat{k}\times \hat{k}-\hat{k}\times \hat{j}+\hat{j}\times \hat{k}-\hat{j}\times \hat{j}[/tex]
[tex]=0+\hat{i}+\hat{i}-0[/tex]
[tex]=2\hat{i}[/tex]
The direction of the cross product depends on the right-hand rule and the resulting cross-product is located on the plane that is perpendicular to the vectors undergoing the cross product.
Taking i, j, k as the unit vector along x, y, z-direction.
Since [tex]i \times i = 0[/tex] it implies the angle∠ between them is 0;
Then: sin(0) = 0
Also;
[tex]j \times j = 0 \\ \\ k\times k = 0[/tex]
Similarly, [tex]i \times j = k[/tex] which implies that the angle ∠ between them = 90°;
Then: sin (90°) = 1
Also;
[tex]j \times k= i \\ \\ k \times i = j[/tex]
[tex]j \times i = - k[/tex] which implies that the angle ∠ between them = -90° or 270°
Then; sin (-90) or Sin ( 270) = -1
Also;
[tex]i \times k = -j \\ \\ j \times i = -k[/tex]
As such i, j, k are unit vectors for x, y, and z-axis.
To determine the following calculations, we have;
(a)
[tex]\Big ( ( i^{\to }+ j^{\to })\times i^{\to }\Big)\times j^{\to }[/tex]
[tex]= ( i^{\to } \times i^{\to } + j^{\to }\times i^{\to }) \times j^{\to }[/tex]
[tex]=(0 - k^{\to })\times j^{\to }[/tex]
[tex]= - k^{\to } \times j^{\to }\\\\= -(-i^{\to }) \\ \\ \mathbf{= i^{\to }}[/tex]
(b)
[tex](j^{\to }+ k^{\to }) \times (j^{\to } + k^{\to })[/tex]
[tex]= j^{\to } \times (j^{\to } \times k ) + k^{\to } \times (j \times k)\\ \\ = j^{\to } \times i^{\to } + k^{\to } \times i^{\to } \\ \\ \mathbf{ = -k^{\to } + j^{\to }}[/tex]
(c)
[tex]4i^{\to } \times (j \times k^{\to }) \\ \\ = 4 (i^{\to } \times i^{\to }) \\ \\ \mathbf{= 0}[/tex]
(d)
[tex](k^{\to} + j^{\to}) \times (k^{\to} - j^{\to})) \\ \\ =(k^{\to} \times k^{\to}) - (k^{\to} \times j^{\to})+(j^{\to} + k^{\to}) - (j^{\to} \times j^{\to}) \\ \\ = 0 + i^{\to} + i^{\to} -0 \\ \\ \mathbf{ = 2 i^{\to}}[/tex]
Therefore, we can conclude that the calculations of the cross-product are well defined from the above explanations.
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Angela took a general aptitude test and scored in the 91st percentile for aptitude in accounting. (a) What percentage of the scores were at or below her score?(b) What percentage were above?
Answer:
a) 91% of the scores were at or below her score.
b) 9% of the scores were above her score.
Step-by-step explanation:
When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.
In this problem, we have that:
Angela scored on the 91st percentile.
(a) What percentage of the scores were at or below her score?
Since Angela scored on the 91st percentile, 91% of the scores were at or below her score.
(b) What percentage were above?
Since Angela scored on the 91st percentile, 9% of the scores were above her score.
Angela scored higher than or equal to 91% of her peers, meaning 9% scored above her.
Explanation:If Angela scored in the 91st percentile on her general aptitude test, that means she scored higher than or equal to 91% of the other scores. Therefore, (a) 91% of scores were at or below Angela's score. As for (b), if you subtract her percentile from 100%, you can determine that 9% of scores were above hers.
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This problem involves two distinct sets of events, which we label A1and A2 and B1 and B2. The events A1and A2 are mutually exclusive and collectively exhaustive within their set. The events B1and B2 are mutually exclusive and collectively exhaustive within their set. Intersections can occur between all events from the two sets.Given P(A1)= 0.8, P(B1|A1) = 0.6, and P(B1|A2) = 0.2, what is P(A1|B1)?
Answer:
0.42
Step-by-step explanation:
Let the events be given as:
For twp mutually exclusive events, the probability of A1 is given as follows:
P (B1A1) = [tex]\frac{ P(B1) x P (BA1)}{P(A1)}[/tex]
= 0.6
Solving the equation above to get B1:
P (B1) = [tex]\frac{(0.8)x (0.6)}{(0.6)}[/tex]
= 0.8
Therefore, computing P (A1B1) gives P(A1) × P (B1)
= (0.8) × (0.6)
= 0.42 Ans
Suppose x is a random variable best described by a uniform probability distribution with c=20 and d=40.
Find the probability P(20≤x≤35).
Answer:
P(20≤x≤35) = 0.75 .
Step-by-step explanation:
We know that the probability distribution function of Uniform Distribution is represented as :
If x follows Uniform(c,d) then,
f(x) = [tex]\frac{1}{d-c}[/tex] where c < x < d
To fond the given probability it is better to first calculate the Cumulative Distribution Function(CDF) of Uniform Distribution.
The CDF of Uniform Distribution is P(X<=x) = [tex]\frac{x-c}{d-c}[/tex] where d > c .
Therefore, P(20<=x<=35) = P(x<=35) - P(x<20)
P(x<=35) = [tex]\frac{x-20}{40-20}[/tex] because we are given c = 20 and d = 40.
= [tex]\frac{35-20}{40-20}[/tex] = 0.75
P(x<20) = [tex]\frac{x-20}{40-20}[/tex] = [tex]\frac{20-20}{40-20}[/tex] = 0
Hence, P(20<=x<=35) = 0.75 - 0 = 0.75.
The probability of x being between 20 and 35 is 0.75 or 75%.
Explanation:The uniform probability distribution is defined as:
P(x) = 1/(b-a) for a ≤ x ≤ b and 0 otherwise.
In this case, a=20 and b=40, so the probability P(20≤x≤35) can be calculated as:
P(20≤x≤35) = (35-20)/(40-20) = 15/20 = 0.75.
Therefore, the probability of x being between 20 and 35 is 0.75 or 75%.
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PLZ HELP A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 55 pounds each, and the small boxes weigh 35 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4950 pounds in boxes, how many of each type of box is it carrying?
Answer:
There were 28.75 large boxes and 96.25 small boxes.
Step-by-step explanation:
Create a system of equations to solve.
State your variables
let x be the number of small boxes
let y be the number of large boxes
35x + 55y = 4950 Equation for weight
x + y = 125 Equation for number of boxes
Rearrange equation for number of boxes to isolate "x".
x = 125 - y
Substitute the new equation into the equation for weight
35x + 55y = 4950
35(125 - y) + 55y = 4950
Expand the brackets
4375 - 35y + 55y = 4950 Combine like terms
4375 + 20y = 4950
Start isolating "y"
4375 + 20y = 4950
4375 - 4375 + 20y = 4950 - 4375 subtract 4375 from both sides
20y = 575
20y/20 = 575/20 divide both sides by 20
y = 28.75 number of large boxes
Calculate "x". Rearrange the equation for number of boxes to isolate "y".
y = 125 - x Substitute this expression
35x + 55y = 4950 equation for weight
35x + 55(125 - x) = 4950 expand the brackets
35x + 6875 - 55x = 4950 combine like terms
6875 - 20x = 4950 start isolating "x"
6875 - 6875 - 20x = 4950 - 6875 subtract 6875 on both sides
-20x = -1925
-20x/-20 = -1925/-20 divide both sides by -20
x = 96.25 number of small boxes
There is a mistake with this question because you should not be able to have partial boxes. However, the answer is:
There were 28.75 large boxes and 96.25 small boxes.
Suppose that we have a standard Solow model with a Cobb-Douglas production function. The central equation of the model is as follows: kt+1 = sAkα t + (1 − δ)kt . Consumption per worker is given by: ct = (1 − s)Akα t . (a) Solve for an expression for the steady state capital stock per worker. In doing so, assume that the level of productivity is fixed at some value A.
Answer:
The answer is shown in the attachment
Step-by-step explanation:
The detailed step by step and appropriate mathematical manipulation for the expression for the steady state capital stock per worker is as shown in the attachment.
Consider the following hypothesis test: H0: LaTeX: \mu\leμ ≤ 12 Ha: LaTeX: \mu>μ > 12 A sample of 25 provided a sample mean LaTeX: \overline{x}x ¯ = 14 and a sample standard deviation s = 4.32. Use LaTeX: \alphaα = 0.05. a. Compute the value of the test statistic.
Answer:
[tex]t=\frac{14-12}{\frac{4.32}{\sqrt{25}}}=2.315[/tex]
[tex]p_v =P(t_{(24)}>2.315)=0.015[/tex]
If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 1% of signficance.
Step-by-step explanation:
Data given and notation
[tex]\bar X = 14[/tex] represent the sample mean
[tex]s=4.32[/tex] represent the sample standard deviation
[tex]n=25[/tex] sample size
[tex]\mu_o =12[/tex] represent the value that we want to test
[tex]\alpha=0.05[/tex] represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is higher than 12, the system of hypothesis would be:
Null hypothesis:[tex]\mu \leq 12[/tex]
Alternative hypothesis:[tex]\mu > 12[/tex]
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
[tex]t=\frac{14-12}{\frac{4.32}{\sqrt{25}}}=2.315[/tex]
P-value
The first step is calculate the degrees of freedom, on this case:
[tex]df=n-1=25-1=24[/tex]
Since is a one side right tailed test the p value would be:
[tex]p_v =P(t_{(24)}>2.315)=0.015[/tex]
Conclusion
If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 1% of signficance.
To calculate the test statistic for a given hypothesis test, use the formula for a one-sample z-test by taking the difference between the sample mean and the population mean under the null hypothesis, divided by the standard error of the mean. For the given values, the test statistic is approximately 2.315.
You asked how to compute the value of the test statistic for a hypothesis test with the following parameters:
Null hypothesis H0: μ ≤ 12
Alternative hypothesis Ha: μ > 12
Sample size n = 25
Sample mean μ = 14
Sample standard deviation s = 4.32
Significance level α = 0.05
To calculate the test statistic, we use the formula for a one-sample z-test since the sample size is large (n ≥ 30) or the population is normally distributed and σ is known.
The test statistic (z) is calculated as follows:
z = (μ - μ0) / (s / √n)
Where:
μ0 is the hypothesized population mean under the null hypothesis.
μ is the sample mean.
s is the sample standard deviation.
n is the sample size.
Substituting the given values:
z = (14 - 12) / (4.32 / √25)
z = 2 / (4.32 / 5)
z = 2 / 0.864
z ≈ 2.315
Therefore, This z value is the test statistic that you would then compare to the critical z value from the z-table that corresponds to the given significance level α = 0.05 for a right-tailed test.
Using the bijection rule to count binary strings with even parity.
Let B = {0, 1}. Bn is the set of binary strings with n bits. Define the set En to be the set of binary strings with n bits that have an even number of 1's. Note that zero is an even number, so a string with zero 1's (i.e., a string that is all 0's) has an even number of 1's.
(a) Show a bijection between B9 and E10. Explain why your function is a bijection.
Answer:
Lets denote c the concatenation of strings. For a binary string a in B9, we define the element f(a) in E10 this way:
f(a) = a c {1} if a has an odd number of 1's f(a) = a c {0} if a has an even number of 1'sStep-by-step explanation:
To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.
f is well defined:
To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.
f is injective (or one on one):
If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.
f is surjective:
Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:
If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = yIf x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = yThis shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.
You select a sample of 50 scores from a population of 2,000 scores. You compute the range and standard deviation on the sample of 50 scores. You then select another sample of 50 scores from the same population. What measure of dispersion is likely to vary most between your first and second samples?
Answer:
The measure of dispersion which is likely to vary most between your first and second samples is the range.
Step-by-step explanation:
The range and standard deviation of a data are measures of dispersion, i.e. they measure the degree to which the data is dispersed.
The formula to compute the range is:
[tex]Range=X_{max}-X_{min}[/tex]
The formula to compute the sample standard deviation is:
[tex]s=\sqrt{\frac{1}{n-1}\sum (X-\bar X)^{2} }[/tex]
The sample size is: n = 50.
As the sample size is large (n = 50 > 30) the sample standard deviation (s) can be used to approximate the population standard deviation (σ). Thus, whatever the sample values be both the standard deviations can be used to approximate the population standard deviation. Hence, it can be said that both the sample standard deviations are approximately equal.Whereas the range of the two samples are very likely to vary since it is based on the minimum and maximum value of the data. For both the samples the minimum and maximum value may be differ. Thus providing different range values.Thus, the measure of dispersion which is likely to vary most between your first and second samples is the range.
Final answer:
The range is more likely to vary between two samples from a population due to its sensitivity to extreme values, whereas the standard deviation is a more stable measure of dispersion that accounts for all values in the dataset.
Explanation:
The measure of dispersion most likely to vary between the first and second samples from the population is the range. The range is sensitive to the particular values in the dataset because it only takes into account the smallest and largest values. Since each sample may have a different set of extreme values, the range can vary greatly from sample to sample. In contrast, the standard deviation is less likely to vary significantly between samples, as it measures the amount of variation or dispersion from the mean of a dataset and takes into account all the values in the set.
When drawing multiple samples from a population, the distribution of the sample means will tend to form a normal distribution around the population mean according to the Central Limit Theorem. In the case of a normally distributed population with a known mean and standard deviation, the sampling distribution of the sample mean will have a standard deviation equal to the population standard deviation divided by the square root of the sample size (known as the standard error).
I need a better explanation how to find length and area of a triangle
Answer:
Height(h) = 24in
Area = 204in²
Step-by-step explanation:
we would use the heron formula because we have all the sides to calulate the area
S = (A+B+C)/2 = (25 + 17 + 26)/2 = 68/2 = 34
area = √s(s-a)(s-b)(s-c) = √34(34-25)(34-17)(34-26) = √34(9)(17)(8) = √34x9x17x8 = √41616 = 204
area= (1/2)bh
204 = (1/2)bh b= 17, h =?
204 = (1/2)17h
204 x 2 = 17h
408 = 17h
h = 408/17 = 24in
Height(h) = 24in
Area = 204in²
You have decided that you want to be a millionaire when you retire in 44 years. If you can earn an annual return of 11.06 percent, how much do you have to invest today? What if you can earn an annual return of 5.53 percent?
Answer:
1. Let amount deposited now be P.
So P*(1.1106^44) = 1,000,000, which means P=9896.06
2. Let amount deposited now be P.
So P*(1.0553^44) = 1,000,000, which means P=93639.42
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let P represent the amount that you need to invest today. Thus, principal = $P
The return would be compounded annually. So
n = 1
The rate at which the principal would be compounded is 11.06%. So
r = 11.06/100 = 0.1106
The investment would be for 44 years. So
t = 44
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years.
A = $1000000
Therefore
1000000 = P(1+0.1106/1)^1×44
1000000 = P(1.1106)^44
P = 1000000/101.05
P = $9896.1
2) if you can earn an annual return of 5.53 percent, then
r = 5.53/100 = 0.053
1000000 = P(1+0.53/1)^1×44
1000000 = P(1.053)^44
P = 1000000/9.7
P = $103093
APPLY IT Rate of Growth The area covered by a patch of moss is growing at a rate of
A'(t)=√ t ln t
cm^2 per dat, for t≥1. ≥ 1. Find the additional amount of area covered by the moss between 4 and 9 days.
Answer:
The additional amount of area covered between 4 to 9 days is 23.71 cm2
Step-by-step explanation:
As the relation is given as a combination of two functions so integration by parts is carried out thus
[tex]\int\limits^9_4 {\sqrt{t}\, ln t} \, dt[/tex]
In order to solve this integral, integration by parts is to be carried out which is given as
[tex]\int u v dx=u \int v dx -\int u'(\int vdx) dx[/tex]
Where
u(x) is a function of x
v(x) is a function of x
u' is the derivative of u wrt to x
Also u and v are defined on using the following sequence ILATE RULE (Inverse, Logarithmic, Algebraic, Trigonometric, Exponent)
As here Logarithmic function is present which is taken as u and the algebraic function is taken as v so
[tex]u= ln t\\v=\sqrt{t}\\u'=\frac{1}{t}[/tex]
[tex]\int v dt =\int t^{1/2} dt =\frac{2}{3}t^{3/2}[/tex]
Substituting the values in equation gives
[tex]\int u v dt=u \int v dt -\int u'(\int vdt) dt\\\int{\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\int(\frac{1}{t} )(\frac{2}{3}t^{3/2}) dt\\\int{\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\int(\frac{2}{3}t^{1/2}) dt\\\int{\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\frac{2}{3}\int(t^{1/2}) dt\\\int{\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\frac{2}{3}(\frac{2}{3}t^{3/2}) +C\\\int{\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\frac{4}{9}(t^{3/2}) +C[/tex]
Now solving the definite integral
[tex]\int\limits^9_4 {\sqrt{t}\, ln t} \, dt=ln t (\frac{2}{3}t^{3/2}) -\frac{4}{9}(t^{3/2}) +C\\\int\limits^9_4 {\sqrt{t}\, ln t} \, dt=[ln t (\frac{2}{3}t^{3/2}) -\frac{4}{9}(t^{3/2})]_{9} -[ln t (\frac{2}{3}t^{3/2}) -\frac{4}{9}(t^{3/2})]_{4}\\\int\limits^9_4 {\sqrt{t}\, ln t} \, dt=18 ln (9)-\frac{16}{3} ln 4 -\frac{76}{9}\\A=\int\limits^9_4 {\sqrt{t}\, ln t} \, dt=23.71 cm^2\\[/tex]
So the additional amount of area covered between 4 to 9 days is 23.71 cm2
The negative sign in 15t-2t belongs to the term____?
The expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.
Solution:
Given expressions are 15t – 2t and 2t – 15t.
To determine 15t – 2t is equivalent to 2t – 15t or not.
Substitute t = 2 in above two expressions.
15t – 2t = 15(2) – 2(2)
= 30 – 4
= 26
2t – 15t = 2(2) – 15(2)
= 4 – 30
= –26
The values of the expressions are different when t = 2.
So, 15t – 2t is not equivalent to 2t – 15t.
Hence the expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.
What is the simplified form of this expression?
(-3x2 + 4x) + (2x2 − x − 11)
Answer:
option b
-x^2 + 3x - 11
Step-by-step explanation:
we have to add the X of the same order
x^2
-3x^2 + 2x^2 = -x^2
x^1
4x + ( -x ) = 3x
x^0
0 + (-11) = -11
finally we accommodate and get the final result
-x^2 + 3x - 11
Answer:-x^2 + 3x - 11
Step-by-step explanation:
I got it right on the test
A company has fixed monthly costs of $100,000 and production costs on its product of $28 per unit. The company sells its product for $74 per unit. The cost function, revenue function and profit function for this situation are
Answer:
The cost function is [tex]C(x)=100000+x\cdot 28[/tex]
The revenue function is [tex]R(x)=x\cdot 74[/tex]
The profit function is [tex]P(x)=46x-100000[/tex]
Step-by-step explanation:
We have the following definitions:
The cost function consists of variable costs and fixed costs and is given by
[tex]C(x)=fixed\:costs+x\cdot variable\:costs[/tex]
The revenue function is given by
[tex]R(x)=x\cdot p(x)[/tex]
where x are the units sold and p(x) is the price per unit.
The profit function is given by
[tex]P(x)=R(x)-C(x)[/tex]
Given:
Fixed costs = $100,000
Variable costs = $28 per unit
Price per unit = $74 per unit
Applying the above definitions and the information given, we get that:
The cost function is [tex]C(x)=100000+x\cdot 28[/tex]
The revenue function is [tex]R(x)=x\cdot 74[/tex]
The profit function is [tex]P(x)=74x-(28x+100000)=46x-100000[/tex]
Final answer:
The total cost for producing 1,000 units of output, given average fixed costs of $100 and average variable costs of $50, is calculated to be $150,000.
Explanation:
The question asks us to calculate total cost of producing 1,000 units of output given the average fixed costs and average variable costs. To find the total cost, we need to add together the total fixed costs (average fixed cost × quantity) and the total variable costs (average variable cost × quantity).
The total fixed cost is $100,000 (since $100 × 1,000 units) and the total variable cost is $50,000 (since $50 × 1,000 units). Therefore, the total cost of producing 1,000 units of output is $150,000.
How do you convert $150,000 US dollars to $240,000 Australian dollars (1.31545 AU) using the exchange rate per US dollar?
Answer:
240,000 AUD to USD = 161,924.79 US Dollars or 150,000 USD to AUD = 222,316.63 Australian Dollars
Step-by-step explanation:
A glass of orange juice contains 3.2 dL of juice. How many milliliters of orange juice are in the glass?
Answer:
There are 320 milliliters of orange juice in the glass.
Step-by-step explanation:
Unit conversion problems can be solved by rules of three.
We have that each dL is worth 100 mL(milliliters).
How many milliliters of orange juice are in the glass?
How many ml are 3.2dL of juice?
1 dL - 100 mL
3.2 dL - x mL
[tex]x = 100*3.2[/tex]
[tex]x = 320[/tex]
There are 320 milliliters of orange juice in the glass.
The measure of juice is 320 milliliters.
Given that
A glass of orange juice contains 3.2 dL of juice.
We have to determine
How many milliliters of orange juice is in the glass?
According to the question
To determine the measure of juice in milliliters following all the steps given below.
A glass of orange juice contains 3.2 dL of juice.
Here 1 dL = 100 milliliters
Then,
The measure of juice in milliliters is,
[tex]\rm = 3.2 \times 100\\\\= 320 \ milliliters[/tex]
Hence, The measure of juice is 320 milliliters.
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Find the perimeter of the following shape, rounded to the nearest tenth:
Answer: the perimeter of the shape is 19.1
Step-by-step explanation:
To determine the length of each side of the quadrilateral, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side
For line AD,
AD² = 2² + 4² = 4 + 16 = 20
AD = √20 = 4.47
For line AB,
AB² = 1² + 5² = 1 + 25 = 26
AB = √26 = 5.1
For line BC,
BC² = 2² + 4² = 4 + 16 = 20
BC = √20 = 4.47
For line CD,
CD² = 1² + 5² = 1 + 25 = 26
CD = √26 = 5.1
The perimeter of a plane figure is the distance around the figure. Therefore
Perimeter = AB + AB + BC + CD
Perimeter = 4.47 + 5.1 + 4.47 + 5.1 =
19.1
Answer:
19.1
Step-by-step explanation:
Got it right on the test! <3
A newly proposed endoscopy method used to screen for colon cancer is tested among a random sample of the population. Given that 16 individuals from a test population of 100,000 individuals has colon cancer and 14 individuals test positive for colon cancer, the researchers should determine the sensitivity of the newly proposed screening method is 0.875.
Please explain why this is true
Answer:
The value of sensitivity obtained is equal to the one given in statement.
Step-by-step explanation:
Sensitivity is the ratio of number of positive test results to the number of individuals having disease. It is the ability of the test to detect all those with disease in the screened population.
Its formula is written as:
Sensitivity = [tex]\frac{number of true positives}{total with disease}[/tex]
So, in this case we have values
sensitivity = 14/16 = 0.875 So, the given statement is true.
An ensemble of 100 identical particles is sent through a Stern-Gerlach apparatus and the z-component of spin is measured. 46 yield the value +\frac{\hbar}{2}+ ℏ 2 while the other 54 give -\frac{\hbar}{2}− ℏ 2. Compute the standard deviation of the measurements.
Answer:
The standard deviation is 0.4984 [tex]\hbar[/tex]
Step-by-step explanation:
In order to find standard deviation, The equation is given as
[tex]\sigma=\sqrt{\frac{1}{n} \sum_{i=1}^{100} (\mu-x_i)^2[/tex]
Here μ is the mean which is calculated as follows
[tex]\mu=\frac{\sum_{i=1}^{100} x_i}{n}\\\mu=\frac{46\times \frac{\hbar}{2}+54\times \frac{-\hbar}{2}}{100}\\\mu=\frac{-4 \hbar}{100}\\\mu=-0.04 \hbar[/tex]
Now the standard deviation is given as
[tex]\sigma=\sqrt{\frac{1}{100} \sum_{i=1}^{100} (-0.04 \hbar-x_i)^2}\\\sigma=\sqrt{\frac{1}{100} [[46 \times(-0.04 \hbar-0.5 \hbar)^2]+[54 \times(-0.04 \hbar+0.5 \hbar)^2]}]\\\sigma=\sqrt{\frac{1}{100} [[46 \times(-0.54 \hbar)^2]+[54 \times(0.46 \hbar)^2]}]\\\sigma=\sqrt{\frac{1}{100} [[46 \times(0.2916 \hbar)]+[54 \times(0.2116 \hbar)]}]\\\sigma=\sqrt{\frac{1}{100} [13.4136 \hbar+11.4264 \hbar}]\\\sigma=\sqrt{\frac{24.84 \hbar}{100}}\\\sigma =0.4984 \hbar[/tex]
So the standard deviation is 0.4984 [tex]\hbar[/tex]
Final answer:
To calculate the standard deviation of the z-component of spin measurements from a Stern-Gerlach experiment, use the formula for standard deviation in a binomial distribution. With 46 particles showing spin up and 54 spin down, the standard deviation is found to be approximately 4.984.
Explanation:
The question involves calculating the standard deviation of the z-component of spin measurements in a Stern-Gerlach experiment. Given that 46 particles yielded a spin of +½ℏ and 54 particles yielded a spin of -½ℏ, we can use these values to compute the standard deviation. The formula for the standard deviation σ in this binomial distribution is σ = √(np(1-p)), where n is the total number of trials and p is the probability of success (getting a +½ℏ spin result).
Using these values, the standard deviation is:
σ = √(100 * (46/100) * (1 - 46/100))
σ = √(100 * 0.46 * 0.54)
σ = √(24.84)
σ = 4.984
The standard deviation of the z-component of spin measurements in this experiment is approximately 4.984.
\
See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly selected, and find the indicated probability. a. What is the probability that exactly five of the selected adults believe in reincarnation? b. What is the probability that all of the selected adults believe in reincarnation? c. What is the probability that at least five of the selected adults believe in reincarnation? d. If six adults are randomly selected, is five a significantly high number who believe in reincarna
Answer:
a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.
b) 0.0064% probability that all of the selected adults believe in reincarnation.
c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.
d) Since [tex]P(X \geq 5) < 0.05[/tex], 5 is a significantly high number of adults who believe in reincarnation in this sample.
Step-by-step explanation:
For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
In this problem we have that:
[tex]n = 6, p = 0.2[/tex]
a. What is the probability that exactly five of the selected adults believe in reincarnation?
This is P(X = 5).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015[/tex]
There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.
b. What is the probability that all of the selected adults believe in reincarnation?
This is P(X = 6).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064[/tex]
There is a 0.0064% probability that all of the selected adults believe in reincarnation.
c. What is the probability that at least five of the selected adults believe in reincarnation?
This is
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564[/tex]
There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.
d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?
5 is significantly high if [tex]P(X \geq 5) < 0.05[/tex]
We have that
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05[/tex]
Since [tex]P(X \geq 5) < 0.05[/tex], 5 is a significantly high number of adults who believe in reincarnation in this sample.
a. The probability that exactly five of the selected adults believe in reincarnation is approximately 0.00256.
b. The probability that all of the selected adults believe in reincarnation is approximately 0.000064.
c. The probability that at least five of the selected adults believe in reincarnation is approximately 0.002624.
d. To determine if five is significantly high, we need a significance level for comparison, which isn't provided in the question.
To solve this problem, we can use the binomial probability formula, where "n" is the number of trials, "p" is the probability of success (believing in reincarnation in this case), and "x" is the number of successes.
a. The probability that exactly five of the selected adults believe in reincarnation is calculated as follows:
P(X = 5) = C(6, 5) * (0.20)^5 * (0.80)^(6-5),
where C(6, 5) is the number of ways to choose 5 out of 6 adults, which equals 6.
P(X = 5) = 6 * (0.20)^5 * (0.80)^1 ≈ 0.00256
b. The probability that all of the selected adults believe in reincarnation is:
P(X = 6) = (0.20)^6 ≈ 0.000064
c. The probability that at least five of the selected adults believe in reincarnation is the sum of the probabilities from parts (a) and (b):
P(X ≥ 5) = P(X = 5) + P(X = 6) ≈ 0.00256 + 0.000064 ≈ 0.002624
d. To determine if five is a significantly high number who believe in reincarnation, we can compare the probability of getting at least five believers (from part c) to a significance level. If this probability is less than the significance level, it would be considered significant. The significance level would depend on the context and what is considered "significant" in the specific analysis.
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complete question should be :
See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly selected, and find the indicated probability. a. What is the probability that exactly five of the selected adults believe in reincarnation? b. What is the probability that all of the selected adults believe in reincarnation? c. What is the probability that at least five of the selected adults believe in reincarnation? d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation .
Customers arrive at Rich Dunn’s Styling Shop at a rate of 3 per hour, distributed in a Poisson fashion. Rich’s service times follow a negative exponential distribution, and Rich can complete an average of 5 haircuts per hour. a) Find the average number of customers waiting for haircuts. b) Find the average number of customers in the shop. c) Find the average time a customer waits until it is his or her turn. d) Find the average time a customer spends in the shop. e) Find the percentage of time that Rich is busy.
Answer:
a) 0.9,b) 1.5,c) 0.3hrs, d) 0.5hrs,e) 60%
Step-by-step explanation:
Given Data:
rate of arrival = 3customers/hr ;
rate of service = 5 haircuts/hr ;
a)
Average number of customers = La = λ²/[μ(μ-λ)]
= 3²/[(5(5-3)]
Average number of customers = La = 0.9
b)
Number of customers in system = Ls = λ/(μ-λ)
= 3/(5-3)
Number of customers in system = Ls = 1.5
c)
Average waiting time = Ta = λ/[μ(μ-λ)]
= 3/[(5(5-3)]
Average waiting time = Ta =0.3hrs or 18mins
d)
Average time spent by customer = Ts = 1/(μ-λ)
= 1/(5-3)
Average time spent by customer = Ts = 0.5hrs or 30mins
e)
% of time = Tr = λ/μ
= 3/5
% of time = Tr = 0.6 or 60%
The arrival of customers follows a Poisson distribution
The average number of customers waiting for haircut is 0.9The average number of customers in the shop is 1.5The average time of waiting for haircut is 0.3 hourThe average time spent in the shop is 0.5 hourRich is busy 60% of the timeThe given parameters are:
[tex]\mathbf{\lambda = 3}[/tex] --- rate of arrival
[tex]\mathbf{\mu= 5}[/tex] ---- rate of service
(a) Average number of customers waiting
This is calculated using:
[tex]\mathbf{L_a = \frac{\lambda^2}{\mu(\mu - \lambda)}}[/tex]
So, we have:
[tex]\mathbf{L_a = \frac{3^2}{5(5 - 3)}}[/tex]
[tex]\mathbf{L_a = \frac{9}{5 \times 2}}[/tex]
[tex]\mathbf{L_a = \frac{9}{10}}[/tex]
[tex]\mathbf{L_a = 0.9}[/tex]
Hence, the average number of customers waiting for haircut is 0.9
(b) Average number of customers in the shop
This is calculated using:
[tex]\mathbf{L_s = \frac{\lambda}{\mu - \lambda}}[/tex]
So, we have:
[tex]\mathbf{L_s = \frac{3}{5 - 3}}[/tex]
[tex]\mathbf{L_s = \frac{3}{2}}[/tex]
[tex]\mathbf{L_s = 1.5}[/tex]
Hence, the average number of customers in the shop is 1.5
(c) Average time of waiting
This is calculated using:
[tex]\mathbf{T_a = \frac{\lambda}{\mu(\mu - \lambda)}}[/tex]
So, we have:
[tex]\mathbf{T_a = \frac{3}{5(5 - 3)}}[/tex]
[tex]\mathbf{T_a = \frac{3}{5 \times 2}}[/tex]
[tex]\mathbf{T_a = \frac{3}{10}}[/tex]
[tex]\mathbf{T_a = 0.3}[/tex]
Hence, the average time of waiting for haircut is 0.3 hour
(d) Average time spent in the shop
This is calculated using:
[tex]\mathbf{T_s = \frac{1}{\mu - \lambda}}[/tex]
So, we have:
[tex]\mathbf{T_s = \frac{1}{5 - 3}}[/tex]
[tex]\mathbf{T_s = \frac{1}{2}}[/tex]
[tex]\mathbf{T_s = 0.5}[/tex]
Hence, the average time spent in the shop is 0.5 hour
(e) Percentage of time Rich is busy
This is calculated as:
[tex]\mathbf{T = \frac{\lambda}{\mu}}[/tex]
So, we have:
[tex]\mathbf{T = \frac{3}{5}}[/tex]
Divide
[tex]\mathbf{T = 0.6}[/tex]
Express as percentage
[tex]\mathbf{T = 60\%}[/tex]
Hence, Rich is busy 60% of the time
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If a student determined that the volume of a sample of water is 11.4 mL, and its mass is 10.98 g, what should the student record as the experimental density of the water sample, with the correct number of significant figures
Answer:1.04 ml/g.
Step-by-step explanation:
The formula we use to find the density :
[tex]\text{Density}=\dfrac{\text{Volume}}{\text{Mass}}[/tex]
We are given that ,
Volume of a sample of water = 11.4 mL
Mass of sample of water = 10.98 g
Then , the experimental density of the water sample will be :-
[tex]\text{Density}=\dfrac{11.4}{10.98}=1.03825136\approx1.04[/tex]
Hence, the experimental density of the water sample is 1.04 ml/g.
please help. i have no idea where to start
Step-by-step explanation:
[tex] \because \triangle \: DEF \sim \triangle NPQ \\ \\ \therefore \: \frac{EF}{PQ} = \frac{DF}{NQ}... (csst) \\ \\ \therefore \: \frac{d}{ \frac{11}{2} } = \frac{7}{9} \\ \\ \therefore \: \frac{2d}{ 11 } = \frac{7}{9} \\ \\ \therefore \: d = \frac{11 \times 7}{2 \times 9} \\ \\ \therefore \: d = \frac{77}{18} \\ [/tex]
Answer:
77/18
Step-by-step explanation:
Similar figures have sides in the same ratio.
Ratio can be obtained using the ratio of DF/NQ
DF/NQ = 7/9
EF/PQ = 7/9
d/(11/2) = 7/9
d = 7/9 × 11/2
d = 77/18
Researchers measure the body temperature of 52 randomly selected adults. They find a mean temperature of 98.2 degrees with a standard deviation of 0.682 degrees. Which of the following is the correct t-test statistic and p-value for a test of the following hypotheses?
H_o: mu = 98.6 degrees
H_a: mu notequalto 98.6 degrees
The test statistic is negative 1. 039.21.and the p-value is less than 0.000001.
The test statistic is negative 0.46.and the p-value is 2 times P(t_51 > -0.46).
The t-test statistic is negative 0.315.and the p-value is P(t_51 < -0.315).
The t-test statistic is negative 3.33.and the p-value is two times P(t_51 < -3.33).
Answer:
The t-test statistic is -3.33.and the p-value is two times P(t_51 < -3.33).
Step-by-step explanation:
Data given and notation
Assuming that the real sample mean is: [tex]\bar X=98.285[/tex] represent the sample mean
[tex]s=0.682[/tex] represent the sample standard deviation
[tex]n=52[/tex] sample size
[tex]\mu_o =98.6[/tex] represent the value that we want to test
[tex]\alpha[/tex] represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to apply a two tailed test.
What are H0 and Ha for this study?
Null hypothesis: [tex]\mu = 98.6[/tex]
Alternative hypothesis :[tex]\mu \neq 98.6[/tex]
Compute the test statistic
The statistic for this case is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
[tex]t=\frac{98.2-98.6}{\frac{0.682}{\sqrt{52}}}=-3.298[/tex]
Now we can calculate the degrees of freedom and we got:
[tex] df = n-1 = 52-1 = 51[/tex]
P value
Since is a two tailed test the p value would be:
[tex]p_v =2*P(t_{51}<-3.3)=0.0018[/tex]
So the most appropiate conclusion for this case would be:
The t-test statistic is -3.33.and the p-value is two times P(t_51 < -3.33).
Let f be the function that determines the area of a circle (in square cm) given the radius of the circle in cm, r. That is, f(r) represents the area of a circle (in square cm) whose radius is r cm. Use function notation to complete the following tasks a. Represent the area (in square cm) of a circle whose radius is 4 cm. Preview syntax error b. Represent how much the area (in square cm) of a circle increases by when its radius increases from 10.9 to 10.91 cm. # Preview syntax error c. Represent the area of 5 circles that all have a radius of 12.7 cm *Preview syntax error d. A circle has a radius of 28 cm. Another larger circle has an area that is 59 square cm more than the first circle. Represent the area of the larger circle. # Preview) syntax error
Part(a):[tex]f(r)=f(4)[/tex]
Part(b):[tex]f(10.91)-f(10.9)[/tex]
Part(c):[tex]5 f(r)=5 f(12.7)[/tex]
Part(d):[tex]28+59 =f(28)+59[/tex]
Area of the circle:
The area of a circle is the region occupied by the circle in a two-dimensional plane. It can be determined easily using a formula,
[tex]A= \pi r^2[/tex]
where [tex]r[/tex] is the radius of the circle
The formula for the area of the circle is,
[tex]A=\pi r^2[/tex]
Part(a):
Given,
Radius([tex]r[/tex])=4 cm
So, the area is [tex]f(r)=f(4)[/tex]
Part(b):
Given,
[tex]r=10.91\\r=10.9[/tex]
The difference in area is,
[tex]f(10.91)-f(10.9)[/tex]
Part(c):
Area of 5 circles are,
[tex]5 f(r)=5 f(12.7)[/tex]
Part(d):
The area of the larger circle is,
Area of the circle of radius [tex]28+59 =f(28)+59[/tex]
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Can u guys Pls help:((((
Answer: angle 8 = 118 degrees
Step-by-step explanation:
The sum of the angles on a straight line is 180 degrees. This means that
angle 1 + angle 3 = 180 degrees
Therefore,
118 + angle 3 = 180 degrees
Subtracting 118 from the left hand side and the right hand side of the equation, it becomes
118 - 118 + angle 3 = 180 - 118
Angle 3 = 62 degrees
Since line d is parallel to line e, then angle 3 = angle 6 because they are alternate angles. Therefore,
Angle 6 = 62 degrees
Since the sum of the angles in a straight line is 180 degrees,
angle 8 = 180 - angle 6
angle 8 = 180 - 62 = 118 degrees
A recent survey estimated that 19 percent of all people living in a certain region regularly use sunscreen when going outdoors. The margin of error for the estimate was 1 percentage point. Based on the estimate and the margin of error, which is an appropriate conclusion?
Final answer:
The appropriate conclusion from the survey is that the true percentage of all people who regularly use sunscreen in the region is estimated to be between 18% and 20%, considering the margin of error of 1 percentage point.
Explanation:
Based on the estimate and the margin of error, an appropriate conclusion is that it can be said with a certain level of confidence, usually 95%, that the true percentage of all people living in that region who regularly use sunscreen when going outdoors is between 18% and 20%. The margin of error gives a range around the estimate to account for the sampling error, and it implies that the actual value in the population should fall within this range. This helps to understand the precision of the survey result and allows for the natural variability that comes from the fact that not every individual in the region was surveyed.
The variability also depends on the size of the sample, which relates to the confidence interval. For example, smaller samples tend to have larger margins of error, while larger samples tend to lead to smaller margins of error and thus, more precise estimates of the population parameter.
The approximate heights of two of the world's tallest mountains are given. Determine which is the taller mountain and by how many meters. Round to the nearest meter. (1 in equals 2.54 cm; 1 ft equals 30.48 cm; 1 yd almost equals 0.9144 m; 1 mi almost equals 1.6 km1 in = 2.54 cm; 1 ft = 30.48 cm; 1 yd ≈ 0.9144 m; 1 mi ≈ 1.6 km) Lhotse: 8516 meters and Ngadi Chuli: 25,866 feet
Answer:
Height of Lhotse mountain is greater than Ngadi Chuli mountain.
Height of Lhotse mountain is 632.0432 meter more than height of Ngadi Chuli mountain.
Step-by-step explanation:
Height of Lhotse mountain = 8516 meters
Height of Ngadi Chuli mountain = 25,866 feet
1 ft = 30.48 cm
[tex]25,866 feet =25,866\times 30.48 m=788,395.68 cm[/tex]
1 cm = 0.01 m
[tex]788,395.68 cm=788,395.68\times 0.01 m=7883.9568 m[/tex]
8516 meters > 7883.9568 m
Height of Lhotse mountain is greater than Ngadi Chuli mountain.
Difference in their height :
8516 meters - 7883.9568 m = 632.0432 m
Height of Lhotse mountain is 632.0432 meter more than height of Ngadi Chuli mountain.
The height of Ngadi Chuli is approximately 7871 meters, while the height of Lhotse is 8516 meters. Therefore, Lhotse is the taller mountain and is about 645 meters taller than Ngadi Chuli.
Explanation:The height of Ngadi Chuli is given in feet, so we must first convert that to meters using the conversion factor 1 ft = 30.48 cm = 0.3048 m. Multiplying 25,866 feet by 0.3048 m/ft gives us an approximate height of 7871 meters for Ngadi Chuli.
Lhotse is given to be 8516 meters tall. Therefore, by comparing these two heights, we can determine that Lhotse is the taller mountain.
The difference in height is found by subtracting the height of Ngadi Chuli from that of Lhotse: 8516 m - 7871 m = 645 m. So, Lhotse is approximately 645 meters taller than Ngadi Chuli.
Learn more about Comparison of Heights here:https://brainly.com/question/31956811
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