A ball is launched from 8 yards off the ground and travels in parabolic motion, landing in a net 80 yards away and also 8 yards off the ground. A wall lies 75% of the way down the path, which the ball cleared by 13 yards.


If the ball’s maximum height during its flight was 80 yards, how many yards tall is the wall?

Answers

Answer 1

Answer:

The answer to this question is the wall is 45.95 yards tall

Step-by-step explanation:

To solve this, we list out the given variables and the unknowns thus

Height of ball at launch = 8 yards

Distance of net from the ball = 80 yards

Distance of the wall down the path = 75%

Maximum height of the ball= 80 yards

equation of Motion of the ball = parabolic motion =

v² = u² - 2gS

S = 80 - 8 = 72 yards

at maximum height v = 0 thus u² = 2×9.81×72 =1412.64

u = 37.59 m/s

also v = u - gt and again at max height v = 0

Therefore 37.59 = 9.81×t or t = 3.83 s

If the motion of the ball is free of obstruction then time of flight before the ball just reaches the 8 yards off the ground = 3.83×2 = 7.66 seconds

Taking the initial velocity as zero at maximum height and from the equation

S = ut + 0.5×gt² we get, where S is the heigt of the ball from touching the actual field ground which is 80 yards we have

80 = 0.5×9.81×t²

so that t² = 2×80÷9.81 = 16.31 or t = 4.04s

Therefore the total time of flight = 4.04 + 3.83 = 7.87 seconds

if the ball is considered as having a constant horizontal velocity, therefore

at 75% of the way the time it took will be 0.75×7.87 = 5.9 seconds

However time it took  the  ball to reach maximum height and then starts descent = 3.83s, and the time at which the ball is directly over the wall = 2.07 seconds on the second half just after reaching mximum height

Thus at 2.07 seconds the distance trvelled from the maximum height is

S = ut +0.5gt² as before where u = 0

hence S = 0.5×9.81×2.07² = 21.05 yards or (80 -21.05) yards off the ground =  58.95 yards

As stated in the question, the ball cleared the wall by 13 yards therefore the height of the wall is 58.95 - 13 = 45.95 yards


Related Questions

Consider the reaction 2x2y2+z2⇌2x2y2z which has a rate law of rate= k[x2y2][z2] select a possible mechanism for the reaction.

Answers

Final answer:

The question is about identifying a reaction mechanism based on the provided rate law, which is derived from the reactant concentrations. A likely mechanism is a single-step process where the reactants come together to form the product, mirroring the rate law's implication that reactant concentration directly influences the reaction rate.

Explanation:

The student is asking about the mechanism of a reaction and its rate law. In chemistry, the rate law expresses the relationship among the reaction rate, the reaction mechanism, and the concentrations of the reactants.

The provided rate law is rate = k[x2y2][z2], which suggests that the reaction is first order with respect to both x2y2 and z2. A plausible mechanism for this reaction would involve a single step where one molecule of each reactant comes together to form the product, 2x2y2z.

In a single-step mechanism, the rate law is derived directly from the stoichiometry of the reactants in the balanced chemical equation. Since the rate law matches the stoichiometry of the reactants, it is likely that this could represent an elementary reaction, given that the stoichiometry and the rate law coincide.

The direct relationship implied by the rate law between the concentration of the reactants and the reaction rate can be explained by the likelihood of reactant particles colliding and reacting being greater with increased concentrations, a concept fundamental in kinetics.

Each chef at "Sushi Emperor" prepares 151515 regular rolls and 202020 vegetarian rolls daily. On Tuesday, each customer ate 222 regular rolls and 333 vegetarian rolls. By the end of the day, 444 regular rolls and 111 vegetarian roll remained uneaten.

Answers

Question:

Each chef at "sushi emperor" prepares 15 regular rolls and 20 vegetarian rolls daily. On tuesday, each customer ate 2 regular rolls & 3 vegetarian rolls. by the end of the day, 4 regular rolls & 1 vegetarian roll remained uneating. how many chefs were on tuesday ? and how many customers were they ?

Answer:

There were 2 chefs and 13 customers on tuesday

Solution:

Let x be the number of chefs at Sushi Emperor and y be the number of customers on Tuesday.

From given,

Each chef prepares 15 regular rolls and 20 vegetarian rolls daily

If each chef prepares 15 regular rolls, then x chefs prepare 15x regular rolls

If each customer ate 2 regular rolls, then y customers ate 2y regular rolls

By the end of the day, 4 regular roll remained un eating

Therefore,

15x - 2y = 4 --------- eqn 1

If each chef prepares 20 vegetarian rolls, then x chefs prepare 20x vegetarian rolls

If each customer ate 3 vegetarian rolls, then y customers ate 3y vegetarian rolls

By the end of the day, 1 vegetarian roll remained uneating

Therefore,

20x - 3y = 1 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

45x - 6y = 12 ------- eqn 3

Multiply eqn 2 by 2

40x - 6y = 2 ------- eqn 4

Subtract eqn 4 from eqn 3

45x - 6y = 12

40x - 6y = 2

( - ) --------------

5x = 10

x = 2

Substitute x = 2 in eqn 1

20(2) - 3y = 1

40 - 3y = 1

3y = 39

y = 13

Thus there were 2 chefs and 13 customers

Statistics can be referred to as numerical facts. In a broader sense, statistics is the field of study dealing with the collection, analysis, presentation and interpretation of data. a. True b. False

Answers

Answer:

True

Step-by-step explanation:

Statistics is indeed a procedure consists of collection, presentation, analysis and presentation of the data. Statistics is widely used in every field of life. For example we want to assess the performance of students. For this purpose we choose a sample of students and ask about their grading. This is the procedure of collection of data. Then this data can be presented in tabular form or graphical form and this stage is known as presentation of the data. Then we evaluate their average and this procedure is known as analysis of data. Then according to average we make statement about performance of students and this stage is interpretation of the data.

please help with a, b, and c. thank you!:)

Answers

Answer:

The answer to your question is below

Step-by-step explanation:

a) The intervals in which the graph is decreasing are the right section of the first parabola, the left section of the second parabola and also the right section of the third parabola.

               (9, 11) U (14.5, 17) U (21, 27)

b) There are only two intervals in which the graph is increasing

                (1, 9) U (17, 21)

c) During the time the graph is increasing, Andre is getting away from his origin.

​At a college, the cost of tuition increased by 10%. Let b represent the former cost of tuition. Use the expression b+0.10b for the new cost of tuition.

Answers

Question is Incomplete,Complete question is given below;

At a college, the cost of tuition increased by 10%. Let b be the former cost of tuition. Use the expression b + 0.10b for the new cost of tuition.

a)  Write an equivalent expression by combining like terms.

b)  What does your equivalent expression tell you about how to find the new cost of tuition?

Answer:

a. The equivalent expression is [tex]1.1b[/tex].

b. The new cost of tuition is 1.1 times the former cost of tuition.

Step-by-step explanation:

Given:

Former cost of tuition = [tex]b[/tex]

the cost of tuition increased by 10%.

New cost of tuition = [tex]b+0.10b[/tex]

Solving for part a.

we need to find the equivalent expression by combining the like terms we get;

Now Combining the like terms we get;

new cost of tuition = [tex]b(1+0.1) = 1.1b[/tex]

Hence The equivalent expression is [tex]1.1b[/tex].

Solving for part b.

we need to to say about equivalent expression about how to find the new cost of tuition.

Solution:

new cost of tuition = [tex]1.1b[/tex]

So we can say that.

The new cost of tuition is 1.1 times the former cost of tuition.

If circumstances are less than desirable or if something seems suspicious or amiss, approach the vehicle form the right-hand or passenger side, especially when:________

Answers

Answer:

Only one person is in the stopped vehicle

Step-by-step explanation:

The only contents of a container are 4 blue disks and 8 green disks. If 3 disks are selected one after the other, and at random and without replacement from the container, what is the probability that 1 of the disks selected is blue, and 2 of the disks selected are green?A. 21/55
B. 28/55
C. 34/55
D. 5/8
E. 139/220

Answers

Answer: B.  [tex]\dfrac{28}{55}[/tex] .

Step-by-step explanation:

Given : Number of blue disks =4

Number of green disks = 8

Total disks = 12

Total number of combinations of drawing any 3 disks from 12 = [tex]^{12}C_3[/tex]

Number of combinations of drawing 1 blue and 2 green disks = [tex]^{4}C_1\times^{8}C_2[/tex]

Now , the probability that 1 of the disks selected is blue, and 2 of the disks selected are green will be :

[tex]\dfrac{^{4}C_1\times^{8}C_2}{^{12}C_3}\\\\=\dfrac{4\times\dfrac{8!}{2!6!}}{\dfrac{12!}{3!9!}}\\\\=\dfrac{4\times28}{220}\\\\=\dfrac{28}{55}[/tex]

Hence, the correct answer is B.  [tex]\dfrac{28}{55}[/tex] .

Julia earns $6 an hour babysitting and earns $5 an hour walking dogs. She earned $43 after working a total of 8 hours at her two jobs. Complete the system of equations below to represent the situation. Let b= the number of hours that Julia babysits and d= the number of hours she walks dogs. _+_=8 _+_=43

Answers

Answer: the equations are

b + d = 8

6x + 5y = 43

Step-by-step explanation:

Let b represent the number of hours that Julia babysits.

Let d represent the number of hours she walks dogs.

Julia worked for a total of 8 hours babysitting and walking the dogs.. This means that

b + d = 8

Julia earns $6 an hour babysitting and earns $5 an hour walking dogs. She earned a total of $43 after working a total of 8 hours at her two jobs. This means that

6x + 5y = 43

A Ferris wheel is 50 meters in diameter and boarded from a platform that is 4 meters above the ground. The six o'clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 4 minutes. How many minutes of the ride are spent higher than 40 meters above the ground?

Answers

Final answer:

To calculate the time spent above 40 meters on a Ferris wheel, we analyze the wheel's structure and use trigonometry to find the proportional time of the ride corresponding to the arc above the 40-meter mark.

Explanation:

Calculating Time Spent Above 40 meters on a Ferris Wheel

To determine how many minutes of the ride on the Ferris wheel are spent higher than 40 meters above the ground, we need first to understand the wheel's structure and motion. Given that the Ferris wheel has a diameter of 50 meters and is boarded from a platform 4 meters above the ground, we can calculate the highest and lowest points riders will reach during the ride. The highest point of the wheel will be 50 meters (the radius) plus 4 meters (the platform height), totaling 54 meters. The lowest point will be 4 meters (platform height) above the ground since the diameter is equal to twice the radius and the wheel's lowest point touches the platform level.

Because riders want to be above 40 meters, we're interested in the segment of the ride where they are between 40 meters and the maximum of 54 meters above the ground. This range covers a portion of the wheel's circumference. If the wheel's highest point is at 12 o'clock and the loading platform is at 6 o'clock, then the 40-meter height will be somewhere between 6 o'clock and 12 o'clock.

Using the fact that the Ferris wheel completes one revolution in 4 minutes, we can find the time spent over 40 meters by calculating the angle θ that corresponds to the arc between 40 meters and 54 meters above the ground. The 40-meter height will fall at the point where the vertical distance from the top of the wheel equals the wheel's radius minus 40 meters. Using this, we can use trigonometry to find θ, and then convert this angle to a proportion of the full revolution time to determine the time spent on this segment of the ride.

4 Erin and Devon are playing a game. Erin has 42 points. If Devon had 14 more points, he'd have double the points Erin has. How many points does Devon have?

Answers

Final answer:

The question is a mathematical problem where we find that Devon has 70 points after setting up and solving an algebraic equation based on the conditions given.

Explanation:

The student's question revolves around a Mathematical problem concerning the points scored by two players, Erin and Devon, in a game. Erin has 42 points, and the question provides a condition that if Devon had 14 more points, he would have double the points Erin has. This scenario can be translated into an algebraic equation to solve for the number of points Devon currently has.

Let's denote the current number of points Devon has as D. According to the problem, if Devon had 14 more points, his total would be D + 14. We are also told that this hypothetical total would be double the points Erin has, which is 42. Therefore, we can write the equation as:

D + 14 = 2 × 42

By solving this equation, we can find out how many points Devon has:

D + 14 = 84  (since 2 × 42 equals 84)D = 84 - 14D = 70

Devon currently has 70 points.

Erin has 42 points. Devon has 70 points. If he had 14 more, he'd have double Erin's points.

let's break it down step by step:

Given:

- Erin has 42 points.

- If Devon had 14 more points, he'd have double the points Erin has.

Let's denote Devon's points as [tex]\( D \).[/tex]

According to the given information, if Devon had 14 more points, he'd have double the points Erin has. So, mathematically, we can represent Devon's points as [tex]\( 2 \times 42 \)[/tex] when we add those 14 points.

So, we can write the equation:

[tex]\[ D + 14 = 2 \times 42 \][/tex]

Now, let's solve for [tex]\( D \):[/tex]

[tex]\[ D + 14 = 84 \][/tex]

Subtract 14 from both sides of the equation:

[tex]\[ D = 84 - 14 \]\[ D = 70 \][/tex]

So, Devon currently has 70 points.

Assume that the weight of two year old babies have distribution that is approximately normal with a mean of 29 pounds and a standard deviation of 3 pounds. what weight of two year old baby corresponds to 10th percentile?

Answers

Answer:

25.15 ponds is the weight of two year old baby corresponds to 10th percentile.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 29 pounds

Standard Deviation, σ = 3 pounds

We are given that the distribution of weight of two year old babies is a bell shaped distribution that is a normal distribution.

Formula:

[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]

We have to find the value of x such that the probability is 0.10

P(X < x)  

[tex]P( X < x) = P( z < \displaystyle\frac{x - 29}{3})=0.10[/tex]  

Calculation the value from standard normal z table, we have,  

[tex]P(z < -1.282) = 0.10[/tex]

[tex]\displaystyle\dfrac{x - 29}{3} = -1.282\\x = 25.154 \approx 25.15[/tex]

Thus, 25.15 ponds is the weight of two year old baby corresponds to 10th percentile.

Significance tests A test of H0: p = 0.65 against Ha: p < 0.65 has test statistic z = −1.78. (a) What conclusion would you draw at the 5% significance level? At the 1% level? (b) If the alternative hypothesis were Ha: p ≠ 0.65, what conclusion would you draw at the 5% significance level? At the 1% level?

Answers

Answer:

(a) At 5% significance level, reject H0

At 1% significance level, reject H0

(b) At 5% significance level, fail to reject H0

At 1% significance level, fail to reject H0

Step-by-step explanation:

(a) The test is a one tailed test

At 5% significance level, the critical value is 1.645

Conclusion: Reject H0 because the test statistic -1.78 is less than the critical value 1.645

At 1% significance level, the critical value is 2.326

Conclusion: Reject H0 because the test statistic -1.78 is less than the critical value 2.326

(b) The test is a two tailed test

At 5% significance level, the critical value is 1.96. The region of no rejection of H0 lies between -1.96 and 1.96

Conclusion: Fail to reject H0 because the test statistic -1.78 falls within -1.96 and 1.96

At 1% significance level, the critical value is 2.576. The region of no rejection of H0 lies between -2.576 and 2.576

Conclusion: Fail to reject H0 because the test statistic falls within -2.576 and 2.576

The conclusion that can be made from an hypothesis test depends on

the significance level and p-value.

Response:

(a) The conclusion at 5% is there is statistical evidence to suggest that p < 0.65

At 1% level; fail to reject H₀: p = 0.65, there is statistical evidence to suggest that p = 0.65

(b) With Hₐ ≠ 0.65, the conclusion at the 5% significance level is that there is sufficient statistical evidence that p = 0.65

At the 1% level, fail to reject H₀: p = 0.65,

Which is the method to draw conclusion from an hypothesis test?

The null hypothesis, H₀: p = 0.65

The alternative hypothesis, Hₐ: p < 0.65

The z-score is z = -1.78, which gives;

The p-value = 0.0375

(a) The significance level is 5%

Which gives, α = 0.05

Given that the p-value is less than the significant level, we have that

there is sufficient evidence against the null hypothesis, given that the

probability that the null hypothesis is correct is less than the significant

level of 5%.

Therefore, reject H₀, p = 0.65

There is sufficient statistical evidence to suggest that the the p is less than 0.65, (p < 0.65)

However, at 1% significant level, α = 0.01, and the p-value, p = 0.0375 is

larger than the significance level.

Therefore, we fail to reject the null hypothesis and there is sufficient statistical evidence to suggest that p = 0.65

(b) Hₐ: p ≠ 0.65

We have;

[tex]\alpha = \dfrac{5 \%}{2} = 2.5 \% = \mathbf{0.025}[/tex]

Which gives;

The p-value (0.0375) is larger than the significant level, therefore, we

fail to reject the null hypothesis.

There is sufficient statistical evidence to suggest that p = 0.65

At the 1% level of significance, we have;

[tex]\alpha = \dfrac{1 \%}{2} = 0.5 \% = 0.005[/tex]

Which gives;

The p-value at z = -1.78 (p = 0.0375) is larger than the significant level

Therefore;

There is sufficient evidence to suggest that p = 0.65

Learn more about hypothesis testing here:

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Calculate the average rate of change of the given function f over the intervals [a, a + h] where h = 1, 0.1, 0.01, 0.001, and 0.0001. (Technology is recommended for the cases h = 0.01, 0.001, and 0.0001.) HINT [See Example 4.] (Round your answers to five decimal places.) f(x) = 3 x ; a = 7

Answers

Step-by-step explanation:

average rate of change of function is given by :

[tex]f= (f(a+h)-f(a))/h[/tex]

where

[tex]f(x)=3x[/tex]

and a= 7

so inserting values is formula for h=1

[tex]f=(f(7+1)-f(7))/1[/tex]

[tex]f= f(8)-f(7)= 3(8)-3(7)=24-21=3[/tex]

now for h= 0.1

[tex]f=(f(7+0.1)-f(7))/0.1=(f(7.1)-f(7))/0.1=(3(7.1)-3(7))/0.1[/tex]

[tex]f=3[/tex]

similarly average rate of change of given function is same for all given step sizes.

Final answer:

The question involved calculating the average rate of change of the function f(x) = 3x over various intervals, showing that the rate of change is constant and equals 3 for all given values of h.

Explanation:

The question asks to calculate the average rate of change of the function f(x) = 3x over the intervals [a, a + h] for values of h = 1, 0.1, 0.01, 0.001, and 0.0001, where a = 7.

The average rate of change is calculated using the formula [tex]\frac{f(a+h) - f(a)}{h}[/tex]

For each value of h, we substitute a and h into the function and use the formula to find the average rate of change.

For h = 1, the average rate of change is 3.

For h = 0.1, the average rate of change is also 3.

For h = 0.01, the average rate of change remains 3.

For h = 0.001, the average rate is again 3.

Similarly, for h = 0.0001, the average rate of change is 3.

Using technology for values of h smaller than 0.1 is recommended due to the precision required in calculations. However, for this particular function, the rate of change is constant across these intervals, simplifying the process.

Jacob bought 13 packs of gum to add to the 5 pieces he already had. He then shared all of his pieces of gum with six friends. If Jacob and his six friends each revived 27 pieces of gum, how many were in each pack

Answers

Answer:

14 gums.

Step-by-step explanation:

Given: Jacob bought 13 pack of gum

           He already had 5 piece of gum.

           He shared gum with six of his friends.

           Each one of them received 27 pieces of gum.

Lets assume the number of gums in each pack be "x".

Total number of gum= [tex]number\ of\ gum\ in\ each\ pack\times number\ of\ pack + 5[/tex]

Also gum has been shared among jacob and his 6 friends, which is 7 person.

∴ Share of each person= [tex]\frac{Total\ number\ of\ gums}{number\ of\ person}[/tex]

Now, forming equation to find number of gums in each pack.

⇒ [tex]\frac{13\times x+5}{7} = 27[/tex]

Multiplying both side by 7

⇒ [tex]13x+5= 189[/tex]

Subtracting both side by 5

⇒ [tex]13x= 189-5[/tex]

⇒[tex]13x= 184[/tex]

Dividing both side by 13

⇒ [tex]x= \frac{184}{13}[/tex]

∴[tex]x= 14.15 \approx 14\ gum[/tex]

Hence, each pack have 14 gums.

Your parents are purchasing a mobile home for $89,000. The sales tax is 4.2%, they make a $3,000 down payment, and they have an average credit score. How much is the principal balance after applying their first month’s payment of $925.67?

Answers

Answer:

$88812.33

Step-by-step explanation:

Principal = $89,000

But there's a sales tax of 4.2%

Tax = (4.2 / 100) * 89000 = $3738

Total cost of the mobile house = $89000 + $3738 = $92,738

However, they made a down payment of $3000

Balance after down payment = $92,738 - $3000 = $89,738

They've also paid the first monthly payment of $925.67

Balance after first monthly payment =

$89,738 - $925.67 = $88,812.33

The principal balance after applying there first monthly payment is $88,812.33

Final answer:

The principal balance, after applying the first month's payment of $925.67 to an initial loan of $89,738 for a mobile home, is $88,812.33.

Explanation:

To calculate the principal balance after the first month’s payment, start by adding the initial price of the mobile home and the sales tax. The sales tax is 4.2% (or 0.042) of $89,000, which comes out to $3,738. Then, subtract the down payment from the sum to get the initial loan amount. So, $89,000 + $3,738 - $3,000 equals $89,738. After applying the first month’s payment of $925.67, subtract that amount from the initial loan, leaving a principal balance of $88,812.33.

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Help asap, thank you! :) 2 questions, multiplying monomials.

Answers

Answer:

Correct answer choices are [tex]27x^{2}[/tex] and [tex]657 cm^{2}[/tex]

Step-by-step explanation:

We are able to arrive at these answers through basic equation used to calculate area of an triangle and monomial laws

Does the graph represent a function? Why or Why Not

Answers

Answer:

not a function - it does not pass the vertical line test.

Step-by-step explanation:

Not a function, doesn't pss the vertical line test.

Home Away, a nongovernmental not-for-profit organization, provides food and shelter to victims of natural disasters. Home Away received a $15,000 gift with the stipulation that the funds be used to buy beds. In which net asset class should Home Away report the contribution?

Answers

Answer:

Home away should record the contribution to a Net assets with donor restriction

Step-by-step explanation

A Net asset with donor restriction is the part of net assets of a not- for - profit making organisation  that is subject to donor-imposed restrictions.  

The stipulation that the fund of $15,000 should be used to buy beds automatically makes it to be classified as a Net assets with donor restriction  item.

I have some geometric sequence questions, will give 5 points for every answer and will give Brainliest!

1. List the first four terms of a geometric sequence with t5 = 24 and t6 = 3
2. List the first four terms of a geometric sequence with t1 = 4 and tn = -3tn-1
3. Find the three geometric means between 1/2 and 8

Thank you so much!!

Answers

Answer:

Step-by-step explanation:

1) since the sixth term is 3 and the fifth term 24, the common ratio would be 3/24 = 1/8

The formula for finding the nth term of a geometric sequence is

Tn = ar^(n - 1)

If t6 = 3,r = 1/8, then

3 = a × 1/8^(6 - 1) = a × (1/8)^5

a = 3/(0.125)^5 = 98304

The first term is 98304.

Second term is 98304 × 1/8 = 12288

Third term is 12288 × 1/8 = 1536

Third term is 1536 × 1/8 = 192

2) t1 = 4

t2 = - 3t(2- 1) = - 3t1 = - 3 × 4 = - 12

t3 = - 3t(3- 1) = - 3t2 = - 3 × - 12 = 36

t4 = - 3t(4- 1) = - 3t3 = - 3 × 36 = - 108

3) let the numbers be t2,t3 and t4

The sequence becomes

1/2, t2,t3, t4,8

The formula for finding the nth term of a geometric sequence is

Tn = ar^(n - 1)

8 = 1/2 × r^(5 - 1)

8 = 1/2 × r^4

16 = r^4

2^4 = r^4

r = 2

t2 = 1/2 × 2 = 1

t3 = 1 × 2 = 2

t4 = 2 × 2 = 4

PLEASE HELP PLEASE PLEASE DUE TONIGHT AAA

Answers

Answer:

Measurement of all angle= [tex]76.79\º+102.66\º+15.35\º+265.16\º= 360\º[/tex]

Step-by-step explanation:

Given angles are [tex]x\º, (\frac{5x}{9} +60)\º, (\frac{x}{5} )\º, (4x-142)\º[/tex]

The given is a quardilateral.

We know the sum of all angles of quardilaterals is 360º

∴ [tex]x\º+ (\frac{5x}{9} +60)\º+ (\frac{x}{5} )\º+(4x-142)\º= 360\º[/tex]

Now, solving the equation to find value of x.

⇒ [tex]x\º+ (\frac{5x}{9} +60)\º+ (\frac{x}{5} )\º+(4x-142)\º= 360\º[/tex]

Opening parenthesis.

⇒ [tex]x\º+ \frac{5x}{9} +60\º+ \frac{x}{5} \º+4x-142\º= 360\º[/tex]

⇒ [tex]5x\º+ \frac{5x}{9} + \frac{x}{5} \º-82\º= 360\º[/tex]

Adding both side by 82

⇒ [tex]5x+ \frac{5x}{9} + \frac{x}{5} = 442[/tex]

Taking LCD 45

⇒ [tex]\frac{45\times 5x+ 5\times 5x+9x}{45} = 442[/tex]

Multiplying both side by 45

⇒ [tex]225x+25x+9x= 19890[/tex]

⇒[tex]259x= 19890[/tex]

Dividing both side by 259

⇒[tex]x= \frac{19890}{259}[/tex]

∴[tex]x= 76.79\º[/tex]

Next subtituting the value of x to find measurement of other interior angle.

[tex]x\º, (\frac{5x}{9} +60)\º, (\frac{x}{5} )\º, (4x-142)\º[/tex]

2. [tex](\frac{5x}{9} +60)\º[/tex]

= [tex]\frac{5\times 76.79}{9} +60= 42.66+ 60[/tex]

= [tex]102.66\º[/tex]

3. [tex](\frac{x}{5} )\º[/tex]

= [tex](\frac{76.79}{5} )\º= 15.35\º[/tex]

4. [tex](4x-142)\º[/tex]

= [tex]4\times 76.79- 42= 307.16-42[/tex]

= [tex]265.16\º[/tex]

What is the ratio cosC?

Answers

Answer: 61.9°

Approximately: 62°

Step-by-step explanation:

Using Pythagoras

(AC)^2 = 17^2 - 15^2

= 289 - 225

√AC = √64

AC = 8

Cos C = Adj/ Hyp

Cos C = 8/17

Cos C = 0.4706

Inverse of Cos C

C = 61.93°

Approximately: 62°

A furniture salesperson earns 4.5% commission on every piece of furniture sold. The salesperson sells a sofa for $1000 and a chair for $200. What commission does the salesperson earn?

Answers

Answer: the salesperson earns $54 as commission.

Step-by-step explanation:

A furniture salesperson earns 4.5% commission on every piece of furniture sold. The salesperson sells a sofa for $1000. This means that the commission that he earned from the sale of the sofa is

4.5/100 × 1000 = 0.045 × 1000 = $45

The salesperson also sold a chair for $200. This means that the commission that he earned from the sale of the chair is

4.5/100 × 200 = 0.045 × 200 = $9

The total commission that the salesperson earns is

45 + 9 = $54

Write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. When the code exits the loop it should print the number of consecutive duplicates encountered. In the above case, that value would be 3.

Answers

To solve the programming task, you would create a loop to read integers, use a counter to track consecutive duplicates and print the count after a negative number is entered to end the input.

The student's question involves writing a piece of code that reads a sequence of non-negative integers, ends the input with a negative integer, and reports the number of consecutive duplicate values entered before the negative integer is encountered. This is a programming task that typically involves a loop and a counter.

To address this question, you would write a loop that continues to accept input until a negative number is entered. Inside the loop, you would use a counter to keep track of the number of consecutive duplicates. Here is a pseudocode example:

Initialize the previous Value to None (or some value that won't occur in the sequence).

Initialize the count Of Duplicates to 0.

Start a loop that reads integers until a negative number is encountered.

Inside the loop, compare the current number to the previous Value.

If they are the same, increment the count Of Duplicates by 1.

Set the previous Value to the current number before the next iteration.

Outside the loop, print count Of Duplicates.

The counter pattern is a fundamental concept in programming that is used to tally occurrences within iteration structures like loops.

hello loves!! I've been stuck on this question for like 2 hours lol! i need some help, ill give 100 points :)

Answers

Answer:

61.12 units²

Step-by-step explanation:

(½ × pi × r²) + (½ × b × h)

½ [(3.14 × 4²) + (8 ×9)]

½(122.24)

61.12 units²

Answer:

61.13 units squared

Step-by-step explanation:

This figure is composed of a semicircle and a triangle. Let's find these areas separately:

1) SEMICIRCLE:

The area of a semicircle is: [tex]A=\frac{\pi r^2}{2}[/tex] , where r is the radius (which is the distance from the center to a point on the circle). In this case, the radius of the circle is 4. So, we have:

[tex]A=\frac{\pi *4^2}{2} =\frac{16\pi }{2} =8\pi[/tex] ≈ 25.13 units squared

2) TRIANGLE:

The area of a triangle is: [tex]A=\frac{bh}{2}[/tex] , where b is the base and h is the height. Here, the base is 8 (b = 8) and the height is 9 (h = 9). So, we have:

[tex]A=\frac{8*9}{2} =\frac{72}{2} =36[/tex] units squared

Finally, we add these two areas together:

25.13 + 36 = 61.13 units squared.

Hope this helps!

Which is the graph of f (x) = 4 (1/2) Superscript x?

Answers

Answer:

Option (2) is correct graph.

Step-by-step explanation:

Given:

The function to graph is given as:

[tex]f(x)=4(\frac{1}{2})^x[/tex]

Now, the above function is an exponential function of the form [tex]f(x)=ka^x[/tex]

Where, 'k' and 'a' are constants.

The range of an exponential function is always greater than 0.

The domain is all real numbers.

Now, for graphing it, we need to find some points on it and its end behaviour.

Now, for x = 0, the function value is given as:

[tex]f(0)=4(\frac{1}{2})^0=4[/tex]

So, (0, 4) is a point on the graph.

Now, for x = 1, the function value is given as:

[tex]f(1)=4(\frac{1}{2})^1=4\times\frac{1}{2}=2[/tex]

So, (1, 2) is another point on the graph.

Now, for x = 2, the function value is given as:

[tex]f(2)=4(\frac{1}{2})^2=4\times\frac{1}{4}=1[/tex]

So, (2, 1) is another point on the graph.

Now, as 'x' tends to ∞, the function value tends to:

[tex]f(x\to\infty)=4\cdot\frac{1}{2}^{\infty}=\frac{4}{\infty}=0[/tex]

So, as

[tex]x\to\infty,f(x)\to0\\\\x\to-\infty,f(x)\to\infty[/tex]

Now, from among all the options, only option (2) fulfills all the conditions given above.

So, option (2) is correct graph.

Answer:

option 2

Step-by-step explanation:

Sixty-seven biscuits are to be fed to 10 pets; each pet is either a cat or a dog. Each dog is to get seven biscuits, and each cat is to get six. How many dogs are there?

Answers

Answer:

There are 7 dogs.

Step-by-step explanation:

7 (dogs) x 7 (biscuits) = 49

3 (cats) x 6 (biscuits) = 18

49 + 18 = 67

Which two-dimensional cross sections are squares?

Select all that apply.

a cross-section that is perpendicular to the base of a cube
a cross-section that is parallel to the base of a triangular pyramid
a cross-section that is parallel to the base of a cylinder
a cross section through the center of a sphere
a cross-section that is perpendicular to the base of a cylinder whose base diameter and height are the same

Answers

Answer:

A cross-section that is perpendicular to the base of a cube.

A cross-section that is perpendicular to the base of a cylinder whose base diameter and height are the same.

Step-by-step explanation:

We have to select from options that the two-dimensional cross section are squares.

The correct options are :

A cross-section that is perpendicular to the base of a cube.

A cross-section that is perpendicular to the base of a cylinder whose base diameter and height are the same.  

In both the cases the length and the width of the section are equal. (Answer)

Final answer:

Among the given options, only the cross-section that is perpendicular to the base of a cube is guaranteed to be a square. The other options will generally result in different shapes, such as triangles or circles.

Explanation:

The question asks which two-dimensional cross sections are squares. To find the answer, we must consider the shape of the object and the orientation of the cross section.

A cross-section that is perpendicular to the base of a cube. If we cut a cube with a plane perpendicular to one of its faces, the cross section is the same shape as the face, which is a square.A cross-section that is parallel to the base of a triangular pyramid would not be a square because the base itself is a triangle.A cross-section that is parallel to the base of a cylinder would be a circle, as it would be cut along the cylinder's circular base.A cross section through the center of a sphere would also result in a circle, assuming the cut goes through the sphere's diameter.A cross-section that is perpendicular to the base of a cylinder whose base diameter and height are the same, also known as a right circular cylinder, would only result in a square if the cylinder is cut along a plane that is at 45 degrees to the base, which is not the typical perpendicular cut, so typically it would not be a square.

At first glance, only the cross-section perpendicular to the base of a cube is a square. However, depending on specific conditions not typically met by the listed shapes, other cross-sections can appear square-shaped. Therefore, generally, the answer is a cross-section that is perpendicular to the base of a cube will be square.

Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin. in the past, 5% of the parts supplied by A and 9% of the parts supplied by B have been defective. A supplies four times as many parts as B. Suppose you reach into the bin and select a part, and find it is nondetective. What is the probability that it was supplied by A

Answers

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let A = a part is supplied by supplier A, B = a part is supplied by supplier B and D = a part is defective.

Given:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event A and B is:

[tex]P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20[/tex]

Compute the probability of selecting a defective product:

[tex]P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058[/tex]

The probability of selecting a non-defective part provided by supplier A is:

[tex]P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807[/tex]

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

The required probability of selecting a non-defective part provided by supplier A is 0.807.

Let,

A part is supplied by supplier A,

B part is supplied by supplier B,

And D = a part is defective.

Given:

P ([tex]\frac{D}{A}[/tex]) =5% = 0.05,

P([tex]\frac{D}{B}[/tex]) = 9% =  0.09

A supplies four times as many parts as B, .

Then, n (A) = 4 and n (B) = 1.

The probability of event A and B is:

Probability of event P(A) = [tex]\frac{n (A)}{n (A) + n(B)}[/tex] = [tex]\frac{4}{4+1}[/tex]

                                 P(A) = [tex]\frac{4}{5}[/tex]

And Probability of Event P(B) = [tex]\frac{n (B )}{n (A) + n(B)} = \frac{1}{4+1}[/tex]

                                        P(B) = [tex]\frac{1}{5}[/tex]

Then , the probability of selecting a defective product:

P(D) = [tex]P(\frac{D}{A}) P(A) + P(\frac{D}{B}) P(B)[/tex]

P(D) = 0.50×0.80 + 0.09×0.20

P(D) = 0.058

The probability of selecting a non-defective part provided by supplier A is

[tex]P(\frac{A}{D'} )= \frac{P(D'(A)) . P(A)}{P(D')} \\\\[/tex]

          = [tex]\frac{1- P(D(A)). P(A)}{1-P(A)} \\\\\frac{(1-0.05) . 0.80}{1- 0.05} \\\\[/tex]

          = 0.807

Hence, the probability of selecting a non-defective part provided by supplier A is 0.807.

For more information about Probability click the live given below.

https://brainly.com/question/23044118

In 1995, Orlando, Florida was about 175,000. At that same time , the population was growing at a rate of about 2000 per years, write an equation in slope - intercept form to find orlando's population for any year

Answers

Answer:

Y=2000x+175,000

Step-by-step explanation:

y=mx+b so your M will be your 2000 and your x is gonna be years, and your b is gonna be 175,000

A tower that is 106 feet tall casts a shadow 141 feet long. Find the angle of elevation of the sun to the nearest degree.

Answers

Final answer:

To determine the angle of elevation of the sun, calculate the inverse tangent (arctan) of the height of the tower (106 feet) divided by the length of its shadow (141 feet). The angle of elevation is approximately 37 degrees to the nearest degree.

Explanation:

To find the angle of elevation of the sun given that a 106 feet tall tower casts a shadow of 141 feet long, we can use trigonometry. Specifically, the tangent of the angle, which is the ratio of the opposite side (the height of the tower) to the adjacent side (the length of the shadow).



We use the formula:

tangent of angle = opposite / adjacent

Tan(angle) = 106 / 141

Now we need to calculate the inverse tangent (arctan) of this ratio to find the angle in degrees:

Angle = arctan(106/141)

After performing this calculation with a calculator or using a trigonometric table, we find that the angle to the nearest degree is approximately 37 degrees.

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