Answer:
[tex]\Delta H=2592.825\ J[/tex]
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
[tex]\Delta H=m\times C\times \Delta T[/tex]
Where,
[tex]\Delta H[/tex] is the enthalpy change
m is the mass
C is the specific heat capacity
[tex]\Delta T[/tex] is the temperature change
Thus, given that:-
Mass of object = 36.2 g
Specific heat = 12.5 J/g°C
[tex]\Delta T=5.73\ ^0C[/tex]
So,
[tex]\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J[/tex]
[tex]\Delta H=2592.825\ J[/tex]
Answer:71.625J
Explanation:Energy(Q)=mCpT
But recall that they said heat capacity (C), not specific heat capacity(cp)....Heat capacity=Mass *cp,but the heat capacity was clearly given so the mass is irrelevant in this case.
Energy (Q)=Heat capacity*Temperature change
Energy=12.5*5.73=71.625J
If the kinetic energy of a particle is equal to twice its rest mass, what is the velocity of the particle? Determine if relativistic calculations are required?
Answer:
The velocity of the particle is 2 m/s,
Explanation:
Kinetic energy is defined as energy of the body due to its motion. It is given by :
[tex]K.E=\frac{1}{2}mv^2[/tex]
Where :
m = mass of the object
v = velocity of the object
We have , particle with mass m and its kinetic energy is twice its mass.
[tex]K.E=2m[/tex]
[tex]2m=\frac{1}{2}mv^2[/tex]
[tex]v^2=\frac{4}{1}[/tex]
[tex]v=2[/tex]
And unit of velocity are m/s , so the velocity of the particle is 2 m/s.
Final answer:
To find the velocity of a particle whose kinetic energy is twice its rest mass, we use relativistic mechanics and find that the velocity is approximately 0.943c. This indicates that relativistic effects are significant and must be considered.
Explanation:
When the kinetic energy (KE) of a particle is twice its rest mass energy (E0), relativistic calculations are needed due to the comparably large energy involved. The rest mass energy is given by the famous equation E0 = mc², where m represents the rest mass and c is the speed of light.
To find the velocity, we use the relativistic relationship between energy and velocity:
KE = (γ - 1)mc², where γ is the Lorentz factor, defined as γ = 1/ √(1 - v²/c²).
Given that KE is twice the rest mass energy (E0), it follows that:
2mc² = (γ - 1)mc²
We can cancel mc² on both sides and solve for γ:
2 = γ - 1 → γ = 3
Now, we can solve for v:
3 = 1/ √(1 - v²/c²)
√(1 - v²/c²) = 1/3
1 - v²/c² = 1/9
v²/c² = 8/9
v = c √(8/9)
v = 0.943c
Therefore, the velocity of the particle is approximately 0.943 times the speed of light, indicating that relativistic effects are indeed significant and must be taken into account.
The increasing concentration of a chemical as it moves through the links in a food chain is called ________.
Answer: Biological Magnification
Explanation:
Organisms acquire toxic substance from the environment along with nutrients and water. Some of the toxins are metabolized and excreted, but others accumulate in specific tissues, especially fat. One of the reasons accumulated toxins are particularly harmful is that the become more concentrated in successive trophic level of the food web, this is the process of biological magnification.
Magnification occurs because the biomass at any given level is produced from a must larger biomass ingested from the level below. Thus the top-level carnivores tend to be the organism most severely affected by toxic compounds in the environment.
Examples of toxins that demonstrate biology magnification are chlorinated hydrocarbons, and many pesticides.
What is the magnitude of the force required to accelerate an electron of mass 9.1×10–31 kg from rest to a speed of 2.0×107 m/s for a distance of 0.50 cm?
Answer:
[tex]3.64\times 10^{-14} N[/tex] is the magnitude of the force required to accelerate an electron of given mass.
Explanation:
Initial velocity of the electron = u
Final velocity of the electron = v = [tex]2.0\times 10^7 m/s[/tex]
Acceleration of the electron = a =?
Distance covered by electron= s = 0.50 cm = 0.005 m ( 1 cm = 0.01 m)
Using third equation of motion :
[tex]v^2-u^2=2as[/tex]
[tex](2.0\times 10^7 m/s)-0^2=2\times a\times 0.005 m[/tex]
[tex]a=4\times 10^{16} m/s^2[/tex]
Mass of an electron = [tex]m=9.1 \times 10^{-31} kg[/tex]
Force on moving electron = F
[tex]F = m\times a[/tex]
[tex]=9.1 \times 10^{-31} kg\times 4\times 10^{16} m/s^2=3.64\times 10^{-14} N[/tex]
[tex]3.64\times 10^{-14} N[/tex] is the magnitude of the force required to accelerate an electron of given mass.
The magnitude of the force required to accelerate an electron is [tex]3.64 \times 10^{-18}N[/tex]
According to Newton's second law, the formula for calculating the required force is expressed as:
F = mam is the mass of the body = [tex]9.1 \times 10^{-31} kg[/tex]a is the acceleration of the bodyGet the required acceleration;
[tex]v^2=u^2+2as\\(2.0 \times 10^7)^2=0^2+2(0.005)a\\4.0 \times 10^{14}=0.01a\\a=4.0\times 10^{12}m/s^2[/tex]
Geet the magnitude of the force required:
[tex]F=9.1\times 10^{-31} \times 4.0 \times 10^{12}\\F=36.4 \times 10^{-19}N\\F=3.64 \times 10^{-18}N[/tex]
Hence the magnitude of the force required to accelerate an electron is [tex]3.64 \times 10^{-18}N[/tex]
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Describe the differences among primitive, igneous, sedimentary, and metamorphic rock, and relate these differences to their origins.
Answer:
Rocks are the aggregate of minerals. There are three distinct categories of rocks, namely the sedimentary, metamorphic and the igneous rocks.
The sedimentary rocks are formed from the deposition, compaction, and lithification of soft sediments that are transported from one place to another by the agents such as wind, water, and ice. For example, Sandstone and Shale. The metamorphic rocks are derived from the previously existing sedimentary, igneous or other metamorphic rocks, due to the influence of extremely high pressure as well as temperature conditions. For example, Quartzite and Marble. The igneous rocks are those rocks that are formed from the cooling and crystallization of magma. For example, Granite and Diorite.All these three types of rocks are formed by different processes and their mode of origins are also different.
You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several different temperatures.
The sphere can expand or shrink to any volume without changing the pressure of the gas inside.
As a result of your experiment, you find that the volume (V) of the gas divided by its temperature (T) is always equal to 1.75.
What would the volume (V) of the gas be at a temperature of 300K? (assume the unit for volume is liters)
Show your work and answer the question with a clear statement. Show each step of your calculations for full points. After showing your calculations, answer the question with a clear statement.
Please help
Volume of the gas is 525 L.
Explanation:
It is given that the volume of the gas divided by the temperature is 1.75.
V/T = 1.75
As per the Charles law, volume is proportional to the temperature.
V ∝ T
V/T = constant
Now we have to find V, and T is given as 300 K.
So plugin the values as,
V/300 = 1.75
Rearranging the equation to get V as,
V = 1.75×300
= 525 L
On a hot sunny day, you get out of the swimming pool and sit in a metal chair, which is very hot. Would you predict that the specific heat of the metal is higher or lower than that of water? Explain.
Answer:
The specific heat capacity of the metal is lower than that of the water as explained as follows
Explanation:
The heat capacity is a measure of propensity of a given object or matter to undergo an increase or decrease in its temperature when subject a given amount of heat, in other words, for a given mass of the substance, it is the amount of heat required to be added to cause it to have a unit temperature change
The specific heat capacity of a material or substance is the amount of heat required to be supplied to raise the temperature of a unit mass of that by one degree Celsius. It is the ratio of the heat capacity of a specimen of a substance divided by the mass of the specimen
Both the water of the swimming pool, the swimmer and the metal chair are all exposed to the same amount of heat from the sun, however the heat required to raise the water temperture by one degree Celsius is higher than heat required to raise the temperature of the metal chair by one degree hence the chairs temperature is higher than the water temperature as shown in the following equation
ΔH = m₁ × C₁ × ΔT₁ = m₂ × C₂ × ΔT₂
Where ΔH = Heat or energy supplied from the sun
m₁ = mass of water in the swimming pool
C₁ = Specific heat capacity of the water in the swimming pool
ΔT₁ = Change in temperature of the swimming pool and
m₂ = mass of metal chair
C₂ = Specific heat capacity of the metal chair material
ΔT₂ = Change in temperature of the metal chair
Where ΔH is the same for both the chair and swimming pool with the chair being hotter than the swimming pool with an asumed temperature change of 1.5 times that of the swimming pool and assuming the same mass of both the swimming pool and the chair are measured we have
m₁ × C₁ × 1.5ΔT₂ = m₁ × C₂ × ΔT₂ then cancelling like terms we have
1.5C₁ = C₂
Hence the heat capacity of the swimming pool water is 1.5 times that of the metal chair
On a hot sunny day, when you sit in a metal chair and it feels very hot, it indicates that the metal has a lower specific heat than water.
Explanation:The specific heat of a material is a measure of the amount of heat energy required to raise the temperature of a given mass of the material by a certain amount. In this case, when you sit in a metal chair on a hot sunny day and it feels very hot, it indicates that the metal has a lower specific heat than that of water.
Metal is generally a good conductor of heat, which means it can rapidly transfer heat energy from the surroundings to your body when in contact. Water, on the other hand, has a higher specific heat and is a poor conductor of heat, so it takes longer to heat up and cool down.
The specific heat of metal depends on the type of metal. Different metals have different specific heat values.
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Convert using the relation ship below
Answer:
25.33125KPa
Explanation:
From the above,
1atm = 101.325KPa
0.25atm = (0.25atm x 101.325KPa) / 1atm = 25.33125KPa
Therefore, 0.25atm = 25.33125KPa
Digoxin is available in a concentration of 0.1 mg/ml. How many ml are required to administer a 75 mcg dose?
Answer : The volume required to administer a 75 mcg dose are, 0.75 mL
Explanation : Given,
Concentration of Digoxin = 0.1 mg/mL
That means, 0.1 mg of Digoxin present in 1 mL of solution.
Mass of dose = 75 mcg = 0.075 mg
Conversion used : (1 mcg = 0.001 mg)
Now we have to determine the volume required to administer a 75 mcg dose.
As, 0.1 mg of Digoxin required in 1 mL of solution
So, 0.075 mg of Digoxin required in [tex]\frac{0.075mg}{0.1mg}\times 1mL=0.75mL[/tex] of solution
Thus, the volume required to administer a 75 mcg dose are, 0.75 mL
Aluminum + oxygen yields aluminum oxide Write a balanced equation for this chemical reaction. A) Al + O → AlO B) Al + O → Al2O3 C) 2Al + 3O2 → Al2O3 D) 4Al + 3O2 → 2Al2O3
Answer:
Answer is D
Explanation:
The balanced equation for the reaction between aluminum and oxygen is: 4Al + 3O₂ -> 2Al₂O₃ (option D)
How to write balanced equation?Balanced equation can be written by ensuring that the reactants and products obtained from the reaction are balanced.
Now we can balanced the equation between aluminum and oxygen as follow:
Aluminum => AlOxygen => O₂Aluminum oxide => Al₂O₃Balanced equation =?Al + O₂ -> Al₂O₃
There are 2 atoms of O on the left side and 3 atom on the right. It can be balanced by writing 3 before O₂ and 2 before Al₂O₃ as shown below:
Al + 3O₂ -> 2Al₂O₃
There are 4 atoms of Al on the right side and 1 atom on the left. It can be balanced by writing 4 before Al as shown below:
4Al + 3O₂ -> 2Al₂O₃
Thus, the equation is balanced and the correct answer to the question is
4Al + 3O₂ -> 2Al₂O₃ (option D)
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Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1."
__H2O2 → __H2O+__O2
Answer:
2H2O2-----2H2O+O2
Explanation:
This is because theres the same number of atoms of each element on both sides
How many solutions does an equation have when the variable adds out and the final sentence is false?
Answer:
None solutionExplanation:
When the variable adds out and the final sentence is false you have arrived to a contradiction, also called absurd, meaning that the starting equality was a wrong assumption that could never be true. Thus, the equation has no solutions.
An example of such situation is this equation:
x + 3 = x + 9To solve it, you use the subtraction property of the equalities: subtract both x and 3 from both sides:
x - x = 9 - 30 = 6The variable added out and the final sentences 0 = 6 is false. That means that none value of x satisfies the original equation and it has no solutions.
Answer:
It has 0 solutions
Explanation:
What is the basic form for the names of ionic compounds containing a metal that forms more than one type of ion?
Answer:
Metal (appropriate charge on metal) nonmetal-ide
Explanation:
1) Write the name of transition metal as shown on the Periodic Table.
2) Write the name and charge for the non-metal.
Use the total charge on the non-metal (or polyatomic ion) find the charge on the transition metal.
3) After the name for the metal, write its charge as a Roman Numeral in parentheses. Example: Iron (II) chloride.
Which example shows a chemical change?
A evaporating water
B. melting ice
C. rust
D cutting pap
The correct answer would be C, a
chemical change.
A barge loaded with lumber and iron ore floats in a lock by a dam (a closed pool of water like a big swimming pool). If some of the cargo is thrown overboard, the level of water in the lock will ___
Answer:
Rise
Explanation:
Because the cargo has no place to go it will make the water level rise
How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lower the temperature to 335.0 K? The following physical data may be useful.
Hvap = 33.9 kJ/molHfus = 9.8 kJ/mol
Cliq = 1.73 J/g
Answer : The energy removed must be, -34.67 kJ
Solution :
The process involved in this problem are :
[tex](1):C_6H_6(l)(425.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(2):C_6H_6(l)(353.0K)\rightarrow C_6H_6(s)(353.0K)\\\\(3):C_6H_6(s)(353.0K)\rightarrow C_6H_6(s)(335.0K)[/tex]
The expression used will be:
[tex]\Delta H=[m\times c_{p,l}\times (T_{final}-T_{initial})]+m\times \Delta H_{fusion}+[m\times c_{p,s}\times (T_{final}-T_{initial})][/tex]
where,
[tex]\Delta H[/tex] = heat available for the reaction = [tex]4.50\times 10^3kJ=4.50\times 10^6J[/tex]
m = mass of benzene = 125 g
[tex]c_{p,s}[/tex] = specific heat of solid benzene = [tex]1.51J/g.K[/tex]
[tex]c_{p,l}[/tex] = specific heat of liquid benzene = [tex]1.73J/g.K[/tex]
[tex]\Delta H_{fusion}[/tex] = enthalpy change for fusion = [tex]9.8kJ/mole=9800J/mole=\frac{9800J/mole}{78g/mole}J/g=125.64J/g[/tex]
Molar mass of benzene = 78 g/mole
Now put all the given values in the above expression, we get:
[tex]\Delta H=[125g\times 1.73J/g.K\times (353-425)K]+125g\times -125.64J/g+[125g\times 1.51J/g.K\times (335-353)K][/tex]
[tex]\Delta H=-34672.5J=-34.67kJ[/tex]
Therefore, the energy removed must be, -34.67 kJ
The density of gold is 19.3g/mL. If you have a 9.00 g piece of gold, what volume will it occupy (in milliliters)
Answer:
The answer to your question is volume = 0.47 ml
Explanation:
To solve this problem use the formula of density, that relates the mass and volume.
Data
density = 19.3 g/ml
mass = 9.0 g
volume = ?
Formula
density = [tex]\frac{mass}{volume}[/tex]
Solve for volume
volume = [tex]\frac{mass}{density}[/tex]
Substitution
Volume = 9 / 19,3
Simplification and result
Volume = 0.47 ml
Final answer:
To determine the volume a 9.00 g piece of gold occupies, divide the mass of gold by its density (19.3g/mL), which calculates to approximately 0.4663 mL.
Explanation:
The question asks to find the volume occupied by a 9.00 g piece of gold, given that the density of gold is 19.3g/mL. To find the volume, we use the formula density = mass/volume, which can be rearranged to find volume as volume = mass/density.
Given:
Mass of gold = 9.00 g
Density of gold = 19.3 g/mL
Applying the values into the formula gives
volume = 9.00 g / 19.3 g/mL
, which equals approximately 0.4663 mL.
Therefore, a 9.00 g piece of gold will occupy about 0.4663 milliliters.
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of ribose was found to contain 5.692 g carbon, 0.955 g hydrogen, and 7.582 g oxygen. Show your work.
Answer:
CH2O
Explanation:
Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.
C = 5.692/14.229 * 100 = 40%
O = 7.582/14.229 * 100 = 53.29%
H = 0.955/14.229 * 100 = 6.71%
We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.
C = 40/12 = 3.333
O = 53.29/16 = 3.33
H = 6.71/2 = 6.71
Dividing by the smaller value which is 3.33
C = 3.33/3.33 = 1
O = 3.33/3.33= 1
H = 6.71/3.33 = 2
The empirical formula of the compound ribose is CH2O
Answer:
CH2O
Explanation:
First divide the given mass of each element by its relative atomic mass.
For carbon 5.692/12 = 0.47
For hydrogen 0.955/1 = 0.955
For oxygen 7.582/16= 0.47
Then we divide each by the lowest ratio
For carbon- 0.47/0.47 =1
For hydrogen- 0.955/0.47= 2
For oxygen- 0.47/0.47 = 1
Hence the empirical formula is CH2O
Jackie goes camping in the Nowhere mountains and brings a few pots and pans to cook. On top of Nowhere mountain (at 3,000 feet above sea level), Jackie realizes her soup cooks much faster than at her house in Austin, TX (at sea level). Explain why this is.
This is because of the low pressure at the mountains.
Explanation:The air pressure or atmospheric pressure is defined as the amount of pressure exerted by the air column of the atmosphere above in the atmosphere per unit area. This air pressure is inversely proportional to the height of the land above sea level. As we go up in the atmosphere, the pressure of Air decrease.
As Jackie goes in the mountains for his picnic, the pressure of air at the mountains is much lower than at her house in Austin, because Austin is at sea level. So water will boil much faster owing to low pressure. Thus, water is boiling at lower temperature. And this low temperature is easily and quickly achievable. So Austin seems that her soup is ready much faster. But the veggies and meat won't be fully cooked at that temperature. So although the soup seems to be ready, it isn't.
Which orbitals form a pi bond?
A.the s orbital and three p orbitals
B.the s orbital and two p orbitals
C.overlapping p orbitals
D.overlapping hybrid orbitals
Answer:
C.overlapping p orbitals
Explanation:
The atoms which comprises of single bond is formed by sigma bond. Sigma bond is formed by the internuclear overlapping of the atomic orbitals. They are formed due to the head on overlapping of the atomic orbitals. Since, the bond is symmetrical about the internuclear axis, it can rotate without the breakage of the bond.
On the other hand, double or triple bonds contains one or two pi bonds respectively along with one sigma bond. Pi bonds are formed by the sideways overlapping and thus they are non-symmetrical about the internuclear axis and thus it breaks if the bond is being rotated.
Thus the answer is:- C.overlapping p orbitals
Final answer:
Pi bonds are formed by the side-by-side overlap of unhybridized p orbitals on adjacent atoms, such as in the carbon atoms of an alkene. The correct answer for which orbitals form a pi bond is C: overlapping p orbitals.
Explanation:
The pi bond (π bond) typically involves the side-by-side overlap of p orbitals that are unhybridized. Notably, pi bonding can also occur with d orbitals or with p orbitals that are part of hybrid orbitals, under certain circumstances. However, in the context of this question and in typical organic structures like ethene (C₂H₄), a pi bond is the result of the sideways overlapping of p orbitals on adjacent carbon atoms. Each has one electron and is perpendicular to the line formed by the sigma bonds in the molecule.
For the given options, the correct answer is C: overlapping p orbitals, which align perpendicularly to the molecular plane formed by sigma bonds and overlap side-by-side to form a pi bond. Therefore, it is the p orbitals that must be unhybridized, as they are in the sp2 hybridization state observed in alkenes such as ethene, where each carbon atom has three sp2 hybrid orbitals in a plane and the unhybridized p orbital perpendicular to that plane leading to pi bonding.
Determine the magnitude of the acceleration experienced by an electron in an electric field of 664 N/CN/C .
Answer:
[tex]a=-1.17\times 10^{14} \hspace{3}\frac{m}{s^2}[/tex]
Explanation:
A charged particle that is in a region where there is an electric field, experiences a force equal to the product of its charge by the intensity of the electric field:
[tex]F_e=q*E[/tex]
If the electric field is uniform, the force is constant and so is the acceleration. Applying the equations of uniformly accelerated rectilinear motion, we obtain the velocity of the particle at any time or after having moved a certain distance:
[tex]a=\frac{qE}{m}[/tex] (1)
Where:
[tex]E=Electric\hspace{3}field\hspace{3}strength=664\frac{N}{C} \\q=Electric\hspace{3}charge\hspace{3}of\hspace{3}the\hspace{3}particle\\m=Mass\hspace{3}of\hspace{3}the\hspace{3}particle[/tex]
The electric charge and the mass of the electron are known constants:
[tex]q=-1.6\times 10^{-19} C\\m=9.1\times 10^{-31} kg[/tex]
So, replacing this data in the equation (1) :
[tex]a=\frac{(-1.6\times 10^{-19})*(664) }{9.1\times 10^{-31} } =-1.167472527\times 10^{14} \approx -1.17\times 10^{14} \hspace{3}\frac{m}{s^2}[/tex]
The minus sign is due to the fact that the charge is negative, therefore it experiences a force in the opposite direction to the field.
Which is the appropriate term for an alloimmune disease in which maternal blood and fetal blood are antigenically incompatible?
Answer:
Erythroblastosis fetalis
Explanation:
Erythroblastosis fetalis, occurs when there is an antigenic incompatibility between a mother and her fetus. When an antigen present in the fetus and absent in the mother crosses the placenta into the maternal circulation, maternal antibodies are produced, causing her body to sense the fetus as a foreign body to be combated. The antibodies return to the fetal circulation and result in red blood cell destruction.
This incompatibility could be in varying forms including:
Rhesus incompatibilityABO incompatibility (blood group)Minor blood group incompatibilityA 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12.6 cm/s. After the collision, the 11.7 g marble moves to the right at 23.7 cm/s. Find the velocity of the 27.3 g marble after the collision. Answer in units of cm/s.
Answer:
The answer to this is
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
Explanation:
To solve the question, let us list out the given variables and their values
Mass of first marble m1 = 27.3g
Velocity of the first marble v1 = 21.0 cm/s
Mass of second marble m2 = 11.7g
Velocity of the second marble v2 = 12.6 cm/s
After collision va1 = unknown and va2 = 23.7 cm/s
From Newton's second law of motion, force = rate of change of momentum produced
Hence m1v1 + m2v2 = m1va1 + m2va2 or
va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
A wooden cylinder 30.0 cm high floats vertically in a tub of water (density =1:00g/cm3).The Top of the cylinder is 13.5cm above the surface of the liquid. What is the density of the wood?
Explanation:
When the cylinder floats on the water the upstream pressure force acts on the wooden cylinder determines the thickness of the wooden cylinder.
When the cylinders float on the gas, the force of the upward thrust correlates to the weight of the water.
Answer is 5.3 X 10 − 3 k g / m 3
Material density is the correlation between the material's mass as well as how much room (volume) it occupies. A material is determined by the density of either the atoms, their size, and how they can be organised.
Which of the following is an example of erosion?
ions in water reacting with rocks
plant roots splitting rocks apart
wind blowing sand against a rock
a glacier carving a valley
Answer:
The answer is a!
Explanation:
Hope this helps!
Zinc citrate is an ingredient in toothpaste. It is synthesis by the reaction of zinc carbonate with citric acid. Water and Carson dioxide are also produced
Answer:
I would answer if you had a question.
The masses of reactants is always greater than the masses of the products in a chemical reaction, because the products are combined together. TRUE FALSE
Answer: False
Explanation: the masses of reactants are always the same as the products in order to conform to the law of conservation of mass.
Answer: False
Explanation:
In a chemical reaction atoms are not created or destroyed, only rearranged.
No change in mass
Cofactors are important because A. they are the building blocks of proteins. B. they signal cells to release enzymes. C. they prevent spikes in blood sugar. D. they serve to inactivate an enzyme, so as to better regulate chemical reactions. E. they enable enzymes to bind to their substrates.
Answer: E. they enable enzymes to bind to their substrates.
Explanation:
The cofactors are the molecules that help the enzyme catalyze the reactions. The Cofactor can be defined as a non-protein chemical compound that either loosely or tightly binds to the enzyme. This facilitates in performing the reactions that enzyme cannot perform alone. They can be divided into prosthetic group and coenzymes. The cofactors enhances the binding affinity of the enzymes with their substrates so that products can be formed.
Answer:
The answer is E: they enable enzymes to bind to their substrates.
Explanation:
Cofactors are inorganic substrates that are needed to: 1) produce a chemical reaction between the enzyme and the substrate, 2) increase the rate of catalysis, and 3) attach to the enzyme just like a prosthetic hand, to effectively allow enzymes carry out the catalysis of the reaction.
WHAT IS THE DEFINITION FOR ISOTOPES, WHAT ARE EXAMPLES OF ISOTOPES, WHAT ARE NON EXAMPLES OF ISOTOPES AND WHAT ARE EXAMPLES OF ISOTOPES?
WILL MAKE BRAINLIEST (THE FIRST PERSON TO ANSWER CORRECTLY)
Isotopes are versions of a chemical element with different neutron numbers. Examples are Hydrogen-1, 2, and 3. Non-examples would be different elemental atoms.
Explanation:Isotopes are variants of a particular chemical element which differ in neutron number, and consequently in nucleon number. All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom.
Examples of isotopes include Hydrogen-1 (Protium), Hydrogen-2 (Deuterium), and Hydrogen-3 (Tritium) - all are isotopes of hydrogen but have different numbers of neutrons. Non-examples of isotopes would be atoms of different elements, like a helium atom (2 protons) compared with a hydrogen atom (1 proton).
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What is the ratio of hydrogen atoms (HH) to oxygen atoms (OO) in 2 LL of water? Enter the simplest whole number ratio in order of hydrogen to oxygen, respectively. Express your answer as two integers, separated by a comma (e.g., 3,4).
Answer: 2, 1
Explanation:
Water has a formula as H2O.
Meaning it contains 2 atoms of Hydrogen and one atom of oxygen. No matter the volume of water, it will always contain 2 atoms of Hydrogen and one atom of oxygen. The ratio of hydrogen to oxygen in a water molecule is (2, 1)
Convertible bonds are examples of: a. Securities that have characteristics of both debt and equity b. Non-recurring items c. Assets d. Treasury stock
Answer:
a. Securities that have characteristics of both debt and equity
Explanation:
A convertible bond is a debt security that can be converted into a certain number of shares and this can be done during specific times in the life of the bond. According to this, convertible bonds are examples of securities that have characteristics of both debt and equity as they are a type of debt that pays interest but can be turned into shares.